My actual problem is - How to obtain a CLLocation Object when the coordinate value on the map is available in Degree-Minute-Second form (as a String), instead of Double.
So, I am Looking for a way to convert Degree-Minute-Second to Double, which i can use to form a CLLocation object.
I came up with a bit of a cleaner answer when figuring this out
// split the string to deal with lat and lon separately
NSArray *parts = [dmsString componentsSeparatedByString:#","];
NSString *latStr = parts[0];
NSString *lonStr = parts[1];
// convert each string
double lat = [self degreesStringToDecimal:latStr];
double lon = [self degreesStringToDecimal:lonStr];
// init your location object
CLLocation *loc = [[CLLocation alloc] initWithLatitude:lat longitude:lon];
The magic
- (double)degreesStringToDecimal:(NSString*)string
{
// split the string
NSArray *splitDegs = [string componentsSeparatedByString:#"\u00B0"]; // unicode for degree symbol
NSArray *splitMins = [splitDegs[1] componentsSeparatedByString:#"'"];
NSArray *splitSecs = [splitMins[1] componentsSeparatedByString:#"\""];
// get each segment of the dms string
NSString *degreesString = splitDegs[0];
NSString *minutesString = splitMins[0];
NSString *secondsString = splitSecs[0];
NSString *direction = splitSecs[1];
// convert degrees
double degrees = [degreesString doubleValue];
// convert minutes
double minutes = [minutesString doubleValue] / 60; // 60 degrees in a minute
// convert seconds
double seconds = [secondsString doubleValue] / 3600; // 60 seconds in a minute, or 3600 in a degree
// add them all together
double decimal = degrees + minutes + seconds;
// determine if this is negative. south and west would be negative values
if ([direction.uppercaseString isEqualToString:#"W"] || [direction.uppercaseString isEqualToString:#"S"])
{
decimal = -decimal;
}
return decimal;
}
Note that I've only tested this with coordinates in Wisconsin, which is North and West. I'm using this tool to verify my calculations.
Let's say you have a the coordinate value in a String -
Split the String To obtain Degree-Minute-Second values in separate strings.
NSString *longlat= #"+39° 44' 39.28", -104° 50' 5.86" "(find a way to escape the " in the string)
//separate lat and long
NSArray *splitLonglat = [longlat componentsSeparatedByString:#","];
//separate Degree-Minute-Seconds
NSArray *arrayLat = [[splitLonglat objectAtIndex:0] componentsSeparatedByString:#" "];
double latitude,longitude;
if([arrayLat count]==3){
//get the double value for latitude
latitude= [self convertDMSToDD_deg:(NSString *)[arrayLat objectAtIndex:0]//degree
min:(NSString *)[arrayLat objectAtIndex:1]//minute
sec:(NSString *)[arrayLat objectAtIndex:2]//seconds
];
}else{
//some values could be in decimal form in the String already, instead of Degree-Minute-Second form and we might not need to convert them.
NSLog(#"latitude in decimal for %#",locationModelObject.name);
latitude=[[splitLonglat objectAtIndex:0]doubleValue];
}
NSArray *arrayLong= [[splitLonglat objectAtIndex:1] componentsSeparatedByString:#" "];
if([arrayLong count]==4){
//get the double value for longitude
longitude= [self convertDMSToDD_deg:(NSString *)[arrayLong objectAtIndex:1]//degree
min:(NSString *)[arrayLong objectAtIndex:2]//minute
sec:(NSString *)[arrayLong objectAtIndex:3]//seconds
];
}else{
//some values could be in decimal form in the String already, instead of Degree-Minute-Second form and we might not need to convert them.
NSLog(#"longitude in decimal for %#",locationModelObject.name);
longitude=[[splitLonglat objectAtIndex:1]doubleValue];
}
//add latitude longitude to the model object
locationModelObject.latitude=latitude;
locationModelObject.longitude=longitude;
The Method which does the conversion
-(double) convertDMSToDD_deg:(NSString*)degrees min:(NSString* )minutes sec:(NSString*)seconds {
int latsign=1;
double degree=[degrees doubleValue];
double minute=[minutes doubleValue];
double second=[seconds doubleValue];
if (degree<0){
latsign = -1;
}
else{
latsign=1;
}
double dd = (degree + (latsign* (minute/60.)) + (latsign* (second/3600.) ) ) ;
return dd;
}
Related
I want to round a double to one decimal place in Objective-C.
In Swift I can do it with an extension:
public extension Double {
/// Rounds the double to decimal places value
func rounded(toPlaces places:Int) -> Double {
let divisor = pow(10.0, Double(places))
return (self * divisor).rounded() / divisor
}
}
However, apparently you cannot call extensions on primitives from Objective-C so I can't use the extension.
I would be happy to do the rounding either on the double directly or as a string, however, neither of the following is working:
double mydub = 122.12022222223322;
NSString *axtstr = [NSString stringWithFormat:#"%2f", mydub]; //gives 122.120222
double rounded = (round(mydub*10)) / 10.0; //gives 122.100000
How do I convert 122.12022222223322; into 122.1?
You need to put a decimal between the % and 2f
[NSString stringWithFormat:#"%.2f", mydub];
double mydouble = 122.12022222223322;
NSString *str = [NSString stringWithFormat:#"%.2f", mydouble];
// = #"122.12"
.. will not round mydouble. Instead it will only apply format to the output as string.
double d = 122.49062222223322;
NSString *dStr = [NSString stringWithFormat:#"%.f %.1f %.2f %.3f", d, d, d, d];
// = #"122 122.5 122.49 122.491"
As Objective-C shares the language rules from C you can round safely with
#include <math.h>
double rounded = round(mydouble);
// = 122.000000
of course you can shift comma with multiplication and dividing the power of ten you want.
double commashifted = round(mydouble*100.0)/100.0;
// = 122.120000;
If you are really into Objective-C Classes to do same in deluxe have a look into 'NSDecimal.h' in the Foundation Framework.
Last but not least you can do the same with C as you did with swift.
double roundbycomma(int commata, double zahl) {
double divisor = pow(10.0, commata);
return round(zahl * divisor) / divisor;
}
I have this method to calculate the standard deviation of an array of NSNumber integers, given a mean. The calculation uses NSDecimals to retain the highest resolution. This is currently demanding many cpu cycles, any help to speed it up while retaining the resolution required is appreciated! Thank you.
-(NSDecimal)standardDeviationOf:(NSMutableArray *)array withMean:(NSDecimal)mean {
if (![array count]) return CPTDecimalFromInt(0);
NSDecimal sumOfSquaredDifferences = CPTDecimalFromInt(0);
for (NSNumber *number in array) {
NSDecimal valueOfNumber = CPTDecimalFromInt([number intValue]);
NSDecimal difference = CPTDecimalSubtract(valueOfNumber, mean);
sumOfSquaredDifferences = CPTDecimalAdd(sumOfSquaredDifferences, CPTDecimalMultiply(difference, difference));
}
return CPTDecimalFromDouble(
sqrt(
CPTDecimalDoubleValue(sumOfSquaredDifferences) / [[NSNumber numberWithInt:[array count]] doubleValue]
)
);
}
An NSDecimal has 38 digits of precision, whereas double has roughly 16 digits of precision. But at the end of your loop, when you convert sumOfSquaredDifferences to double for the sqrt function, all the extra precision you had in the NSDecimal is "lost". You might as well perform the arithmetic of your inner loop using double, which should be much faster than NSDecimal:
double sumOfSquaredDifferences = 0;
double valueOfMean = [mean doubleValue];
for (NSNumber *number in array) {
double valueOfNumber = [number intValue];
double difference = valueOfNumber - valueOfMean;
sumOfSquaredDifferences += difference * difference;
}
return CPTDecimalFromDouble(sqrt(sumOfSquaredDifferences /
double([array count])));
I am trying to trim zeros after a decimal point as below but it's not giving desired result.
trig = [currentVal doubleValue];
trig = trig/100;
NSNumberFormatter *formatter = [[NSNumberFormatter alloc] init];
[formatter setMaximumFractionDigits:0];
display.text = [formatter stringFromNumber:[NSNumber numberWithDouble:trig]];
The number is still being displayed without trimming zeros after the decimal point.
Here currentVal is the number I am entering.
For example if i pass "trig" = 123 (Initially "trig" = 123 after doing trig/100 i want to display 1.23 but it is displaying as 1.23000000).
Sometimes the straight C format specifiers do an easier job than the Cocoa formatter classes, and they can be used in the format string for the normal stringWithFormat: message to NSString.
If your requirement is to not show any trailing zeroes, then the "g" format specifier does the job:
float y = 1234.56789f;
NSString *s = [NSString stringWithFormat:#"%g", y];
Notice that there is no precision information, which means that the printf library will remove the trailing zeroes itself.
There is more information in the docs, which refer to IEEE's docs.
In case this helps someone. I wanted 1 decimal value but no '.0' on the end if the float was '1.0'. Using %g would give scientific notation for longer numbers, following ugliness worked well enough for me as high accuracy wasn't critical.
// Convert to 1 dp string,
NSString* dirtyString = [NSString stringWithFormat: #"%.1f", self.myFloat];
// Convert back to float that is now a maximum of 1 dp,
float myDirtyFloat = [dirtyString floatValue];
// Output the float subtracting the zeros the previous step attached
return [NSString stringWithFormat: #"%g", myDirtyFloat];
This will not display any decimal value after the decimal point:
display.text = [NSString stringWithFormat:#"%1.0f", trig];
This will just trim the zeros after the decimal point:
isplay.text = [NSString stringWithFormat:#"%3.2f", trig];
display.text = [display.text stringByTrimmingCharactersInSet:[NSCharacterSet characterSetWithCharactersInString:[NSString stringWithFormat#"0"]]];
Note, this may leave you with the trailing decimal point. "124." may happen. I guess that some smarter solution will be posted soon.
From the documentation, it looks like setFractionDigits: is only for converting the other way.
The best thing to do is probably to convert your number to an integer before formatting it e.g.
double converted = round(trig); // man round for docs
You can use also the formatting functions of stringWithFormat: of NSString, but then you will lose all the localisation advantages you get with NSNumberFormatter.
This may not be a proper solution where there is NSNumberFormetter Class, But I just did this rather then googling a lot! ;)
Here is an example, if it helps:
-(NSString*) trimZerosAfterDecimalPoint:(NSString*)string_ {
double doubleValue=[string_ doubleValue];
long leftPart=(long)doubleValue;
double rightPart=doubleValue-(double)leftPart;
NSString *rightPartAsStr=[NSString stringWithFormat:#"%f", rightPart];
int i=0;
for (i=rightPartAsStr.length-1; i>=2; i--) {
if ([rightPartAsStr characterAtIndex:i]!='0') {
rightPartAsStr=[rightPartAsStr substringWithRange:NSMakeRange(2, i-1)];
break;
}
}
if (i<2) {
string_=[NSString stringWithFormat:#"%ld", leftPart];
} else {
string_=[NSString stringWithFormat:#"%ld.%#", leftPart, rightPartAsStr];
}
return string_;
}
I just had to do this for one of my programs and heres how I went about it:
- (void) simplify{
int length = (int)[self.calcString length];
for (int i = (int)[self.calcString length]; i > 0; i--) {
if ([self.calcString rangeOfString:#"."].location != NSNotFound) {
NSRange prevChar = NSMakeRange(i-1, 1);
if ([[self.calcString substringWithRange:prevChar] isEqualToString:#"0"]||
[[self.calcString substringWithRange:prevChar] isEqualToString:#"."])
length--;
else
break;
}
self.calcString = [self.calcString substringToIndex:length];
}
}
This works
display.text = [#(trig) stringValue];
it is because of your datatype cannot be formatted is such a manner.
Here is my situation. Its driving me nuts:
I have an NSMutableArray with a count value of 517. I have a double value that is my multiplier.
double multiplier = 0.1223;
double result = [myArray count] * multiplier; // 63 even (wrong!)
In fact it should be 63.2291. If I go:
double result = [myArray count] * 0.1223; // 63.2291 (right!)
or..
double result = 517 * multiplier; // 63.2291 (right!)
Does this make any sense to anyone?
Addendum:
here is my actual function:
- (double) getValueForPercentage:(double)percVal
{
int adjustedCount = [originalData count] - 1;
double final = percVal * (double)adjustedCount;
return final;
}
I never get any digits beyond the decimal point when I do this. It does however work if I get rid of the "-1", a-la:
- (double) getValueForPercentage:(double)percVal
{
int adjustedCount = [originalData count];
double final = percVal * (double)adjustedCount;
return final;
}
Of course, I need to have the -1.
Second addendum:
Another interesting thing I noted was, if I pass a hard-coded number to this function it works fine, but if I pass the double value that I need to use, it fails:
int pointCount = [srcData getDayCount];
for (int i = 0; i < pointCount; i++) {
double progress = (double)i/(double)(pointCount - 1);
double satv = [srcData getValueForPercentage:progress];
// satv is always a number without any digits beyond the decimal
}
Well, when I started to have these issues i looked around a bit and found no reason or explanation.
What I do now is make everything become an NSNumber and then call doubleValue on it. This should yield the results you're looking for:
NSNumber * pointCount = [NSNumber numberWithUnsignedInt: [srcData getDayCount]];
for (NSInteger i = 0; i < [pointCount intValue]; i++) {
NSNumber * count = [ NSNumber numberWithInt: i ];
double progress = [count doubleValue]/[pointCount doubleValue] - 1.0;
double satv = [srcData getValueForPercentage:progress];
// satv is always a number without any digits beyond the decimal
}
Hope it helps.
I have the value 25.00 in a float, but when I print it on screen it is 25.0000000.
How can I display the value with only two decimal places?
It is not a matter of how the number is stored, it is a matter of how you are displaying it. When converting it to a string you must round to the desired precision, which in your case is two decimal places.
E.g.:
NSString* formattedNumber = [NSString stringWithFormat:#"%.02f", myFloat];
%.02f tells the formatter that you will be formatting a float (%f) and, that should be rounded to two places, and should be padded with 0s.
E.g.:
%f = 25.000000
%.f = 25
%.02f = 25.00
Here are few corrections-
//for 3145.559706
Swift 3
let num: CGFloat = 3145.559706
print(String(format: "%f", num)) = 3145.559706
print(String(format: "%.f", num)) = 3145
print(String(format: "%.1f", num)) = 3145.6
print(String(format: "%.2f", num)) = 3145.56
print(String(format: "%.02f", num)) = 3145.56 // which is equal to #"%.2f"
print(String(format: "%.3f", num)) = 3145.560
print(String(format: "%.03f", num)) = 3145.560 // which is equal to #"%.3f"
Obj-C
#"%f" = 3145.559706
#"%.f" = 3146
#"%.1f" = 3145.6
#"%.2f" = 3145.56
#"%.02f" = 3145.56 // which is equal to #"%.2f"
#"%.3f" = 3145.560
#"%.03f" = 3145.560 // which is equal to #"%.3f"
and so on...
You can also try using NSNumberFormatter:
NSNumberFormatter* nf = [[[NSNumberFormatter alloc] init] autorelease];
nf.positiveFormat = #"0.##";
NSString* s = [nf stringFromNumber: [NSNumber numberWithFloat: myFloat]];
You may need to also set the negative format, but I think it's smart enough to figure it out.
I made a swift extension based on above answers
extension Float {
func round(decimalPlace:Int)->Float{
let format = NSString(format: "%%.%if", decimalPlace)
let string = NSString(format: format, self)
return Float(atof(string.UTF8String))
}
}
usage:
let floatOne:Float = 3.1415926
let floatTwo:Float = 3.1425934
print(floatOne.round(2) == floatTwo.round(2))
// should be true
In Swift Language, if you want to show you need to use it in this way. To assign double value in UITextView, for example:
let result = 23.954893
resultTextView.text = NSString(format:"%.2f", result)
If you want to show in LOG like as objective-c does using NSLog(), then in Swift Language you can do this way:
println(NSString(format:"%.2f", result))
IN objective-c, if you are dealing with regular char arrays (instead of pointers to NSString) you could also use:
printf("%.02f", your_float_var);
OTOH, if what you want is to store that value on a char array you could use:
sprintf(your_char_ptr, "%.02f", your_float_var);
The problem with all the answers is that multiplying and then dividing results in precision issues because you used division. I learned this long ago from programming on a PDP8.
The way to resolve this is:
return roundf(number * 100) * .01;
Thus 15.6578 returns just 15.66 and not 15.6578999 or something unintended like that.
What level of precision you want is up to you. Just don't divide the product, multiply it by the decimal equivalent.
No funny String conversion required.
in objective -c is u want to display float value in 2 decimal number then pass argument indicating how many decimal points u want to display
e.g 0.02f will print 25.00
0.002f will print 25.000
Here's some methods to format dynamically according to a precision:
+ (NSNumber *)numberFromString:(NSString *)string
{
if (string.length) {
NSNumberFormatter * f = [[NSNumberFormatter alloc] init];
f.numberStyle = NSNumberFormatterDecimalStyle;
return [f numberFromString:string];
} else {
return nil;
}
}
+ (NSString *)stringByFormattingString:(NSString *)string toPrecision:(NSInteger)precision
{
NSNumber *numberValue = [self numberFromString:string];
if (numberValue) {
NSString *formatString = [NSString stringWithFormat:#"%%.%ldf", (long)precision];
return [NSString stringWithFormat:formatString, numberValue.floatValue];
} else {
/* return original string */
return string;
}
}
e.g.
[TSPAppDelegate stringByFormattingString:#"2.346324" toPrecision:4];
=> 2.3453
[TSPAppDelegate stringByFormattingString:#"2.346324" toPrecision:0];
=> 2
[TSPAppDelegate stringByFormattingString:#"2.346324" toPrecision:2];
=> 2.35 (round up)
Another method for Swift (without using NSString):
let percentage = 33.3333
let text = String.localizedStringWithFormat("%.02f %#", percentage, "%")
P.S. this solution is not working with CGFloat type only tested with Float & Double
Use NSNumberFormatter with maximumFractionDigits as below:
NSNumberFormatter *formatter = [[NSNumberFormatter alloc] init];
formatter.maximumFractionDigits = 2;
NSLog(#"%#", [formatter stringFromNumber:[NSNumber numberWithFloat:12.345]]);
And you will get 12.35
If you need to float value as well:
NSString* formattedNumber = [NSString stringWithFormat:#"%.02f", myFloat];
float floatTwoDecimalDigits = atof([formattedNumber UTF8String]);
lblMeter.text=[NSString stringWithFormat:#"%.02f",[[dic objectForKey:#"distance"] floatValue]];