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Closed 10 years ago.
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Select Records multiple times from table
I want to have my query return (multiple) rows for the value of TABLE_B.QTY.
TABLE A
SALESNR ITEMNR LINENR
100 B2001 1
101 B2002 2
102 A1021 3
TABLE B
LINENR COLOR QTY
1 WHITE 3
2 BLACK 1
3 BROWN 8
For instance, with the following query:
SELECT TABLE_A.SALESNR, TABLE_A.ITEMNR, TABLE_B.COLOR, TABLE_B.QTY
FROM TABLE_A INNER JOIN TABLE_B ON TABLE_B.LINENR = TABLE_A.LINENR
I get:
100 B2001 White 3
What I need is:
100 B2001 White 3
100 B2001 White 3
100 B2001 White 3
Is there a way to do this?
Can't think of the right keywords to Google this...
Thnx,
Mike
This will work as long as QTY is less than 2047
SELECT TABLE_A.SALESNR, TABLE_A.ITEMNR, TABLE_B.COLOR, TABLE_B.QTY
FROM TABLE_A
INNER JOIN TABLE_B ON TABLE_B.LINENR = TABLE_A.LINENR
INNER JOIN master..spt_values ON type = 'P' AND number < TABLE_B.QTY
use this if QTY exceeds 2047:
;WITH a AS
(
SELECT TABLE_A.SALESNR, TABLE_A.ITEMNR, TABLE_B.COLOR, TABLE_B.QTY, 1 row
FROM TABLE_A
INNER JOIN TABLE_B ON TABLE_B.LINENR = TABLE_A.LINENR
WHERE QTY > 0
union all
SELECT SALESNR, ITEMNR, COLOR, QTY, row+1
FROM a
WHERE QTY > row
)
SELECT SALESNR, ITEMNR, COLOR, QTY from a
OPTION (MAXRECURSION 0)
The cross join won't do it if you have one row in each table, which I interpret it as. I would suggest, if possible, to re-design your data model to solve this - or loop in code where you use this data.
You can loop in the T-SQL if absolutely needed.
regards, Olle
Can't seem to comment other peoples posts, just wanted to say, nice solution, to t-clausen.dk!
Related
How to repeat rows based on column value in snowflake using sql.
I tried a few methods but not working such as dual and connect by.
I have two columns: Id and Quantity.
For each ID, there are different values of Quantity.
So if you have a count, you can use a generator:
with ten_rows as (
select row_number() over (order by null) as rn
from table(generator(ROWCOUNT=>10))
), data(id, count) as (
select * from values
(1,2),
(2,4)
)
SELECT
d.*
,r.rn
from data as d
join ten_rows as r
on d.count >= r.rn
order by 1,3;
ID
COUNT
RN
1
2
1
1
2
2
2
4
1
2
4
2
2
4
3
2
4
4
Ok let's start by generating some data. We will create 10 rows, with a QTY. The QTY will be randomly chosen as 1 or 2.
Next we want to duplicate the rows with a QTY of 2 and leave the QTY =1 as they are.
Obviously you can change all parameters above to suit your needs - this solution works super fast and in my opinion way better than table generation.
Simply stack SPLIT_TO_TABLE(), REPEAT() with a LATERAL() join and voila.
WITH TEN_ROWS AS (SELECT ROW_NUMBER()OVER(ORDER BY NULL)SOME_ID,UNIFORM(1,2,RANDOM())QTY FROM TABLE(GENERATOR(ROWCOUNT=>10)))
SELECT
TEN_ROWS.*
FROM
TEN_ROWS,LATERAL SPLIT_TO_TABLE(REPEAT('hire me $10/hour',QTY-1),'hire me $10/hour')ALTERNATIVE_APPROACH;
I want to write a query in SQL. Can someone help me for writing oracle sql query for below result table
Table 1 Data
prodno description
1 Laptop
2 Charger
3 Mouse
Table 2 Data
prodno prodset_no
1 1
2 1
3 1
1 2
3 2
1 3
2 3
Result Table
prodset_no prodset_desc
1 Laptop,Charger,Mouse
2 Laptop,Mouse
3 Laptop,Charger
JOIN the two table and then use listagg to produce comma separated output:
select t2.prodset_no,
listagg(t1.description, ',') within group (
order by t1.prodno
) prodset_desc
from table2 t2
join table1 t1 on t2.prodno = t1.prodno
group by t2.prodset_no;
Also, worth a note that the listagg has a limit of 4000 bytes. If you hit that limit, you can either use XMLAGG or rethink the problem and not do it in SQL at all but rather handle it in your application code.
This question already has answers here:
How to get rows having sum equal to given value
(4 answers)
Closed 9 years ago.
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here is table T :-
id num
-------
1 50
2 20
3 90
4 40
5 10
6 60
7 30
8 100
9 70
10 80
and the following is a fictional sql
select *
from T
where sum(num) = '150'
the expected result is :-
(A)
id num
-------
1 50
8 100
(B)
id num
-------
2 20
7 30
8 100
(C)
id num
-------
4 40
5 10
8 100
the 'A' case is most preferred !
i know this case is related to combinations.
in real world - client gets items from a shop, and because of an agreement between him and the shop, he pay every Friday. the payment amount is not the exact total of items
for example: he gets 5 books of 50 € ( = 250 € ), and on Friday he bring 150 €, so the first 3 books are perfect match - 3 * 50 = 150. i need to find the id's of those 3 books !
any help would be appreciated!
You can use recursive query in MSSQL to solve this.
SQLFiddle demo
The first recursive query build a tree of items with cumulative sum <= 150. Second recursive query takes leafs with cumulative sum = 150 and output all such paths to its roots. Also in the final results ordered by ItemsCount so you will get preferred groups (with minimal items count) first.
WITH CTE as
( SELECT id,num,
id as Grp,
0 as parent,
num as CSum,
1 as cnt,
CAST(id as Varchar(MAX)) as path
from T where num<=150
UNION all
SELECT t.id,t.num,
CTE.Grp as Grp,
CTE.id as parent,
T.num+CTE.CSum as CSum,
CTE.cnt+1 as cnt,
CTE.path+','+CAST(t.id as Varchar(MAX)) as path
from T
JOIN CTE on T.num+CTE.CSum<=150
and CTE.id<T.id
),
BACK_CTE as
(select CTE.id,CTE.num,CTE.grp,
CTE.path ,CTE.cnt as cnt,
CTE.parent,CSum
from CTE where CTE.CSum=150
union all
select CTE.id,CTE.num,CTE.grp,
BACK_CTE.path,BACK_CTE.cnt,
CTE.parent,CTE.CSum
from CTE
JOIN BACK_CTE on CTE.id=BACK_CTE.parent
and CTE.Grp=BACK_CTE.Grp
and BACK_CTE.CSum-BACK_CTE.num=CTE.CSum
)
select id,NUM,path, cnt as ItemsCount from BACK_CTE order by cnt,path,Id
If you restrict your problem to "which two numbers add up to a value", the solution is as follows:
SELECT t1.id, t1.num, t2.id,t2.num
FROM T t1
INNER JOIN T t2
ON t1.id < t2.id
WHERE t1.num + t2.num = 150
If you also want the result for three and more numbers you can achieve that by using the above query as a base for recursive SQL. Don't forget to specify a maximum recursion depth!
To find the id's of the books that the client is paying, you would need to have a table with your clients, and another one to store the orders of the client, and what products he bought.
Otherwise it would be impossible to know what product the payment refers to.
I've been trying to solve this problem over the weekend, without luck so far. I have two tables:
TopOffers:
OfferId RetailerId Order
1 38 0
2 8 3
3 17 2
4 22 1
And Offers:
Id RetailerId Name Description etc...
1 3 Strawberry Red and smelly
2 38 Cookie Crunchy
3 17 Onion Of the nice kind
4 22 Apple Cheap
5 8 Toothbrush Lasts extra long!
My goal is to get the top 10 Offers for each Retailer ID. The order in which they should be listed is specified by the Order field in the TopOffer table (Sort order is Ascending). On top of that, the result should be padded to 10 offers when there are less than 10 TopOffer records for a retailer. The TopOffer table always contains 10 or less records per retailer.
So far I've managed to get this going, which works (I realize it doesn't get the top 10, but rather everything that's in the TopOffer table, which is alright, since the TopOffer table is always equal to or smaller than the top 10 for any retailer):
SELECT b.*
FROM
(
SELECT o.Id, to.`Order` FROM Offer AS o
LEFT JOIN TopOffer AS to
ON o.Id = to.OfferId
) AS a,
(
SELECT o.*, to.`Order` FROM Offer AS o
LEFT JOIN TopOffer AS to
ON o.Id = to.OfferId
) AS b
WHERE a.`Order` >= b.`Order` AND a.Id = b.Id
GROUP BY b.RetailerId, b.Id
HAVING Count(1) BETWEEN 1 AND 10
ORDER BY RetailerId, `Order` ASC
Unfortunately I can't seem to find any way of padding the result of this query with offers that don't have an entry in the TopOffer table if there aren't 10 TopOffer records for that retailer.
My sincerest thanks in advance for any help!
If you create a virtual table with numbers 1-10 you can left join to your results to get 10 of each
select number, results.*
from
(select 1 as number union select 2 union select 3 ... union select 10) numbers
left join
(your query here) results
on numbers.number = results.rank
Let's say I have this table:
|Fld | Number|
1 5
2 2
And I want to make a select that retrieves as many Fld as the Number field has:
|Fld |
1
1
1
1
1
2
2
How can I achieve this? I was thinking about making a temporary table and instert data based on the Number, but I was wondering if this could be done with a single Select statement.
PS: I'm new to SQL
You can join with a numbers table:
SELECT Fld
FROM yourtable
JOIN Numbers
ON yourtable.Number <= Numbers.Number
A numbers table is just a table with a list of numbers:
Number
1
2
3
etc...
Not an great solution (since you still query your table twice, but maybe you can work from it)
SELECT t1.fld, t1.number
FROM table t1, (
SELECT ROWNUM number FROM dual
CONNECT BY LEVEL <= (SELECT MAX(number) FROM t1)) t2
WHERE t2.number<=t1.number
It generates maximum amount of rows needed and then filters it by each row.
I don't know if your RDBMS version supports it (although I rather suspect it does), but here is a recursive version:
WITH remaining (fld, times) as (SELECT fld, 1
FROM <table>
UNION ALL
SELECT a.fld, a.times + 1
FROM remaining as a
JOIN <table> as b
ON b.fld = a.fld
AND b.number > a.times)
SELECT fld
FROM remaining
ORDER BY fld
Given your source data table, it outputs this (count included for verification):
fld times
=============
1 1
1 2
1 3
1 4
1 5
2 1
2 2