Updating Xml attributes with new values in a SQL Server 2008 table - sql

Question

I have a table in SQL Server 2008 that it has some columns. One of these columns is in Xml format
and I want to update some attributes.
For example my Xml column's name is XmlText and it's value in 5 first rows is such as:
<Identification Name="John" Family="Brown" Age="30" />
<Identification Name="Smith" Family="Johnson" Age="35" />
<Identification Name="Jessy" Family="Albert" Age="60" />
<Identification Name="Mike" Family="Brown" Age="23" />
<Identification Name="Sarah" Family="Johnson" Age="30" />
and I want to change all Age attributes that are 30 to 40 such as below:
<Identification Name="John" Family="Brown" Age="40" />
<Identification Name="Smith" Family="Johnson" Age="35" />
<Identification Name="Jessy" Family="Albert" Age="60" />
<Identification Name="Mike" Family="Brown" Age="23" />
<Identification Name="Sarah" Family="Johnson" Age="40" />

Answer 1

From the early versions of your question it looks like your XML actually is on different rows in a table. If that is the case you can use this.
update YourTable set
XMLText.modify('replace value of (/Identification/#Age)[1] with "40"')
where XMLText.value('(/Identification/#Age)[1]', 'int') = 30
Working sample using a table variable.
declare #T table(XMLText xml)
insert into #T values('<Identification Name="John" Family="Brown" Age="30" />')
insert into #T values('<Identification Name="Smith" Family="Johnson" Age="35" />')
insert into #T values('<Identification Name="Jessy" Family="Albert" Age="60" />')
insert into #T values('<Identification Name="Mike" Family="Brown" Age="23" />')
insert into #T values('<Identification Name="Sarah" Family="Johnson" Age="30" />')
update #T set
XMLText.modify('replace value of (/Identification/#Age)[1] with "40"')
where XMLText.value('(/Identification/#Age)[1]', 'int') = 30
select *
from #T

Answer 2

Try this:
declare #xml XML
SET #xml = '<Root>
<Identification Name="John" Family="Brown" Age="30" />
<Identification Name="Smith" Family="Johnson" Age="35" />
<Identification Name="Jessy" Family="Albert" Age="60" />
<Identification Name="Mike" Family="Brown" Age="23" />
<Identification Name="Sarah" Family="Johnson" Age="30" />
</Root>'
DECLARE #nodeCount int
DECLARE #i int
SET #i = 1
SELECT #nodeCount = #xml.value('count(/Root/Identification/#Age)','int')
PRINT 'Number of nodes found: ' + STR(#nodeCount)
WHILE (#i <= #nodeCount)
BEGIN
Set #xml.modify('replace value of (/Root/Identification/#Age)[.=30][1] with "40"')
SET #i = #i + 1
END
SELECT #xml

Answer 3

The modify method is your response. But if you need to have a condition you can use if expression in with section of this method.
DECLARE #t TABLE (RecordXML XML);
Declare #xml XML
SET #xml = '<Root>
<Identification Name="John" Family="Brown" Age="30" />
<Identification Name="Smith" Family="Johnson" Age="35" />
<Identification Name="Jessy" Family="Albert" Age="60" />
<Identification Name="Mike" Family="Brown" Age="23" />
<Identification Name="Sarah" Family="Johnson" Age="30" />
</Root>'
INSERT #t VALUES (#xml);
Declare #value nvarchar(50)
DECLARE #oldvalue nvarchar(50)
SET #value = '40'
SET #oldvalue = '30'
Declare #update_count xml
select #update_count = #xml.query('count(/Root/Identification/#Age[.=sql:variable("#oldvalue")])')
Declare #number int
select #number = convert(int, (convert(nvarchar(50), #update_count)))
declare #Node int
set #Node = 1
while #Node <= #number
begin
UPDATE
#t
SET
RecordXML.modify('replace value of
(/Root/Identification/#Age[.=sql:variable("#oldvalue")])[1] with sql:variable("#value")')
WHERE
RecordXML.exist('/Root/Identification[#Age=sql:variable("#oldvalue")]') = 1;
set #Node = #Node + 1
end
SELECT * FROM #t;