reproducing grep "my pattern" myfile.log | sort | uniq | wc -l in awk - awk

Question

If I perform this grep on my target file I get eg 275 as result.
But I want to learn awk so tried this in awk:
awk 'BEGIN { count=0 } /my pattern/ { count++ } END { print count }' myfile.log
And this prints the 275 as expected.
So getting ambitious I created an awk script like this:
BEGIN {
print "Log File Analysis";
message=0;
events=0;
}
{
/message/ { messages++; }
/event/ { events++; }
}
END {
print "messages:\t" messages;
print "events:\t" events;
}
I get a syntax error,
$ awk -f test_learn.awk test_log.log
awk: test_learn.awk:16: /message/ { messages++; }
awk: test_learn.awk:16: ^ syntax error
What am I doing wrong?
I am using awk from MinGW shell on windows 7.

Answer 1

try
awk 'BEGIN { count=0 }; /my pattern/{count++ }; END { print count }' myfile.log
OR
awk 'BEGIN { count=0}; { if ($0 ~ /my pattern/) count++ }; END { print count };' myfile.log
Better yet, as variables are initialized as zero by default, you don't need the BEGIN block, so
awk '/my pattern/{count++ }; END { print count };' myfile.log
You can either have a default loop applied to all lines in a file, as in 2d example with the if, or you can have multiple blocks, "filtered" by pattern, as above, and in your edited addition.
When doing one-liners have you have, some awks required the semi-colon to separate the BEGIN and END blocks from the main loop block.
Edit
Same Idea with your 2nd issue, and integrating Ed Morton's improvments (thanks)
/message/ { messages++ }
/event/ { events++ }
END {
print "Log File Analysis"
print "messages:\t" messages
print "events:\t" events
}
IHTH