Currently, I am creating dataSource in spring applicationContext.xml by reading DB credentials from a property file.
<!-- property config -->
<bean class="org.springframework.beans.factory.config.PropertyPlaceholderConfigurer">
<property name="location"><value>/WEBINF/resources/springConfig.properties</value></property>
</bean>
<!-- Database connection Oracle 10g jdbc -->
<bean id="dataSource" class="oracle.jdbc.pool.OracleDataSource" destroy-method="close">
<property name="URL" value="${url}" />
<property name="user" value="${user}" />
<property name="password" value="${password}" />
<property name="connectionCachingEnabled" value="true" />
</bean>
Then i am referencing it using context.getBean
DataSource dataSource = (DataSource)context.getBean("dataSource");
I need to modify my applicationContext to create dataSource by not reading a property file but by using Weblogic JDBC datasource (I am not sure if its jndiTemplate or jdbcTemplate)
Please provide an example and do i need to change the way i do getBean("dataSource") once i use the jndiTemplate?
You want to do a JNDI datasource lookup. Here's an example:
http://middlewaremagic.com/weblogic/?p=5106
Related
Does anyone know how to construct the database connection string with multisubnet failover as true? We are trying to connect to a SQL Server which is on AOAG (Always on availability group).
We are trying to connect via application where we are using org.springframework.jdbc.datasource.DriverManagerDataSource to create a data source bean and then using it in application.
<bean id="dataSource" class="org.springframework.jdbc.datasource.DriverManagerDataSource">
<property name="driverClassName" value="${DRIVER_CLASS}"/>
<property name="url" value="${JDBC_URL}"/>
<property name="username" value="{userName}"/>
<property name="password" value="{******}"/>
</bean>
Are you looking for
MultiSubnetFailover=True
From https://learn.microsoft.com/en-us/sql/database-engine/availability-groups/windows/listeners-client-connectivity-application-failover
I am trying to concatenate the job parameter, #{jobParameters['arg1']} with myfeed.query to dynamically pick the right query from the properties file. But it's not getting resolved.
below is the exception log
Caused by: org.springframework.jdbc.BadSqlGrammarException: Executing query; bad SQL grammar [${myfeed.queryZONE1}]
below is the code snippet in the xml file.
<bean id="itemReader" class="org.springframework.batch.item.database.JdbcCursorItemReader" scope="step">
<property name="dataSource" ref="dataSource" />
<property name="sql">
<value>${myfeed.query#{jobParameters['arg1']}}</value>
</property>
<property name="rowMapper">
<bean class="com.sgcib.loa.matrix.mapper.MyFeedRowMapper" />
</property>
</bean>
To do that, you will need to declare explicit properties for your PropertyPlaceholderConfigurer :
<bean id="propertiesConfigurer" class="org.springframework.beans.factory.config.PropertyPlaceholderConfigurer">
<property name="properties" ref="properties" />
</bean>
<bean id="properties" class="org.springframework.beans.factory.config.PropertiesFactoryBean">
<property name="location">
<value>file:xxxxxxx.properties</value>
</property>
</bean>
Then using Spring Expression Language (spEL), you can get the right property with :
<property name="sql" value="#{properties.getProperty('myfeed.query' + jobParameters['arg1'])}" /></property>
Note that this solution maintains compatibility with ${...} syntax.
The above solution does not work, tested solution is One ItemReader, 2 SQL Query, jdbcTemplate?
http://incomplete-code.blogspot.in/2013/06/dynamically-switch-sql-statements-in.html
Is there an obvious way to use two JPA consumers/producers in the Camel Spring DSL to talk to two different database instances? I tried to configure two EntityManagerFactory instances pointing to two Persistence Units but end up with the following when error :(
Caused by: org.apache.camel.NoSuchBeanException: No bean could be found in the registry for: Found 2 beans of type: interface javax.persistence.EntityManagerFactory. Only one bean expected.
Camel Version: 2.13.2
You might have to make 2 entity manager factories, and have them point at different persistence units.
<bean id="entityManagerFactory"
class="org.springframework.orm.jpa.LocalEntityManagerFactoryBean">
<property name="persistenceUnitName" value="primary" />
</bean>
<bean id="entityManagerFactory2"
class="org.springframework.orm.jpa.LocalEntityManagerFactoryBean">
<property name="persistenceUnitName" value="secondary" />
</bean>
then when you set up the jpa bean, you can specify two different origins
<bean id="jpa" class="org.apache.camel.component.jpa.JpaComponent">
<property name="entityManagerFactory" ref="entityManagerFactory" />
<property name="transactionManager" ref="transactionManager" />
</bean>
<bean id="jpa2" class="org.apache.camel.component.jpa.JpaComponent">
<property name="entityManagerFactory" ref="entityManagerFactory2" />
<property name="transactionManager" ref="transactionManager" />
</bean>
and use:
<from uri="jpa://
or
<from uri="jpa2://
I am using fuse 6.0 and activemq 5.8. Instead of defining activemq poolable connection factory in each bundle, it makes sense to define in a common bundle and expose it as osgi service. I created blue print file in FUSE_HOME/etc and opened an osgi service like this.
<osgix:cm-properties id="prop" persistent-id="xxx.xxx.xxx.properties" />
<bean id="jmsConnectionFactory" class="org.apache.activemq.ActiveMQConnectionFactory">
<property name="brokerURL" value="${xxx.url}" />
<property name="userName" value="${xxx.username}" />
<property name="password" value="${xxx.password}" />
</bean>
<bean id="pooledConnectionFactory" class="org.apache.activemq.pool.PooledConnectionFactory" init-method="start" destroy-method="stop">
<property name="maxConnections" value="${maxconnections}" />
<property name="connectionFactory" ref="jmsConnectionFactory" />
</bean>
<service ref="pooledConnectionFactory" interface="javax.jms.ConnectionFactory">
<service-properties>
<entry key="name" value="localhost"/>
</service-properties>
</service>
and when i try to access this service in both blueprint files and spring text files like this
<reference id="pooledConnectionFactory" interface="javax.jms.ConnectionFactory"/>
bean id="jmsConfig" class="org.apache.camel.component.jms.JmsConfiguration">
<property name="connectionFactory" ref="pooledConnectionFactory"/>
<property name="concurrentConsumers" value="${xxx.concurrentConsumers}"/>
</bean>
<bean id="activemq" class="org.apache.activemq.camel.component.ActiveMQComponent">
<property name="configuration" ref="jmsConfig"/>
</bean>
but I am getting following expection during bundles startup.
Failed to add Connection ID:PLNL6237-55293-1401929434025-11:1201, reason: java.lang.SecurityException: User name [null] or password is invalid.
I even defined compendium definition in my bundles.
How can i solve this problem? any help is appreciated.
I found this online https://issues.apache.org/jira/i#browse/SM-2183
Do i need to upgrade?
It looks to me like you're using the property placeholders incorrectly. First of all, you should know what osgix:cm-properties only exposes the properties at the persistent id that you specify. You can treat it like a java.util.Properties object, and even inject it into a bean as one. This does however mean that it makes no attempt to resolve the properties.
To resolve properties, use spring's property placeholder configurer.
<bean class="org.springframework.beans.factory.config.PropertyPlaceholderConfigurer">
<property name="properties" ref="prop"/>
</bean>
P.S. The persistent id of cm-properties is the name of the file, not including the file type. You don't need the .properties at the end.
I use BoneCP in my Spring-based application.
<bean id="dataSource" class="com.jolbox.bonecp.BoneCPDataSource" destroy-method="close">
<property name="driverClass" value="com.mysql.jdbc.Driver" />
<property name="jdbcUrl" value="jdbc:mysql://ec2-23-21-211-???.compute-1.amazonaws.com:3306/?????" />
<property name="username" value="*****"/>
<property name="password" value="********"/>
<property name="idleConnectionTestPeriod" value="60"/>
<property name="idleMaxAge" value="240"/>
<property name="maxConnectionsPerPartition" value="3"/>
<property name="minConnectionsPerPartition" value="1"/>
<property name="partitionCount" value="1"/>
<property name="acquireIncrement" value="5"/>
<property name="statementsCacheSize" value="100"/>
<property name="releaseHelperThreads" value="3"/>
</bean>
Is there any short value for jdbcURL?
You can inject it via environmental variable through the CloudBees SDK.
1.Inject the datasource and the following environmental variables via bees app:bind
With the CloudBees SDK:
bees app:bind -a appName -db dbName -as mydb
It will automatically inject a datasource and will create these three environmental variables:
${DATABASE_URL_DB}
${DATABASE_USERNAME_DB}
${DATABASE_PASSWORD_DB}
Please, be aware that you will use on this way one active connection for the maxActive: '20' by default on the Tomcat JDBC Connection Pool.
2.Enable PlaceHolder on Spring framework and mark system-properties-mode as "OVERRIDE".
<context:property-placeholder location="classpath:spring/data-access.properties" system-properties-mode="OVERRIDE"/>
Example here.
3.On your datasource.xml configuration file, then you could use something like this:
value= "jdbc:"+ ${DATABASE_URL_DB}
Be aware that the recommended way to get the datasource on CloudBees is always using JNDI.
In this way, you will use our own implementation of the datasource, so you don't have to write the username, the password or the URL of the database. Instead of all these lines, you can just replace all of them for this one:
<jee:jndi-lookup id="dataSource" jndi-name="jdbc/mydb" resource-ref="true"/>