Matrix view generated from two selected columns of a table - sql

Suppose i have a table containing Project_type, Project_No, OS_Platform columns. Here I have limited Project_types and limited OS_Platforms. I want a database view which produces a matrix between Project_type and OS_Platform.
MY_TABLE :
Project_Type Project_No OS_Platform
Drivers 345 Linux
WebService 453 Windows
Drivers 034 Windows
Drivers 953 Solaris
DesktopApp 840 Windows
WebService 882 Solaris
Now I have Project_type and OS_Platform as selected columns. I want a matrix view of these two columns with distinct rows and column names.
Project_Type Linux Windows Solaris
WebService null true true
Drivers true true true
DesktopApp null true null
Can anyone tell me if it is possible. How is that possible ?

You could also try using the dedicated PIVOT feature if it is supported by the SQL product you are using. For instance, the following would work in SQL Server 2005+:
SELECT *
FROM (
SELECT DISTINCT
Project_Type,
'true' AS flag,
OS_Platform
FROM MY_TABLE
) s
PIVOT (
MAX(flag)
FOR OS_Platform IN (
Linux, Windows, Solaris
)
) p
;
Oracle Database is another product that supports PIVOT, although I'm not sure in which version it was first introduced. You would be able to run the above query in Oracle after enclosing every column in the PIVOT's IN list in single quotes, like this:
... IN (
'Linux', 'Windows', 'Solaris'
)
...

This is basically a PIVOT query where you transpose your rows of data into columns. The easiest way to perform this since you want a true/null value is using an aggregate function and a CASE statement:
select project_type,
max(case when os_platform ='Linux' then 'true' else null end) Linux,
max(case when os_platform ='Windows' then 'true' else null end) Windows,
max(case when os_platform ='Solaris' then 'true' else null end) Solaris
from yourtable
group by project_type
See SQL Fiddle with Demo
The result is:
| PROJECT_TYPE | LINUX | WINDOWS | SOLARIS |
---------------------------------------------
| DesktopApp | (null) | true | (null) |
| Drivers | true | true | true |
| WebService | (null) | true | true |

You'll want to pivot/unpivot your values to transpose them into your format of choice.
Here's a google search for pivot on stack overflow. Any of these will do you fine. https://www.google.com/search?q=sql+pivot+unpivot+site%3Astackoverflow.com&oq=sql+pivot+unpivot+site%3Astackoverflow.com&aqs=chrome.0.57.9985&sugexp=chrome,mod=8&sourceid=chrome&ie=UTF-8
Now, there are 2 types of answers you'll see there. The first is a regular pivot/unpivot operation. These work very well (easily, not fast) with known data sets. That is, if you know all project types and platforms, this will work fine.
The second type is a dynamic pivot, or a pivot created by using dynamic SQL. This is messier, but allows you any combination of fields.
Good luck!

Related

SQL: aggregate and condense

I could do with something I can’t figure out how to do. I have a simple query that I need to aggregate and condense. Here is the base script:
select t.serial, t.make, t.model, t.upgrade_date, t.software_version
FROM table t
Order by t.serial
These are electrical devices that have been software upgraded (up to 3 times). The script above, of course, will provided multiple rows for the same device but with varying software versions while the make and model remain constant. I understand how to aggregate this to a single row using max to, for example, show the latest software version. However, what I need is to aggregate and have a condensed column showing EVERY software_version (in order) the device has been at.
It could look like this:
+------------------------------------------+
| Serial | Make | Model | Version_history |
+------------------------------------------+
| A Terra 1 1.1, 1.9, 2.1 |
+------------------------------------------+
Alternatively, and possibly better, it would be fine to show each software_version as a column header with ‘upgrade_date’ if the device was at that version. Actually, it would be useful to know both methods.
This could look like this:
+------------------------------------------------------------------------+
| Serial Make Model 1.1 1.9 2.1 2.3 |
+------------------------------------------------------------------------+
| A Terra 1 01-Jan-2019 17-Jun-2019 31-Dec-2019 |
+------------------------------------------------------------------------+
No doubt this is really simple but I can’t for the life of me figure it out.
Use LISTAGG:
select serial,
make,
model,
LISTAGG( software_version, ',' ) WITHIN GROUP ( ORDER BY upgrade_date )
AS Version_history,
LISTAGG( upgrade_date, ',' ) WITHIN GROUP ( ORDER BY upgrade_date )
AS Version_dates
FROM table
GROUP BY serial, make, model
Order by serial
Alternatively, and possibly better, it would be fine to show each software_version as a column header with ‘upgrade_date’ if the device was at that version.
If you know the versions then you can do this with a PIVOT:
SELECT serial,
make,
model,
"1.1",
"1.9",
"2.1",
"2.3"
FROM table
PIVOT ( MAX( upgrade_date ) FOR software_version IN (
'1.1' AS "1.1",
'1.9' AS "1.9",
'2.1' AS "2.1",
'2.3' AS "2.3"
) )
db<>fiddle
If you don't know the versions then this would be a dynamic pivot and is not a simple SQL query. You would need to use a two stage process to first generate a dynamic SQL query and then second use EXECUTE IMMEDIATE to run the query. In general, you shouldn't use dynamic pivots and, instead, transpose rows to columns in whatever programming interface you're using to access the database (Java, Python, C#, etc.).

Collecting multiple values from different rows and creating columns from them in SQL

I want to import data from one sql database to another. The database containing the data is structured differently than the one I have now.
My database has the tables Person and Person_Data
Person columns:
id(PK, int) | Person_Name(text)| Person_Data_id(FK, int)
Person_Data columns:
Person_Data_id(PK, int) | Date_Of_Birth(text)| City_Of_Birth(text) | Favorite_City(text)|
The other database has the neccesary data to populate this, but is structured a bit differently. It has these tables:
ExternalPerson, ExternalProperty
ExternalPerson columns:
|PersonID(PK, int) | Name(string) |
| 0 |"John" |
| 1 |"Bob" |
ExternalProperty columns:
|PersonId|PropertyName|PropertyAttribute|PropertyValue|
| 0 |"Birth" | "City" |"Rome" |
| 1 |"Birth" | "City" |"Vienna" |
| 0 |"Birth" | "Date" |"1982-02-01" |
| 0 |"Favorite" | "City" |"New York" |
As you can see, the external database contains information that could be inserted in the regular one. It's just that some of the columns are stored in rows instead. I want to merge it, so that, for each PersonID, we pick up the Value for Birth and City and put it in City_Of_Birth etc. The external database is structured so that each combination of PersonID, PropertName and PropertyAttribute only has one row, so there is no risk for disambiguity. All combinations of PropertyName and PropertyAttribute present in the external database also have a correcponding column in the Person_Data table. There might be missing data though, for example in our case, Bob does not have a value for date of Birth or Favorite city, in which case those entries should be null. That is, I want to transform the two tables ExternalPerson and ExternalProperty into
|id(PK, int)|Name |Date_Of_Birth|City_Of_Birth|Favorite_City|
|auto |"John"|"1982-02-01" |"Rome" |"New York" |
|increment |"Bob" | NULL |"Vienna" |NULL |
I have tried various combinations of JOIN, GROUP BY, SELECT CASE WHEN and COALESCE to no avail. I feel like this should be possible to do, but have not succeded to find the SQL commands to extract the rows from the external database into columns. For example the line
SELECT
Name,
PropertValue AS City_Of_Birth
FROM
ExternalProperty
WHERE PropertyName LIKE 'Birth' AND PropertyAttribute LIKE 'City'
will output the City_Of_Birth in a single column together with Name, but I don't know how to aggregate the result.
Does anybody have any idea on how to do this? Thanks in advance.
I am using Microsoft SQL Server Management Studio 2017 and Microsoft SQL Server 2017 (RTM) - 14.0.1000.169 (X64)
You can aggregate with MAX()
MAX(CASE WHEN PropertyName LIKE 'Birth' AND PropertyAttribute LIKE 'City' THEN PropertyValue ELSE NULL END) AS City_Of_Birth

SQL: Using row values as column headers

I'm building a fairly large table for a client, and they want the data represented in a certain way. My table is currently like this:
DATE_RECEIVED | NAME | DOB | ANALYTE | RESULT
'YYYY/MM' |STRING |'MM/DD/YYYY' | String | String
2011/03 |Name, A| 07/31/1056 | AAAA | Positive
2011/03 |Name, A| 07/31/1056 | BBBB | Negative
What I need to do is something like a pivot - each "Analyte" is to be its own column, with the "result" being the value in the column, like this:
DATE_RECEIVED | NAME | DOB | AAAA | BBBB |
2011/03 |Name, A| 07/31/1056 | Positive | Negative |
I've tried a few things with PIVOT, but I think that I'm still too novice to understand how the logic for that function works. Either that, or the version of SQL I'm using doesn't support pivoting. Looking through similar questions on this site didn't really get me any closer to solving the problem because I don't really feel like I understand my problem well enough to know what I need to do to fix it. Anyway, I'm completely stumped. If anyone could give me a place to start, that would be extremely helpful. Thanks!
...Also, I know I'm using Oracle SQL, but I don't know what version. If it helps, I'm writing everything in TOAD for Oracle version 12.6.
If you can't use PIVOT (maybe your version of Oracle doesn't support it), then it is possible to use CASE instead together with an aggregate:
SELECT date_received, name, dob
, MAX(CASE WHEN analyte = 'AAAA' THEN result END) AS aaaa
, MAX(CASE WHEN analyte = 'BBBB' THEN result END) AS bbbb
FROM mytable
GROUP BY date_received, name, dob
UPDATE: Here is how you might accomplish the same thing with PIVOT:
SELECT * FROM (
SELECT date_received, name, dob, analyte, result
FROM mytable
) PIVOT ( MAX(result) FOR (analyte) IN ('AAAA' AS a,'BBBB' AS b) );
SQL Fiddle Demo here.
Note that with a PIVOT you still need an aggregate function - MAX() will do here, and so will MIN if there is only one value! AS in the PIVOT clause names the resulting columns.
The other thing with PIVOT is that the possible values have to be explicitly named. You can get around that by using XML (read more about how to do that), but then all your results will be XML-ized.

Oracle in-line method to produce CSV for relation

I have the following tables:
ALERT (ID,Name)
1 | Alert A
2 | Alert B
ALERT_BRAND_XREF (ALERT_ID, BRAND_ID)
1 | 1
1 | 2
2 | 1
BRAND (ID, NAME)
1 | Brand A
2 | Brand B
I am trying to write one statement to return a list of alerts with the applicable brands as a CSV list in one field. Desired results:
Alert A | Brand A, Brand B
Alert B | Brand A
Is there a way to do this without writing a separate function? I would like to do it in one self-contained SQL statement if possible.
This is Oracle 9i.
In MySQL this would be easy with the GROUP_CONCAT() function, but it looks like to do the equivalent in Oracle it's a little messy:
Oracle group_concat() updated (again)
Look to this solutions, its very useful. Using SYS_CONNECT_BY_PATH and analytic functions.
Here's another way to turn a repeating group into a comma setarated list.
It uses the MODEL clause of Oracle's dialect of SQL. (Oracle 10g)
http://plsqlnotes.blogspot.com/2007/09/using-model-for-generating-csv-by_2227.html#links
(Replaces my previous wrong answer).
In oracle you can use wm_concat()
SELECT a.Name , wm_concat(b.Name) FROM
ALERT a,
ALERT_BRAND_XREF abx ,
BRAND b
where a.id = abx.ALERT_ID
and abx.BRAND_ID = b.id
group by a.Name;

Is there any difference between GROUP BY and DISTINCT

I learned something simple about SQL the other day:
SELECT c FROM myTbl GROUP BY C
Has the same result as:
SELECT DISTINCT C FROM myTbl
What I am curious of, is there anything different in the way an SQL engine processes the command, or are they truly the same thing?
I personally prefer the distinct syntax, but I am sure it's more out of habit than anything else.
EDIT: This is not a question about aggregates. The use of GROUP BY with aggregate functions is understood.
MusiGenesis' response is functionally the correct one with regard to your question as stated; the SQL Server is smart enough to realize that if you are using "Group By" and not using any aggregate functions, then what you actually mean is "Distinct" - and therefore it generates an execution plan as if you'd simply used "Distinct."
However, I think it's important to note Hank's response as well - cavalier treatment of "Group By" and "Distinct" could lead to some pernicious gotchas down the line if you're not careful. It's not entirely correct to say that this is "not a question about aggregates" because you're asking about the functional difference between two SQL query keywords, one of which is meant to be used with aggregates and one of which is not.
A hammer can work to drive in a screw sometimes, but if you've got a screwdriver handy, why bother?
(for the purposes of this analogy, Hammer : Screwdriver :: GroupBy : Distinct and screw => get list of unique values in a table column)
GROUP BY lets you use aggregate functions, like AVG, MAX, MIN, SUM, and COUNT.
On the other hand DISTINCT just removes duplicates.
For example, if you have a bunch of purchase records, and you want to know how much was spent by each department, you might do something like:
SELECT department, SUM(amount) FROM purchases GROUP BY department
This will give you one row per department, containing the department name and the sum of all of the amount values in all rows for that department.
What's the difference from a mere duplicate removal functionality point of view
Apart from the fact that unlike DISTINCT, GROUP BY allows for aggregating data per group (which has been mentioned by many other answers), the most important difference in my opinion is the fact that the two operations "happen" at two very different steps in the logical order of operations that are executed in a SELECT statement.
Here are the most important operations:
FROM (including JOIN, APPLY, etc.)
WHERE
GROUP BY (can remove duplicates)
Aggregations
HAVING
Window functions
SELECT
DISTINCT (can remove duplicates)
UNION, INTERSECT, EXCEPT (can remove duplicates)
ORDER BY
OFFSET
LIMIT
As you can see, the logical order of each operation influences what can be done with it and how it influences subsequent operations. In particular, the fact that the GROUP BY operation "happens before" the SELECT operation (the projection) means that:
It doesn't depend on the projection (which can be an advantage)
It cannot use any values from the projection (which can be a disadvantage)
1. It doesn't depend on the projection
An example where not depending on the projection is useful is if you want to calculate window functions on distinct values:
SELECT rating, row_number() OVER (ORDER BY rating) AS rn
FROM film
GROUP BY rating
When run against the Sakila database, this yields:
rating rn
-----------
G 1
NC-17 2
PG 3
PG-13 4
R 5
The same couldn't be achieved with DISTINCT easily:
SELECT DISTINCT rating, row_number() OVER (ORDER BY rating) AS rn
FROM film
That query is "wrong" and yields something like:
rating rn
------------
G 1
G 2
G 3
...
G 178
NC-17 179
NC-17 180
...
This is not what we wanted. The DISTINCT operation "happens after" the projection, so we can no longer remove DISTINCT ratings because the window function was already calculated and projected. In order to use DISTINCT, we'd have to nest that part of the query:
SELECT rating, row_number() OVER (ORDER BY rating) AS rn
FROM (
SELECT DISTINCT rating FROM film
) f
Side-note: In this particular case, we could also use DENSE_RANK()
SELECT DISTINCT rating, dense_rank() OVER (ORDER BY rating) AS rn
FROM film
2. It cannot use any values from the projection
One of SQL's drawbacks is its verbosity at times. For the same reason as what we've seen before (namely the logical order of operations), we cannot "easily" group by something we're projecting.
This is invalid SQL:
SELECT first_name || ' ' || last_name AS name
FROM customer
GROUP BY name
This is valid (repeating the expression)
SELECT first_name || ' ' || last_name AS name
FROM customer
GROUP BY first_name || ' ' || last_name
This is valid, too (nesting the expression)
SELECT name
FROM (
SELECT first_name || ' ' || last_name AS name
FROM customer
) c
GROUP BY name
I've written about this topic more in depth in a blog post
There is no difference (in SQL Server, at least). Both queries use the same execution plan.
http://sqlmag.com/database-performance-tuning/distinct-vs-group
Maybe there is a difference, if there are sub-queries involved:
http://blog.sqlauthority.com/2007/03/29/sql-server-difference-between-distinct-and-group-by-distinct-vs-group-by/
There is no difference (Oracle-style):
http://asktom.oracle.com/pls/asktom/f?p=100:11:0::::P11_QUESTION_ID:32961403234212
Use DISTINCT if you just want to remove duplicates. Use GROUPY BY if you want to apply aggregate operators (MAX, SUM, GROUP_CONCAT, ..., or a HAVING clause).
I expect there is the possibility for subtle differences in their execution.
I checked the execution plans for two functionally equivalent queries along these lines in Oracle 10g:
core> select sta from zip group by sta;
---------------------------------------------------------------------------
| Id | Operation | Name | Rows | Bytes | Cost (%CPU)| Time |
---------------------------------------------------------------------------
| 0 | SELECT STATEMENT | | 58 | 174 | 44 (19)| 00:00:01 |
| 1 | HASH GROUP BY | | 58 | 174 | 44 (19)| 00:00:01 |
| 2 | TABLE ACCESS FULL| ZIP | 42303 | 123K| 38 (6)| 00:00:01 |
---------------------------------------------------------------------------
core> select distinct sta from zip;
---------------------------------------------------------------------------
| Id | Operation | Name | Rows | Bytes | Cost (%CPU)| Time |
---------------------------------------------------------------------------
| 0 | SELECT STATEMENT | | 58 | 174 | 44 (19)| 00:00:01 |
| 1 | HASH UNIQUE | | 58 | 174 | 44 (19)| 00:00:01 |
| 2 | TABLE ACCESS FULL| ZIP | 42303 | 123K| 38 (6)| 00:00:01 |
---------------------------------------------------------------------------
The middle operation is slightly different: "HASH GROUP BY" vs. "HASH UNIQUE", but the estimated costs etc. are identical. I then executed these with tracing on and the actual operation counts were the same for both (except that the second one didn't have to do any physical reads due to caching).
But I think that because the operation names are different, the execution would follow somewhat different code paths and that opens the possibility of more significant differences.
I think you should prefer the DISTINCT syntax for this purpose. It's not just habit, it more clearly indicates the purpose of the query.
For the query you posted, they are identical. But for other queries that may not be true.
For example, it's not the same as:
SELECT C FROM myTbl GROUP BY C, D
I read all the above comments but didn't see anyone pointed to the main difference between Group By and Distinct apart from the aggregation bit.
Distinct returns all the rows then de-duplicates them whereas Group By de-deduplicate the rows as they're read by the algorithm one by one.
This means they can produce different results!
For example, the below codes generate different results:
SELECT distinct ROW_NUMBER() OVER (ORDER BY Name), Name FROM NamesTable
SELECT ROW_NUMBER() OVER (ORDER BY Name), Name FROM NamesTable
GROUP BY Name
If there are 10 names in the table where 1 of which is a duplicate of another then the first query returns 10 rows whereas the second query returns 9 rows.
The reason is what I said above so they can behave differently!
If you use DISTINCT with multiple columns, the result set won't be grouped as it will with GROUP BY, and you can't use aggregate functions with DISTINCT.
GROUP BY has a very specific meaning that is distinct (heh) from the DISTINCT function.
GROUP BY causes the query results to be grouped using the chosen expression, aggregate functions can then be applied, and these will act on each group, rather than the entire resultset.
Here's an example that might help:
Given a table that looks like this:
name
------
barry
dave
bill
dave
dave
barry
john
This query:
SELECT name, count(*) AS count FROM table GROUP BY name;
Will produce output like this:
name count
-------------
barry 2
dave 3
bill 1
john 1
Which is obviously very different from using DISTINCT. If you want to group your results, use GROUP BY, if you just want a unique list of a specific column, use DISTINCT. This will give your database a chance to optimise the query for your needs.
If you are using a GROUP BY without any aggregate function then internally it will treated as DISTINCT, so in this case there is no difference between GROUP BY and DISTINCT.
But when you are provided with DISTINCT clause better to use it for finding your unique records because the objective of GROUP BY is to achieve aggregation.
They have different semantics, even if they happen to have equivalent results on your particular data.
Please don't use GROUP BY when you mean DISTINCT, even if they happen to work the same. I'm assuming you're trying to shave off milliseconds from queries, and I have to point out that developer time is orders of magnitude more expensive than computer time.
In Teradata perspective :
From a result set point of view, it does not matter if you use DISTINCT or GROUP BY in Teradata. The answer set will be the same.
From a performance point of view, it is not the same.
To understand what impacts performance, you need to know what happens on Teradata when executing a statement with DISTINCT or GROUP BY.
In the case of DISTINCT, the rows are redistributed immediately without any preaggregation taking place, while in the case of GROUP BY, in a first step a preaggregation is done and only then are the unique values redistributed across the AMPs.
Don’t think now that GROUP BY is always better from a performance point of view. When you have many different values, the preaggregation step of GROUP BY is not very efficient. Teradata has to sort the data to remove duplicates. In this case, it may be better to the redistribution first, i.e. use the DISTINCT statement. Only if there are many duplicate values, the GROUP BY statement is probably the better choice as only once the deduplication step takes place, after redistribution.
In short, DISTINCT vs. GROUP BY in Teradata means:
GROUP BY -> for many duplicates
DISTINCT -> no or a few duplicates only .
At times, when using DISTINCT, you run out of spool space on an AMP. The reason is that redistribution takes place immediately, and skewing could cause AMPs to run out of space.
If this happens, you have probably a better chance with GROUP BY, as duplicates are already removed in a first step, and less data is moved across the AMPs.
group by is used in aggregate operations -- like when you want to get a count of Bs broken down by column C
select C, count(B) from myTbl group by C
distinct is what it sounds like -- you get unique rows.
In sql server 2005, it looks like the query optimizer is able to optimize away the difference in the simplistic examples I ran. Dunno if you can count on that in all situations, though.
In that particular query there is no difference. But, of course, if you add any aggregate columns then you'll have to use group by.
You're only noticing that because you are selecting a single column.
Try selecting two fields and see what happens.
Group By is intended to be used like this:
SELECT name, SUM(transaction) FROM myTbl GROUP BY name
Which would show the sum of all transactions for each person.
From a 'SQL the language' perspective the two constructs are equivalent and which one you choose is one of those 'lifestyle' choices we all have to make. I think there is a good case for DISTINCT being more explicit (and therefore is more considerate to the person who will inherit your code etc) but that doesn't mean the GROUP BY construct is an invalid choice.
I think this 'GROUP BY is for aggregates' is the wrong emphasis. Folk should be aware that the set function (MAX, MIN, COUNT, etc) can be omitted so that they can understand the coder's intent when it is.
The ideal optimizer will recognize equivalent SQL constructs and will always pick the ideal plan accordingly. For your real life SQL engine of choice, you must test :)
PS note the position of the DISTINCT keyword in the select clause may produce different results e.g. contrast:
SELECT COUNT(DISTINCT C) FROM myTbl;
SELECT DISTINCT COUNT(C) FROM myTbl;
I know it's an old post. But it happens that I had a query that used group by just to return distinct values when using that query in toad and oracle reports everything worked fine, I mean a good response time. When we migrated from Oracle 9i to 11g the response time in Toad was excellent but in the reporte it took about 35 minutes to finish the report when using previous version it took about 5 minutes.
The solution was to change the group by and use DISTINCT and now the report runs in about 30 secs.
I hope this is useful for someone with the same situation.
Sometimes they may give you the same results but they are meant to be used in different sense/case. The main difference is in syntax.
Minutely notice the example below. DISTINCT is used to filter out the duplicate set of values. (6, cs, 9.1) and (1, cs, 5.5) are two different sets. So DISTINCT is going to display both the rows while GROUP BY Branch is going to display only one set.
SELECT * FROM student;
+------+--------+------+
| Id | Branch | CGPA |
+------+--------+------+
| 3 | civil | 7.2 |
| 2 | mech | 6.3 |
| 6 | cs | 9.1 |
| 4 | eee | 8.2 |
| 1 | cs | 5.5 |
+------+--------+------+
5 rows in set (0.001 sec)
SELECT DISTINCT * FROM student;
+------+--------+------+
| Id | Branch | CGPA |
+------+--------+------+
| 3 | civil | 7.2 |
| 2 | mech | 6.3 |
| 6 | cs | 9.1 |
| 4 | eee | 8.2 |
| 1 | cs | 5.5 |
+------+--------+------+
5 rows in set (0.001 sec)
SELECT * FROM student GROUP BY Branch;
+------+--------+------+
| Id | Branch | CGPA |
+------+--------+------+
| 3 | civil | 7.2 |
| 6 | cs | 9.1 |
| 4 | eee | 8.2 |
| 2 | mech | 6.3 |
+------+--------+------+
4 rows in set (0.001 sec)
Sometimes the results that can be achieved by GROUP BY clause is not possible to achieved by DISTINCT without using some extra clause or conditions. E.g in above case.
To get the same result as DISTINCT you have to pass all the column names in GROUP BY clause like below. So see the syntactical difference. You must have knowledge about all the column names to use GROUP BY clause in that case.
SELECT * FROM student GROUP BY Id, Branch, CGPA;
+------+--------+------+
| Id | Branch | CGPA |
+------+--------+------+
| 1 | cs | 5.5 |
| 2 | mech | 6.3 |
| 3 | civil | 7.2 |
| 4 | eee | 8.2 |
| 6 | cs | 9.1 |
+------+--------+------+
Also I have noticed GROUP BY displays the results in ascending order by default which DISTINCT does not. But I am not sure about this. It may be differ vendor wise.
Source : https://dbjpanda.me/dbms/languages/sql/sql-syntax-with-examples#group-by
In terms of usage, GROUP BY is used for grouping those rows you want to calculate. DISTINCT will not do any calculation. It will show no duplicate rows.
I always used DISTINCT if I want to present data without duplicates.
If I want to do calculations like summing up the total quantity of mangoes, I will use GROUP BY
In Hive (HQL), GROUP BY can be way faster than DISTINCT, because the former does not require comparing all fields in the table.
See: https://sqlperformance.com/2017/01/t-sql-queries/surprises-assumptions-group-by-distinct.
The way I always understood it is that using distinct is the same as grouping by every field you selected in the order you selected them.
i.e:
select distinct a, b, c from table;
is the same as:
select a, b, c from table group by a, b, c
Funtional efficiency is totally different.
If you would like to select only "return value" except duplicate one, use distinct is better than group by. Because "group by" include ( sorting + removing ) , "distinct" include ( removing )
Generally we can use DISTINCT for eliminate the duplicates on Specific Column in the table.
In Case of 'GROUP BY' we can Apply the Aggregation Functions like
AVG, MAX, MIN, SUM, and COUNT on Specific column and fetch
the column name and it aggregation function result on the same column.
Example :
select specialColumn,sum(specialColumn) from yourTableName group by specialColumn;
There is no significantly difference between group by and distinct clause except the usage of aggregate functions.
Both can be used to distinguish the values but if in performance point of view group by is better.
When distinct keyword is used , internally it used sort operation which can be view in execution plan.
Try simple example
Declare #tmpresult table
(
Id tinyint
)
Insert into #tmpresult
Select 5
Union all
Select 2
Union all
Select 3
Union all
Select 4
Select distinct
Id
From #tmpresult