I am attempting to write Oracle SQL.
I am looking for solution something similar. Please find below data I have
start_date end_date customer
01-01-2012 31-06-2012 a
01-01-2012 31-01-2012 b
01-02-2012 31-03-2012 c
I want the count of customer in that date period. My result should look like below
Month : Customer Count
JAN-12 : 2
FEB-12 : 2
MAR-12 : 2
APR-12 : 1
MAY-12 : 1
JUN-12 : 1
One option would be to generate the months separately in another query and join that to your data table (note that I'm assuming that you intended customer A to have an end-date of June 30, 2012 since there is no June 31).
SQL> ed
Wrote file afiedt.buf
1 with mnths as(
2 select add_months( date '2012-01-01', level - 1 ) mnth
3 from dual
4 connect by level <= 6 ),
5 data as (
6 select date '2012-01-01' start_date, date '2012-06-30' end_date, 'a' customer from dual union all
7 select date '2012-01-01', date '2012-01-31', 'b' from dual union all
8 select date '2012-02-01', date '2012-03-31', 'c' from dual
9 )
10 select mnths.mnth, count(*)
11 from data,
12 mnths
13 where mnths.mnth between data.start_date and data.end_date
14 group by mnths.mnth
15* order by mnths.mnth
SQL> /
MNTH COUNT(*)
--------- ----------
01-JAN-12 2
01-FEB-12 2
01-MAR-12 2
01-APR-12 1
01-MAY-12 1
01-JUN-12 1
6 rows selected.
WITH TMP(monthyear,start_date,end_date,customer) AS (
select LAST_DAY(start_date),
CAST(ADD_MONTHS(start_date, 1) AS DATE),
end_date,
customer
from data
union all
select LAST_DAY(start_date),
CAST(ADD_MONTHS(start_date, 1) AS DATE),
end_date,
customer
from TMP
where LAST_DAY(end_date) >= LAST_DAY(start_date)
)
SELECT TO_CHAR(MonthYear, 'MON-YY') TheMonth,
Count(Customer) Customers
FROM TMP
GROUP BY MonthYear
ORDER BY MonthYear;
SQLFiddle
Related
I have 3 month tables for January, February and March.
January table:
ID
Date
1
01/01/2022
2
01/02/2022
3
01/02/2022
1
01/10/2022
4
01/12/2022
February table:
ID
Date
1
02/01/2022
2
02/07/2022
3
02/10/2022
2
02/15/2022
5
02/17/2022
March table:
ID
Date
1
03/19/2022
2
03/11/2022
3
03/14/2022
3
03/25/2022
6
03/13/2022
Lets assume i make a UNION ALL between all three tables. Now taking March as reference point, i need to classify each ID according to the last date it appeared in the table (the same ID can be repeated in the table with the same or different date, the max date is to be used for the excercise). Now i need to check in which months the IDs appear and be able to sort them according to the month where the ID is present.
Months
ID
Last Date
Jan-Feb-Mar
1
03/19/12
Jan-Feb-Mar
2
03/11/12
Jan-Feb-Mar
3
03/14/12
Jan
4
01/12/2022
Feb
5
02/17/2022
Mar
6
03/13/2022
Also i would need to classify according to a range of days since the last date an ID appeared. The range of days are the following: 1-30, 31-60 and 61-90. It should look something like this table below, even better if the field Months from the previous example shown is added too
Range of Days
ID
Last Date
Months
1-30
1
03/19/12
Jan-Feb-Mar
1-30
2
03/11/12
Jan-Feb-Mar
1-30
3
03/14/12
Jan-Feb-Mar
61-90
4
01/12/2022
Jan
31-60
5
02/17/2022
Feb
1-30
6
03/13/2022
Mar
Try this...
WITH
t_jan AS
(
Select 1 "ID", To_Date('01/01/2022', 'mm/dd/yyyy') "DT" From DUAL UNION ALL
Select 2 "ID", To_Date('01/02/2022', 'mm/dd/yyyy') "DT" From DUAL UNION ALL
Select 3 "ID", To_Date('01/02/2022', 'mm/dd/yyyy') "DT" From DUAL UNION ALL
Select 1 "ID", To_Date('01/10/2022', 'mm/dd/yyyy') "DT" From DUAL UNION ALL
Select 4 "ID", To_Date('01/12/2022', 'mm/dd/yyyy') "DT" From DUAL
),
t_feb AS
(
Select 1 "ID", To_Date('02/01/2022', 'mm/dd/yyyy') "DT" From DUAL UNION ALL
Select 2 "ID", To_Date('02/07/2022', 'mm/dd/yyyy') "DT" From DUAL UNION ALL
Select 3 "ID", To_Date('02/10/2022', 'mm/dd/yyyy') "DT" From DUAL UNION ALL
Select 2 "ID", To_Date('02/15/2022', 'mm/dd/yyyy') "DT" From DUAL UNION ALL
Select 5 "ID", To_Date('02/17/2022', 'mm/dd/yyyy') "DT" From DUAL
),
t_mar AS
(
Select 1 "ID", To_Date('03/19/2022', 'mm/dd/yyyy') "DT" From DUAL UNION ALL
Select 2 "ID", To_Date('03/11/2022', 'mm/dd/yyyy') "DT" From DUAL UNION ALL
Select 3 "ID", To_Date('03/14/2022', 'mm/dd/yyyy') "DT" From DUAL UNION ALL
Select 3 "ID", To_Date('03/25/2022', 'mm/dd/yyyy') "DT" From DUAL UNION ALL
Select 6 "ID", To_Date('03/13/2022', 'mm/dd/yyyy') "DT" From DUAL
),
-- -- -- -- -- -- -- -- -- -- -- --
mnths AS
(
Select
LISTAGG(MONTHS, '-') WITHIN GROUP (ORDER BY To_Char(DT, 'mm')) "MONTHS",
ID "ID",
Max(DT) "DT"
From
(
Select To_Char(Max(DT), 'Mon') "MONTHS", ID, Max(DT) "DT" From t_jan Group By ID UNION ALL
Select To_Char(Max(DT), 'Mon') "MONTHS", ID, Max(DT) "DT" From t_feb Group By ID UNION ALL
Select To_Char(Max(DT), 'Mon') "MONTHS", ID, Max(DT) "DT" From t_mar Group By ID
)
Group By
ID
),
days AS
(
Select
m.MONTHS "MONTHS",
m.ID "ID",
m.DT "DT",
Max(LAST_DAY(m.DT)) OVER() "LAST_DT",
Max(LAST_DAY(m.DT)) OVER() - m.DT "DAYS"
From
mnths m
)
SELECT
CASE
WHEN d.DAYS Between 1 And 30 THEN '1-30'
WHEN d.DAYS Between 31 And 60 THEN '31-60'
WHEN d.DAYS Between 61 And 90 THEN '61-90'
ELSE
'???'
END "RANGE_OF_DAYS",
d.ID "ID",
d.DT "LAST_DATE",
d.MONTHS "MONTHS"
FROM
days d
ORDER BY
d.ID
--
-- Result
--
-- RANGE_OF_DAYS ID LAST_DATE MONTHS
-- 1-30 1 19-MAR-22 Jan-Feb-Mar
-- 1-30 2 11-MAR-22 Jan-Feb-Mar
-- 1-30 3 25-MAR-22 Jan-Feb-Mar
-- 61-90 4 12-JAN-22 Jan
-- 31-60 5 17-FEB-22 Feb
-- 1-30 6 13-MAR-22 Mar
I have the following table showing when customers bought a certain product. The data I have is CustomerID, Amount, Dat. I am trying to create the column ProductsIn30Days, which represents how many products a customer bought in the range Dat-30 days inclusive the current day.
For example, ProductsIn30Days for CustomerID 1 on Dat 25.3.2020 is 7, since the customer bought 2 products on 25.3.2020 and 5 more products on 24.3.2020, which falls within 30 days before 25.3.2020.
CustomerID
Amount
Dat
ProductsIn30Days
1
1
23.3.2018
1
1
2
24.3.2020
2
1
3
24.3.2020
5
1
2
25.3.2020
7
1
2
24.5.2020
2
1
1
15.6.2020
3
2
7
24.3.2017
7
2
2
24.3.2020
2
I tried something like this with no success, since the partition only works on a single date rather than on a range like I would need:
select CustomerID, Amount, Dat,
sum(Amount) over (partition by CustomerID, Dat-30)
from table
Thank you for help.
You can use an analytic SUM function with a range window:
SELECT t.*,
SUM(Amount) OVER (
PARTITION BY CustomerID
ORDER BY Dat
RANGE BETWEEN INTERVAL '30' DAY PRECEDING AND CURRENT ROW
) AS ProductsIn30Days
FROM table_name t;
Which, for the sample data:
CREATE TABLE table_name (CustomerID, Amount, Dat) AS
SELECT 1, 1, DATE '2018-03-23' FROM DUAL UNION ALL
SELECT 1, 2, DATE '2020-03-24' FROM DUAL UNION ALL
SELECT 1, 3, DATE '2020-03-24' FROM DUAL UNION ALL
SELECT 1, 2, DATE '2020-03-25' FROM DUAL UNION ALL
SELECT 1, 2, DATE '2020-05-24' FROM DUAL UNION ALL
SELECT 1, 1, DATE '2020-06-15' FROM DUAL UNION ALL
SELECT 2, 7, DATE '2017-03-24' FROM DUAL UNION ALL
SELECT 2, 2, DATE '2020-03-24' FROM DUAL;
Outputs:
CUSTOMERID
AMOUNT
DAT
PRODUCTSIN30DAYS
1
1
2018-03-23 00:00:00
1
1
2
2020-03-24 00:00:00
5
1
3
2020-03-24 00:00:00
5
1
2
2020-03-25 00:00:00
7
1
2
2020-05-24 00:00:00
2
1
1
2020-06-15 00:00:00
3
2
7
2017-03-24 00:00:00
7
2
2
2020-03-24 00:00:00
2
Note: If you have values on the same date then they will be tied in the order and always aggregated together (i.e. rows 2 & 3). If you want them to be aggregated separately then you need to order by something else to break the ties but that would not work with a RANGE window.
db<>fiddle here
I'm working with Oracle and I have a table with a column of type TIMESTAMP. I was wondering how can I extract the records from last 4 weeks of activity on the database, partitioned by week.
Following rows are inserted on week 1
kc 2 04-10-2021
vc 3 06-10-2021
vk 4 07-10-2021
Following rows are inserted on week2
cv 1 12-10-2021
ck 5 14-10-2021
Following rows are inserted on week3
vv 7 19-10-2021
Following rows are inserted on week4
vx 7 29-10-2021
Table now has
SQL>select * from tab;
NAME VALUE TIMESTAMP
-------------------- ----------
kc 2 04-10-2021
vc 3 06-10-2021
vk 4 07-10-2021
cv 1 12-10-2021
ck 5 14-10-2021
vv 7 19-10-2021
vx 7 29-10-2021
I would like a query which would give me the number of rows added each week, in the last 4 weeks.
This is what I would like to see
numofrows week
--------- -----
3 1
2 2
1 3
1 4
One option is to use to_char function and its iw parameter:
SQL> with test (name, datum) as
2 (select 'kc', date '2021-10-04' from dual union all
3 select 'vc', date '2021-10-06' from dual union all
4 select 'vk', date '2021-10-07' from dual union all
5 select 'cv', date '2021-10-12' from dual union all
6 select 'ck', date '2021-10-14' from dual union all
7 select 'vv', date '2021-10-19' from dual union all
8 select 'vx', DATE '2021-10-29' from dual
9 )
10 select to_char(datum, 'iw') week,
11 count(*)
12 from test
13 where datum >= add_months(sysdate, -1) --> the last month
14 group by to_char(datum, 'iw');
WE COUNT(*)
-- ----------
42 1
43 1
40 3
41 2
SQL>
Line #13: I intentionally used "one month" instead of "4 weeks" as I thought (maybe wrongly) that you, actually, want that (you know, "a month has 4 weeks" - not exactly, but close, sometimes not close enough).
If you want 4 weeks, what is that, then? Sysdate minus 28 days (as every week has 7 days)? Then you'd modify line #13 to
where datum >= trunc(sysdate - 4*7)
Or, maybe it is really the last 4 weeks:
SQL> with test (name, datum) as
2 (select 'kc', date '2021-10-04' from dual union all
3 select 'vc', date '2021-10-06' from dual union all
4 select 'vk', date '2021-10-07' from dual union all
5 select 'cv', date '2021-10-12' from dual union all
6 select 'ck', date '2021-10-14' from dual union all
7 select 'vv', date '2021-10-19' from dual union all
8 select 'vx', DATE '2021-10-29' from dual
9 ),
10 temp as
11 (select to_char(datum, 'iw') week,
12 count(*) cnt,
13 row_number() over (order by to_char(datum, 'iw') desc) rn
14 from test
15 group by to_char(datum, 'iw')
16 )
17 select week, cnt
18 from temp
19 where rn <= 4
20 order by week;
WE CNT
-- ----------
40 3
41 2
42 1
43 1
SQL>
Now you have several options, see which one fits the best (if any).
I "simulated" missing data (see TEST CTE), created a calendar (calend) and ... did the job. Read comments within code:
SQL> with test (name, datum) as
2 -- sample data
3 (select 'vv', date '2021-10-19' from dual union all
4 select 'vx', DATE '2021-10-29' from dual
5 ),
6 calend as
7 -- the last 31 days; 4 weeks are included, obviously
8 (select max_datum - level + 1 datum
9 from (select max(a.datum) max_datum from test a)
10 connect by level <= 31
11 ),
12 joined as
13 -- joined TEST and CALEND data
14 (select to_char(c.datum, 'iw') week,
15 t.name
16 from calend c left join test t on t.datum = c.datum
17 ),
18 last4 as
19 -- last 4 weeks
20 (select week, count(name) cnt,
21 row_number() over (order by week desc) rn
22 from joined
23 group by week
24 )
25 select week, cnt
26 from last4
27 where rn <= 4
28 order by week;
WE CNT
-- ----------
40 0
41 0
42 1
43 1
SQL>
I was going through this forum for my query to get data for previous 7 days,but most of them give it for current date.Below is my requirement:
I have a Table 1 as below:
These are start dates of week which is monday
from_date
2016-01-04
2016-01-11
2016-01-18
Table 2
I have all days of week here starting from monday.Ex: jan 04 - monday to jan 10 - sunday and so on for other weeks also.
get_date flag value
2016-01-04 N 4
2016-01-05 N 9
2016-01-06 Y 2
2016-01-07 Y 13
2016-01-08 Y 7
2016-01-09 Y 8
2016-01-10 Y 8
2016-01-11 Y 1
2016-01-12 Y 9
2016-01-13 N 8
2016-01-14 N 24
2016-01-15 N 8
2016-01-16 Y 4
2016-01-17 Y 5
2016-01-18 Y 9
2016-01-19 Y 2
2016-01-20 Y 8
2016-01-21 Y 4
2016-01-22 N 9
2016-01-23 N 87
2016-01-24 Y 3
Expected Result
here wk is the unique number for each start-end dates respectively
avg value is the avg of the values for the dates in that week.
last 2 days of the week are weekend days.
say 2016-01-09 and 2016-01-10 are weekends
from_date get_date Wk Total_days Total_weekdays_flag_Y Total_weekenddays_flag_Y Avg_value
2016-01-04 2016-01-10 1 7 3 2 6.714285714
2016-01-11 2016-01-17 2 7 2 2 8.428571429
2016-01-18 2016-01-24 3 7 4 1 17.42857143
Could anyone help me with this as I am not good at sql.
Thanks
select
from_date
, Wk
, count(case when day_of_week <=5 and flag = 'Y' then 1 end) as Total_weekdays_flag_Y
, count(case when day_of_week > 5 and flag = 'Y' then 1 end) as Total_weekenddays_flag_Y
, avg(value) as Avg_value
from (
select trunc(get_date,'IW') as from_date
, (trunc(get_date,'IW')- trunc(date'2016-01-04','IW'))/7 + 1 as Wk
, flag
, value
, get_date - trunc(get_date,'IW') as day_of_week
from Table_2)
group by from_date, Wk
order by from_date, Wk;
EDIT:
/*generate some test_data for table 2*/
with table_2 (get_date, flag, value) as (
select date'2016-01-03' + level,
DECODE(mod(level,3),0,'Y','N'),
round(dbms_random.value(0,10))
from dual connect by level < 101
),
/*generate some test_weeks for table 1*/
table_1 (FROM_date) as (select date'2016-01-04' + (level-1)*7 from dual connect by level < 101 )
/*main query */
select
from_date
, Wk
, count(day_of_week) as total
, count(case when day_of_week <=5 and flag = 'Y' then 1 end) as Total_weekdays_flag_Y
, count(case when day_of_week > 5 and flag = 'Y' then 1 end) as Total_weekenddays_flag_Y
, avg(value) as Avg_value
from (
select last_value(from_date ignore nulls) over (order by get_date) as from_date
,last_value(Wk ignore nulls) over (order by get_date) as Wk
, flag
, value
, get_date - trunc(get_date,'IW') as day_of_week
from Table_2 t2
full join (select row_number() over (order by from_date) as wk,from_date from table_1) t1 on t2.get_date = t1.from_date
)
group by from_date, Wk
having count(day_of_week) > 0
order by from_date, Wk
In the query below, I create the test data right within the query; in final form, you would delete the subqueries table_1 and table_2 and use the rest.
The syntax will work from Oracle 11.2 on. In Oracle 11.1, you need to move the column names in factored subqueries to the select... from dual part. Or, since you really only have one subquery (prep) and an outer query, you can write prep as an actual, in-line subquery.
Your arithmetic seems off on the average for the first week.
In your sample output you use get_date for the last day of the week. That is odd, since in table_2 that name has a different meaning. I used to_date in my output. I also do not show total_days - that is always 7, so why include it at all? (If it is not always 7, then there is something you didn't tell us; anyway, a count(...), if that is what it should be, is easy to add).
with
-- begin test data, can be removed in final solution
table_1 ( from_date ) as (
select date '2016-01-04' from dual union all
select date '2016-01-11' from dual union all
select date '2016-01-18' from dual
)
,
table_2 ( get_date, flag, value ) as (
select date '2016-01-04', 'N', 4 from dual union all
select date '2016-01-05', 'N', 9 from dual union all
select date '2016-01-06', 'Y', 2 from dual union all
select date '2016-01-07', 'Y', 13 from dual union all
select date '2016-01-08', 'Y', 7 from dual union all
select date '2016-01-09', 'Y', 8 from dual union all
select date '2016-01-10', 'Y', 8 from dual union all
select date '2016-01-11', 'Y', 1 from dual union all
select date '2016-01-12', 'Y', 9 from dual union all
select date '2016-01-13', 'N', 8 from dual union all
select date '2016-01-14', 'N', 24 from dual union all
select date '2016-01-15', 'N', 8 from dual union all
select date '2016-01-16', 'Y', 4 from dual union all
select date '2016-01-17', 'Y', 5 from dual union all
select date '2016-01-18', 'Y', 9 from dual union all
select date '2016-01-19', 'Y', 2 from dual union all
select date '2016-01-20', 'Y', 8 from dual union all
select date '2016-01-21', 'Y', 4 from dual union all
select date '2016-01-22', 'N', 9 from dual union all
select date '2016-01-23', 'N', 87 from dual union all
select date '2016-01-24', 'Y', 3 from dual
),
-- end test data, continue actual query
prep ( get_date, flag, value, from_date, wd_flag ) as (
select t2.get_date, t2.flag, t2.value, t1.from_date,
case when t2.get_date - t1.from_date <= 4 then 'wd' else 'we' end
from table_1 t1 inner join table_2 t2
on t2.get_date between t1.from_date and t1.from_date + 6
)
select from_date,
from_date + 6 as to_date,
row_number() over (order by from_date) as wk,
count(case when flag = 'Y' and wd_flag = 'wd' then 1 end)
as total_weekday_Y,
count(case when flag = 'Y' and wd_flag = 'we' then 1 end)
as total_weekend_Y,
round(avg(value), 6) as avg_value
from prep
group by from_date;
Output:
FROM_DATE TO_DATE WK TOTAL_WEEKDAY_Y TOTAL_WEEKEND_Y AVG_VALUE
---------- ---------- ---- --------------- --------------- ----------
2016-01-04 2016-01-10 1 3 2 7.285714
2016-01-11 2016-01-17 2 2 2 8.428571
2016-01-18 2016-01-24 3 4 1 17.428571
I want to make a query, which shows the progress of the number of users on my webpage by week.
I use following query to run the users database and get the number, grouped by a week:
SELECT TRUNC(FAB.LICENSE_DATE, 'IW'),
COUNT(DISTINCT FAB.STATEMENT_NUMBER) AS "Number of account statements"
FROM USERS FAB
GROUP BY TRUNC(FAB.LAST_UPDATED_TIME, 'IW');
This gives following output:
Date | Users
----------------------
2015/09/07 | 5
2015/09/14 | 4
2015/09/21 | 6
But this is actually not what I want to achieve. I want to have the following output:
Date | Users
----------------------
2015/09/07 | 5
2015/09/14 | 9 (5 + 4)
2015/09/21 | 15 (5 + 4 + 6)
How to modify the query so I get all the results?
SQL Fiddle
Oracle 11g R2 Schema Setup:
CREATE TABLE USERS (
LICENSE_DATE,
LAST_UPDATED_TIME,
STATEMENT_NUMBER
) AS
SELECT DATE '2015-09-07', DATE '2015-09-07', 1 FROM DUAL
UNION ALL SELECT DATE '2015-09-08', DATE '2015-09-08', 2 FROM DUAL
UNION ALL SELECT DATE '2015-09-08', DATE '2015-09-08', 3 FROM DUAL
UNION ALL SELECT DATE '2015-09-09', DATE '2015-09-09', 4 FROM DUAL
UNION ALL SELECT DATE '2015-09-12', DATE '2015-09-12', 5 FROM DUAL
UNION ALL SELECT DATE '2015-09-14', DATE '2015-09-15', 6 FROM DUAL
UNION ALL SELECT DATE '2015-09-15', DATE '2015-09-16', 7 FROM DUAL
UNION ALL SELECT DATE '2015-09-16', DATE '2015-09-16', 8 FROM DUAL
UNION ALL SELECT DATE '2015-09-17', DATE '2015-09-18', 9 FROM DUAL
UNION ALL SELECT DATE '2015-09-21', DATE '2015-09-21', 10 FROM DUAL
UNION ALL SELECT DATE '2015-09-21', DATE '2015-09-26', 11 FROM DUAL
UNION ALL SELECT DATE '2015-09-22', DATE '2015-09-22', 12 FROM DUAL
UNION ALL SELECT DATE '2015-09-23', DATE '2015-09-25', 13 FROM DUAL
UNION ALL SELECT DATE '2015-09-24', DATE '2015-09-24', 14 FROM DUAL
UNION ALL SELECT DATE '2015-09-27', DATE '2015-09-27', 15 FROM DUAL;
Query 1:
SELECT LAST_UPDATED_WEEK,
SUM( NUM_STATEMENTS ) OVER ( ORDER BY LAST_UPDATED_WEEK ROWS BETWEEN UNBOUNDED PRECEDING AND CURRENT ROW ) AS "Number of account statements"
FROM (
SELECT TRUNC(LAST_UPDATED_TIME, 'IW') AS LAST_UPDATED_WEEK,
COUNT(DISTINCT STATEMENT_NUMBER) AS NUM_STATEMENTS
FROM USERS
GROUP BY
TRUNC( LAST_UPDATED_TIME, 'IW')
)
Results:
| LAST_UPDATED_WEEK | Number of account statements |
|-----------------------------|------------------------------|
| September, 07 2015 00:00:00 | 5 |
| September, 14 2015 00:00:00 | 9 |
| September, 21 2015 00:00:00 | 15 |
SELECT TRUNC(FAB.LICENSE_DATE, 'IW'),
SUM(COUNT(DISTINCT FAB.STATEMENT_NUMBER)) OVER (ORDER BY TRUNC(FAB.LAST_UPDATED_TIME, 'IW')) as "Number of account statements"
FROM USERS FAB
GROUP BY TRUNC(FAB.LAST_UPDATED_TIME, 'IW');
You can use this code block for your problem :
select u.date
,(select sum(u1.users)
from users u1
where u1.ddate <= u.date) as users
from users u;
It gives this output :
07.09.2015 5
14.09.2015 9
21.09.2015 15
Good luck
Hello you can try this code too.
WITH t1 AS
( SELECT to_date('01/01/2015','mm/dd/yyyy') rn, 5 usrs FROM dual
UNION ALL
SELECT to_date('02/01/2015','mm/dd/yyyy') rn, 4 usrs FROM dual
UNION ALL
SELECT to_date('03/01/2015','mm/dd/yyyy') rn, 8 usrs FROM dual
UNION ALL
SELECT to_date('04/01/2015','mm/dd/yyyy') rn, 2 usrs FROM dual
)
SELECT rn,
usrs,
sum(usrs) over (order by rn ROWS BETWEEN UNBOUNDED PRECEDING AND CURRENT ROW) cumm_usrs
FROM t1
GROUP BY rn,
usrs;