Lets say my string value is as follows
12345.12
after converting it to NSNumber its coming as 12345.1223122
But I want the accurate number from string
Is there a way to achieve it.
Code that I'm using right now
NSNumberFormatter * f = [[NSNumberFormatter alloc] init];
[f setNumberStyle:NSNumberFormatterCurrencyStyle];
NSNumber * myNumber = [f numberFromString:aString];
[f release];
If you're dealing with currency-type numbers (just a guess from your use of the currency style formatter) you probably want to use NSDecimalNumber. Unlike standard floating point types, decimal numbers use a base-10 exponent so that you always get exactly the expected accuracy when dealing with money problems — i.e. they're the same as using integers and then moving the decimal point around in the base-10 representation.
Try Like this...
NSNumberFormatter * f = [[NSNumberFormatter alloc] init];
[f setNumberStyle:NSNumberFormatterCurrencyStyle];
NSNumber * myNumber=[NSNumber numberWithFloat:[[f numberFromString:aString] floatValue]];
I think it will be helpful to you.
Do this:
NSNumberFormatter * f = [[NSNumberFormatter alloc] init];
[f setNumberStyle:NSNumberFormatterDecimalStyle];
[f setMaximumFractionDigits:2];
NSNumber * myNumber = [f numberFromString:aString];
[f release];
NSLog(#"%#",myNumber);
It's a few years, but this works:
double d = [#"123.45" doubleValue];
NSNumber* n = [NSNumber numberWithDouble:d];
Related
I'm currently using the following methodology to turn a NSString number (like #"123.456") into a NSDecimalNumber after rounding (like 123.46), but it feels hacky. Is there a more intended solution?
+ (NSDecimalNumber*)decimalNumberForString:(NSString*)str accuracy:(NSUInteger)accuracy
{
NSNumberFormatter *formatter = [[NSNumberFormatter alloc] init];
formatter.numberStyle = NSNumberFormatterNoStyle;
formatter.maximumFractionDigits = accuracy;
formatter.roundingMode = NSNumberFormatterRoundHalfUp;
NSNumber *numberVersion = [formatter numberFromString:str];
return [[NSDecimalNumber alloc] initWithDecimal:numberVersion.decimalValue];
}
Take a look at NSDecimalNumberHandler and NSDecimalNumber's
-decimalNumberByRoundingAccordingToBehavior:
method.
You can create a NSDecimalNumber with your unedited string, then create a new NSDecimal number that's rounded according to the rules you set on NSDecimalNumberHandler.
There's no need to edit your input string.
Use [NSDecimalNumber decimalNumberWithString:], like this:
NSDecimalNumber *number = [NSDecimalNumber decimalNumberWithString:#"123.456"];
The number of decimal places only affects the string representation of the number; once the number is stored in an NSDecimalNumber object it can be formatted back to a string in any way you desire.
Ok, so I am writing a calculator app now. So far, I'm not having much luck in regard to decimals (my most recent approach hasn't worked well).
-(void) DecimalAdded
{
NSNumberFormatter *formatter = [[NSNumberFormatter alloc] init];
[formatter setNumberStyle:NSNumberFormatterDecimalStyle];
[formatter setAlwaysShowsDecimalSeparator:YES];
[formatter setGeneratesDecimalNumbers:YES];
[formatter setDecimalSeparator:#"."];
//first convert the float value of CN into NSnumber
NSNumber *nextstepNumFromCNF= [NSNumber numberWithFloat:currentNumber];
//now we have to convert that number into a string
NSString *CNconverted = [formatter stringFromNumber:nextstepNumFromCNF];
NSNumber *CNdecmAddedAndReadyForPars = [formatter numberFromString:CNconverted];
currentNumber = currentNumber*10 + [CNdecmAddedAndReadyForPars floatValue];
CalculatorScreen = [NSMutableString stringWithFormat: #"%#", CNconverted];
I can append the string to the Calculator screen I can say the number is 1, I see "1." as I'm typing. However this is usually converted to 1 during th float conversion (which is correct).
What is this best way to accomplish this?
Is there any way to format an NSNumber with leading 0's and decimals? For example, I need to have the ability to write 4.5 as well as 000. Currently I have it where it will allow decimals, but not leading 0's.
NSNumberFormatter *f = [[NSNumberFormatter alloc] init];
f.numberStyle = NSNumberFormatterNoStyle;
NSString *myString = [f numberFromString:#"4.5"];
NSLog(#"myString: %#",myString);
NSString *myOtherString = [f numberFromString:#"000"];
NSLog(#"myOtherString:%#",myOtherString);
The output from above would be: 'myString:4.5' and 'myOtherString:0'. I need to be able to do both '4.5' and '000' as output.
I have looked at Apple's "Data Formatting Guide" without much success.
Note that [f numberFromString:#"4.5"] returns an NSNumber* not a NSString*
You want something like this:
NSNumberFormatter *f = [[NSNumberFormatter alloc] init];
f.numberStyle = NSNumberFormatterNoStyle;
NSNumber *myNumber;
NSString *myString;
myNumber = [f numberFromString:#"4.5"];
[f setNumberStyle:kCFNumberFormatterDecimalStyle];
myString = [f stringFromNumber:myNumber];
NSLog(#"myString: %#",myString);
myNumber = [f numberFromString:#"000"]; // Note that the extra zeros are useless
[f setFormatWidth:3];
[f setPaddingCharacter:#"0"];
myString = [f stringFromNumber:myNumber];
NSLog(#"myString: %#",myString);
NSLog output:
myString: 4.5
myString: 000
If you don't have strings to start with just create number like:
myNumber = [NSNumber numberWithFloat:4.5];
myNumber = [NSNumber numberWithInt:0];
Or just use standard formatting:
myString = [NSString stringWithFormat:#"%.1f", [myNumber floatValue]];
myString = [NSString stringWithFormat:#"%03d", [myNumber intValue]];
Or if you don't need an NSNumber representation just use standard formatting :
myString = [NSString stringWithFormat:#"%.1f", 4.5];
myString = [NSString stringWithFormat:#"%03d", 0];
You could try something like:
NSString *myString = [NSString stringWithFormat:#"%03f", [myNSNumber floatValue]];
This, following the printf format, will print your number forcing at least 3 digits to be printed and padding with '0's any empty space.
How about this as a variation on theme for the 000's
NSNumber *myNumber;
NSString *myString =#"000" ;
NSString * myStringResult;
NSNumberFormatter *f = [[NSNumberFormatter alloc] init];
f.numberStyle = NSNumberFormatterNoStyle;
[f setHasThousandSeparators:FALSE]; //-- remove seperator
[f setMinimumIntegerDigits:[myString length ]]; //-- set minimum number of digits to display using the string length.
myNumber = [f numberFromString:myString];
myStringResult = [f stringFromNumber:myNumber];
NSLog(#"myStringResult: %#",myStringResult);
Since this is asked often and Apple's docs suck, this is the answer that people will be looking for. The link below has two solutions. One using NSString stringWithFormat: and the other using NSNumberFormatter.
https://stackoverflow.com/a/11131497/1058199
In the following code, I want the the number that satisfies if (isKgs) to be rounded to one decimal point.
For example right now it is giving me 2.2643534543 but I just want 2.3.
Any ideas?
NSNumber *weightInPounds = [self.pickerArray objectAtIndex:row];
NSNumber *weightInKilos = [[DDUnitConverter massUnitConverter] convertNumber: weightInPounds fromUnit: DDMassUnitUSPounds toUnit: DDMassUnitKilograms];
NSString *temp = [NSString stringWithFormat:#"%# kgs", [weightInKilos stringValue]];
[self.firstComponentText setString:temp];
The the type of number from the picker is float, I believe.
You can format the NSNumber object using an NSNumberFormatter object. An example,
NSNumber * decimal = [NSNumber numberWithFloat:2.2643534543];
NSNumberFormatter * formatter = [[NSNumberFormatter alloc] init];
[formatter setNumberStyle:NSNumberFormatterDecimalStyle];
[formatter setRoundingMode:NSNumberFormatterRoundHalfUp];
[formatter setMaximumFractionDigits:1];
NSLog(#"%#", [formatter stringFromNumber:decimal]);
If I have a number int aNum = 2000000 how do I format this so that I can display it as the NSString 2,000,000?
Use NSNumberFormatter.
Specifically:
NSNumberFormatter *formatter = [NSNumberFormatter new];
[formatter setNumberStyle:NSNumberFormatterDecimalStyle]; // this line is important!
NSString *formatted = [formatter stringFromNumber:[NSNumber numberWithInteger:2000000]];
[formatter release];
By default NSNumberFormatter uses the current locale so the grouping separators are set to their correct values by default. The key thing is to remember to set a number style.
Don't do your own number formatting. You will almost certainly not get all the edge cases right or correctly handle all possible locales. Use the NSNumberFormatter for formatting numeric data to a localized string representation.
You would use the NSNumberFormatter instance method -setGroupingSeparator: to set the grouping separator to #"," (or better yet [[NSLocale currentLocale] objectForKey:NSLocaleGroupingSeparator]; thanks #ntesler) and -setGroupingSize: to put a grouping separator every 3 digits.
There's a static method on NSNumberFormatter that does just what you need:
int aNum = 2000000;
NSString *display = [NSNumberFormatter localizedStringFromNumber:#(aNum)
numberStyle:NSNumberFormatterDecimalStyle];
This way is a little more succinct than creating a new NSNumberFormatter if you don't need to do any additional configuration of the formatter.
Even easier:
NSNumber *someNumber = #(1234567890);
NSString *modelNumberString = [NSString localizedStringWithFormat:#"%#", someNumber];
NSLog(#"Number with commas: %#", modelNumberString);
coworker just taught me this today. #amazing
Think some as i will get this post looking for sample.
So if you are working with number make attention on next params:
setNumberStyle:NSNumberFormatterCurrencyStyle // if you are working with currency
It could be also
setNumberStyle:NSNumberFormatterDecimalStyle
All code is For ARC.
If you are working with Integer and need to get result such as 200,000
int value = 200000;
NSNumberFormatter * formatter = [NSNumberFormatter new];
[formatter setNumberStyle:NSNumberFormatterDecimalStyle];
NSString * newString = [formatter stringFromNumber:[NSNumber numberWithInteger:value]];
If you are working with Float and need to get result such as 200,000.00
float value = 200000;
NSNumberFormatter * formatter = [NSNumberFormatter new];
[formatter setNumberStyle:NSNumberFormatterDecimalStyle];
[formatter setMaximumFractionDigits:2]; // Set this if you need 2 digits
NSString * newString = [formatter stringFromNumber:[NSNumber numberWithFloat:value]];
EDIT
To have ability to use different digital separators use NSLocale.
Add to code where NSLocale is specified on Locale Identifier:
[formatter setLocale:[[NSLocale alloc] initWithLocaleIdentifier:#"de_DE"]];
or use current local:
[formatter setLocale:[NSLocale currentLocale]];
Swift version
let formatter = NSNumberFormatter()
formatter.numberStyle = .DecimalStyle
formatter.maximumFractionDigits = decimalPlaces
let result = formatter.stringFromNumber(NSNumber(double: 8.0))
By http://ios.eezytutorials.com
An easy solution could be this. My answer is almost same like #Nazir's answer but with a small trick.
double current_balance = 2000000.00;
NSNumberFormatter * formatter = [NSNumberFormatter new];
[formatter setNumberStyle:NSNumberFormatterDecimalStyle];
//[formatter setNumberStyle:NSNumberFormatterCurrencyStyle]; //if you want for currency with $ sign
[formatter setMinimumFractionDigits:2]; // Set this if you need 2 digits
[formatter setMaximumFractionDigits:2]; // Set this if you need 2 digits
NSString * currency_format = [NSString stringWithFormat:#"%#", [formatter stringFromNumber:[NSNumber numberWithDouble:current_balance]]];
For Swift 4.0
let formatter = NumberFormatter()
formatter.numberStyle = .decimal
formatter.minimumFractionDigits = 2
formatter.maximumFractionDigits = 2
let result = formatter.string(from: NSNumber(value: 123456))
For those who need to do it with strings of numbers and not just integers (I.e. Big Numbers) I made the following macro:
#define addCommas(__string) (\
(^NSString *(void){\
NSString *__numberString = __string;\
NSString *__integerPortion = __numberString;\
NSString *__decimalPortion = #"";\
if ([__string containsString:#"."]) {\
__integerPortion = [__numberString componentsSeparatedByString:#"."][0];\
__decimalPortion = st(#".%#", [__numberString componentsSeparatedByString:#"."][1]);\
}\
int __i = (int)__integerPortion.length-3;\
while (__i > 0) {\
__integerPortion = st(#"%#,%#", substringInRange(__integerPortion, 0, __i), substringInRange(__integerPortion, __i, (int)__integerPortion.length));\
__i -= 3;\
}\
__numberString = st(#"%#%#", __integerPortion, __decimalPortion);\
return __numberString;\
})()\
)