SupplierId NetAmt
1 400
2 400
3 300
2 200
SupplierId RecdAmt
2 200
2 200
2 200
Expectect result:
1 400
3 300
First Table is Inward Table and Second Table is Payment Table when i do payment to supplier who's payment done fully should not show again
you can do like this
select SupplierId , NetAmt from table1
where SupplierId not in (select SupplierId from table2)
or
you can also try this
SELECT SupplierId , NetAmt
FROM Table1 t1
LEFT JOIN Table2 t2 ON t1.SupplierId = t2.SupplierId
WHERE t2.SupplierId IS NULL
Seems you need to get the balance per supplier
SELECT ISNULL(NetTable.SupID, RecTable.SupID) AS SupID, (ISNULL(NetTable.TotalNet,0) - ISNULL(RecTable.TotalRec,0)) AS BalAmt
FROM (SELECT SupID, SUM(NetAmt) AS TotalNet FROM Table_1 GROUP BY SupID) AS NetTable
LEFT OUTER JOIN
(SELECT SupID, SUM(RecAmt) AS TotalRec FROM Table_2 GROUP BY SupID) AS RecTable
ON NetTable.SupID = RecTable.SupID
WHERE NetTable.TotalNet <> RecTable.TotalRec
Need to GROUP BY supplier each table separately & JOIN the summaries.
Related
I have three tables, table1 is connected to table2 and table3, but table2 and table3 are not connected. I need an output count of table2 and table3 for each table1 row. I have to use joins and a group by table1.name
SELECT Tb_Product.Name, count(TB_Offers.Prod_ID) 'Number of Offers', count(Tb_Requests.Prod_ID) 'Number of Requests'
FROM Tb_Product LEFT OUTER JOIN
Tb_Requests ON Tb_Product.Prod_ID = Tb_Requests.Prod_ID LEFT OUTER JOIN
TB_Offers ON Tb_Product.Prod_ID = TB_Offers.Prod_ID
GROUP BY Tb_Product.Name
I need to combine these queries:
SELECT Tb_Product.[Name], count(TB_Offers.Prod_ID) 'Number of Offers'
FROM Tb_Product LEFT OUTER JOIN
TB_Offers ON Tb_Product.Prod_ID = TB_Offers.Prod_ID
GROUP BY Tb_Product.[Name]
SELECT Tb_Product.[Name], count(Tb_Requests.Prod_ID) 'Number of Requests'
FROM Tb_Product LEFT OUTER JOIN
Tb_Requests ON Tb_Product.Prod_ID = Tb_Requests.Prod_ID
GROUP BY Tb_Product.[Name]
Results:
Name Number of Offers
Airplane 6
Auto 5
Bike 3
Camera 0
Computer 12
Milk 4
Oil 4
Orange 6
Telephone 0
Truck 6
TV 4
Name Number of Requests
Airplane 1
Auto 5
Bike 0
Camera 2
Computer 6
Milk 4
Oil 5
Orange 6
Telephone 0
Truck 1
TV 5
My results for offers and requests are the same value. I am not sure what I am doing wrong with the joins. Do I need to somehow join product to request and separately join product to offers? This needs to be done in one query.
This is for a class. Explanation would also be appreciated.
The simplest way to do this is to count the distinct values of each column:
SELECT
Tb_Product.Name,
count(distinct TB_Offers.Prod_ID) 'Number of Offers',
count(distinct Tb_Requests.Prod_ID) 'Number of Requests'
FROM
Tb_Product
LEFT OUTER JOIN
Tb_Requests ON Tb_Product.Prod_ID = Tb_Requests.Prod_ID
LEFT OUTER JOIN
TB_Offers ON Tb_Product.Prod_ID = TB_Offers.Prod_ID
GROUP BY
Tb_Product.Name
This is necessary because of the way joins work consecutively to produce a rowset that is a combination of all the input relations. COUNT() normally performs a count of non-null values in a column.
You can also do something like this, which aggregates the counts from the child tables independently and then joins them to the base table:
SELECT
p.Name,
o.cnt as Offer_Count,
r.cnt as Request_Count
FROM
TB_Product p
LEFT OUTER JOIN
(SELECT Prod_ID, COUNT(1) cnt FROM TB_Offers GROUP BY Prod_ID) o
LEFT OUTER JOIN
(SELECT Prod_ID, COUNT(1) cnt FROM TB_Requests GROUP BY Prod_ID) r
More explanation...
Let's say you have two products:
Prod_ID
Name
1
Widget
2
Gizmo
And two offers, one for each product:
Offer_ID
Prod_ID
100
1
200
2
And two requests for each product:
Request_ID
Prod_ID
1001
1
1002
1
2001
2
2002
2
Now you join Product relation to Offer relation on Prod_ID, you get a result like this:
Prod_ID
Name
Offer_ID
Prod_ID
1
Widget
100
1
2
Gizmo
200
2
Now when you join that relation to Requests on Prod_ID, you get something like this:
Prod_ID
Name
Offer_ID
Prod_ID
Request_ID
Prod_ID
1
Widget
100
1
1001
1
1
Widget
100
1
1002
1
2
Gizmo
200
2
2001
2
2
Gizmo
200
2
2002
2
Now when you count any of these columns you get 4 because each column has 4 values.
I just want to get the result which displays the reference which is not tallied in sum of table2. when i run my query below it will give me an wrong sum which it gets doubled even if group by cusid ,refno.
Table 1
RefNo
CusID
TotalAmount
1
1001
50
2
1001
30
3
1002
40
Table 2
RefNo
CusID
Particular
Amount
1
1001
Paper
30
1
1001
Pencil
30
2
1001
Ball
15
2
1001
Rubber
20
3
1002
Laptop
50
select * from Table1 a
INNER JOIN (Select CusID,RefNo, SUM(Amount) as CorrectTotal from Table2 group by
CusID,RefNo,
)b
ON b.CusID= a.CusID AND b.RefNo= a.RefNo
where a.TotalAmount != CorrectTotal
Expected Result
If you do it with FULL JOIN and with GROUP BY, you will also get rows where there is no record in the other table.
SELECT COALESCE(a.RefNo, b.RefNo) AS RefNo
, COALESCE(a.CusID, b.CusID) AS CusID
, a.TotalAmount
, SUM(b.Amount) AS CorrectTotal
FROM table1 a
FULL JOIN table2 b ON a.RefNo = b.RefNo
AND a.CusID = b.CusID
GROUP BY COALESCE(a.RefNo, b.RefNo)
, COALESCE(a.CusID, b.CusID)
, a.TotalAmount
ORDER BY 1, 2
Output
RefNo
CusID
TotalAmount
CorrectTotal
1
1001
50
60
2
1001
30
35
3
1002
40
50
8
888
88
(null)
9
999
(null)
99
See running demo on SQL Fiddle.
The other answer will work, but if you don't want to mess with a GROUP BY on the whole query you can also use an APPLY to do this:
SELECT a.*, c.CorrectAmount
FROM Table1 a
OUTER APPLY (
SELECT SUM(Amount) AS CorrectAmount
FROM Table2 b
WHERE b.CusID = a.CusID AND b.RefNo = a.RefNo
) c
WHERE a.TotalAmount <> c.CorrectAmount
I need to write a SELECT query in SQL Server which uses a JOIN or UNION that selects distinct ItmNo or Code rows from 3 tables OnHand, Sale and Purchase.
Here are the details of the tables I have and what I need. ItmNo and/or Code columns can be used as foreign keys to join the tables.
These are my input tables-
Table OnHand
ID ItmNo Code Qty
----------------------------------
1 I001 001 100
2 I001 001 50
3 I003 003 300
Table Sale
ID ItmNo Code Qty
----------------------------------
1 I001 001 100
2 I004 004
3 I003 003 120
Table Purchase
ID ItmNo Code Qty
----------------------------------
1 I005 005 10
2 I003 003 200
3 I003 003 300
And this is what I need as output. Only DISTINCT ItmNo and Code should be displayed here:
ID ItmNo Code SumQtyOnHand SumQtyOnSale SumQtyOnPurchase
------------------------------------------------------------------------------
1 I001 001 150 100
2 I003 003 300 120 500
3 I005 005 10
Here is the SELECT query that I have tried is below but I cannot get the output I want-
SELECT
A.ItmNo, A.Code,
A2.TOTAL SumQtyOnHand,
B.TOTAL SumQtyOnSale,
C.TOTAL SumQtyOnPurchase
FROM
dbo.OnHand A
LEFT JOIN
(SELECT ItmNo, Code, SUM(Qty) TOTAL
FROM dbo.OnHand
GROUP BY ItmNo, Code) A2 ON A.ItmNo = A2.ItmNo
LEFT JOIN
(SELECT ItmNo, Code, SUM(Qty) TOTAL
FROM dbo.Sale
GROUP BY ItmNo, Code) B ON A.ItmNo = A2.ItmNo
LEFT JOIN
(SELECT ItmNo, Code, SUM(Qty) TOTAL
FROM dbo.Purchase
GROUP BY ItmNo, Code) C ON A.ItmNo = A2.ItmNo
Please suggest the correction in the SELECT query to achieve the above output.
Thanks in advance!
I think you are on the right track with the prea-ggregation subqueries. Then, you can full join. The syntax is a bit cumbersome in SQL Server, that does not support the using() clause:
select
coalesce(o.itmno, s.itemno, p.itemno) as itemno,
coalesce(o.code, s.code, p.code) as code,
o.SumQtyOnHand,
s.SumQtyOnSale,
p.SumQtyOnPurchase
from (
select itmno, code, sum(qty) SumQtyOnHand
from dbo.onhand
group by itmno, code
) o
full join (
select itmno, code, sum(qty) SumQtyOnSale
from dbo.sale
group by itmno, code
) s on s.itmno = o.itmno and s.code = o.code
full join (
select itmno, code, sum(qty) SumQtyOnPurchase
from dbo.purchase
group by itmno, code
) p on p.itemno = coalesce(s.itemno, o.itemno) and p.code = coalesce(s.code, o.code)
It might be simpler expressed with union all and aggregation:
select itemno, code,
sum(qtyOnHand) as SumQtyOnHand,
sum(qtyOnSale) as SumQtyOnSale,
sum(qtyOnPurchase) as SumQtyOnPurchase
from (
select itemno, code, qty as qtyOnHand, null as qtyOnSale, null as qtyOnPurchase from dbo.onhand
union all select itemno, code, null, qty, null from dbo.sale
union all select itemno, code, null, null, qty from dbo.purchase
) t
group by itemno, code
i have 1 table inventory_movement here is data in table
product_id | staff_name | status | sum | reference_number
--------------------------------------------------
1 zes cp 1 000122
2 shan cp 4 000133
i have another table inventory_orderproduct where i have cost date
orderdate product_id cost
--------------------------------
01/11/2018 1 3200
01/11/2018 2 100
02/11/2018 1 4000
02/11/2018 1 500
03/11/2018 2 2000
i want this result
product_id| staff_name | status | sum reference_number | cost
--------------------------------------------------------------
1 zes cp 1 000122 4000
2 shan cp 4 000133 2000
here is my query
select ipm.product_id,
case when ipm.order_by_id is not null then
(select au.first_name from users_staffuser us inner join auth_user au on us.user_id= au.id
where us.id = ipm.order_by_id) else '0' end as "Staff_name"
,ipm.status,
Sum(ipm.quantity), ip.reference_number
from inventory_productmovement ipm
inner join inventory_product ip on ipm.product_id = ip.id
inner join users_staffuser us on ip.branch_id = us.branch_id
inner join auth_user au on us.user_id = au.id
AND ipm.status = 'CP'
group by ipm.product_id, au.first_name, ipm.status,
ip.reference_number, ip.product_name
order by 1
Here is the solution of your question.its working fine.if you like the answer please vote!
SELECT i.product_id,i.staff_name,i.status,i.sum reference_number ,s.Cost
FROM (SELECT product_id,MAX(cost) AS Cost
FROM inventory_orderproduct
GROUP BY product_id ) s
JOIN inventory_movement i ON i.product_id =s.product_id
In the given situation, this should work fine:
Select table1.product_id, table2.staff_name, table2.status, table2.reference_number,
MAX(table1.cost)
FROM table2
LEFT JOIN table1 ON table1.product_id = table2.product_id
GROUP BY table2.product_id, table2.staff_name, table2.status, table2.reference_number
You can use the below query to get MAX cost for products
SELECT i.product_id,i.staff_name,i.status,i.sum reference_number ,s.MAXCost
FROM (SELECT product_id,MAX(cost) AS MAXCost
FROM inventory_orderproduct
GROUP BY product_id ) s
JOIN inventory_movement i ON i.product_id =s.product_id
For Retrieving the cost using the latest date use the below query
WITH cte as (
SELECT product_id,cost
,ROW_NUMBER() OVER (PARTITION BY product_id ORDER BY orderdate DESC) AS Rno
FROM inventory_orderproduct )
SELECT i.product_id,i.staff_name,i.status,i.sum reference_number ,s.Cost
FROM cte s
JOIN inventory_movement i ON i.product_id =s.product_id
WHERE s.Rno=1
You can use below query it will pick the data according to the latest date
WITH result as (
SELECT product_id,cost
,ROW_NUMBER() OVER (PARTITION BY product_id ORDER BY date DESC)
FROM inventory_orderproduct )
SELECT i.product_id,i.staff_name,i.status,i.sum reference_number ,s.Cost
FROM result s
JOIN inventory_movement i ON i.product_id =s.product_id
i have these tables
table 1
id price
1 30
2 40
3 50
table 2
id price
1 70
2 5
3 10
i want a query that would sum the the price value based on the ID
like if table1.id=table2.id then sum table1.price and table2.price
the end result should be something like this
table 3
id price
1 100
2 45
3 60
You can;
SELECT
TABLE1.ID,
TABLE1.PRICE+TABLE2.PRICE
FROM TABLE1
INNER JOIN TABLE2 ON TABLE1.ID = TABLE2.ID;
Or if there are duplicate IDs in either table;
SELECT
TABLE1.ID,
SUM(TABLE1.PRICE+TABLE2.PRICE)
FROM TABLE1
INNER JOIN TABLE2 ON TABLE1.ID = TABLE2.ID
GROUP BY TABLE1.ID;