I have a sql table
Project ID Employee ID Total Days
1 100 1
1 100 1
1 100 2
1 100 6
1 200 8
1 200 2
Now i need this table to look like
Project ID Employee ID Total Days
1 100 10
1 200 10
As iam new to sql,i am little confuse to use SUM() based on above condition.
This query below produces two columns: EmployeeID, totalDays.
SELECT EmployeeID, SUM(totalDays) totalDays
FROM tableName
GROUP BY EmployeeID
follow-up question: why is in your desired result the projectId is 1 and 2?
Here are two approaches
Declare #t Table(ProjectId Int, EmployeeId Int,TotalDays Int)
Insert Into #t Values(1,100,1),(1,100,1),(1,100,2),(1,100,6),(1,200,8),(1,200,2)
Approach1:
Select ProjectId,EmployeeId,TotalDays = Sum(TotalDays)
From #t
Group By ProjectId,EmployeeId
Approach2:
;With Cte As(
Select
ProjectId
,EmployeeId
,TotalDays = Sum(TotalDays) Over(Partition By EmployeeId)
,Rn = Row_Number() Over(Partition By EmployeeId Order By EmployeeId)
From #t )
Select ProjectId,EmployeeId,TotalDays
From Cte Where Rn = 1
Result
ProjectId EmployeeId TotalDays
1 100 10
1 200 10
select min("Project ID")as 'Project ID',"Employee ID"
, SUM("Total Days") as 'Total Days'
from table1
group by "Employee ID"
Related
I Tried as shown below:
CREATE TABLE #TEMP
(
ID INT,
EmpID INT,
AMOUNT INT
)
INSERT INTO #TEMP VALUES(1,1,10)
INSERT INTO #TEMP VALUES(2,1,5)
INSERT INTO #TEMP VALUES(3,2,6)
INSERT INTO #TEMP VALUES(4,3,8)
INSERT INTO #TEMP VALUES(5,3,10)
.
.
.
SELECT * FROM #TEMP
ID EmpID AMOUNT
1 1 10
2 1 5
3 2 6
4 3 8
5 4 10
UPDATE #TEMP
SET AMOUNT = SUM(AMOUNT) - 11
Where EmpID = 1
Expected Output:
Table consists of employeeID's along with amount assigned to Employee I need to subtract amount from amount filed depending on employee usage. Amount "10" should be deducted from ID = 1 and amount "1" should be deducted from ID = 2.
Amount: Credits available for that particular employee depending on date.
So i need to reduce credits from table depending on condition first i need to subtract from old credits. In my condition i need to collect 11 rupees from empID = 1 so first i need to collect 10 rupee from ID=1 and 1 rupee from the next credit i.e ID=2. For this reason in my expected output for ID=1 the value is 0 and final output should be like
ID EmpID AMOUNT
1 1 0
2 1 4
3 2 6
4 3 8
5 4 10
Need help to update records. Check error in my update statement.
Declare #Deduct int = -11,
#CurrentDeduct int = 0 /*this represent the deduct per row */
update #TEMP
set #CurrentDeduct = case when abs(#Deduct) >= AMOUNT then Amount else abs(#Deduct) end
, #Deduct = #Deduct + #CurrentDeduct
,AMOUNT = AMOUNT - #CurrentDeduct
where EmpID= 1
I think you want the following: subtract amounts from 11 while remainder is positive. If this is true, here is a solution with recursive cte:
DECLARE #t TABLE ( id INT, amount INT )
INSERT INTO #t VALUES
( 1, 10 ),
( 2, 5 ),
( 3, 3 ),
( 4, 2 );
WITH cte
AS ( SELECT * , 17 - amount AS remainder
FROM #t
WHERE id = 1
UNION ALL
SELECT t.* , c.remainder - t.amount AS remainder
FROM #t t
CROSS JOIN cte c
WHERE t.id = c.id + 1 AND c.remainder > 0
)
UPDATE t
SET amount = CASE WHEN c.remainder > 0 THEN 0
ELSE -remainder
END
FROM #t t
JOIN cte c ON c.id = t.id
SELECT * FROM #t
Output:
id amount
1 0
2 0
3 1
4 2
Here I use 17 as start remainder.
If you use sql server 2012+ then you can do it like:
WITH cte
AS ( SELECT * ,
17 - SUM(amount) OVER ( ORDER BY id ) AS remainder
FROM #t
)
SELECT id ,
CASE WHEN remainder >= 0 THEN 0
WHEN remainder < 0
AND LAG(remainder) OVER ( ORDER BY id ) >= 0
THEN -remainder
ELSE amount
END
FROM cte
First you should get a cumulative sum on amount:
select
id,
amount,
sum(amount) over (order by id) running_sum
from #TEMP;
From here we should put 0 on rows before running_sum exceeds the value 11. Update the row where the running sum exceeds 11 and do nothing to rows after precedent row.
select
id,
amount
running_sum,
min(case when running_sum > 11 then id end) over () as decide
from (
select
id,
amount,
sum(amount) over (order by id) running_sum
from #TEMP
);
From here we can do the update:
merge into #TEMP t
using (
select
id,
amount
running_sum,
min(case when running_sum > 11 then id end) over () as decide
from (
select
id,
amount,
sum(amount) over (order by id) running_sum
from #TEMP
)
)a on a.id=t.id
when matched then update set
t.amount = case when a.id = a.decide then a.running_sum - 11
when a.id < a.decide then 0
else a.amount
end;
See an SQLDFIDDLE
I am trying to get a specific row from a subquery, but I cannot use an aggregate function in a WHERE clause and I have read that I should be using a HAVING clause but I have no idea where to start.
This is my current sql statement:
SELECT *
FROM
(
select ID, SUM(BALANCE) AS Balance FROM bankacc GROUP BY ID
)A
I will get :
ID | Balance
1 | 30
2 | 40
3 | 50
4 | 50
I need the rows with the MAX(Balance), but I have no idea where to start, please help.
With window function:
DECLARE #t TABLE ( ID INT, Amount MONEY )
INSERT INTO #t
VALUES ( 1, 10 ),
( 1, 10 ),
( 1, 10 ),
( 2, 5 ),
( 2, 20 ),
( 3, 50 )
SELECT ID ,
Amount
FROM ( SELECT ID ,
SUM(Amount) AS Amount ,
RANK() OVER ( ORDER BY SUM(Amount) DESC ) AS rn
FROM #t
GROUP BY ID
) t
WHERE rn = 1
With TOP and TIES:
SELECT TOP 1 WITH TIES
ID ,
SUM(Amount) AS Amount
FROM #t
GROUP BY ID
ORDER BY Amount desc
These versions will return rows where sum will be max, not just top 1 row.
Output:
ID Amount
3 50.00
you can wrap it in a subquery:
SELECT q.id, max(q.b)
FROM
(
select ID, SUM(BALANCE) b FROM bankacc GROUP BY ID
) q
group by q.id
or order them in dessending order and get first record:
select top 1 ID, SUM(BALANCE) b FROM bankacc GROUP BY ID order by b desc
in MySQL you need to use limit 1 instead of top 1
I think this should be simple.
-- This will return only 1 record, even if there are 2 records for MAX same amount
SELECT top 1 ID ,
Amount
FROM ( SELECT ID ,
SUM(Amount) AS Amount
FROM Table
GROUP BY ID
) t
Order by Amount desc,ID asc
Using Window function : This will return what you want.
SELECT ID ,
Amount
FROM ( SELECT ID ,
SUM(Amount) AS Amount ,
RANK() OVER ( ORDER BY SUM(Amount) DESC ) AS rnk
FROM Table
GROUP BY ID
) t
WHERE rnk = 1
I had a table like
ID UserID rupees time
1 1 200 2014-01-05
---------------------------------
2 1 500 2014-04-06
----------------------------------
3 2 10 2014-05-05
----------------------------------
4 2 20 2014-05-06
----------------------------------
I want the output lie
ID UserID Rupees time CumulativeSum
1 1 200 2014-01-05 200
-------------------------------------------------
2 1 500 2014-04-06 700
-------------------------------------------------
3 2 10 2014-05-06 10
-------------------------------------------------
4 2 20 2014-05-06 30
---------------------------------------------------
How can i get this table as purput
Please try using CTE:
;With T as(
select
*,
ROW_NUMBER() over(partition by UserId order by [time]) RN
from tbl
)
select
UserID,
rupees,
[time],
(select SUM(rupees)
from T b
where b.UserID=a.UserID and b.RN<=a.RN) CumulativeSum
from T a
For records with column value time increasing, try the below query:
select
UserID,
rupees,
[time],
(select SUM(rupees)
from tbl b
where b.UserID=a.UserID and b.[time]<=a.[time]) CumulativeSum
from tbl a
For SQL Server 2012 or later, you can use SUM() with an OVER clause that specifies a ROW clause:
declare #t table (ID int,UserID int,rupees int,[time] date)
insert into #t(ID,UserID,rupees,[time]) values
(1,1,200,'20140105'),
(2,1,500,'20140406'),
(3,2, 10,'20140505'),
(4,2, 20,'20140506')
select
*,
SUM(rupees) OVER (
PARTITION BY UserID
ORDER BY id /* or time? */
ROWS BETWEEN
UNBOUNDED PRECEDING AND
CURRENT ROW)
as total
from #t
Result:
ID UserID rupees time total
----------- ----------- ----------- ---------- -----------
1 1 200 2014-01-05 200
2 1 500 2014-04-06 700
3 2 10 2014-05-05 10
4 2 20 2014-05-06 30
DECLARE #t table (UserID INT,rupees INT,DateKey Date )
INSERT INTO #t VALUES
(1,200,'2014-01-05'),
(2,300,'2014-01-06'),
(2,800,'2014-03-06')
select UserID,
rupees,
DateKey,
(SELECT SUM(rupees)from #t t
where t.rupees <= tt.rupees) from #t tt
GROUP BY UserID,rupees,DateKey
Hope this too helps you.
DECLARE #tab TABLE (id INT,userId INT,rupees INT,[time] Date)
INSERT INTO #tab VALUES
(1,1,200 ,'2014-01-05'),
(2,1,500 ,'2014-04-06'),
(3,2,10 ,'2014-05-05'),
(4,2,20 ,'2014-05-06')
SELECT LU.id,LU.userId,LU.rupees,LU.time,SUM(b.rupees) CumulativeSum
FROM (SELECT *,ROW_NUMBER() OVER (PARTITION BY userId ORDER BY [time]) R FROM #tab) B
JOIN (SELECT *,ROW_NUMBER() OVER (PARTITION BY userId ORDER BY [time]) R FROM #tab) LU
ON B.userId = LU.userId AND B.R <= LU.R
GROUP BY LU.id,LU.userId,LU.rupees,LU.time
Result
I am assuming that you are not using SQL Server 2012, which provides the cumulative sum function. The other answers use some form of the row_number() function, but these seems totally unnecessary. I usually approach cumulative sums using correlated subqueries:
select ID, UserID, rupees, [time],
(select sum(rupees)
from table t2
where t2.UserId = t.UserId and
t2.ID <= t.ID
) as CumulativeSum
from table t;
This requires having a column that uniquely identifies each row, and that seems to be the purpose of id. For performance, I would want to have an index on table(UserId, ID, rupees).
select *, SUM(rupees) OVER (
PARTITION BY UserID
ORDER BY id) as CumSum from #tbl
I have a table:
PropertyID Amount
--------------------------
1 40
1 20
1 10
2 10
2 90
I would like to achieve :
PropertyId Amount Total_Amount
---------------------------------------
1 40 70
1 20 70
1 10 70
2 10 100
2 90 100
using below query :
SELECT
PropertyID,
SUM(Amount),
SUM(TotalAmount)
FROM
yourTable
WHERE
EndDate IS NULL
GROUP BY
PropertyID
Output:
PropertyId Amount TotalAmount
-------------------------------------
1 70 70
2 100 100
Let me know how can I get my desired output ...
You can do this using window functions:
select PropertyID, Amount,
sum(Amount) over (partition by PropertyId) as TotalAmount
from yourtable;
The window function for sum() does the following. It calculates the sum of amount for groups of rows in the same group. The group is defined by the partition by clause, so rows with the same value of PropertyId are in the same group.
SELECT PropertyID,
Amount,
(select sum(yt.Amount)
from yourTable yt where yt.PropertyID==y.PropertyID and yt.EndDate IS NULL)
as TotalAmount
FROM yourTable y
WHERE y.EndDate IS NULL
I need to run a sweepstakes script to get X amount of winners from a customers table. Each customer has N participations. The table looks like this
CUSTOMER-A 5
CUSTOMER-B 8
CUSTOMER-C 1
I can always script to have CUSTOMER-A,B and C inserted 5, 8 and 1 times respectively in a temp table and then select randomly using order by newid() but would like to know if there's a more elegant way to address this.
(Update: Added final query.)
(Update2: Added single query to avoid temp table.)
Here's the hard part using a recursive CTE plus the final query that shows "place".
Code
DECLARE #cust TABLE (
CustomerID int IDENTITY,
ParticipationCt int
)
DECLARE #list TABLE (
CustomerID int,
RowNumber int
)
INSERT INTO #cust (ParticipationCt) VALUES (5)
INSERT INTO #cust (ParticipationCt) VALUES (8)
INSERT INTO #cust (ParticipationCt) VALUES (1)
INSERT INTO #cust (ParticipationCt) VALUES (3)
INSERT INTO #cust (ParticipationCt) VALUES (4)
SELECT * FROM #cust
;WITH t AS (
SELECT
lvl = 1,
CustomerID,
ParticipationCt
FROM #Cust
UNION ALL
SELECT
lvl = lvl + 1,
CustomerID,
ParticipationCt
FROM t
WHERE lvl < ParticipationCt
)
INSERT INTO #list (CustomerID, RowNumber)
SELECT
CustomerID,
ROW_NUMBER() OVER (ORDER BY NEWID())
FROM t
--<< All rows
SELECT * FROM #list ORDER BY RowNumber
--<< All customers by "place"
SELECT
CustomerID,
ROW_NUMBER() OVER (ORDER BY MIN(RowNumber)) AS Place
FROM #list
GROUP BY CustomerID
Results
CustomerID ParticipationCt
----------- ---------------
1 5
2 8
3 1
4 3
5 4
CustomerID RowNumber
----------- -----------
4 1
1 2
1 3
2 4
1 5
5 6
2 7
2 8
4 9
2 10
2 11
2 12
1 13
5 14
5 15
3 16
5 17
1 18
2 19
2 20
4 21
CustomerID Place
----------- -----
4 1
1 2
2 3
5 4
3 5
Single Query with No Temp Table
It is possible to get the answer with a single query that does not use a temp table. This works fine, but I personally like the temp table version better so you can validate the interim results.
Code (Single Query)
;WITH List AS (
SELECT
lvl = 1,
CustomerID,
ParticipationCt
FROM #Cust
UNION ALL
SELECT
lvl = lvl + 1,
CustomerID,
ParticipationCt
FROM List
WHERE lvl < ParticipationCt
),
RandomOrder AS (
SELECT
CustomerID,
ROW_NUMBER() OVER (ORDER BY NEWID()) AS RowNumber
FROM List
)
SELECT
CustomerID,
ROW_NUMBER() OVER (ORDER BY MIN(RowNumber)) AS Place
FROM RandomOrder
GROUP BY CustomerID
try this:
Select Top X CustomerId
From (Select CustomerId,
Rand(CustomerId) *
Count(*) /
(Select Count(*)
From Table) Sort
From Table
Group By CustomerId) Z
Order By Sort Desc
EDIT: abovbe assumed multiple rows per customer, one row per participation... Sorry, following assumes one row per customer, with column Participations holding number of participations for that customer.
Select Top 23 CustomerId
From ( Select CustomerId,
Participations - RAND(CustomerId) *
(Select SUM(Participations ) From customers) sort
from customers) Z
Order By sort desc