the following statement:
group by datepart(wk, createdon)
Groups the selected rows according to the week in which they fall. My select statement shows the following:
SELECT
datepart(wk, createdon) week,
How do I display the actual datetime of the week("12-10-2012"), instead of the number ("12")?
If I understand you correctly, you're wanting to group by week but also return the full datetime. You must include the selected fields in aggregate columns.
Thusly should work:
SELECT DATEPART(wk, createdon) week, createdon
FROM TableName
GROUP BY DATEPART(wk, createdon), createdon
Works on MSSQL2008R2
Edit:
As the OP seems to want the starting date of the week, SO has the answer.
One option is using a cte with ROW_NUMBER instead:
WITH CTE AS
(
SELECT
RN = ROW_NUMBER() OVER (PARTITION BY datepart(wk, createdon) ORDER BY createdon)
, DATEADD(ww, DATEDIFF(ww,0,createdon), 0) As Week
, *
FROM dbo.Table
)
SELECT * FROM CTE
WHERE RN = 1
You can't group by a week, and then show constituent parts of it, i.e. days. You will need group by the date instead.
Related
I have a table that sends out messages, I would like to get a total count of the messages that have been going out month by month over the last year . I am new to SQL so I am having trouble with it . I am using MSSQL 2012 this is my sql
SELECT sentDateTime, MessageID, status AS total, CONVERT(NVARCHAR(10), sentDateTime, 120) AS Month
FROM MessageTable
WHERE CAST(sentDateTime AS DATE) > '2017-04-01'
GROUP BY CONVERT(NVARCHAR(10), sentDateTime, 120), sentDateTime, MessageID, status
ORDER BY Month;
I think the month() and year() functions are more convenient than datepart() for this purpose.
I would go for:
select year(sentDateTime) as yr, month(sentDateTime) as mon, count(*)
from MessageTable
where sentDateTime > '2017-04-01'
group by year(sentDateTime), month(sentDateTime)
order by min(sentDateTime);
Additional notes:
Only include the columns in the select that you care about. This would be the ones that define the month and the count.
Only include the columns in the group by that you care about. Every combination of the expressions in the group by found in the data define a column.
There is no need to convert sentDateTime to a date explicitly for the comparison.
The order by orders the results by time. Using the min() is a nice convenience.
Including the year() makes sure you don't make a mistake -- say by including data from 2018-04 with 2017-04.
-- this selects the part of the date you are looking for, replace this with the date format you are using, this should give you what you are looking for
SELECT DATEPART(mm, GETDATE())
SELECT COUNT(DATEPART(mm, sentDateTime)), MessageID, status
From MessageTable where Cast(sentDateTime as date) > '2017-04-01'
group by DATEPART(mm, sentDateTime), MessageID, status
order by DATEPART(mm, sentDateTime)
You can group by the month number of the sentDateTime with the function DATEPART(MONTH, sentDateTime). The next select will also yield results if no message was sent for a particular month (total = 0).
;WITH PossibleMonths AS
(
SELECT
M.PossibleMonth
FROM
(VALUES
(1),(2),(3),(4),(5),(6),(7),(8),(9),(10),(11),(12)) M(PossibleMonth)
),
MonthTotals AS
(
select
COUNT(1) AS Total,
DATEPART(MONTH, sentDateTime) [Month]
From
MessageTable
where
Cast(sentDateTime as date) > '2017-04-01'
group by
DATEPART(MONTH, sentDateTime)
)
SELECT
P.PossibleMonth,
Total = ISNULL(T.Total, 0)
FROM
PossibleMonths AS P
LEFT JOIN MonthTotals AS T ON P.PossibleMonth = T.Month
How can I make a query in SQL Server to query for all rows for the next 5 days.
The problem is that it has to be days with records, so the next 5 days, might become something like, Today, Tomorrow, some day in next month, etc...
Basically I want to query the database for the records for the next non empty X days.
The table has a column called Date, which is what I want to filter.
Why not split the search into 2 queries. First one searches for the date part, the second uses that result to search for records IN the dates returned by the first query.
#Anagha is close, just a little modification and it is OK.
SELECT *
FROM TABLE
WHERE DATE IN (
SELECT DISTINCT TOP 5 DATE
FROM TABLE
WHERE DATE >= referenceDate
ORDER BY DATE
)
You can use following SQL query where 5 different dates are fetched at first then all rows for those selected dates are displayed
declare #n int = 5;
select *
from myData
where
datecol in (
SELECT distinct top (#n) cast(datecol as date) as datecol
FROM myData
WHERE datecol >= '20180101'
ORDER BY datecol
)
Try this:
select date from table where date in (select distinct top 5 date
from table where date >= getdate() order by date)
If your values are dates, you can use `dense_rank():
select t.*
from (select t.*, dense_rank() over (order by datecol) as seqnum
from t
where datecol >= cast(getdate() as date)
) t
where seqnum <= 5;
If the column has a time component and you still want to define days by midnight-to-midnight (as suggested by the question), just convert to date:
select t.*
from (select t.*,
dense_rank() over (order by cast(datetimecol as date)) as seqnum
from t
where datetimecol >= cast(getdate() as date)
) t
where seqnum <= 5;
I have a list of orders in a table. these all have a date against them. How do I write a query to return the minimum orders in a year and the associated year.
SELECT Max(YearCounts.[CountForYear]) AS [MinForYear]
FROM ( SELECT COUNT(PK) AS [CountForYear] FROM Orders
WHERE DATEPART( year , TransactionDate) > '2002'
GROUP BY DATEPART( Year, TransactionDate ) ) YearCounts
So I am looking for 98008 orders in 2003 as an example
Thanks for the answers, I checked them out, the sub query option executed fastest. I take on board the single quotes comments, thanks for the assistance.
Just use TOP 1
SELECT TOP 1 YearCounts.[CountForYear] AS [MinForYear],
YearCounts.[YEAR]
FROM ( SELECT COUNT(PK) AS [CountForYear],
DATEPART( year , TransactionDate) as [YEAR] FROM Orders
WHERE DATEPART( year , TransactionDate) > '2002'
GROUP BY DATEPART( Year, TransactionDate ) ) YearCounts
ORDER BY YearCounts.[CountForYear]
You can do this without a subquery, just by using top and order by:
SELECT TOP 1 DATEPART(year, TransactionDate), COUNT(PK) AS CountForYear
FROM Orders o
WHERE DATEPART(year , TransactionDate) > 2002
GROUP BY DATEPART(Year, TransactionDate )
ORDER BY COUNT(PK) DESC ;
You can also write this using the year function (which I personally find easier to read):
SELECT TOP 1 YEAR(TransactionDate), COUNT(PK) AS CountForYear
FROM Orders o
WHERE YEAR(TransactionDate) > 2002
GROUP BY YEAR(TransactionDate)
ORDER BY COUNT(PK) DESC ;
Your original query had single quotes around '2002'. This is unnecessary. You should express numeric constants without single quotes. Only use single quotes for string and date constants.
How do I get a maximium daily value of a numerical field over a year in MS-SQL
This would query the daily maximum of value over 2008:
select
datepart(dayofyear,datecolumn)
, max(value)
from yourtable
where '2008-01-01' <= datecolumn and datecolumn < '2009-01-01'
group by datepart(dayofyear,datecolumn)
Or the daily maximum over each year:
select
datepart(year,datecolumn),
, datepart(dayofyear,datecolumn)
, max(value)
from yourtable
group by datepart(year,datecolumn), datepart(dayofyear,datecolumn)
Or the day(s) with the highest value in a year:
select
Year = datepart(year,datecolumn),
, DayOfYear = datepart(dayofyear,datecolumn)
, MaxValue = max(MaxValue)
from yourtable
inner join (
select
Year = datepart(year,datecolumn),
, MaxValue = max(value)
from yourtable
group by datepart(year,datecolumn)
) sub on
sub.Year = yourtable.datepart(year,datecolumn)
and sub.MaxValue = yourtable.value
group by
datepart(year,datecolumn),
datepart(dayofyear,datecolumn)
You didn't mention which RDBMS or SQL dialect you're using. The following will work with T-SQL (MS SQL Server). It may require some modifications for other dialects since date functions tend to change a lot between them.
SELECT
DATEPART(dy, my_date),
MAX(my_number)
FROM
My_Table
WHERE
my_date >= '2008-01-01' AND
my_date < '2009-01-01'
GROUP BY
DATEPART(dy, my_date)
The DAY function could be any function or combination of functions which gives you the days in the format that you're looking to get.
Also, if there are days with no rows at all then they will not be returned. If you need those days as well with a NULL or the highest value from the previous day then the query would need to be altered a bit.
Something like
SELECT dateadd(dd,0, datediff(dd,0,datetime)) as day, MAX(value)
FROM table GROUP BY dateadd(dd,0, datediff(dd,0,datetime)) WHERE
datetime < '2009-01-01' AND datetime > '2007-12-31'
Assuming datetime is your date column, dateadd(dd,0, datediff(dd,0,datetime)) will extract only the date part, and then you can group by that value to get a maximum daily value. There might be a prettier way to get only the date part though.
You can also use the between construct to avoid the less than and greater than.
Group on the date, use the max delegate to get the highest value for each date, sort on the value, and get the first record.
Example:
select top 1 theDate, max(theValue)
from TheTable
group by theDate
order by max(theValue) desc
(The date field needs to only contain a date for this grouping to work, i.e. the time component has to be zero.)
If you need to limit the query for a specific year, use a starting and ending date in a where claues:
select top 1 theDate, max(theValue)
from TheTable
where theDate between '2008-01-01' and '2008-12-13'
group by theDate
order by max(theValue) desc
I am trying to do a nice SQL statement inside a stored procedure.
I looked at the issue of seeing the number of days that events happened between two dates.
My example is sales orders: for this month, how many days did we have sales orders?
Suppose this setup:
CREATE TABLE `sandbox`.`orders` (
`year` int,
`month` int,
`day` int,
`desc` varchar(255)
)
INSERT INTO orders (year, month, day, desc)
VALUES (2009,1,1, 'New Years Resolution 1')
,(2009,1,1, 'Promise lose weight')
,(2009,1,2, 'Bagel')
,(2009,1,12, 'Coffee to go')
For this in-data the result should be 3, since there has been three days with sale.
The best solution I found is as below.
However, making a temporary table, counting that then dropping it seemes excess. It "should" be possible in one statement.
Anyone who got a "nicer" solution then me?
/L
SELECT [Year], [Month], [Day]
INTO #Some_Days
FROM Quarter
WHERE Start >= '2009-01-01' AND [End] < '2009-01-16'
GROUP BY [Year], [Month], [Day]
SELECT count(*) from #Some_Days
Apologies if I'm misunderstanding the question, but perhaps you could do something like this, as an option:
SELECT COUNT(*) FROM
(SELECT DISTINCT(SomeColumn)
FROM MyTable
WHERE Something BETWEEN 100 AND 500
GROUP BY SomeColumn) MyTable
... to get around the temp-table creation and disposal?
There are two basic options which I can see. One is to group everything up in a sub query, then count those distinct rows (Christian Nunciato's answer). The second is to combine the multiple fields and count distinct values of that combined value.
In this case, the following formula coverts the three fields into a single datetime.
DATEADD(YEAR, [Quarter].Year, DATEADD(MONTH, [Quarter].Month, DATEADD(DAY, [Quarter].DAY, 0), 0), 0)
Thus, COUNT(DISTINCT [formula]) will give the answer you need.
SELECT
COUNT(DISTINCT DATEADD(YEAR, [Quarter].Year, DATEADD(MONTH, [Quarter].Month, DATEADD(DAY, [Quarter].DAY, 0), 0), 0))
FROM
Quarter
WHERE
[Quarter].Start >= '2009-01-01'
AND [Quarter].End < '2009-01-16'
I usually use the sub query route, but depending on what you're doing, indexes, size of table, simplicity of the formula, etc, this Can be faster...
Dems.
How about:
SELECT COUNT(DISTINCT day) FROM orders
WHERE (year, month) = (2009, 1);
Actually, I don't know if TSQL supports tuple comparisons, but you get the idea.
COUNT(DISTINCT expr) is standard SQL and should work everywhere.
You should use nested Select statements. Inner one should contain group by clause, and the outer one should count it. I think "Christian Nunciato" helped you already.
Select Count(1) As Quantity
From
(
SELECT [Year], [Month], [Day]
INTO #Some_Days
FROM Quarter
WHERE Start >= '2009-01-01' AND [End] < '2009-01-16'
GROUP BY [Year], [Month], [Day]
) AS InnerResultSet
SELECT [Year], [Month], [Day]
FROM Quarter
WHERE Start >= '2009-01-01' AND [End] < '2009-01-16'
GROUP BY [Year], [Month], [Day]
COMPUTE COUNT(*)