I have two files I merged them based key using below code
file1
-------------------------------
1 a t p bbb
2 b c f aaa
3 d y u bbb
2 b c f aaa
2 u g t ccc
2 b j h ccc
file2
--------------------------------
1 11 bbb
2 22 ccc
3 33 aaa
4 44 aaa
I merged these two file based key using below code
awk 'NR==FNR{a[$3]=$0;next;}{for(x in a){if(x==$5) print $1,$2,$3,$4,a[x]};
My question is how I can save $2 of file2 in variable or array and print after a[x] again.
My desired result is :
1 a t p 1 11 bbb 11
2 b c f 3 33 aaa 33
2 b c f 4 44 aaa 44
3 d y u 1 11 bbb 11
2 b c f 3 33 aaa 33
2 b c f 4 44 aaa 44
2 u g t 2 22 ccc 22
2 b j h 2 22 ccc 22
As you see the first 7 columns is the result of my merge code. I need add the last column (field 2 of a[x]) to my result.
Important:
My next question is if I have .awk file, how I can use some bash script code like (| column -t) or send result to file (awk... > result.txt)? I always use these codes in command prompt. Can I use them inside my code in .awk file?
Simply add all of file2 to an array, and use split to hold the bits you want:
awk 'FNR==NR { two[$0]++; next } { for (i in two) { split(i, one); if (one[3] == $NF) print $1,$2,$3,$4, i, one[2] } }' file2 file1
Results:
1 a t p 1 11 bbb 11
2 b c f 3 33 aaa 33
2 b c f 4 44 aaa 44
3 d y u 1 11 bbb 11
2 b c f 3 33 aaa 33
2 b c f 4 44 aaa 44
2 u g t 2 22 ccc 22
2 b j h 2 22 ccc 22
Regarding your last question; you can also add 'pipes' and 'writes' inside of your awk. Here's an example of a pipe to column -t:
Contents of script.awk:
FNR==NR {
two[$0]++
next
}
{
for (i in two) {
split(i, one)
if (one[3] == $NF) {
print $1,$2,$3,$4, i, one[2] | "column -t"
}
}
}
Run like: awk -f script.awk file2 file1
EDIT:
Add the following to your shell script:
results=$(awk '
FNR==NR {
two[$0]++
next
}
{
for (i in two) {
split(i, one)
if (one[3] == $NF) {
print $1,$2,$3,$4, i, one[2] | "column -t"
}
}
}
' $1 $2)
echo "$results"
Run like:
./script.sh file2.txt file1.txt
Results:
1 a t p 1 11 bbb 11
2 b c f 3 33 aaa 33
2 b c f 4 44 aaa 44
3 d y u 1 11 bbb 11
2 b c f 3 33 aaa 33
2 b c f 4 44 aaa 44
2 u g t 2 22 ccc 22
2 b j h 2 22 ccc 22
Your current script is:
awk 'NR==FNR { a[$3]=$0; next }
{ for (x in a) { if (x==$5) print $1,$2,$3,$4,a[x] } }'
(Actually, the original is missing the second close brace for the second pattern/action pair.)
It seems that you process file2 before you process file1.
You shouldn't need the loop in the second code. And you can make life easier for yourself by using the splitting in the first phase to keep the values you need:
awk 'NR==FNR { c1[$3] = $1; c2[$3] = $2; next }
{ print $1, $2, $3, $4, c1[$5], c2[$5], $5, c2[$5] }'
You can upgrade that to check whether c1[$5] and c2[$5] are defined, presumably skipping the row if they are not.
Given your input files, the output is:
1 a t p 1 11 bbb 11
2 b c f 4 44 aaa 44
3 d y u 1 11 bbb 11
2 b c f 4 44 aaa 44
2 u g t 2 22 ccc 22
2 b j h 2 22 ccc 22
Give or take column spacing, that's what was requested. Column spacing can be fixed by using printf instead of print, or setting OFS to tab, or ...
The c1 and c2 notations for column 1 and 2 is OK for two columns. If you need more, then you should probably use the 2D array notation:
awk 'NR==FNR { for (i = 1; i <= NF; i++) col[i,$3] = $i; next }
{ print $1, $2, $3, $4, col[1,$5], col[2,$5], $5, col[2,$5] }'
This produces the same output as before.
To achieve what you ask, save the second field after the whole line in the processing of your first file, with a[$3]=$0 OFS $2. For your second question, awk has a variable to separate fields in output, it's OFS, assign a tabulator to it and play with it. Your script would be like:
awk '
BEGIN { OFS = "\t"; }
NR==FNR{
a[$3]=$0 OFS $2;
next;
}
{
for(x in a){
if(x==$5) print $1,$2,$3,$4,a[x]
}
}
' file2 file1
That yields:
1 a t p 1 11 bbb 11
2 b c f 4 44 aaa 44
3 d y u 1 11 bbb 11
2 b c f 4 44 aaa 44
2 u g t 2 22 ccc 22
2 b j h 2 22 ccc 22
Related
I have an AWK program that does a join of two files, file1 and file2. The files are joined based on a set of columns. I placed the AWK program into a bash script that I named join.sh. See below. Here is an example of how the script is executed:
./join.sh '1,2,3,4' '2,3,4,5' file1 file2
That says this: Do a join of file1 and file2, using columns (fields) 1,2,3,4 of file1 and columns (fields) 2,3,4,5 of file2.
That works great.
Now what I would like to do is to filter file2 and pipe the results to the join tool:
./fetch.sh ident file2 | ./join.sh '1,2,3,4' '2,3,4,5' file1
fetch.sh is a bash script containing an AWK program that fetches the rows in file2 with primary key ident and outputs to stdout the rows that were fetched.
Unfortunately, that pipeline is not working. I get no results.
Recap: I want the join program to be able to read the second file either from a file that I specify on the command line or from data received via a pipe. How to do that?
Here is my bash script, named join.sh
#!/bin/bash
awk -v f1cols=$1 -v f2cols=$2 '
BEGIN { FS=OFS="\t"
m=split(f1cols,f1,",")
n=split(f2cols,f2,",")
}
{ sub(/\r$/, "") }
NR == 1 { b[0] = $0 }
(NR == FNR) && (NR > 1) { idx2=$(f2[1])
for (i=2;i<=n;i++)
idx2=idx2 $(f2[i])
a[idx2] = $0
next
}
(NR != FNR) && (FNR == 1) { print $0, b[0] }
FNR > 1 { idx1=$(f1[1])
for (i=2;i<=m;i++)
idx1=idx1 $(f1[i])
for (idx1 in a)
print $0, a[idx1]
}' $3 $4
I'm not sure if this is 'correct' as you haven't provided any example input and expected output, but does using - to signify stdin work for your use-case? E.g.
cat file1
1 2 3 4
AA BB CC DD
AA EE FF GG
cat file2
1 2 3 4
AA ZZ YY XX
AA 11 22 33
./join.sh '1' '1' file1 file2
1 2 3 4 1 2 3 4
AA ZZ YY XX AA BB CC DD
AA ZZ YY XX AA EE FF GG
AA 11 22 33 AA BB CC DD
AA 11 22 33 AA EE FF GG
cat file2 | ./join.sh '1' '1' file1 -
1 2 3 4 1 2 3 4
AA ZZ YY XX AA BB CC DD
AA ZZ YY XX AA EE FF GG
AA 11 22 33 AA BB CC DD
AA 11 22 33 AA EE FF GG
be able to read(...)from data received via a pipe
GNU AWK does support Using getline from a Pipe consider following simple example
awk 'BEGIN{cmd="seq 7";while((cmd | getline) > 0){print $1*7};close(cmd)}' emptyfile
gives output
7
14
21
28
35
42
49
Explanation: I process output of seq 7 command (numbers from 1 to 7 inclusive, each on separate line), body of while is executed for each line of seq 7 output, fields are set like for normal processing.
I have a file
a x 0 3
a x 0 1
b,c x 4 4
dd x 3 5
dd x 2 5
e,e,t x 5 7
a b 1 9
cc b 2 1
cc b 1 1
e,e,t b 1 2
e,e,t b 1 2
e,e,t b 1 2
for each element in $1$2, I want print the sum $3, $4 and the number of occurrences/lenght/counts
So that I have
a x 0 4 0 2
b,c x 4 4 1 1
dd x 5 10 2 2
e,e,t x 5 7 1 1
a b 1 9 1 1
cc b 3 2 2 2
e,e,t b 3 6 3 3
I am using
awk -F"\t" '{for(n=2;n<=NF; ++n) a[$1 OFS $2][n]+=$n}
END {for(i in a) {
printf "%s", i
for (n=3; n<=4; ++n) printf "\t%s", a[i][n], a[i][n]++
printf "\n" }}' file
but it's only printing the sums, not the counts
The actual file has many columns: the keys are $4$6$7$8 and the numerical columns are $9-$13
You may use this awk:
cat sum.awk
BEGIN {
FS = OFS = "\t" # set input/output FS to tab
}
{
k = $1 OFS $2 # create key using $1 tab $2
if (!(k in map3)) # if k is not in map3 save it in an ordered array
ord[++n] = k
map3[k] += $3 # sum of $3 in array map3 using key as k
$3 > 0 && ++fq3[k] # frequency of $3 if it is > 0
map4[k] += $4 # sum of $4 in array map4 using key as k
$4 > 0 && ++fq4[k] # frequency of $4 if it is > 0
}
END {
for(i=1; i<=n; ++i) # print everything by looping through ord array
print ord[i], map3[ord[i]], map4[ord[i]], fq3[ord[i]]+0, fq4[ord[i]]+0
}
Then use it as:
awk -f sum.awk file
a x 0 4 0 2
b,c x 4 4 1 1
dd x 5 10 2 2
e,e,t x 5 7 1 1
a b 1 9 1 1
cc b 3 2 2 2
e,e,t b 3 6 3 3
I have 5 tab delim files
file 0 is basically a key
A
C
F
AA
BC
CC
D
KKK
S
file1
A 2
C 3
F 5
AA 5
BC 4
D 7
file2
A 2
C 3
F 7
D 10
file3
A 2
C 2
F 5
CC 4
D 7
file4
A 1
C 3
F 5
CC 4
D 7
KKK 10
I would like to merge all files based on the 1st column and print 0 in missing fields.
A 2 2 2 1
C 3 3 2 3
F 5 7 5 5
AA 5 0 0 0
BC 4 0 0 0
CC 0 0 4 4
D 7 10 7 7
KKK 0 0 0 10
S 0 0 0 0
Columns must keep the order of input file0, file1, file2, file3, file4
I was going to wait til you included your own attempt in your question but since you have 2 answers already anyway....
$ cat tst.awk
NR==FNR {
key2rowNr[$1] = ++numRows
rowNr2key[numRows] = $1
next
}
FNR==1 { ++numCols }
{
rowNr = key2rowNr[$1]
vals[rowNr,numCols] = $2
}
END {
for (rowNr=1; rowNr<=numRows; rowNr++) {
printf "%s", rowNr2key[rowNr]
for (colNr=1; colNr<=numCols; colNr++) {
printf "%s%d", OFS, vals[rowNr,colNr]
}
print ""
}
}
$ awk -f tst.awk file0 file1 file2 file3 file4
A 2 2 2 1
C 3 3 2 3
F 5 7 5 5
AA 5 0 0 0
BC 4 0 0 0
CC 0 0 4 4
D 7 10 7 7
KKK 0 0 0 10
S 0 0 0 0
awk solution
awk '
FNR==1{f++}
{
a[f""$1]=$2
b[$1]++
}
END{
for(i in b){
printf i" "
for(j=1;j<=f;j++){
tmp=j""i
if(tmp in a){
printf a[tmp]" "
}else{
printf 0" "
}
}
print ""
}
}
' file*
oupput :
A 2 2 2 1
AA 5 0 0 0
BC 4 0 0 0
C 3 3 2 3
CC 0 0 4 4
D 7 10 7 7
F 5 7 5 5
KKK 0 0 0 10
S 0 0 0 0
first i store every value for each file number and key value in variable a
then store all uniqe key in variable b
and in END block, checked if key is exists or not, if exists print it OR not exist print 0
we can delete file0, if delete it, awk show only exists key in file1,2,3,4,..
Not awk, but this sort of joining of files on a common field is exactly what join is meant for. Complicated a bit by it only working with two files at a time; you have to pipe the results of each one into the next as the first file.
$ join -o 0,2.2 -e0 -a1 <(sort file0) <(sort file1) \
| join -o 0,1.2,2.2 -e0 -a1 - <(sort file2) \
| join -o 0,1.2,1.3,2.2 -e0 -a1 - <(sort file3) \
| join -o 0,1.2,1.3,1.4,2.2 -e0 -a1 - <(sort file4) \
| tr ' ' '\t'
A 2 2 2 1
AA 5 0 0 0
BC 4 0 0 0
C 3 3 2 3
CC 0 0 4 4
D 7 10 7 7
F 5 7 5 5
KKK 0 0 0 10
S 0 0 0 0
Caveats: This requires a shell like bash or zsh that understands <(command) redirection. Sorting all the files in advance is an alternative. Or as pointed out, even though join normally requires its input files to be sorted on the column that's being joined on, it works anyways without the sorts for this particular input.
With GNU awk you can use the ENDFILE clause to make sure you have enough elements in all rows, e.g.:
parse.awk
BEGIN { OFS = "\t" }
# Collect all information into the `h` hash
{ h[$1] = (ARGIND == 1 ? $1 : h[$1] OFS $2) }
# At the end of each file do the necessary padding
ENDFILE {
for(k in h) {
elems = split(h[k], a, OFS)
if (elems != ARGIND)
h[k] = h[k] OFS 0
}
}
# Print the content of `h`
END {
for(k in h)
print h[k]
}
Run it like this:
awk -f parse.awk file[0-4]
Output:
AA 5 0 0 0
A 2 2 2 1
C 3 3 2 3
D 7 10 7 7
BC 4 0 0 0
CC 0 0 4 4
S 0 0 0 0
KKK 0 0 0 10
F 5 7 5 5
NB: This solution assumes you only have two columns per file (except the first one).
You could use coreutils join to determine missing fields and add them to each file:
sort file0 > file0.sorted
for file in file[1-4]; do
{
cat $file
join -j 1 -v 1 file0.sorted <(sort $file) | sed 's/$/ 0/'
} | sort > $file.sorted
done
Now you just need to paste them together:
paste file0.sorted \
<(cut -d' ' -f2 file1.sorted) \
<(cut -d' ' -f2 file2.sorted) \
<(cut -d' ' -f2 file3.sorted) \
<(cut -d' ' -f2 file4.sorted)
Output:
A 2 2 2 1
AA 5 0 0 0
BC 4 0 0 0
C 3 3 2 3
CC 0 0 4 4
D 7 10 7 7
F 5 7 5 5
KKK 0 0 0 10
S 0 0 0 0
To figure out my problem, I subtract column 3 and create a new column 5 with new values, then I print the previous and current line if the value found is equal to 25 in column 5.
Input file
1 1 35 1
2 5 50 1
2 6 75 1
4 7 85 1
5 8 100 1
6 9 125 1
4 1 200 1
I tried
awk '{$5 = $3 - prev3; prev3 = $3; print $0}' file
output
1 1 35 1 35
2 5 50 1 15
2 6 75 1 25
4 7 85 1 10
5 8 100 1 15
6 9 125 1 25
4 1 200 1 75
Desired Output
2 5 50 1 15
2 6 75 1 25
5 8 100 1 15
6 9 125 1 25
Thanks in advance
you're almost there, in addition to previous $3, keep the previous $0 and only print when condition is satisfied.
$ awk '{$5=$3-p3} $5==25{print p0; print} {p0=$0;p3=$3}' file
2 5 50 1 15
2 6 75 1 25
5 8 100 1 15
6 9 125 1 25
this can be further golfed to
$ awk '25==($5=$3-p3){print p0; print} {p0=$0;p3=$3}' file
check the newly computed field $5 whether equal to 25. If so print the previous line and current line. Save the previous line and previous $3 for the computations in the next line.
You are close to the answer, just pipe it another awk and print it
awk '{$5 = $3 - prev3; prev3 = $3; print $0}' oxxo.txt | awk ' { curr=$0; if($5==25) { print prev;print curr } prev=curr } '
with Inputs:
$ cat oxxo.txt
1 1 35 1
2 5 50 1
2 6 75 1
4 7 85 1
5 8 100 1
6 9 125 1
4 1 200 1
$ awk '{$5 = $3 - prev3; prev3 = $3; print $0}' oxxo.txt | awk ' { curr=$0; if($5==25) { print prev;print curr } prev=curr } '
2 5 50 1 15
2 6 75 1 25
5 8 100 1 15
6 9 125 1 25
$
Could you please try following.
awk '$3-prev==25{print line ORS $0,$3} {$(NF+1)=$3-prev;prev=$3;line=$0}' Input_file | column -t
Here's one:
$ awk '{$5=$3-q;t=p;p=$0;q=$3;$0=t ORS $0}$10==25' file
2 5 50 1 15
2 6 75 1 25
5 8 100 1 15
6 9 125 1 25
Explained:
$ awk '{
$5=$3-q # subtract
t=p # previous to temp
p=$0 # store previous for next round
q=$3 # store subtract value for next round
$0=t ORS $0 # prepare record for output
}
$10==25 # output if equals
' file
No checking for duplicates so you might get same record printed twice. Easiest way to fix is to pipe the output to uniq.
I'm looking for a more elegant way to do this (for more than >100 columns):
awk '{a[$1]+=$4}{b[$1]+=$5}{c[$1]+=$6}{d[$1]+=$7}{e[$1]+=$8}{f[$1]+=$9}{g[$1]+=$10}END{for(i in a) print i,a[i],b[i],c[i],d[i],e[i],f[i],g[i]}'
Here is the input:
a1 1 1 2 2
a2 2 5 3 7
a2 2 3 3 8
a3 1 4 6 1
a3 1 7 9 4
a3 1 2 4 2
and output:
a1 1 1 2 2
a2 4 8 6 15
a3 3 13 19 7
Thanks :)
I break the one-liner down into lines, to make it easier to read.
awk '{n[$1];for(i=2;i<=NF;i++)a[$1,i]+=$i}
END{for(x in n){
printf "%s ", x
for(y=2;y<=NF;y++)printf "%s%s", a[x,y],(y==NF?ORS:FS)
}
}' file
this awk command should work with your 100 columns file.
test with your file:
kent$ cat f
a1 1 1 2 2
a2 2 5 3 7
a2 2 3 3 8
a3 1 4 6 1
a3 1 7 9 4
a3 1 2 4 2
kent$ awk '{n[$1];for(i=2;i<=NF;i++)a[$1,i]+=$i}END{for(x in n){printf "%s ", x;for(y=2;y<=NF;y++)printf "%s%s", a[x,y],(y==NF?ORS:OFS)}}' f
a1 1 1 2 2
a2 4 8 6 15
a3 3 13 19 7
Using arrays of arrays in gnu awk version 4
awk '{for (i=2;i<=NF;i++) a[$1][i]+=$i}
END{for (i in a)
{ printf i FS;
for (j in a[i]) printf a[i][j] FS
printf RS}
}' file
a1 1 1 2 2
a2 4 8 6 15
a3 3 13 19 7
If you care about order of output try this
$ cat file
a1 1 1 2 2
a2 2 5 3 7
a2 2 3 3 8
a3 1 4 6 1
a3 1 7 9 4
a3 1 2 4 2
Awk Code :
$ cat tester
awk 'FNR==NR{
U[$1] # Array U with index being field1
for(i=2;i<=NF;i++) # loop through columns thats is column2 to NF
A[$1,i]+=$i # Array A holds sum of columns
next # stop processing the current record and go on to the next record
}
($1 in U){ # Here we read same file once again,if field1 is found in array U, then following statements
for(i=1;i<=NF;i++)
s = s ? s OFS A[$1,i] : A[$1,i] # I am writing sum to variable s since I want to use only one print statement, here you can use printf also
print $1,s # print column1 and variable s
delete U[$1] # We have done, so delete array element
s = "" # reset variable s
}' OFS='\t' file{,} # output field separator is tab you can set comma also
Resulting
$ bash tester
a1 1 1 2 2
a2 4 8 6 15
a3 3 13 19 7
If you want to try this on a Solaris/SunOS system, change awk to /usr/xpg4/bin/awk , /usr/xpg6/bin/awk , or nawk
--edit--
As requested in comment here is one liner, in above post for better reading purpose I had commented and it became several lines.
$ awk 'FNR==NR{U[$1];for(i=2;i<=NF;i++)A[$1,i]+=$i;next}($1 in U){for(i=1;i<=NF;i++)s = s ? s OFS A[$1,i] : A[$1,i];print $1,s;delete U[$1];s = ""}' OFS='\t' file{,}
a1 1 1 2 2
a2 4 8 6 15
a3 3 13 19 7