Read Number of lines in Large Text File VB6 - vba

Question

I have text File of Size 230MB. I want to Count Number of Lines OF that File.
I tried "Scripting.FileSystemOblect" but it goes out Of memory.
Please Help.
Thanks.

Answer 1

Normal Windows line breaks are CRLF, so you can count the LFs and add 1 to the count in cases where the last line of your files doesn't have one after it.
In true VB (i.e. VB5, VB6, etc.) you can make use of the byte-oriented String operations to speed many tasks. If we can assume the text files contain ANSI then this is pretty fast:
Option Explicit
Private Sub Main()
Const BUFSIZE As Long = 100000
Dim T0 As Single
Dim LfAnsi As String
Dim F As Integer
Dim FileBytes As Long
Dim BytesLeft As Long
Dim Buffer() As Byte
Dim strBuffer As String
Dim BufPos As Long
Dim LineCount As Long
T0 = Timer()
LfAnsi = StrConv(vbLf, vbFromUnicode)
F = FreeFile(0)
Open "big.txt" For Binary Access Read As #F
FileBytes = LOF(F)
ReDim Buffer(BUFSIZE - 1)
BytesLeft = FileBytes
Do Until BytesLeft = 0
If BufPos = 0 Then
If BytesLeft < BUFSIZE Then ReDim Buffer(BytesLeft - 1)
Get #F, , Buffer
strBuffer = Buffer 'Binary copy of bytes.
BytesLeft = BytesLeft - LenB(strBuffer)
BufPos = 1
End If
Do Until BufPos = 0
BufPos = InStrB(BufPos, strBuffer, LfAnsi)
If BufPos > 0 Then
LineCount = LineCount + 1
BufPos = BufPos + 1
End If
Loop
Loop
Close #F
'Add 1 to LineCount if last line of your files do not
'have a trailing CrLf.
MsgBox "Counted " & Format$(LineCount, "#,##0") & " lines in" & vbNewLine _
& Format$(FileBytes, "#,##0") & " bytes of text." & vbNewLine _
& Format$(Timer() - T0, "0.0#") & " seconds."
End Sub
Given a 7,000,000 line file of 293MB it only takes 0.7 seconds here. But note that I had not rebooted to ensure that the file wasn't cached when I ran that test. Without caching (i.e. after a reboot) I'd expect it to take as long as 5 times that.
Converting to handle Unicode text files is fairly simple. Just replace the B-functions by the non-B equivalents, make sure you set BUFSIZE to a multiple of 2, and search for vbLf instead of an ANSI LF byte.

Answer 2

You can do it by reading each line into the same variable. There's no need to save all the lines:
dim s as string
dim n as integer
open "filename.txt" for input as 1
n = 0
do while not eof(1)
line input #1, s
n = n + 1
loop
This has not been tested, and it's been a while since I've done any VB6, but it should be close.

Answer 3

This takes about 6 seconds for me on a 480mb binary file with 1mil+ 0xD (vbcr)
Dim buff() As Byte
Dim hF As Integer
Dim i As Long, n As Long
hF = FreeFile(0)
Open "c:\windows\Installer\2f91fd.msp" For Binary Access Read As #hF
ReDim buff(LOF(hF) - 1)
Get #hF, , buff()
Close #hF
For i = 0 To UBound(buff)
If buff(i) = 13 Then n = n + 1
Next
MsgBox n