I've been reading David Drapers' blog on the new feature - the extension of share webscripts, but I didn't find any working examples. What is the file naming and structure convention?
From what I gather, I have a module configuration file, and I don't know how to name it or where to put it (share/WEB-INF/classes/alfresco?)
Also, I understood that my custom client side resources (.js and .css files) go to META-INF/custom-dashlet/extension/ in the JAR file. Is this correct? Finally, the *.get.js and *.get.html.ftl go to webscripts/com/mycompany/mypackage/*?
So I have now:
*share/WEB-INF/lib/mypackage.jar*
and in it:
*META-INF/mypackage/extension/myfile.js
webscripts/com/mycompany/mypackage/myfile.get.js
webscripts/com/mycompany/mypackage/myfile.get.html.ftl
*
and the
*share/WEB-INF/classes/alfresco/something.xml*
This question was also posted to the Alfresco forums here: https://forums.alfresco.com/en/viewtopic.php?f=48&t=46438
The answer provided was as follows:
An extension module a Surf configuration object so you should place XML files containing module configuration in any of the locations where Surf config gets picked up... e.g. <web-server>/webapps/share/WEB-INF/classes/alfresco/site-data (there are lots of places where Surf configuration gets picked up, but alfresco/site-data on the classpath is the most common). Extension config files should be placed in the extensions folder within the directory. So you could place an extension config file in: alfresco/site-data/extensions or alfresco/web-extension/site-data/extensions, for example.
You could create a JAR file containing this folder structure. Everything that the extension refers to (e.g. WebScripts, other Surf config objects such as Pages, Template-Instances, Components, etc) should just be placed in their normal location. These can also be built into a JAR file.
If you want to access resources (e.g. CSS, images, JS) from a JAR file then place them in the META-INF folder of the JAR. You should place your JAR file in the <web-server>/webapps/share/WEB-INF/lib directory (obviously your server will need to be restarted to pick up new JAR contents).
WebScripts should be in (on the classpath):
alfresco/site-webscripts
alfresco/web-extension/site-webscripts
webscripts
You can also configure other locations in the Surf configuration from which to load Surf config objects/WebScripts. It's pretty much endlessly customizable but you should probably just stick to the default locations configured for Share.
Related
I have created the default play application in IntelliJ in directory P. I have over-written the default index.scala.html with my own html code. The html code refers to some css and js files which are outside the directory P. To include these external files, I added the directory of these files using project configuration settings.
My webpage doesn't load properly as the server returns 404 for the css and js files. What am I doing wrong?
When you added your directory using project structure, you only say:
Hey, IDEA, please consider this folder part of my project, consider
its contents source code and display it when I open my project.
However, when you deploy or run your app, you only deploy the usual folders to the server, which contain the resources which will be available for clients to access.
The external directory is not part of these directories and will not be deployed.
What you can do is to copy the file from the external directory as a part of your build process before deploying the application.
EDIT: Detailed answer here: What is intellij's build process for play applications
Is it possible to externalize rest-messages.properties in SDR?
I tried to move it to ./config folder, for example, but it didn't work.
The rest-messages.properties (used to add custom details to your ALPS descriptions) goes to the same location where you would put custom application-*.properties or messages-*.properties file.
For instance, for a Spring Boot project the .properties file are located in the src/main/resources/ directory.
You can also set custom config locations for your .properties file.
Edit after the OP's comment: However, I tried using a custom rest-messages.properties outside of the project .jar (as I usually do with my application.properties), and it does not seem to work.
I have a dir structure for Intellij 12:
...
...test
- java
- com.mycompany.myproject
- package1 (contains code, etc,.)
- resourcePackage (want to contain .json files but can't mark as a resource)
- myOtherJunk.json
- o o o
- resources
- aResource.json
The thing is if I right click on my package name (com.mycompany.myproject) I can only add packages and not directories (like that of an existing resource folder).
However, I don't want to use that existing resource folder for the .json files that I'm going to read into per my test class.
So, I need something to support:
// this already works for the resources directory per the .json file but doesn't for the
// myOtherJunk.json per the resourcePackage.
InputStream is = MyClassTest.class.getResourceAsStream("aResource.json");
This can be solved in several ways. An example of a good approach would be the following folder structure:
src
main
java
resources
test
java
resources
When this is done, you put all you java classes under src/main/java/com.mycompany package and any resources under /src/main/resources/com/mycompany folder.
To link them together, go to the project properties, and find the Path tab. Mark the src/main/java and src/main/resources as source folders. (see the screen-shot attached)
If you link them together, you'll be able to use getResourceAsStream() method.
If you wonder why you should use the following folder structure - this is standard maven way of keeping things clean and tidy.
Directories Creation
Intellij creates directories when you ask her to create package. It is not an error.
If you create package "com", it will create the dir "com", and if you create a source file there, it will think that the file is in the package "com".
If you create package "com.next.pack", it will create three nested dirs "com", then "next", then "pack", and if you create a source file there, it will think that the file is in the package "com.next.pack".
Directories Structures
Only the path under the source root is taken as a package. Any directory(ies) can be set as a source root(s).
Resources roots
Make practically any structure of directories. Somewhere in it there is the root dir of resources. Right-click it and Mark Directory As ... Resources Root.
Notice, the same method can be used for the directories structures for tests, test classes, and test resources. Look here.
Please use #ContextConfiguration annotation to load the resource files. Please see below example.
#ContextConfiguration( { "/app-config.xml", "/test-data-access-config.xml",application-test.yml })
I have written a java Servlet web application, using NetBeans 7.2.1. The program have some jar file libraries that I have attached to the project. The application runs fine using NetBeans and Apache Tomcat 7.0.27.
My problem is that some of the jar file libraries that I am using in the project, need to access to some folders and files. I put these folder and files on the same directory as the whole NetBeans project is. but I got this exception:
Exception: java.lang.RuntimeException: java.io.FileNotFoundException
So I used these codes to find out where should I put them:
out.println("current directory: " + new File(".").getAbsolutePath());
out.println("current directory: " + System.getProperty("user.dir"));
out.println("current directory: " + getServletContext().getRealPath(("/")));
So I figured out that the current working directory is:
C:\Program Files\Apache Software Foundation\Apache Tomcat 7.0.27\bin
My question is that how can I set different directory address for each web application? I have many web applications and some of them use the same resource file names. I can't just put all of them in one directory.
Please note that I don't have access to the source code of jar files to change the. I just need a way to set the absolute path that the jar files use.
I have the same problem when I put the WAR file on the unix server. The extracted WAR file is in this location on the server:
/data02/tools/Apache/Tomcat/apache-tomcat-6.0.37/webapps/BANNEROnline
But I figure I should put the resource folders and files in this path (moosavi3 is my username!):
/home/moosavi3
How can I change the path?
The working directory is the directory from which java.[exe,bin] is started. I assume the bin directory is where the tomcat start-up script is? If the jars are all using this working directory I don't believe there is a way to make different web-apps have different working directory, they're all loaded on the same jvm (java.exe) from the same working directory.
A working directory is the directory from which a binary is started, it is not some arbitrary value that you can change.
I suspect these jar files where meant to be run as standalone applications and expected the filesystem resources they are trying to access to be in the same location as themselves.
Any filesystem resources would have to be moved to the location of your java.exe so that the correct file path resolution can result from your jars.
Standard Servlet project requires external libraries to be placed in the 'WEB-INF/lib' directory under project root. You can search google for 'servlet directory structure' and do your own research for more information. Shared libraries between web applications can be placed in the 'lib' directory under tomcat root, they should be picked up by tomcat jvm. My recommendation would be to keep the dependencies project specific, because you may need different versions in different projects in the future.
Update:
Read this page on the tomcat documentation, it will explain exactly how the project should be structured, and how to add a library that will be shared across all web applications:
http://tomcat.apache.org/tomcat-7.0-doc/appdev/deployment.html
Update 2:
The following Stackoverflow link explains several options how to add a static file to your web application, that will available at runtime.
https://stackoverflow.com/a/2161583/940754
Update 3:
Add a path to the classpath using the project's manifest:
http://docs.oracle.com/javase/tutorial/deployment/jar/downman.html
The architecture of my web application is highly modular. I am using apache tiles as the templating framework. The app modules are bundled as different jar files and put inside WEB-INF/lib folder. So each jar file will contain its own tiles configuration files (containing tiles definitions) and related jsp templates.
I am using CompleteAutoloadTilesListener which is a part of tiles-extras package to read the tiles config files from the jar files. But the jsp files aren't picked up by tiles. When I access any definition, it couldn't find the jsp template file.
A configuration change will solve this problem? or should I subclass any tiles base class to let tiles load jsps from the jar?
Someone else ran into this problem before and even wrote a blog about it
It mentions this issue that is fixed, so you should be able to use the same setup and load your tiles definitions from the classpath.
I haven't tested it, but it looks like a sensible solution.