Split string by comma in SQL Server 2008 - sql

Question

There are two strings a and b
The a string contains comma. I would like to split the a string by comma, then go through every element .
IF the b string contains any element which split by comma will return 0
(e.g: a = "4,6,8" ; b = "R3799514" because the b string contains 4 so return 0)
How to achieve this with a stored procedure? Thanks in advance!
I have seen a split function:
CREATE FUNCTION dbo.Split(#String varchar(8000), #Delimiter char(1))
returns #temptable TABLE (items varchar(8000))
as
begin
declare #idx int
declare #slice varchar(8000)
select #idx = 1
if len(#String)<1 or #String is null return
while #idx!= 0
begin
set #idx = charindex(#Delimiter,#String)
if #idx!=0
set #slice = left(#String,#idx - 1)
else
set #slice = #String
if(len(#slice)>0)
insert into #temptable(Items) values(#slice)
set #String = right(#String,len(#String) - #idx)
if len(#String) = 0 break
end
return
end
select top 10 * from dbo.split('Chennai,Bangalore,Mumbai',',')

Answer 1

Following will work -
DECLARE #A VARCHAR (100)= '4,5,6'
DECLARE #B VARCHAR (100)= 'RXXXXXX'
DECLARE #RETURN_VALUE BIT = 1 --DEFAULT 1
SELECT items
INTO #STRINGS
FROM dbo.split(#A,',')
IF EXISTS(SELECT 1 FROM #STRINGS S WHERE CHARINDEX(items, #B) > 0)
SET #RETURN_VALUE = 0
PRINT #RETURN_VALUE
DROP TABLE #STRINGS
You can also use CONTAINS instead of CHARINDEX -
IF EXISTS(SELECT 1 FROM #STRINGS S WHERE CONTAINS(items, #B))
SET #RETURN_VALUE = 0