Check if two NSStrings are similar - objective-c

I present a tricky question that I am not sure how to approach. So, I have formulated a plist containing dictionaries which contain two objects:
The Country Name
The Plug Size Of The Country
There are only 210 countries/facts though.
And, I have enabled to search through a list of many many countries, in which there might be a fact or not. But here is my problem, I am using a web service called Geonames and the user can use a search bar display controller to search for countries, and these plist country names paired with plug sizes are actually from a Wikipedia article.
Now, the country naming in Geonames and in my plist from Wikipedia might be named slightly different, maybe with an extra space, an extra dash, an extra letter. This is why I want to see if the geoname country string is very similar to the one in the plist.
So, this would not be isEqualToString: because that finds if it is exact, can the compare: method work?
How can I approach this? Here is an example:
Geoname returns (not a real country just an example):
Yiting
But plist may return:
Yitting
So with 1 extra 't', but there are other circumstances. I would like these to be compared as exact, or at least similar, so I could consider them as a match.
Are there any tutorials, resources, projects etc. you could point me towards?
Thank you! Bye!

The Soundex algorithm is useful in cases like this.
I found a sample implementation on github.

You need to implement an algorithm for approximate matching of strings. One of the most popular such algorithms is Levenshtein distance, one of several Edit distance algorithms. The distance is calculated as the number of editing operations required to transform string A into string B - inserting, deleting, or changing a character counts as one edit operation. The closer are the strings, the smaller is the edit distance between them. You can calculate pairwise edit distances, and find the smallest one to identify the match.

You may find this post about auto update/complete useful:
I've tested that UITextViews work well while adhering to the UITextViewDelegate protocol in your UIViewController class and will produce a result similar to what you'll find in the Messages app. I haven't checked if UITextField and UITextFieldDelegate do as well.

Related

Machine Learning text comparison model

I am creating a machine learning model that essentially returns the correctness of one text to another.
For example; “the cat and a dog”, “a dog and the cat”. The model needs to be able to identify that some words (“cat”/“dog”) are more important/significant than others (“a”/“the”). I am not interested in conjunction words etc. I would like to be able to tell the model which words are the most “significant” and have it determine how correct text 1 is to text 2, with the “significant” words bearing more weight than others.
It also needs to be able to recognise that phrases don’t necessarily have to be in the same order. The two above sentences should be an extremely high match.
What is the basic algorithm I should use to go about this? Is there an alternative to just creating a dataset with thousands of example texts and a score of correctness?
I am only after a broad overview/flowchart/process/algorithm.
I think TF-IDF might be a good fit to your problem, because:
Emphasis on words occurring in many documents (say, 90% of your sentences/documents contain the conjuction word 'and') is much smaller, essentially giving more weight to the more document specific phrasing (this is the IDF part).
Ordering in Term Frequency (TF) does not matter, as opposed to methods using sliding windows etc.
It is very lightweight when compared to representation oriented methods like the one mentioned above.
Big drawback: Your data, depending on the size of corpus, may have too many dimensions (the same number of dimensions as unique words), you could use stemming/lemmatization in order to mitigate this problem to some degree.
You may calculate similiarity between two TF-IDF vector using cosine similiarity for example.
EDIT: Woops, this question is 8 months old, sorry for the bump, maybe it will be of use to someone else though.

Oracle String Conversion - Alpha String to Numeric Score, Fuzzy Match

I'm working with a lot of name data where the following events are happening:
In one stream the data is submitted as "Sung" and in the other stream "Snug" my initial thought to this was to convert Sung and Snug to where each character equals a number then the sums would be the same, so even if they transverse a character, I'd be able to bucket these appropriately.
The other is where in one stream it comes in as "Lillly" as opposed to "Lilly" in the other stream. I'd like to figure out how to fuzzy match these such that I can identify them. I'm not sure if this is possible in Oracle.
I'm working with many millions of data points and trying to figure out how to write these classification buckets such that I can stop having so much noise in my primary task of finding where people are truly different people as opposed to a clerical error.
Any thoughts would be very appreciated.
A common measure for such distance is called Levenshtein distance (Wikipedia here). This measures the "edit" distance between two strings -- number of edit operations needed to convert one into the other.
That's the good news. More good news is that Oracle even has an implementation in the UTL_MATCH library.
The bad news is that it is really, really expensive on millions of data points. Unfortunately, I cannot help you there so much. One idea is to determine which names are "close enough" because they already share a certain minimum number of characters.
Another method is to convert the strings to what they sound like. That is called soundex. You may be able to use the two together -- assuming your names are predominantly English (the soundex algorithm was invented by the US Census Bureau, so it would work best on names in America).

How do I implement these strong password requirements?

No keyboard patterns. i.e. keys that are adjacent vertically or horizontally on a keyboard. For example, 'ZXCVBN123' should be rejected.
No commonly used words and no words written backwards or disguised with special characters. For example 'Universe1' and 'Un1ver$e' should be rejected.
Well, first you need to define exactly what you want. What are keyboard patterns? Is 'jk' a keyboard pattern, or just 'jkl'? What's the shortest pattern there is? Is 'gy' a pattern? First you need to define what a pattern really.
Then you should make a list of all the available patterns (There aren't all that many. You have 36 starting points and 4 directions to go from each starting point). When you get a password, try to locate each of the patterns in it. Note that if you decide the shortest pattern is 3 letters long, you don't need to search for 4-letter patterns, all 4-letter patterns already contain 3-letter patterns.
As for words, that's easier, but first you need to make a list of all disallowed transformations ($->S, 1->i, etc...). Once you get a word, apply all the transformations and get yourself a 'normalized' word. Compare the normalized password against a dictionary of all legal words twice - the second time reverse the password.
You will probably need to do something a little more complicated than that, because you need to ignore numbers at the end of the word - sometimes. 1ncredible can be a substitute for 'incredible', although ncredible is not a word.
If you inspect the code of http://howsecureismypassword.net you can see that the password is compared to a large array of usual passwords.
On the page threre is a reference to the page http://xato.net/passwords/more-top-worst-passwords/ which lists the top 10.000 most common passwords.
One approach would be to download that list and check the users passwords against it or at least some top 100 of them.

Testing how close together two letters can be (2D)

I'm working on a small design project, part of which involved writing out text in a given font such that the letters of a word are just touching each other on their right and left sides.
I've thought of implementing this as follows - create GlyphVectors of two letters, create Shape objects using vector.getOutline(), then create Area objects and intersect them.
The only thing I'm missing with this method is the ability to shift the second letter to the right until the intersect is empty.
Is there a way to do this, or do I need to use a different approach?
TIA
eta: ok, I've figured out I can use AffineTransform. Now, is there a way to tell the size (surface area) of the Area created by the intersection of two letters?
How precise do you want this to be? Pixel precision is much easier to attain than vector precision. Have you considered linearisation (usually done through
public PathIterator getPathIterator(AffineTransform at, double flatness)
) of outlines and then doing search in opposite directions among all points? This seems to be the most obvious solution even though it is not vector-precise.

Algorithm for almost similar values search

I have Persons table in SQL Server 2008.
My goal is to find Persons who have almost similar addresses.
The address is described with columns state, town, street, house, apartment, postcode and phone.
Due to some specific differences in some states (not US) and human factor (mistakes in addresses etc.), address is not filled in the same pattern.
Most common mistakes in addresses
Case sensitivity
Someone wrote "apt.", another one "apartment" or "ap." (although addresses aren't written in English)
Spaces, dots, commas
Differences in writing street names, like 'Dr. Jones str." or "Doctor Jones street" or "D. Jon. st." or "Dr Jones st" etc.
The main problem is that data isn't in the same pattern, so it's really difficult to find similar addresses.
Is there any algorithm for this kind of issue?
Thanks in advance.
UPDATE
As I mentioned address is separated into different columns. Should I generate a string concatenating columns or do your steps for each column?
I assume I shouldn't concatenate columns, but if I'll compare columns separately how should I organize it? Should I find similarities for each column an union them or intersect or anything else?
Should I have some statistics collecting or some kind of educating algorithm?
Suggest approaching it thus:
Create word-level n-grams (a trigram/4-gram might do it) from the various entries
Do a many x many comparison for string comparison and cluster them by string distance. Someone suggested Levenshtein; there are better ones for this kind of task, Jaro-Winkler Distance and Smith-Waterman work better. A libraryt such as SimMetrics would make life a lot easier
Once you have clusters of n-grams, you can resolve the whole string using the constituent subgrams i.e. D.Jones St => Davy Jones St. => DJones St.
Should not be too hard, this is an all-too-common problem.
Update: Based on your update above, here are the suggested steps
Catenate your columns into a single string, perhaps create a db "view" . For example,
create view vwAddress
as
select top 10000
state town, street, house, apartment, postcode,
state+ town+ street+ house+ apartment+ postcode as Address
from ...
Write a separate application (say in Java or C#/VB.NET) and Use an algorithm like JaroWinkler to estimate the string distance for the combined address, to create a many x many comparison. and write into a separate table
address1 | address n | similarity
You can use Simmetrics to get the similarity thus:
JaroWinnkler objJw = new JaroWinkler()
double sim = objJw.GetSimilarity (address1, addres n);
You could also trigram it so that an address such as "1 Jones Street, Sometown, SomeCountry" becomes "1 Jones Street", "Jones Street Sometown", and so on....
and compare the trigrams. (or even 4-grams) for higher accuracy.
Finally you can order by similarity to get a cluster of most similar addresses and decide an approprite threshold. Not sure why you are stuck
I would try to do the following:
split up the address in multiple words, get rid of punctuation at the same time
check all the words for patterns that are typically written differently and replace them with a common name (e.g. replace apartment, ap., ... by apt, replace Doctor by Dr., ...)
put all the words back in one string alphabetically sorted
compare all the addresses using a fuzzy string comparison algorithm, e.g. Levenshtein
tweak the parameters of the Levenshtein algorithm (e.g. you want to allow more differences on longer strings)
finally do a manual check of the strings
Of course, the solution to keep your data 'in shape' is to have explicit fields for each of your characteristics in your database. Otherwise, you will end up doing this exercise every few months.
The main problem I see here is to exactly define equality.
Even if someone writes Jon. and another Jone. - you will never be able to say if they are the same. (Jon-Jonethan,Joneson,Jonedoe whatever ;)
I work in a firm where we have to handle exact this problem - I'm afraid I have to tell you this kind of checking the adress lists for navigation systems is done "by hand" most of the time. Abbrevations are sometimes context dependend, and there are other things that make this difficult. Ofc replacing string etc is done with python - but telling you the MEANING of such an abbr. can only done by script in a few cases. ("St." -> Can be "Saint" and "Street". How to decide? impossible...this is human work.).
Another big problem is as you said "Is there a street "DJones" or a person? Or both? Which one is ment here? Is this DJones the same as Dr Jones or the same as Don Jones? Its impossible to decide!
You can do some work with lists as presented by another answer here - but it will give you enough "false positives" or so.
You have a postcode field!!!
So, why don't you just buy a postcode table for your country
and use that to clean up your street/town/region/province information?
I did a project like this in the last centuary. Basicly it was a consolidation of two customer files after a merger, and, involved names and addresses from three different sources.
Firstly as many posters have suggested, convert all the common words and abbreveations and spelling mistakes to a common form "Apt." "Apatment" etc. to "Apt".
Then look through the name and identifiy the first letter of the first name, plus the first surname. (Not that easy consider "Dr. Med. Sir Henry de Baskerville Smythe") but dont worry where there are amiguities just take both! So if you lucky you get HBASKERVILLE and HSMYTHE. Now get rid of all the vowels as thats where most spelling variations occur so now you have HBSKRVLL HSMTH.
You would also get these strings from "H. Baskerville","Sir Henry Baskerville Smith" and unfortunately "Harold Smith" but we are talking fuzzy matching here!
Perform a similar exercise on the street, and apartment and postcode fields. But do not throw away the original data!
You now come to the interesting bit first you compare each of the original strings and give say 50 points for each string that matches exactly. Then go through you "normalised" strings and give say 20 points for each one that matches exactly. Then go through all the strings and give say 5 points for each four character or more substring they have in common. For each pair compared you will end up with some with scores > 150 which you can consider as a certain match, some with scores less than 50 which you can consider not matched and some inbetween which have some probability of matching.
You need some more tweaking to improve this by adding various rules like "subtract 20 points for a surname of 'smith'". You really have to keep running and tweaking until you get happy with the resulting matches, but, once you look at the results you get a pretty good feel which score to consider a "match" and which are the false positives you need to get rid of.
I think the amount of data could affect what approach works best for you.
I had a similar problem when indexing music from compilation albums with various artists. Sometimes the artist came first, sometimes the song name, with various separator styles.
What I did was to count the number of occurrences on other entries with the same value to make an educated guess wether it was the song name or an artist.
Perhaps you can use soundex or similar algorithm to find stuff that are similar.
EDIT: (maybe I should clarify that I assumed that artist names were more likely to be more frequently reoccurring than song names.)
One important thing that you mention in the comments is that you are going to do this interactively.
This allows to parse user input and also at the same time validate guesses on any abbreviations and to correct a lot of mistakes (the way for example phone number entry works some contact management systems - the system does the best effort to parse and correct the country code, area code and the number, but ultimately the user is presented with the guess and has the chance to correct the input)
If you want to do it really good then keeping database/dictionaries of postcodes, towns, streets, abbreviations and their variations can improve data validation and pre-processing.
So, at least you would have fully qualified address. If you can do this for all the input you will have all the data categorized and matches can then be strict on certain field and less strict on others, with matching score calculated according weights you assign.
After you have consistently pre-processed the input then n-grams should be able to find similar addresses.
Have you looked at SQL Server Integration Services for this? The Fuzzy Lookup component allows you to find 'Near matches': http://msdn.microsoft.com/en-us/library/ms137786.aspx
For new input, you could call the package from .Net code, passing the value row to be checked as a set of parameters, you'd probably need to persist the token index for this to be fast enough for user interaction though.
There's an example of address matching here: http://msdn.microsoft.com/en-us/magazine/cc163731.aspx
I'm assuming that response time is not critical and that the problem is finding an existing address in a database, not merging duplicates. I'm also assuming the database contains a large number of addresses (say 3 million), rather than a number that could be cleaned up economically by hand or by Amazon's Mechanical Turk.
Pre-computation - Identify address fragments with high information content.
Identify all the unique words used in each database field and count their occurrences.
Eliminate very common words and abbreviations. (Street, st., appt, apt, etc.)
When presented with an input address,
Identify the most unique word and search (Street LIKE '%Jones%') for existing addresses containing those words.
Use the pre-computed statistics to estimate how many addresses will be in the results set
If the estimated results set is too large, select the second-most unique word and combine it in the search (Street LIKE '%Jones%' AND Town LIKE '%Anytown%')
If the estimated results set is too small, select the second-most unique word and combine it in the search (Street LIKE '%Aardvark%' OR Town LIKE '%Anytown')
if the actual results set is too large/small, repeat the query adding further terms as before.
The idea is to find enough fragments with high information content in the address which can be searched for to give a reasonable number of alternatives, rather than to find the most optimal match. For more tolerance to misspelling, trigrams, tetra-grams or soundex codes could be used instead of words.
Obviously if you have lists of actual states / towns / streets then some data clean-up could take place both in the database and in the search address. (I'm very surprised the Armenian postal service does not make such a list available, but I know that some postal services charge excessive amounts for this information. )
As a practical matter, most systems I see in use try to look up people's accounts by their phone number if possible: obviously whether that is a practical solution depends upon the nature of the data and its accuracy.
(Also consider the lateral-thinking approach: could you find a mail-order mail-list broker company which will clean up your database for you? They might even be willing to pay you for use of the addresses.)
I've found a great article.
Adding some dlls as sql user-defined functions we can use string comparison algorithms using SimMetrics library.
Check it
http://anastasiosyal.com/archive/2009/01/11/18.aspx
the possibilities of such variations are countless and even if such an algorithm exists, it can never be fool-proof. u can't have a spell checker for nouns after all.
what you can do is provide a drop-down list of previously entered field values, so that they can select one, if a particular name already exists.
its better to have separate fields for each value like apartments and so on.
You could throw all addresses at a web service like Google Maps (I don't know whether this one is suitable, though) and see whether they come up with identical GPS coordinates.
One method could be to apply the Levenshtein distance algorithm to the address fields. This will allow you to compare the strings for similarity.
Edit
After looking at the kinds of address differences you are dealing with, this may not be helpful after all.
Another idea is to use learning. For example you could learn, for each abbreviation and its place in the sentence, what the abbreviation means.
3 Jane Dr. -> Dr (in 3rd position (or last)) means Drive
Dr. Jones St -> Dr (in 1st position) means Doctor
You could, for example, use decision trees and have a user train the system. Probably few examples of each use would be enough. You wouldn't classify single-letter abbreviations like D.Jones that could be David Jones, or Dr. Jones as likely. But after a first level of translation you could look up a street index of the town and see if you can expand the D. into a street name.
Again, you would run each address through the decision tree before storing it.
It feels like there should be some commercial products doing this out there.
A possibility is to have a dictionary table in the database that maps all the variants to the 'proper' version of the word:
*Value* | *Meaning*
Apt. | Apartment
Ap. | Apartment
St. | Street
Then you run each word through the dictionary before you compare.
Edit: this alone is too naive to be practical (see comment).