Sql query: Link data to all days between two given dates - sql

I have a table with that looks like
Date | BookID | Rating | Review
2012-10-12 | 2 | 3 | 3
2012-10-13 | 2 | 7 | 9
2012-10-16 | 3 | 4 | 2
Each day, a book can receive a number of rating and review
I am trying to write a query that given two dates, it displays the rating and review for each book, for EACH day in between the two given dates. Even when that day has no rating or no review I still want to display the date and the BookID
For example, in the table above, I want the query to return something like
Date | BookID | Rating | Review
2012-10-12 | 2 | 3 | 3
2012-10-13 | 2 | 7 | 9
2012-10-14 | 2 | null | null
2012-10-15 | 2 | null | null
2012-10-16 | 3 | 4 | 2
How can I do this please?

--set up test data
DECLARE #Reviews TABLE([Date] date, BookId int, Rating int, Review int)
INSERT INTO #Reviews VALUES
('2012-10-12', 2, 3, 3),
('2012-10-13', 2, 7, 9),
('2012-10-16', 3, 4, 2)
--setup query parameters
DECLARE #StartDate date,
#EndDate date
SELECT #StartDate = '2012-10-12',
#EndDate = '2012-10-16'
--run query
;WITH IntervalSet AS
(
SELECT #StartDate AS [Date]
UNION ALL
SELECT DATEADD(DAY,1,[Date]) AS [Date]
FROM IntervalSet
WHERE DATEADD(DAY,1,[Date])<=#EndDate
)
SELECT I.[Date], B.BookId, R.Rating, R.Review
FROM
(
SELECT BookId, Min([Date]) as EarliestDate
FROM #Reviews
GROUP BY BookId
) B
JOIN IntervalSet I
ON I.[Date] >= b.EarliestDate
LEFT
JOIN #Reviews R
ON R.[Date] = I.[Date]
AND R.BookId = B.BookId
ORDER BY I.[Date], B.BookId
OPTION(MAXRECURSION 0)
This gives the results:
Date BookId Rating Review
---------- ----------- ----------- -----------
2012-10-12 2 3 3
2012-10-13 2 7 9
2012-10-14 2 NULL NULL
2012-10-15 2 NULL NULL
2012-10-16 2 NULL NULL
2012-10-16 3 4 2
That's one extra row than the results you posted, but I believe is correct - it doesn't return any rows for a bookid before the first review which looks like what you were after

Something like this:
SQLFIDDLEEXAMPLE
WITH mycte AS
(
SELECT cast('2012-01-01' AS datetime) DateValue
UNION ALL
SELECT DateValue + 1
FROM mycte
WHERE DateValue + 1 < '2014-12-31'
)
SELECT
CONVERT(char(10), mycte.DateValue,126) as Date,
b.BookID,
(SELECT Rating FROM tbl WHERE BookID = b.BookID
AND Date = mycte.DateValue) as Rating,
(SELECT Review FROM tbl WHERE BookID = b.BookID
AND Date = mycte.DateValue) as Review
FROM mycte, (SELECT distinct BookID
FROM tbl) b
WHERE mycte.DateValue >= '2012-10-12'
AND mycte.DateValue <= '2012-10-15'
OPTION (MAXRECURSION 0)
Result:
| DATE | BOOKID | RATING | REVIEW |
-----------------------------------------
| 2012-10-12 | 2 | 3 | 3 |
| 2012-10-12 | 3 | (null) | (null) |
| 2012-10-13 | 2 | 7 | 9 |
| 2012-10-13 | 3 | (null) | (null) |
| 2012-10-14 | 2 | (null) | (null) |
| 2012-10-14 | 3 | (null) | (null) |
| 2012-10-15 | 2 | (null) | (null) |
| 2012-10-15 | 3 | (null) | (null) |

Related

SQL Server Get all Birthday Years

I have a table in SQL Server that is Composed of
ID, B_Day
1, 1977-02-20
2, 2001-03-10
...
I want to add rows to this table for each year of a birthday, up to the current birthday year.
i.e:
ID, B_Day
1,1977-02-20
1,1978-02-20
1,1979-02-20
...
1,2020-02-20
2, 2001-03-10
2, 2002-03-10
...
2, 2019-03-10
I'm struggling to determine what the best strategy for accomplishing this. I thought about recursively self-joining, but that creates far too many layers. Any suggestions?
The following should work
with row_gen
as (select top 200 row_number() over(order by name)-1 as rnk
from master..spt_values
)
select a.id,a.b_day,dateadd(year,rnk,b_day) incr_b_day
from dbo.t a
join row_gen b
on dateadd(year,b.rnk,a.b_day)<=getdate()
https://dbfiddle.uk/?rdbms=sqlserver_2017&fiddle=0d06c95e1914ca45ca192d0d192bd2e0
You can use recursive approach :
with cte as (
select t.id, t.b_day, convert(date, getdate()) as mx_dt
from table t
union all
select c.id, dateadd(year, 1, c.b_day), c.mx_dt
from cte c
where dateadd(year, 1, c.b_day) < c.mx_dt
)
select c.id, c.b_day
from cte c
order by c.id, c.b_day;
Default recursion is 100, you can add query hint for more recursion option (maxrecursion 0).
If your dataset is not too big, one option is to use a recursive query:
with cte as (
select id, b_day bday0, b_day, 1 lvl from mytable
union all
select
id,
bday0,
dateadd(year, lvl, bday0), lvl + 1
from cte
where dateadd(year, lvl, bday0) <= getdate()
)
select id, b_day from cte order by id, b_day
Demo on DB Fiddle:
id | b_day
-: | :---------
1 | 1977-02-20
1 | 1978-02-20
1 | 1979-02-20
1 | 1980-02-20
1 | 1981-02-20
1 | 1982-02-20
1 | 1983-02-20
1 | 1984-02-20
1 | 1985-02-20
1 | 1986-02-20
1 | 1987-02-20
1 | 1988-02-20
1 | 1989-02-20
1 | 1990-02-20
1 | 1991-02-20
1 | 1992-02-20
1 | 1993-02-20
1 | 1994-02-20
1 | 1995-02-20
1 | 1996-02-20
1 | 1997-02-20
1 | 1998-02-20
1 | 1999-02-20
1 | 2000-02-20
1 | 2001-02-20
1 | 2002-02-20
1 | 2003-02-20
1 | 2004-02-20
1 | 2005-02-20
1 | 2006-02-20
1 | 2007-02-20
1 | 2008-02-20
1 | 2009-02-20
1 | 2010-02-20
1 | 2011-02-20
1 | 2012-02-20
1 | 2013-02-20
1 | 2014-02-20
1 | 2015-02-20
1 | 2016-02-20
1 | 2017-02-20
1 | 2018-02-20
1 | 2019-02-20
1 | 2020-02-20
2 | 2001-03-01
2 | 2002-03-01
2 | 2003-03-01
2 | 2004-03-01
2 | 2005-03-01
2 | 2006-03-01
2 | 2007-03-01
2 | 2008-03-01
2 | 2009-03-01
2 | 2010-03-01
2 | 2011-03-01
2 | 2012-03-01
2 | 2013-03-01
2 | 2014-03-01
2 | 2015-03-01
2 | 2016-03-01
2 | 2017-03-01
2 | 2018-03-01
2 | 2019-03-01
2 | 2020-03-01

Count previous row only if > 2 days later

In SQL Server 2012 using Studio: I need results displayed count of distinct clientnumbers (CN) for re-entry, grouped by Type like this:
Type CountOfCN
5 1
10 3
Only a RE-entry counts (ENTRY_NO 1 never counts) and it has to be more than 2 days after the end of the previous entry for that clientnumber. So basically ENTRY_NO 1 doesn't count. ENTRY_NO 2 counts if it's startdate is more than 2 days after the enddate of ENTRY_NO 1, and so on with ENTRY_NO 3, 4, 5.
I got ENTRY_NO by doing a ROW_NUMBER function when I created the table. I have no idea how to go about creating a datediff or dateadd function (?) to look at the previous row's enddate and calculate it with my startdate for each CN?
Here is my table:
CN STARTDATE ENDDATE TYPE ENTRY_NO
1 1/1/2018 1/20/2018 10 1
1 1/21/2018 1/30/2018 5 2
1 2/3/2018 NULL 10 3
2 1/1/2018 1/20/2018 10 1
2 1/27/2018 1/30/2018 10 2
3 1/1/2018 1/20/2018 5 1
3 1/27/2018 1/30/2018 10 2
3 2/10/2018 2/20/2018 5 3
4 1/7/2018 1/30/2018 5 1
5 1/27/2018 1/30/2018 5 1
5 1/31/2018 NULL 5 2
So the rows that should be in the results are ENTRY_NO 2 for CN 1, ENTRY_NO 2 for CN 2, ENTRY_NO 2 & 3 for CN 3.
Only the last Entry may/may not have a NULL enddate
Using the LAG window function you can get the previous enddate.
SELECT *
FROM
(
SELECT * ,
LAG(ENDDATE) OVER (PARTITION BY CN ORDER BY STARTDATE) AS prevEndDate
FROM yourtable
) q
WHERE DATEDIFF(d, prevEndDate, STARTDATE) > 2
AND ENDDATE IS NOT NULL
Inner join the table to itself on the conditions you want to enforce:
Can't be Entry_No 1
The Entry_No on one side is one greater than on the other side
Previous Entry must be more than 2 days earlier
Both sides of the join have the same CN
Use that join to create a CTE or derived table, and then SELECT from it, grouping by Type and getting the COUNT(*)
So this ended up being more involved than I first thought, but here it goes...
You can run this example in SSMS.
Create a table variable matching your definition above:
DECLARE #data TABLE ( CN INT, STARTDATE DATETIME, ENDDATE DATETIME, [TYPE] INT, ENTRY_NO INT );
Insert data given:
INSERT INTO #data ( CN, STARTDATE, ENDDATE, [TYPE], ENTRY_NO ) VALUES
( 1, '1/1/2018', '1/20/2018', 10, 1 )
, ( 1, '1/21/2018', '1/30/2018', 5, 2 )
, ( 1, '2/3/2018', NULL, 10, 3 )
, ( 2, '1/1/2018', '1/20/2018', 10, 1 )
, ( 2, '1/27/2018', '1/30/2018', 10, 2 )
, ( 3, '1/1/2018', '1/20/2018', 5, 1 )
, ( 3, '1/27/2018', '1/30/2018', 10, 2 )
, ( 3, '2/10/2018', '2/20/2018', 5, 3 )
, ( 4, '1/7/2018', '1/30/2018', 5, 1 )
, ( 5, '1/27/2018', '1/30/2018', 5, 1 )
, ( 5, '1/31/2018', NULL, 5, 2 );
Confirm inserted data:
+----+-------------------------+-------------------------+------+----------+
| CN | STARTDATE | ENDDATE | TYPE | ENTRY_NO |
+----+-------------------------+-------------------------+------+----------+
| 1 | 2018-01-01 00:00:00.000 | 2018-01-20 00:00:00.000 | 10 | 1 |
| 1 | 2018-01-21 00:00:00.000 | 2018-01-30 00:00:00.000 | 5 | 2 |
| 1 | 2018-02-03 00:00:00.000 | NULL | 10 | 3 |
| 2 | 2018-01-01 00:00:00.000 | 2018-01-20 00:00:00.000 | 10 | 1 |
| 2 | 2018-01-27 00:00:00.000 | 2018-01-30 00:00:00.000 | 10 | 2 |
| 3 | 2018-01-01 00:00:00.000 | 2018-01-20 00:00:00.000 | 5 | 1 |
| 3 | 2018-01-27 00:00:00.000 | 2018-01-30 00:00:00.000 | 10 | 2 |
| 3 | 2018-02-10 00:00:00.000 | 2018-02-20 00:00:00.000 | 5 | 3 |
| 4 | 2018-01-07 00:00:00.000 | 2018-01-30 00:00:00.000 | 5 | 1 |
| 5 | 2018-01-27 00:00:00.000 | 2018-01-30 00:00:00.000 | 5 | 1 |
| 5 | 2018-01-31 00:00:00.000 | NULL | 5 | 2 |
+----+-------------------------+-------------------------+------+----------+
Run SQL to get type count given your business rules:
ENTRY_NO must be greater than 1
Current CN ENDDATE must be greater than 2 days from previous ENDDATE
T-SQL:
SELECT
[TYPE], COUNT( DISTINCT CN ) AS ClientCount
FROM #data
WHERE
CN IN (
SELECT DISTINCT CN FROM (
SELECT
dat.CN
, dat.ENTRY_NO
, dat.[TYPE]
, DATEDIFF( DD
, LAG( ENDDATE, 1, NULL ) OVER ( PARTITION BY CN ORDER BY CN, ENDDATE ) -- gets enddate for previous CN entry
, ENDDATE
) AS DayDiff
FROM #data dat
) AS Clients
WHERE
Clients.ENTRY_NO >= 2
AND Clients.DayDiff > 2
)
GROUP BY
[TYPE]
ORDER BY
[TYPE];
Returns:
+------+-------------+
| TYPE | ClientCount |
+------+-------------+
| 5 | 2 |
| 10 | 3 |
+------+-------------+
A quick look at the IN subquery shows us that CNs 1, 2, and 3 will be included during the "TYPE" count.
SELECT
dat.CN
, dat.ENTRY_NO
, dat.[TYPE]
, DATEDIFF( DD
, LAG( ENDDATE, 1, NULL ) OVER ( PARTITION BY CN ORDER BY CN, ENDDATE ) -- gets enddate for previous CN entry
, ENDDATE
) AS DayDiff
FROM #data dat
ORDER BY
dat.CN, dat.ENTRY_NO;
+----+----------+------+---------+
| CN | ENTRY_NO | TYPE | DayDiff |
+----+----------+------+---------+
| 1 | 1 | 10 | NULL |
| 1 | 2 | 5 | 10 |
| 1 | 3 | 10 | NULL |
| 2 | 1 | 10 | NULL |
| 2 | 2 | 10 | 10 |
| 3 | 1 | 5 | NULL |
| 3 | 2 | 10 | 10 |
| 3 | 3 | 5 | 21 |
| 4 | 1 | 5 | NULL |
| 5 | 1 | 5 | NULL |
| 5 | 2 | 5 | NULL |
+----+----------+------+---------+

Get list of counts by date

I have two tables. One containing a list of applications. And another one containing counts associated to them every week. Now I want to get as a result the app name and the count for this week and the previous. Let me explain this.
app:
+----+-------------+
| id | name |
+----+-------------+
| 1 | Office 2007 |
+----+-------------+
| 2 | Office 2010 |
+----+-------------+
| 3 | Office 2013 |
+----+-------------+
count:
+----+--------+-------+------------+
| id | app_id | count | date |
+----+--------+-------+------------+
| 1 | 1 | 200 | 2016-01-11 |
+----+--------+-------+------------+
| 2 | 2 | 500 | 2016-01-11 |
+----+--------+-------+------------+
| 3 | 3 | 750 | 2016-01-11 |
+----+--------+-------+------------+
| 4 | 1 | 180 | 2016-01-18 |
+----+--------+-------+------------+
| 5 | 2 | 378 | 2016-01-18 |
+----+--------+-------+------------+
| 6 | 3 | 1000 | 2016-01-18 |
+----+--------+-------+------------+
And this is the result I need. I need all the applications with the count of this week and the previous:
+-------------+-----------------+-----------------+
| app | count_this_week | count_prev_week |
+-------------+-----------------+-----------------+
| Office 2007 | 180 | 200 |
+-------------+-----------------+-----------------+
| Office 2010 | 378 | 500 |
+-------------+-----------------+-----------------+
| Office 2013 | 1000 | 750 |
+-------------+-----------------+-----------------+
A script runs every week which fills the count table. And now I need to get a report also on a weekly basis.
Honestly I'm a bit lost as I don't know how to declare the conditions for the columns.
You can try to group first by DATEPART(WEEK,C.date),name and then split the counts into 2 columns using another GROUP BY. Something like this
EDIT
If there are exactly 1 record per week per app, you can do with just one group by like this.
SELECT
appname,
SUM(CASE WHEN weekno = 0 THEN sumcount ELSE 0 END) as thisweek,
SUM(CASE WHEN weekno = 1 THEN sumcount ELSE 0 END) as lastweek
FROM
(
SELECT
DATEPART(WEEK,CURRENT_TIMESTAMP) - DATEPART(WEEK,C.date) as weekno,
name as appname,
count as sumcount
FROM App A
INNER JOIN CountTable C ON A.[id] = C.[app_id]
WHERE DATEPART(WEEK,C.date) BETWEEN DATEPART(WEEK,CURRENT_TIMESTAMP) - 1 AND DATEPART(WEEK,CURRENT_TIMESTAMP)
)T
GROUP BY appname
Query
SELECT
appname,
SUM(CASE WHEN weekno = 0 THEN sumcount ELSE 0 END) as thisweek,
SUM(CASE WHEN weekno = 1 THEN sumcount ELSE 0 END) as lastweek
FROM
(
SELECT
DATEPART(WEEK,CURRENT_TIMESTAMP) - DATEPART(WEEK,C.date) as weekno,
name as appname,
SUM(count) as sumcount
FROM App A INNER JOIN CountTable C ON A.[id] = C.[app_id]
WHERE DATEPART(WEEK,C.date) BETWEEN DATEPART(WEEK,CURRENT_TIMESTAMP) - 1 AND DATEPART(WEEK,CURRENT_TIMESTAMP)
GROUP BY DATEPART(WEEK,C.date),name
) AS T
GROUP BY appname
SQL Fiddle
Output
| appname | thisweek | lastweek |
|-------------|----------|----------|
| Office 2007 | 180 | 200 |
| Office 2010 | 378 | 500 |
| Office 2013 | 1000 | 750 |
You can use this generic query with a variable for the current week day:
DECLARE #week date = '2016-01-18';
WITH data AS (
SELECT a.name, c.[count]
, w = CASE WHEN c.[date] = #week THEN 0 ELSE 1 END
FROM #Counts c
INNER JOIN #Apps a ON c.app_id = a.id
WHERE [date] = #week OR [date] = DATEADD(day, -7, #week)
)
SELECT App = name, count_this_week = [0], count_prev_week = [1]
FROM data d
PIVOT (
MAX([count])
FOR w IN ([0], [1])
) p
Output:
App count_this_week count_prev_week
Office 2007 180 200
Office 2010 378 500
Office 2013 1000 750
Your data:
DECLARE #Apps TABLE ([id] int, [name] varchar(11));
DECLARE #Counts TABLE([id] int, [app_id] int, [count] int, [date] date);
INSERT INTO #Apps([id], [name])
VALUES
(1, 'Office 2007'),
(2, 'Office 2010'),
(3, 'Office 2013')
;
INSERT INTO #Counts([id], [app_id], [count], [date])
VALUES
(1, 1, 200, '2016-01-11'),
(2, 2, 500, '2016-01-11'),
(3, 3, 750, '2016-01-11'),
(4, 1, 180, '2016-01-18'),
(5, 2, 378, '2016-01-18'),
(6, 3, 1000, '2016-01-18')
;
SELECT *
FROM count
JOIN app ON app.id=count.app_id
WHERE date BETWEEN '2016-01-18' AND '2016-01-11'

SQL select flag based on count and/or flag of joined table

I have a Customer table and an Address table.
The Address table has a flag which is either INVOICE, CORRESPONDENCE or DELIVERY.
A Customer can have 0 to many Address records.
I want to be able to query both tables and generate a flag for each customer based on the address data - no address records = NONE, 1 or more INVOICE records = HASINVOICE, no INVOICE but 1 or more others = HASOTHER
so, for the following data:
+------------+---------+
| CustomerID | Name |
+------------+---------+
| 1 | Peter |
| 2 | Ray |
| 3 | Egon |
| 4 | Winston |
| 5 | Dana |
+------------+---------+
+-----------+------------+----------------+
| AddressID | CustomerID | AddressType |
+-----------+------------+----------------+
| 1 | 1 | INVOICE |
| 2 | 1 | DELIVERY |
| 3 | 2 | DELIVERY |
| 4 | 2 | CORRESPONDENCE |
| 5 | 4 | INVOICE |
| 6 | 5 | CORRESPONDENCE |
+-----------+------------+----------------+
I would expect the following output:
+------------+---------+-------------+
| CustomerID | Name | AddressFlag |
+------------+---------+-------------+
| 1 | Peter | HASINVOICE |
| 2 | Ray | HASOTHER |
| 3 | Egon | NONE |
| 4 | Winston | HASINVOICE |
| 5 | Dana | HASOTHER |
+------------+---------+-------------+
Is this possible, for SQL 2000, using a single query and no cursors?
I don't have a 2000 instance handy (you really should upgrade, you're 4-5 releases behind), but I think that this should work:
declare #Customers table (CustomerID int,Name varchar(10))
insert into #Customers (CustomerID,Name)
select 1,'Peter' union all select 2,'Ray' union all
select 3,'Egon' union all select 4,'Winston' union all
select 5,'Dana'
declare #Addresses table (AddressID int, CustomerID int,
AddressType varchar(30))
insert into #Addresses (AddressID,CustomerID,AddressType)
select 1,1,'INVOICE' union all select 2,1,'DELIVERY' union all
select 3,2,'DELIVERY' union all select 4,2,'CORRESPONDENCE' union all
select 5,4,'INVOICE' union all select 6,5,'CORRESPONDENCE'
select
c.CustomerID,
c.Name,
CASE MAX(CASE
WHEN a.AddressType = 'Invoice' THEN 2
WHEN a.AddressType IS NOT NULL THEN 1
END
) WHEN 2 THEN 'HASINVOICE'
WHEN 1 THEN 'HASOTHER'
ELSE 'NONE'
END as AddressFlag
from
#Customers c
left join
#Addresses a
on
c.CustomerID = a.CustomerID
group by
c.CustomerID,
c.Name
Produces:
CustomerID Name AddressFlag
----------- ---------- -----------
5 Dana HASOTHER
3 Egon NONE
1 Peter HASINVOICE
2 Ray HASOTHER
4 Winston HASINVOICE

SQL - Grouping with aggregation

I have a table (TABLE1) that lists all employees with their Dept IDs, the date they started and the date they were terminated (NULL means they are current employees).
I would like to have a resultset (TABLE2) , in which every row represents a day starting since the first employee started( in the sample table below, that date is 20090101 ), till today. (the DATE field). I would like to group the employees by DeptID and calculate the total number of employees for each row of TABLE2.
How do I this query? Thanks for your help, in advance.
TABLE1
DeptID EmployeeID StartDate EndDate
--------------------------------------------
001 123 20100101 20120101
001 124 20090101 NULL
001 234 20110101 20120101
TABLE2
DeptID Date EmployeeCount
-----------------------------------
001 20090101 1
001 20090102 1
... ... 1
001 20100101 2
001 20100102 2
... ... 2
001 20110101 3
001 20110102 3
... ... 3
001 20120101 1
001 20120102 1
001 20120103 1
... ... 1
This will work if you have a date look up table. You will need to specify the department ID. See it in action.
Query
SELECT d.dt, SUM(e.ecount) AS RunningTotal
FROM dates d
INNER JOIN
(SELECT b.dt,
CASE
WHEN c.ecount IS NULL THEN 0
ELSE c.ecount
END AS ecount
FROM dates b
LEFT JOIN
(SELECT a.DeptID, a.dt, SUM([count]) AS ecount
FROM
(SELECT DeptID, EmployeeID, 1 AS [count], StartDate AS dt FROM TABLE1
UNION ALL
SELECT DeptID, EmployeeID,
CASE
WHEN EndDate IS NOT NULL THEN -1
ELSE 0
END AS [count], EndDate AS dt FROM TABLE1) a
WHERE a.dt IS NOT NULL AND DeptID = 1
GROUP BY a.DeptID, a.dt) c ON c.dt = b.dt) e ON e.dt <= d.dt
GROUP BY d.dt
Result
| DT | RUNNINGTOTAL |
-----------------------------
| 2009-01-01 | 1 |
| 2009-02-01 | 1 |
| 2009-03-01 | 1 |
| 2009-04-01 | 1 |
| 2009-05-01 | 1 |
| 2009-06-01 | 1 |
| 2009-07-01 | 1 |
| 2009-08-01 | 1 |
| 2009-09-01 | 1 |
| 2009-10-01 | 1 |
| 2009-11-01 | 1 |
| 2009-12-01 | 1 |
| 2010-01-01 | 2 |
| 2010-02-01 | 2 |
| 2010-03-01 | 2 |
| 2010-04-01 | 2 |
| 2010-05-01 | 2 |
| 2010-06-01 | 2 |
| 2010-07-01 | 2 |
| 2010-08-01 | 2 |
| 2010-09-01 | 2 |
| 2010-10-01 | 2 |
| 2010-11-01 | 2 |
| 2010-12-01 | 2 |
| 2011-01-01 | 3 |
| 2011-02-01 | 3 |
| 2011-03-01 | 3 |
| 2011-04-01 | 3 |
| 2011-05-01 | 3 |
| 2011-06-01 | 3 |
| 2011-07-01 | 3 |
| 2011-08-01 | 3 |
| 2011-09-01 | 3 |
| 2011-10-01 | 3 |
| 2011-11-01 | 3 |
| 2011-12-01 | 3 |
| 2012-01-01 | 1 |
Schema
CREATE TABLE TABLE1 (
DeptID tinyint,
EmployeeID tinyint,
StartDate date,
EndDate date)
INSERT INTO TABLE1 VALUES
(1, 123, '2010-01-01', '2012-01-01'),
(1, 124, '2009-01-01', NULL),
(1, 234, '2011-01-01', '2012-01-01')
CREATE TABLE dates (
dt date)
INSERT INTO dates VALUES
('2009-01-01'), ('2009-02-01'), ('2009-03-01'), ('2009-04-01'), ('2009-05-01'),
('2009-06-01'), ('2009-07-01'), ('2009-08-01'), ('2009-09-01'), ('2009-10-01'),
('2009-11-01'), ('2009-12-01'), ('2010-01-01'), ('2010-02-01'), ('2010-03-01'),
('2010-04-01'), ('2010-05-01'), ('2010-06-01'), ('2010-07-01'), ('2010-08-01'),
('2010-09-01'), ('2010-10-01'), ('2010-11-01'), ('2010-12-01'), ('2011-01-01'),
('2011-02-01'), ('2011-03-01'), ('2011-04-01'), ('2011-05-01'), ('2011-06-01'),
('2011-07-01'), ('2011-08-01'), ('2011-09-01'), ('2011-10-01'), ('2011-11-01'),
('2011-12-01'), ('2012-01-01')
you need somthing along these lines.
SELECT *
, ( SELECT COUNT(EmployeeID) AS EmployeeCount
FROM TABLE1 AS f
WHERE t.[Date] BETWEEN f.BeginDate AND f.EndDate
)
FROM ( SELECT DeptID
, BeginDate AS [Date]
FROM TABLE1
UNION
SELECT DeptID
, EndDate AS [Date]
FROM TABLE1
) AS t
EDIT since OP clarified that he wants all the dates here is the updated solution
I have excluded a Emplyee from Count if his job is ending on that date.But if you want to include change t.[Date] < f.EndDate to t.[Date] <= f.EndDate in the below solution. Plus I assume the NULL value in EndDate mean Employee still works for Department.
DECLARE #StartDate DATE = (SELECT MIN(StartDate) FROM Table1)
,#EndDate DATE = (SELECT MAX(EndDate) FROM Table1)
;WITH CTE AS
(
SELECT DISTINCT DeptID,#StartDate AS [Date] FROM Table1
UNION ALL
SELECT c.DeptID, DATEADD(dd,1,c.[Date]) AS [Date] FROM CTE AS c
WHERE c.[Date]<=#EndDate
)
SELECT * ,
EmployeeCount=( SELECT COUNT(EmployeeID)
FROM TABLE1 AS f
WHERE f.DeptID=t.DeptID AND t.[Date] >= f.StartDate
AND ( t.[Date] < f.EndDate OR f.EndDate IS NULL )
)
FROM CTE AS t
ORDER BY 1
OPTION ( MAXRECURSION 0 )
here is SQL Fiddler demo.I have added another department and added an Employee to it.
http://sqlfiddle.com/#!3/5c4ec/1