Oracle 11G R2 SQL rows to columns - sql

Question

I have a table of bank staff information that looks like this:
branchNumber Position firstName lastName staffNumber
------------ -------- --------- -------- -----------
25 Manager john doe 11111
25 Secretary robert paulson 11112
25 Secretary cindy lu 11113
66 Manager tim timson 22223
66 Manager jacob jacobson 22224
66 Secretary henry henryson 22225
66 Supervisor paul paulerton 22226
I am actually done with this, but I completed the assignment using SQL common table expressions, and I can't use them in this project, I need them in this format.
branchNumber numOfManagers numOfSecretaries numOfSupervisors totalEmployees
------------ ------------- ---------------- ---------------- --------------
25 1 2 0 3
66 2 1 1 4
My issue is getting multiple columns with information from a row, I have this so far,
SELECT branchNumber, COUNT(*) AS numOfManagers
FROM Staff
WHERE position = 'Manager'
GROUP BY branchNumber, Position;
This outputs the correct information for numOfManagers, but making the next three columns eludes me without using CTE's. I tried sub selects too, with no luck. Anybody have any ideas?

Answer 1

You can use something like this:
select branchnumber,
sum(case when Position ='Manager' then 1 else 0 end) numofManagers,
sum(case when Position ='Secretary' then 1 else 0 end) numofSecretaries,
sum(case when Position ='Supervisor' then 1 else 0 end) numofSupervisors,
count(*) totalEmployees
from yourtable
group by branchnumber
See SQL Fiddle with Demo
Or you can use the PIVOT function:
select branchnumber,
'Manager', 'Secretary', 'Supervisor',
TotalEmployees
from
(
select t1.branchnumber,
t1.position,
t2.TotalEmployees
from yourtable t1
inner join
(
select branchnumber, count(*) TotalEmployees
from yourtable
group by branchnumber
) t2
on t1.branchnumber = t2.branchnumber
) x
pivot
(
count(position)
for position in ('Manager', 'Secretary', 'Supervisor')
) p;
See SQL Fiddle with Demo