Date Error Invalid Number - sql

I would like to add 10 minutes to sysdate,
select to_char(SYSDATE,'dd-Mon-yyyy hh:mi:ss') + 10/1440 from dual
when I tried the above I got the error
ORA-01722: invalid number


The error appears because you add 10/1440 to char not to date.
Try this:
select SYSDATE + 10/1440 from dual;
or
select to_char(SYSDATE+ 10/1440,'dd-Mon-yyyy hh:mi:ss') from dual;
or
select to_char( sysdate + interval '10' minute,'dd-Mon-yyyy hh:mi:ss')
from dual;
Here you can find more information.
Here you can find similar problem on SO, there are more solutions.


You don't need to "to_char" the date first.
Either
select SYSDATE + 10/1440 from dual;
or
select to_char(SYSDATE + 10/1440,'dd-Mon-yyyy hh:mi:ss') from dual;
depending on whether you just want a date or a string representation of the date formatted in a certain way.

Related

display name of day in oracle

i want to display in output as : today is wednesday
my code:
select to_char(sysdate,'today is' 'day' ) from dual ;
it is not working.

You need to include the raw text you want in the output in double quotes in the format specification:
select to_char(sysdate, '"today is" day') from dual ;
Output (as of 2020-03-04)
today is wednesday
Demo on dbfiddle

Use concat() or the concatenation operator || to prepend the 'today is ' string.
SELECT concat('today is ', to_char(sysdate, 'day'))
FROM dual;
or
SELECT 'today is ' || to_char(sysdate, 'day')
FROM dual;

SQL check day of week

How to check if it's a weekend in SQL?
I know I can convert sysdate to a number using this
SQL> select to_char(sysdate, 'd') from dual;
TO_CHAR(SYSDATE,'D')
But I'm not really sure how to check if today is a 6 or 7.

Do not use TO_CHAR with the D format model for this as it is dependant on the NLS_TERRITORY session parameter.
For example, when SYSDATE = 2018-09-10 (a Monday):
ALTER SESSION SET NLS_TERRITORY = 'France';
SELECT TO_CHAR( SYSDATE, 'D' ) FROM DUAL;
Outputs 1 but the same query in a different territory:
ALTER SESSION SET NLS_TERRITORY = 'America';
SELECT TO_CHAR( SYSDATE, 'D' ) FROM DUAL;
Outputs 2.
Instead, you can use TRUNC and the IW format model:
SELECT TRUNC( SYSDATE ) - TRUNC( SYSDATE, 'IW' ) FROM DUAL
Outputs 0 for Monday (and 1 for Tuesday ... 6 for Sunday) and is independent of the NLS_TERRITORY setting.
So you could filter this to give weekends as:
SELECT *
FROM DUAL
WHERE TRUNC( SYSDATE ) - TRUNC( SYSDATE, 'IW' ) IN ( 5, 6 )
or
SELECT *
FROM DUAL
WHERE SYSDATE - TRUNC( SYSDATE, 'IW' ) >= 5
If you want the days 1-indexed for consistency with your expected output from TO_CHAR (rather then 0-indexed) then just add 1 to the value.

sysdate is a pseudo column. You don't need to query it, you can evaluate it directly:
IF TO_CHAR(SYSDATE, 'D') IN ('6', '7') THEN
-- Do something
END IF;

I would avoid the ambiguous 'D' format as this varies between territories (the week starts after the weekend where I live), and use
if to_char(sysdate,'fmDY','nls_date_language=English') like 'S%'
then
Regarding the 'D' format, unfortunately to_char doesn't let you specify nls_territory inline, so without an explicit alter session command, it will rely on the session settings at runtime. I've seen production bugs due to this, where the same code worked in London but failed in New York.

And here's the logic in a reusable function, but flipped to ask "Is it a weekday?" (not a weekend). You could add a parameter for the start day of the weekdays (2 is the default in Oracle; Sunday is day #1).
CREATE OR REPLACE FUNCTION is_weekday (date_in IN DATE)
RETURN BOOLEAN
IS
BEGIN
RETURN TO_CHAR (date_in, 'D') BETWEEN 2 AND 6;
END;
/
DECLARE
l_date DATE := DATE '2018-09-10';
BEGIN
DBMS_OUTPUT.put_line ('If your weekend is Saturday and Sunday....');
FOR indx IN 1 .. 7
LOOP
DBMS_OUTPUT.put_line (
TO_CHAR (l_date, 'FMDay, Month DD YYYY')
|| ' is '
|| CASE WHEN NOT is_weekday (l_date) THEN 'not ' END
|| 'a weekday');
l_date := l_date + 1;
END LOOP;
END;
/
Try it in LiveSQL:
https://livesql.oracle.com/apex/livesql/file/content_G8NQSY6NP48NPJX96RLQ51SUE.html

Inject character to date column

I have a date column.
select RETAIL_ACQUISITION_DTTM from XXXXX.TABLE_2348
13/07/2018
I want to select the value as such it returns as below,
2018-07-13T00:00:00
so it has to display the date as YYYY-MM-DD with T and then HH24:MI:SS

You need to convert your string (why is it stored as a string?) to a date using a format model that matches the actual string value:
to_date(RETAIL_ACQUISITION_DTTM, 'DD/MM/YYYY')
Having that format model wrong is why you get the 0013 year in your result.
Then you can convert that date back to a string with to_char(), and you can embed the fixed T as a character literal with double quotes, using a format model like 'YYYY-MM-DD"T"HH24:MI:SS':
with TABLE_2348 (RETAIL_ACQUISITION_DTTM) as (
select '13/07/2018' from dual
)
select to_char(to_date(RETAIL_ACQUISITION_DTTM, 'DD/MM/YYYY'),
'YYYY-MM-DD"T"HH24:MI:SS') as RETAIL_ACQUISITION_DTTM
from XXXXX.TABLE_2348;
RETAIL_ACQUISITION_
-------------------
2018-07-13T00:00:00
You could also just ignore that it is a date and use string manipulation:
with TABLE_2348 (RETAIL_ACQUISITION_DTTM) as (
select '13/07/2018' from dual
)
select substr(RETAIL_ACQUISITION_DTTM, 7, 4)
|| '-' || substr(RETAIL_ACQUISITION_DTTM, 4, 2)
|| '-' ||substr(RETAIL_ACQUISITION_DTTM, 1, 2)
|| 'T00:00:00' as RETAIL_ACQUISITION_DTTM
from XXXXX.TABLE_2348;
RETAIL_ACQUISITION_
-------------------
2018-07-13T00:00:00
If the column is actually a date rather than a string then you are doing unnecessary conversions, including implicit ones which rely on your NLS settings, and you are losing the original time from the value if it was not midnight anyway:
alter session set nls_date_format = 'DD-MON-RR';
with TABLE_2348 (RETAIL_ACQUISITION_DTTM) as (
select to_date('2018-07-13 12:34:56', 'YYYY-MM-DD HH24:MI:SS') from dual
)
select to_char(to_date(RETAIL_ACQUISITION_DTTM, 'YYYY-MM-DD-HH24:MI:SS'),
'YYYY-MM-DD HH24:MI:SS') as RETAIL_ACQUISITION_DTTM from XXXXX.TABLE_2348;
RETAIL_ACQUISITION_
-------------------
0013-07-20 18:00:00
That is really doing:
to_char(
to_date(
to_char(
RETAIL_ACQUISITION_DTTM,
'DD-MON-RR'), ---- from your session NLS_DATE_FORMAT setting
'YYYY-MM-DD-HH24:MI:SS'),
'YYYY-MM-DD HH24:MI:SS')
If you skip to extra steps you can just format the date directly:
with TABLE_2348 (RETAIL_ACQUISITION_DTTM) as (
select to_date('2018-07-13 12:34:56', 'YYYY-MM-DD HH24:MI:SS') from dual
)
select to_char(RETAIL_ACQUISITION_DTTM,
'YYYY-MM-DD"T"HH24:MI:SS') as RETAIL_ACQUISITION_DTTM
from XXXXX.TABLE_2348;
RETAIL_ACQUISITION_
-------------------
2018-07-13T12:34:56
which also doesn't rely on your NLS settings, so won't break in interesting ways if it's run in another session with different settings.

replace sysdate with your column name if its date type.
Using Single to_char:
select to_char(sysdate,'--YYYY-MM-DD"T"hh24:mi:ss') from dual;
Using two to_char and concatenation for simplification.
select to_char(sysdate,'--'||'YYYY-MM-DD')||'T'||to_char(sysdate,'hh24:mi:ss') from dual; -- 13/07/2018
select '--'||to_char(sysdate,'YYYY-MM-DD')||'T'||to_char(sysdate,'hh24:mi:ss') from dual; -- 13/07/2018

SQL filter query output based on difference of two timestamp field [duplicate]

I have a table as follows:
Filename - varchar
Creation Date - Date format dd/mm/yyyy hh24:mi:ss
Oldest cdr date - Date format dd/mm/yyyy hh24:mi:ss
How can I calcuate the difference in hours minutes and seconds (and possibly days) between the two dates in Oracle SQL?
Thanks

You can substract dates in Oracle. This will give you the difference in days. Multiply by 24 to get hours, and so on.
SQL> select oldest - creation from my_table;
If your date is stored as character data, you have to convert it to a date type first.
SQL> select 24 * (to_date('2009-07-07 22:00', 'YYYY-MM-DD hh24:mi')
- to_date('2009-07-07 19:30', 'YYYY-MM-DD hh24:mi')) diff_hours
from dual;
DIFF_HOURS
----------
2.5
Note:
This answer applies to dates represented by the Oracle data type DATE.
Oracle also has a data type TIMESTAMP, which can also represent a date (with time). If you subtract TIMESTAMP values, you get an INTERVAL; to extract numeric values, use the EXTRACT function.

To get result in seconds:
select (END_DT - START_DT)*60*60*24 from MY_TABLE;
Check [https://community.oracle.com/thread/2145099?tstart=0][1]

select
extract( day from diff ) Days,
extract( hour from diff ) Hours,
extract( minute from diff ) Minutes
from (
select (CAST(creationdate as timestamp) - CAST(oldcreationdate as timestamp)) diff
from [TableName]
);
This will give you three columns as Days, Hours and Minutes.

declare
strTime1 varchar2(50) := '02/08/2013 01:09:42 PM';
strTime2 varchar2(50) := '02/08/2013 11:09:00 PM';
v_date1 date := to_date(strTime1,'DD/MM/YYYY HH:MI:SS PM');
v_date2 date := to_date(strTime2,'DD/MM/YYYY HH:MI:SS PM');
difrence_In_Hours number;
difrence_In_minutes number;
difrence_In_seconds number;
begin
difrence_In_Hours := (v_date2 - v_date1) * 24;
difrence_In_minutes := difrence_In_Hours * 60;
difrence_In_seconds := difrence_In_minutes * 60;
dbms_output.put_line(strTime1);
dbms_output.put_line(strTime2);
dbms_output.put_line('*******');
dbms_output.put_line('difrence_In_Hours : ' || difrence_In_Hours);
dbms_output.put_line('difrence_In_minutes: ' || difrence_In_minutes);
dbms_output.put_line('difrence_In_seconds: ' || difrence_In_seconds);
end ;
Hope this helps.

You may also try this:
select to_char(to_date('1970-01-01 00:00:00', 'yyyy-mm-dd hh24:mi:ss')+(end_date - start_date),'hh24:mi:ss')
as run_time from some_table;
It displays time in more human readable form, like: 00:01:34.
If you need also days you may simply add DD to last formatting string.

Calculate age from HIREDATE to system date of your computer
SELECT HIREDATE||' '||SYSDATE||' ' ||
TRUNC(MONTHS_BETWEEN(SYSDATE,HIREDATE)/12) ||' YEARS '||
TRUNC((MONTHS_BETWEEN(SYSDATE,HIREDATE))-(TRUNC(MONTHS_BETWEEN(SYSDATE,HIREDATE)/12)*12))||
'MONTHS' AS "AGE " FROM EMP;

You could use to_timestamp function to convert the dates to timestamps and perform a substract operation.
Something like:
SELECT
TO_TIMESTAMP ('13.10.1990 00:00:00','DD.MM.YYYY HH24:MI:SS') -
TO_TIMESTAMP ('01.01.1990:00:10:00','DD.MM.YYYY:HH24:MI:SS')
FROM DUAL

In oracle 11g
SELECT end_date - start_date AS day_diff FROM tablexxx
suppose the starT_date end_date is define in the tablexxx

select days||' '|| time from (
SELECT to_number( to_char(to_date('1','J') +
(CLOSED_DATE - CREATED_DATE), 'J') - 1) days,
to_char(to_date('00:00:00','HH24:MI:SS') +
(CLOSED_DATE - CREATED_DATE), 'HH24:MI:SS') time
FROM request where REQUEST_ID=158761088 );

If you want something that looks a bit simpler, try this for finding events in a table which occurred in the past 1 minute:
With this entry you can fiddle with the decimal values till you get the minute value that you want. The value .0007 happens to be 1 minute as far as the sysdate significant digits are concerned. You can use multiples of that to get any other value that you want:
select (sysdate - (sysdate - .0007)) * 1440 from dual;
Result is 1 (minute)
Then it is a simple matter to check for
select * from my_table where (sysdate - transdate) < .00071;

If you select two dates from 'your_table' and want too see the result as a single column output (eg. 'days - hh:mm:ss') you could use something like this.
First you could calculate the interval between these two dates and after that export all the data you need from that interval:
select extract (day from numtodsinterval (second_date
- add_months (created_date,
floor (months_between (second_date,created_date))),
'day'))
|| ' days - '
|| extract (hour from numtodsinterval (second_date
- add_months (created_date,
floor (months_between (second_date,created_date))),
'day'))
|| ':'
|| extract (minute from numtodsinterval (second_date
- add_months (created_date,
floor (months_between (second_date, created_date))),
'day'))
|| ':'
|| extract (second from numtodsinterval (second_date
- add_months (created_date,
floor (months_between (second_date, created_date))),
'day'))
from your_table
And that should give you result like this:
0 days - 1:14:55

select (floor(((DATE2-DATE1)*24*60*60)/3600)|| ' : ' ||floor((((DATE2-DATE1)*24*60*60) -floor(((DATE2-DATE1)*24*60*60)/3600)*3600)/60)|| ' ' ) as time_difference from TABLE1

(TO_DATE(:P_comapre_date_1, 'dd-mm-yyyy hh24:mi') - TO_DATE(:P_comapre_date_2, 'dd-mm-yyyy hh24:mi'))*60*60*24 sum_seconds,
(TO_DATE(:P_comapre_date_1, 'dd-mm-yyyy hh24:mi') - TO_DATE(:P_comapre_date_2, 'dd-mm-yyyy hh24:mi'))*60*24 sum_minutes,
(TO_DATE(:P_comapre_date_1, 'dd-mm-yyyy hh24:mi') - TO_DATE(:P_comapre_date_2, 'dd-mm-yyyy hh24:mi'))*24 sum_hours,
(TO_DATE(:P_comapre_date_1, 'dd-mm-yyyy hh24:mi') - TO_DATE(:P_comapre_date_2, 'dd-mm-yyyy hh24:mi')) sum_days

select to_char(actual_start_date,'DD-MON-YYYY hh24:mi:ss') start_time,
to_char(actual_completion_date,'DD-MON-YYYY hh24:mi:ss') end_time,
floor((actual_completion_date-actual_start_date)*24*60)||'.'||round(mod((actual_completion_date-actual_start_date)*24*60*60,60)) diff_time
from fnd_concurrent_requests
order by request_id desc;

If You want get date defer from using table and column.
SELECT TO_DATE( TO_CHAR(COLUMN_NAME_1, 'YYYY-MM-DD'), 'YYYY-MM-DD') -
TO_DATE(TO_CHAR(COLUMN_NAME_2, 'YYYY-MM-DD') , 'YYYY-MM-DD') AS DATEDIFF
FROM TABLE_NAME;

This will count time between to dates:
SELECT
(TO_CHAR( TRUNC (ROUND(((sysdate+1) - sysdate)*24,2))*60,'999999')
+
TO_CHAR(((((sysdate+1)-sysdate)*24)- TRUNC(ROUND(((sysdate+1) - sysdate)*24,2)))/100*60 *100, '09'))/60
FROM dual

Here's another option:
with tbl_demo AS
(SELECT TO_DATE('11/26/2013 13:18:50', 'MM/DD/YYYY HH24:MI:SS') dt1
, TO_DATE('11/28/2013 21:59:12', 'MM/DD/YYYY HH24:MI:SS') dt2
FROM dual)
SELECT dt1
, dt2
, round(dt2 - dt1,2) diff_days
, round(dt2 - dt1,2)*24 diff_hrs
, numtodsinterval((dt2 - dt1),'day') diff_dd_hh_mm_ss
from tbl_demo;

Single query that will return time difference of two timestamp columns:
select INS_TS, MAIL_SENT_TS, extract( hour from (INS_TS - MAIL_SENT_TS) ) timeDiff
from MAIL_NOTIFICATIONS;

select round( (tbl.Todate - tbl.fromDate) * 24 * 60 * 60 )
from table tbl

for oracle sql I justbn did this and works perfect :
SELECT trunc(date_col_1) - trunc(date_col_2)
FROM TABLE;

$sql="select bsp_bp,user_name,status,
to_char(ins_date,'dd/mm/yyyy hh12:mi:ss AM'),
to_char(pickup_date,'dd/mm/yyyy hh12:mi:ss AM'),
trunc((pickup_date-ins_date)*24*60*60,2),message,status_message
from valid_bsp_req where id >= '$id'";

Subtracting the difference between two time intervals in oracle sql [duplicate]

I have a table as follows:
Filename - varchar
Creation Date - Date format dd/mm/yyyy hh24:mi:ss
Oldest cdr date - Date format dd/mm/yyyy hh24:mi:ss
How can I calcuate the difference in hours minutes and seconds (and possibly days) between the two dates in Oracle SQL?
Thanks

You can substract dates in Oracle. This will give you the difference in days. Multiply by 24 to get hours, and so on.
SQL> select oldest - creation from my_table;
If your date is stored as character data, you have to convert it to a date type first.
SQL> select 24 * (to_date('2009-07-07 22:00', 'YYYY-MM-DD hh24:mi')
- to_date('2009-07-07 19:30', 'YYYY-MM-DD hh24:mi')) diff_hours
from dual;
DIFF_HOURS
----------
2.5
Note:
This answer applies to dates represented by the Oracle data type DATE.
Oracle also has a data type TIMESTAMP, which can also represent a date (with time). If you subtract TIMESTAMP values, you get an INTERVAL; to extract numeric values, use the EXTRACT function.

To get result in seconds:
select (END_DT - START_DT)*60*60*24 from MY_TABLE;
Check [https://community.oracle.com/thread/2145099?tstart=0][1]

select
extract( day from diff ) Days,
extract( hour from diff ) Hours,
extract( minute from diff ) Minutes
from (
select (CAST(creationdate as timestamp) - CAST(oldcreationdate as timestamp)) diff
from [TableName]
);
This will give you three columns as Days, Hours and Minutes.

declare
strTime1 varchar2(50) := '02/08/2013 01:09:42 PM';
strTime2 varchar2(50) := '02/08/2013 11:09:00 PM';
v_date1 date := to_date(strTime1,'DD/MM/YYYY HH:MI:SS PM');
v_date2 date := to_date(strTime2,'DD/MM/YYYY HH:MI:SS PM');
difrence_In_Hours number;
difrence_In_minutes number;
difrence_In_seconds number;
begin
difrence_In_Hours := (v_date2 - v_date1) * 24;
difrence_In_minutes := difrence_In_Hours * 60;
difrence_In_seconds := difrence_In_minutes * 60;
dbms_output.put_line(strTime1);
dbms_output.put_line(strTime2);
dbms_output.put_line('*******');
dbms_output.put_line('difrence_In_Hours : ' || difrence_In_Hours);
dbms_output.put_line('difrence_In_minutes: ' || difrence_In_minutes);
dbms_output.put_line('difrence_In_seconds: ' || difrence_In_seconds);
end ;
Hope this helps.

You may also try this:
select to_char(to_date('1970-01-01 00:00:00', 'yyyy-mm-dd hh24:mi:ss')+(end_date - start_date),'hh24:mi:ss')
as run_time from some_table;
It displays time in more human readable form, like: 00:01:34.
If you need also days you may simply add DD to last formatting string.

Calculate age from HIREDATE to system date of your computer
SELECT HIREDATE||' '||SYSDATE||' ' ||
TRUNC(MONTHS_BETWEEN(SYSDATE,HIREDATE)/12) ||' YEARS '||
TRUNC((MONTHS_BETWEEN(SYSDATE,HIREDATE))-(TRUNC(MONTHS_BETWEEN(SYSDATE,HIREDATE)/12)*12))||
'MONTHS' AS "AGE " FROM EMP;

You could use to_timestamp function to convert the dates to timestamps and perform a substract operation.
Something like:
SELECT
TO_TIMESTAMP ('13.10.1990 00:00:00','DD.MM.YYYY HH24:MI:SS') -
TO_TIMESTAMP ('01.01.1990:00:10:00','DD.MM.YYYY:HH24:MI:SS')
FROM DUAL

In oracle 11g
SELECT end_date - start_date AS day_diff FROM tablexxx
suppose the starT_date end_date is define in the tablexxx

select days||' '|| time from (
SELECT to_number( to_char(to_date('1','J') +
(CLOSED_DATE - CREATED_DATE), 'J') - 1) days,
to_char(to_date('00:00:00','HH24:MI:SS') +
(CLOSED_DATE - CREATED_DATE), 'HH24:MI:SS') time
FROM request where REQUEST_ID=158761088 );

If you want something that looks a bit simpler, try this for finding events in a table which occurred in the past 1 minute:
With this entry you can fiddle with the decimal values till you get the minute value that you want. The value .0007 happens to be 1 minute as far as the sysdate significant digits are concerned. You can use multiples of that to get any other value that you want:
select (sysdate - (sysdate - .0007)) * 1440 from dual;
Result is 1 (minute)
Then it is a simple matter to check for
select * from my_table where (sysdate - transdate) < .00071;

If you select two dates from 'your_table' and want too see the result as a single column output (eg. 'days - hh:mm:ss') you could use something like this.
First you could calculate the interval between these two dates and after that export all the data you need from that interval:
select extract (day from numtodsinterval (second_date
- add_months (created_date,
floor (months_between (second_date,created_date))),
'day'))
|| ' days - '
|| extract (hour from numtodsinterval (second_date
- add_months (created_date,
floor (months_between (second_date,created_date))),
'day'))
|| ':'
|| extract (minute from numtodsinterval (second_date
- add_months (created_date,
floor (months_between (second_date, created_date))),
'day'))
|| ':'
|| extract (second from numtodsinterval (second_date
- add_months (created_date,
floor (months_between (second_date, created_date))),
'day'))
from your_table
And that should give you result like this:
0 days - 1:14:55

select (floor(((DATE2-DATE1)*24*60*60)/3600)|| ' : ' ||floor((((DATE2-DATE1)*24*60*60) -floor(((DATE2-DATE1)*24*60*60)/3600)*3600)/60)|| ' ' ) as time_difference from TABLE1

(TO_DATE(:P_comapre_date_1, 'dd-mm-yyyy hh24:mi') - TO_DATE(:P_comapre_date_2, 'dd-mm-yyyy hh24:mi'))*60*60*24 sum_seconds,
(TO_DATE(:P_comapre_date_1, 'dd-mm-yyyy hh24:mi') - TO_DATE(:P_comapre_date_2, 'dd-mm-yyyy hh24:mi'))*60*24 sum_minutes,
(TO_DATE(:P_comapre_date_1, 'dd-mm-yyyy hh24:mi') - TO_DATE(:P_comapre_date_2, 'dd-mm-yyyy hh24:mi'))*24 sum_hours,
(TO_DATE(:P_comapre_date_1, 'dd-mm-yyyy hh24:mi') - TO_DATE(:P_comapre_date_2, 'dd-mm-yyyy hh24:mi')) sum_days

select to_char(actual_start_date,'DD-MON-YYYY hh24:mi:ss') start_time,
to_char(actual_completion_date,'DD-MON-YYYY hh24:mi:ss') end_time,
floor((actual_completion_date-actual_start_date)*24*60)||'.'||round(mod((actual_completion_date-actual_start_date)*24*60*60,60)) diff_time
from fnd_concurrent_requests
order by request_id desc;

If You want get date defer from using table and column.
SELECT TO_DATE( TO_CHAR(COLUMN_NAME_1, 'YYYY-MM-DD'), 'YYYY-MM-DD') -
TO_DATE(TO_CHAR(COLUMN_NAME_2, 'YYYY-MM-DD') , 'YYYY-MM-DD') AS DATEDIFF
FROM TABLE_NAME;

This will count time between to dates:
SELECT
(TO_CHAR( TRUNC (ROUND(((sysdate+1) - sysdate)*24,2))*60,'999999')
+
TO_CHAR(((((sysdate+1)-sysdate)*24)- TRUNC(ROUND(((sysdate+1) - sysdate)*24,2)))/100*60 *100, '09'))/60
FROM dual

Here's another option:
with tbl_demo AS
(SELECT TO_DATE('11/26/2013 13:18:50', 'MM/DD/YYYY HH24:MI:SS') dt1
, TO_DATE('11/28/2013 21:59:12', 'MM/DD/YYYY HH24:MI:SS') dt2
FROM dual)
SELECT dt1
, dt2
, round(dt2 - dt1,2) diff_days
, round(dt2 - dt1,2)*24 diff_hrs
, numtodsinterval((dt2 - dt1),'day') diff_dd_hh_mm_ss
from tbl_demo;

Single query that will return time difference of two timestamp columns:
select INS_TS, MAIL_SENT_TS, extract( hour from (INS_TS - MAIL_SENT_TS) ) timeDiff
from MAIL_NOTIFICATIONS;

select round( (tbl.Todate - tbl.fromDate) * 24 * 60 * 60 )
from table tbl

for oracle sql I justbn did this and works perfect :
SELECT trunc(date_col_1) - trunc(date_col_2)
FROM TABLE;

$sql="select bsp_bp,user_name,status,
to_char(ins_date,'dd/mm/yyyy hh12:mi:ss AM'),
to_char(pickup_date,'dd/mm/yyyy hh12:mi:ss AM'),
trunc((pickup_date-ins_date)*24*60*60,2),message,status_message
from valid_bsp_req where id >= '$id'";