I have a list of data need to be grouped, but we only want to group data that count are greater than 3.
AA
AA
BB
CCC
CCC
CCC
return
AA 1
AA 1
BB 1
CCC 3
Thank you for your help
select data, case when total < 3 then 1 else total end total
from
(
select data, Count(Data) Total
from tbl
group by data
) g
join (select 1 union all select 2) a(b)
on a.b <= case when total < 3 then Total else 1 end
order by data
This should perform faster than LittleBobbyTables's answer most of the time.
Off the top of my head, you could use a get a count of everything with a count greater than 2, and then use UNION ALL to get any records not in the first query:
SELECT 'AA' AS Data
INTO #Temp
UNION ALL SELECT 'AA'
UNION ALL SELECT 'BB'
UNION ALL SELECT 'CCC'
UNION ALL SELECT 'CCC'
UNION ALL SELECT 'CCC'
SELECT Data, COUNT(Data) AS MyCount
FROM #Temp
GROUP BY Data
HAVING COUNT(Data) > 2
UNION ALL
SELECT Data, 1
FROM #Temp
WHERE Data NOT IN (
SELECT Data
FROM #Temp
GROUP BY Data
HAVING COUNT(Data) > 2
)
ORDER BY Data
DROP TABLE #Temp
Use the window functions for this:
select col, count(*) as cnt
from (select col, count(*) over (partition by col) as colcnt,
row_number() over (order by (select NULL)) as seqnum
from t
) t
group by col, (case when colcnt < 3 then seqnum else NULL end)
This calculates the total count over the column and a unique identifier for each row. The group by clause then tests for the condition. If less than 3, then it uses the identifier to get each row. If greater, it uses a constant value (NULL) in this case.
Related
I have below Data and need to select all columns with sum of one column
id size desc1, desc2
1 13 xxx yyy
1 13 xxx yyy
1 10 mmm kkk
1 10 mmm kkk
I need below output
id **total_size** desc1 des2
1 23 xxx yyy
1 23 xxx yyy
1 23 mmm kkk
1 23 mmm kkk
total_size should be sum (distinct size)
select a.id
,a.size
,sum(b.size) as 'total_size'
,a.desc1
,a.desc2
from (
select *, row_number() over (order by id, size, desc1, desc2) as 'RowNumber'
from #tmp
) a
left join (
select *, row_number() over(partition by id, size order by id) as 'dupe'
from #tmp
) b
on a.id = b.id
and b.dupe=1
group by a.RowNumber
,a.id
,a.size
,a.desc1
,a.desc2
Not here to argue, but you should really consider reviewing the data structure you're working with.
Select your data, adding a column to number the rows
Join a copy of your data (with distinct records only)
Sum the size column from the list of distinct records
You just need to add sum(distinct "size") over (partition by id) for computing total_size column for each row in your SQL :
with tab(id,"size","desc1","desc2") as
(
select 1 ,13,'xxx','yyy' from dual union all
select 1 ,13,'xxx','yyy' from dual union all
select 1 ,10,'mmm','kkk' from dual union all
select 1 ,10,'mmm','kkk' from dual
)
select t.id,
sum(distinct t."size") over (partition by id) as "total_size",
t."desc1",t."desc2"
from tab t;
P.S. size is a reserved keyword, so, cannot be used as a column name, unless quoted. as "size"
I have rows that look like .
OrderNo OrderStatus SomeOtherColumn
A 1
A 1
A 3
B 1 X
B 1 Y
C 2
C 3
D 2
I want to return all orders that have only one possible value of orderstatus. For e.g Here order B has only order status 1 SO result should be
B 1 X
B 1 Y
Notes:
Rows can be duplicated with same order status. For e.g. B here.
I am interested in the order having a very peculiar status for e.g. 1 here and not having any other status. So if B had a status of 3 at any point of time it is disqualified.
You can use not exists:
select t.*
from t
where not exists (select 1
from t t2
where t.orderno = t2.orderno and t.OrderStatus = t2.OrderStatus
);
If you just want the orders where this is true, you can use group by and having:
select orderno
from t
group by orderno
having min(OrderStatus) = max(OrderStatus);
If you only want a status of 1 then add max(OrderStatus) = 1 to the having clause.
Here is one way to do it. It does not handle the case where the status can be NULL; if that is possible, you will need to explain how you want it handled.
SQL> create table test_data ( orderno, status, othercol ) as (
2 select 'A', 1, null from dual union all
3 select 'A', 1, null from dual union all
4 select 'A', 3, null from dual union all
5 select 'B', 1, 'X' from dual union all
6 select 'B', 1, 'Y' from dual union all
7 select 'C', 2, null from dual union all
8 select 'C', 3, null from dual union all
9 select 'D', 2, null from dual
10 );
Table created.
SQL> variable input_status number
SQL> exec :input_status := 1
PL/SQL procedure successfully completed.
SQL> column orderno format a8
SQL> column othercol format a8
SQL> select orderno, status, othercol
2 from (
3 select t.*, count(distinct status) over (partition by orderno) as cnt
4 from test_data t
5 )
6 where status = :input_status
7 and cnt = 1
8 ;
ORDERNO STATUS OTHERCOL
-------- ---------- --------
B 1 X
B 1 Y
One way to handle NULL status (if that may happen), if in that case the orderno should be rejected (not included in the output), is to define the cnt differently:
count(case when status != :input_status or status is null then 1 end)
over (partition by orderno) as cnt
and in the outer query change the WHERE clause to a single condition,
where cnt = 0
Count distinct OrderStatus partitioned by OrderNo and show only rows where number equals one:
select OrderNo, OrderStatus, SomeOtherColumn
from ( select t.*, count(distinct orderstatus) over (partition by orderno) cnt
from t )
where cnt = 1
SQLFiddle demo
Just wanted to add something to Gordon's answer, using a stats function:
select orderno
from t
group by orderno
having variance(orderstatus) = 0;
I have a table in which I have multiple IDs which can have a value or 0. The IDs come from different sources so I would like to know what is the percentage of IDs with the value 0 as a percentage of total IDs, for each source file.
Sample Data:
ID Source
1 aaa
0 aaa
2 bbb
0 ccc
3 ccc
0 ccc
5 aaa
0 bbb
6 bbb
7 bbb
I need to display Output like:
CountOfIDs0 TotalIDs Source PercentageIDs0
2 3 ccc 66.6%%
1 3 aaa 33.3%%
1 4 bbb 25%
Thanks!
If you want a result like 66.6% rather than 66.7%, you would use trunc() rather than round() (although the latter is probably better). And you need to round a/b to three decimal places, so there is one left after you multiply by 100.
Then, you can have both counts in one query, and you can add the percentage calculation also in the same query.
select count(case when propkey = 0 then 1 end) countid0,
count(propkey) totalidcount,
source,
to_char(round(count(case when properkey = 0 then 1 end)/count(properkey), 3)*100)
|| '%' percentageids0
from......
Apply round function.
select count(id) as TotalIDs ,Source, sum(case when id=0 then 1 end) countid0,
to_char((sum(case when id=0 then 1 end)/count(id))*100)||'%' as PercentageIDs0
from Table1 group by Source
For Unique record you have to use DISTINCT Query
I would do it that way:
With MyRows AS (
SELECT 1 ID, 'aaa' SOURCE FROM DUAL UNION ALL
SELECT 0, 'aaa' FROM DUAL UNION ALL
SELECT 2, 'bbb' FROM DUAL UNION ALL
SELECT 0, 'ccc' FROM DUAL UNION ALL
SELECT 3, 'ccc' FROM DUAL UNION ALL
SELECT 0, 'ccc' FROM DUAL UNION ALL
SELECT 5, 'aaa' FROM DUAL UNION ALL
SELECT 0, 'bbb' FROM DUAL UNION ALL
SELECT 6, 'bbb' FROM DUAL UNION ALL
SELECT 7, 'bbb' FROM DUAL
)
SELECT
DISTINCT SOURCE,
SUM(CASE WHEN ID = 0 THEN 1 ELSE 0 END) OVER (PARTITION BY SOURCE) ZERO_IDS,
COUNT(ID) OVER (PARTITION BY SOURCE) TOTAL_IDS,
(100 * SUM(CASE WHEN ID = 0 THEN 1 ELSE 0 END) OVER (PARTITION BY SOURCE))/(COUNT(ID) OVER (PARTITION BY SOURCE)) PERCENTAGE
FROM MyRows
;
I calculated percentage of values in a column by using below query
Select A.,B., to_char((A.count_service/B.count_total)*100)||'%' from
(Select type_cd, count(type_cd) as count_type
from table1
group by type_cd) A
cross join
(Select count(type_cd) as count_total
from table1) B ;
select Source,
ROUND(100*number/sum(number) OVER (PARTITION BY p),2) as percentage,
sum(number) OVER (PARTITION BY p) as total
from(
select 1 p,
Source ,
count(Source) number
from declaration_assessment_result
GROUP by Source
)x
I want to achieve a running value, but condition is reset on some specific column value.
Here is my select statement:
with tbl(emp,salary,ord) as
(
select 'A',1000,1 from dual union all
select 'B',1000,2 from dual union all
select 'K',1000,3 from dual union all
select 'A',1000,4 from dual union all
select 'B',1000,5 from dual union all
select 'D',1000,6 from dual union all
select 'B',1000,7 from dual
)
select * from tbl
I want to reset count on emp B if the column value is B, then count is reset to 0 and started again increment by 1:
emp salary ord running_count
A 1000 1 0
B 1000 2 1
K 1000 3 0
A 1000 4 1
B 1000 5 2
D 1000 6 0
B 1000 7 1
Here order column is ord.
I want to achieve the whole thing by select statement, not using the cursor.
You want to define groups were the counting takes place. Within a group, the solution is row_number().
You can define the group by doing a cumulative sum of B values. Because B ends the group, you want to count the number of B after each record.
This results in:
select t.*,
row_number() over (partition by grp order by ord) - 1 as running_count
from (select t.*,
sum(case when emp = 'B' then 1 else 0 end) over (order by ord desc) as grp
from tbl t
) t;
Let's say I have a data
ID
AAA
ABB
ABC
BDS
BRD
CXD
DCU
ETS
I would like to count distinct to a first letter rows and get the number of their appearance to the right. Sorry I know I am not a very good user of a technical language, but I am new to SQL and English is not my first language.
So by script I would like to return
ID Total
A 3
B 2
C 1
D 1
E 1
I have tried
select left(id,1), count(left(id,1) as Total
from Places
group by Id
order by Total desc;
, but it didn't work. Your help will be greatly appreciated.
select left(id,1), count(*) as Total
from Places
group by left(id,1)
order by Total desc;
Is this you need?
declare #t table(val varchar(10))
insert into #t
select 'AAA' union all
select 'ABB' union all
select 'ABC' union all
select 'BDS' union all
select 'BRD' union all
select 'CXD' union all
select 'DCU' union all
select 'ETS'
select left(t1.val,1) as id ,count(t1.val) as total from #t as t1 left join
(
select distinct right(val,1) as val from #t
) as t2 on t1.val =t2.val
group by left(t1.val,1)
Result is
id total
---- -----------
A 3
B 2
C 1
D 1
E 1