ipython works wrongs wrong with awk? - awk

Question

Dear all！ I find a question with ipython.
When I input
!ls -l | awk '{print $$1}'
It gives me:
drwxr-xr-x 2 ckivip ckivip 4096 Oct 11 20:38 Desktop
drwxr-xr-x 6 ckivip ckivip 4096 Oct 11 22:57 Documents
drwxrwxr-x 3 ckivip ckivip 4096 Oct 11 12:53 Downloads
drwxr-xr-x 6 ckivip ckivip 4096 Sep 29 18:22 Epigenetics
drwxr-xr-x 2 ckivip ckivip 4096 Sep 20 14:59 Music
drwxr-xr-x 23 ckivip ckivip 4096 Oct 10 11:02 Pictures
drwxr-xr-x 8 ckivip ckivip 4096 Sep 20 15:21 Project
drwx------ 5 ckivip ckivip 4096 Sep 25 21:31 R
drwxr-xr-x 5 ckivip ckivip 4096 Oct 9 19:23 Share
However, when I input
!ls -l | awk '{print $1}'
It gives me:
drwxr-xr-x
drwxr-xr-x
drwxrwxr-x
drwxr-xr-x
drwxr-xr-x
drwxr-xr-x
drwxr-xr-x
drwx------
It's so annoying about the "$" symbol. And the most ugly thing is that I also can't transport the variables in python to shell using '$' when I use 'awk' function. How can I deal with it?

Answer 1

I'm not familiar with ipython but to address the part about passing the values of shell variables to awk: you do that with 'awk -v variable=value', so if you have a shell variable "$1" that contains the value "3" and you want awk to print the 3rd field of your input based on that, then the syntax is:
awk -v f="$1" '{ print $f }'
so in the above you could try:
!ls -l | awk -v f="$1" '{print $f}'
or if doubling the shell "$"s is required:
!ls -l | awk -v f="$$1" '{print $f}'
Hope that helps.