In this case, I want to extract the beginning text in a cell and leave the remainder intact.
e.g. a series of cells contain:
2nd Unit. Miami
3rd Production Staff. Toronto
1st Ad. San Francisco
I want to break this up without using Text to columns as previous rows are formatted differently and these last few rows are outliers that I want to handle.
I thought Regular Expressions might do it, but that seems a bit complex.
My algorithm idea is:
1. grab the wanted text (what function or custom sub would do that?)
2. Past the text to it's new location
3. Cut the text from the cell, leaving the remaining text.
Seems simple but I'm still wending my way through VBA forest, and at the rate I'm going it's going to end up faster doing it by hand. But this seems like a good opportunity to learn some VBA tricks.
TIA
Update:
I want to take the text up to the ".\ " and move it to a different column, keeping the remainder where it is.
VBA is unnecessary. To get the text after .\ in cell A1: =MID(A1,FIND(".\",A1,1)+2,LEN(A1)) to get the text before .\ in A1: =LEFT(A1,FIND(".\",A1,1)-1).
As additional information, Find returns the placement in the string where .\ appears. It is the equivalent of InStr in VBA. If .\ is not in the cell, it will display #VALUE, because I didn't bother to add error checking.
Since you seem to want to modify the cell text in place, VBA will be required.
Inside a loop that sets cl to the cell to be processed:
str = cl.value
i = Instr(str, ".\")
cl = Trim(Mid$(str, i + 2)) ' assuming you want to exclude the ".\"
cl.Offset(0, 1) Trim(Left$(str, i - 1)) ' Places the original first part one cell to the right
For the sake of anyone who had this same question, here is the fully tested, working code.
Function RE6(strData As String) As String
Dim RE As Object, REMatches As Object
Set RE = CreateObject("vbscript.regexp")
With RE
.MultiLine = False
.Global = False
.IgnoreCase = True
.Pattern = "[0-9][0-9][0-9][0-9]B"
RE6 = .test(strData)
End With
Set REMatches = RE.Execute(strData)
If REMatches.Count > 0 Then
RE6 = True
Else
RE6 = False
End If
End Function
Sub territory()
Dim strTest As String, str As String, cl As Range
strTest = ActiveCell.Value
Set cl = ActiveCell
If RE6(strTest) = True Then
str = cl.Value
i = InStr(str, ". ")
cl = Trim(Mid$(str, i + 2))
cl.Offset(0, 1) = Trim(Left(str, i - 1))
cl.Offset(0, 2) = "Instance"
MsgBox RE6(strTest)
End If
End Sub
Related
I am looking for a solution to validate and highlight my cell in case false.
I tried the most promising solution: Regex. But still can not find the pattern I need.
My latest attempt was this pattern: "[A-Z-0-9_.]" This works only if the cell contains only a symbol and nothing else, if the symbol is part of a string it does not work.
Problem is that it does not catch cells that have an odd character in a string of text: Example C4UNIT| or B$GROUP.
Specification Cell can contain only capital characters and two allowed symbols Dash - and Underbar _
This is my complete code:
Function ValidateCellContent()
Sheets("MTO DATA").Select
Dim RangeToCheck As Range
Dim CellinRangeToCheck As Range
Dim CollNumberFirst As Integer
Dim CollNumberLast As Integer
Dim RowNumberFirst As Integer
Dim RowNumberLast As Integer
'--Start on Column "1" and Row "3"
CollNumberFirst = 1
RowNumberFirst = 3
'--Find last Column used on row "2" (Write OMI Headings)
CollNumberLast = Cells(2, Columns.count).End(xlToLeft).Column
RowNumberLast = Cells(Rows.count, 1).End(xlUp).Row
'--Set value of the used range of cell addresses like: "A3:K85"
Set RangeToCheck = Range(Chr(64 + CollNumberFirst) & RowNumberFirst & ":" & Chr(64 + CollNumberLast) & RowNumberLast)
Debug.Print "Cells used in active Range = " & (Chr(64 + CollNumberFirst) & RowNumberFirst & ":" & Chr(64 + CollNumberLast) & RowNumberLast)
For Each CellinRangeToCheck In RangeToCheck
Debug.Print "CellinRangeToCheck value = " & CellinRangeToCheck
If Len(CellinRangeToCheck.Text) > 0 Then
'--Non Printables (Space,Line Feed,Carriage Return)
If InStr(CellinRangeToCheck, " ") _
Or InStr(CellinRangeToCheck, Chr(10)) > 0 _
Or InStr(CellinRangeToCheck, Chr(13)) > 0 Then
CellinRangeToCheck.Font.Color = vbRed
CellinRangeToCheck.Font.Bold = True
'--Allowed Characters
ElseIf Not CellinRangeToCheck.Text Like "*[A-Z-0-9_.]*" Then
CellinRangeToCheck.Font.Color = vbRed
CellinRangeToCheck.Font.Bold = True
Else
CellinRangeToCheck.Font.Color = vbBlack
CellinRangeToCheck.Font.Bold = False
End If
End If
Next CellinRangeToCheck
End Function
Try this:
Option Explicit
Private Sub Worksheet_Change(ByVal Target As Range)
'we want only validate when cell content changed, if whole range is involved (i.e. more than 1 cell) then exit sub
If Target.Cells.Count > 1 Then Exit Sub
'if there is error in a cell, also color it red
If IsError(Target) Then
Target.Interior.ColorIndex = 3
Exit Sub
End If
'validate cell with our function, if cell content is valid, it'll return True
'if it i s not valid, then color cell red
If Not ValidateText(Target.Value) Then
Target.Interior.ColorIndex = 3
End If
End Sub
Function ValidateText(ByVal txt As String) As Boolean
Dim i As Long, char As String
'loop through all characters in string
For i = 1 To Len(txt)
char = Mid(txt, i, 1)
If Not ((Asc(char) >= 65 And Asc(char) <= 90) Or char = "-" Or char = "_") Then
'once we come upon invalid character, we can finish the function with False result
ValidateText = False
Exit Function
End If
Next
ValidateText = True
End Function
I've originally assumed you wanted to use RegEx to solve your problem. As per your comment you instead seem to be using the Like operator.
Like operator
While Like accepts character ranges that may resemble regular expressions, there are many differences and few similarities between the two:
Like uses ! to negate a character range instead of the ^ used in RegEx.
Like does not allow/know quantifiers after the closing bracket ] and thus always matches a single character per pair of brackets []. To match multiple characters you need to add multiple copies of your character range brackets.
Like does not understand advanced concepts like capturing groups or lookahead / lookbehind
probably more differences...
The unavailability of quantifiers leaves Like in a really bad spot for your problem. You always need to have one character range to compare to for each character in your cell's text. As such the only way I can see to make use of the Like operator would be as follows:
Private Function IsTextValid(ByVal stringToValidate As String) As Boolean
Dim CharValidationPattern As String
CharValidationPattern = "[A-Z0-9._-]"
Dim StringValidationPattern As String
StringValidationPattern = RepeatString(CharValidationPattern, Len(stringToValidate))
IsTextValid = stringToValidate Like StringValidationPattern
End Function
Private Function RepeatString(ByVal stringToRepeat As String, ByVal repetitions As Long) As String
Dim Result As String
Dim i As Long
For i = 1 To repetitions
Result = Result & stringToRepeat
Next i
RepeatString = Result
End Function
You can then pass the text you want to check to IsTextValid like that:
If IsTextValid("A.ASDZ-054_93") Then Debug.Print "Hurray, it's valid!"
As per your comment, a small Worksheet_Change event to place into the worksheet module of your respective worksheet. (You will also need to place the above two functions there. Alternatively you can make them public and place them in a standard module.):
Private Sub Worksheet_Change(ByVal Target As Range)
Dim ValidationRange As Range
Set ValidationRange = Me.Range("A2:D5")
Dim TargetCell As Range
For Each TargetCell In Target.Cells
' Only work on cells falling into the ValidationRange
If Not Intersect(TargetCell, ValidationRange) Is Nothing Then
If IsTextValid(TargetCell.Text) Then
TargetCell.Font.Color = vbBlack
TargetCell.Font.Bold = False
Else
TargetCell.Font.Color = vbRed
TargetCell.Font.Bold = True
End If
End If
Next TargetCell
End Sub
Regular Expressions
If you want to continue down the RegEx road, try this expression:
[^A-Z0-9_-]+
It will generate a match, whenever a passed-in string contains one or more characters you don't want. All cells with only valid characters should not return a match.
Explanation:
A-Z will match all capital letters,
0-9 will match all numbers,
_- will match underscore and dash symbols.
The preceding ^ will negate the whole character set, meaning the RegEx only matches characters not in the set.
The following + tells the RegEx engine to match one or more characters of the aforementioned set. You only want to match your input, if there is at least one illegal char in there. And if there are more than one, it should still match.
Once in place, adapting the system to changing requirements (different chars considered legal) is as easy as switching out a few characters between the [brackets].
See a live example online.
I want to ask for a letter color in an If conditional:
string="asdfghjkl"
for i=1 to len(string)
letter = mid(string, i, 1)
input_letter = inputbox("Write a letter")
if letter = input_letter 'and letter.Font.Color = RGB(31,78,120)
'my code here
endif
next
The and letter.Font.Color = RGB(31,78,120) is not working. It says i need an object.
Is there any similar way to ask this? This RGB color is blue, and I am using this code to transform the entire sentence to blue (with the record macro excel setting)
With Selection.Font
.ThemeColor = xlThemeColorAccent1
.TintAndShade = -0.499984740745262
End With
Thanks
Regarding your question's problem:
The .Font.Color is a property of the class Range, but in your line of code:
if letter = input_letter 'and letter.Font.Color = RGB(31,78,120)
... you're trying to access this property in the variable letter, which is a String (you don't explicitly declare it as such, but it gets automatically declared when you execute letter = mid(string, i, 1) just above).
That is why you get an Object required exception: you're trying to access the property .Font.Color on something that is not a Range object (actually, not an Object at all).
Regarding your real need:
I'm not sure to understand what you're trying to do. Are you trying to reach a multi-colored text into a single cell in Excel? If I've got it right, you'll have a string:
string="asdfghjkl"
(please note: you can't call your variable String, that's a reserved keyword for the code. Think of calling it something else, though I guess you already do that in your real code or you wouldn't be able to execute it at all).
... and, for each letter of that string,
for i=1 to len(string)
... you want the user to give you a color. In that case, you can't do it in Excel. If not that, could you please express better your real need?
The code below comes closest to your OP logic and comment using the .Characters property of a cell Range (B11) containing your string value:
Code
Option Explicit
Sub test()
Dim blue As Long: blue = RGB(31, 78, 120)
Dim s As String: s = "asdfgh"
Dim letter As String
Dim input_letter As String
Dim i As Integer
Dim rng As Range
Set rng = ThisWorkbook.Worksheets("MySheet").Range("B11")
With rng
.Value = s
' color whole string
.Characters(1, Len(s)).Font.Color = blue
For i = 1 To Len(s)
letter = Mid(s, i, 1)
input_letter = InputBox("Write a letter")
If letter = input_letter And .Characters(i, 1).Font.Color = blue Then
'color found character
.Characters(i, 1).Font.Color = vbWhite
ElseIf input_letter = "" Then Exit For
End If
Next
End With
End Sub
Notes
Always use Option Explicitin your modules declaration head. So you would see that String isn't allowed as variable name as it's a function.
The extra color check in the If condition seems redundant, as characters so long a r e blue.
You seem to prefer repeated InputBoxes within the For - Next loop, could be reduced to a single call.
I'm currently busy with Excel tooling and learning a lot but i got a question. Currently i have a couple rows with data in the rows. In the rows there is a lot of data but i need a specific part of the row. Of course i can delete it all manually but to do that for 3000 rows i will be wasting a lot of time.
Can any one help me with a macro that filters data. The data i need is between [ and ] so for example [data]
I hope you guys can help me out and if you need more information just ask me! I hope you guys can help me!
Example String ROW:
[Sandwitch]><xsd:element name="T8436283"
So what do i need?
So i need a macro that only gets the Sandwitch out of it and paste it in the B column. The string with all the information stays at column A and the Sandwitch goes to Column B and that for all rows.
Option 1: Find/Replace
1) Copy data in another column (just saving original copy)
2) Perform Find/Replace "*["
3) Perform Find/Replace "]"
Now you have data which was between [].
Option 2: Use formulas
1) Lets assume that original data in Column "A"
2) Apply this formula in column "B" which will extract data between []
=MID(A1,FIND("[",A1)+1,FIND("]",A1)-FIND("[",A1)-1)
Option 3: Macro
If it is absolutely needed, I can help create a macro, otherwise try first two easier options.
A general purpose "find element in s starting x up to next y":
Function GenExtract(FromStr As String, _
StartSep As String, EndSep As String) _
As Variant
Dim StPos As Long
Dim EnPos As Long
GenExtract = CVErr(xlErrNA)
If StartSep = "" Or EndSep = "" Then Exit Function 'fail
StPos = InStr(1, FromStr, Left(StartSep, 1))
If StPos = 0 Or StPos = Len(FromStr) Then Exit Function 'fail
EnPos = InStr(StPos + 1, FromStr, Left(EndSep, 1))
If EnPos = 0 Then Exit Function 'fail
GenExtract = Mid(FromStr, StPos + 1, EnPos - StPos - 1)
End Function
If the two separators are the same, as per quotes, it gives the first string enclosed by those.
If you want to get your feet wet in Regular Expressions, the following code will take you there. You have to add a reference to the VB Scripting Library
Tools > References > Microsoft VBScript Regular Expressions 5.5
Then the code is as follows:
Sub textBetweenStuffs()
Dim str As String
Dim regEx As RegExp
Dim m As Match
Dim sHolder As MatchCollection
Dim bracketCollection As Collection
Dim quoteCollection As Collection
Set regEx = New RegExp
'Matches anything in between an opening bracket and first closing bracket
regEx.Pattern = "\[(.*?\])"
str = "[Sandwitch]><xsd:element name=""T8436283"""
'populates matches into match collection
Set sHolder = regEx.Execute(str)
Set bracketCollection = New Collection
'loop through values in match collection to do with as you wish
For Each m In sHolder
bracketCollection.Add m.Value
Next i
Set sHolder = Nothing
'get values between Quotations
regEx.Pattern = "\"(.*?\")"
'populates matches into match collection
Set sHolder = regEx.Execute(str)
Set quoteCollection = New Collection
'loop through values in match collection to do with as you wish
For Each m In sHolder
quoteCollection.Add m.Value
Next i
End Sub
I've got a column which contains rows that have parameters in them. For example
W2 = [PROD][FO][2.0][Customer]
W3 = [PROD][GD][1.0][P3]
W4 = Issues in production for customer
I have a function that is copying other columns into another sheet, however for this column, I need to do the following
Search the cell and look for [P*]
The asterisk represents a number between 1 and 5
If it finds [P*] then copy P* to the sheet "Calculations" in column 4
Basically, remove everything from the cell except where there is a square bracket, followed by P, a number and a square bracket
Does anyone know how I can do this? Alternatively, it might be easier to copy the column across and then remove everything that doesn't meet the above criteria.
Second Edit:
I edited here to use a regular expression instead of a loop. This may be the most efficient method to achieve your goal. See below and let us know if it works for you:
Function MatchWithRegex(sInput As String) As String
Dim oReg As Object
Dim sOutput As String
Set oReg = CreateObject("VBScript.RegExp")
With oReg
.Pattern = "[[](P[1-5])[]]"
End With
If oReg.test(sInput) Then
sOutput = oReg.Execute(sInput)(0).Submatches(0)
Else
sOutput = ""
End If
MatchWithRegex = sOutput
End Function
Sub test2()
Dim a As String
a = MatchWithRegex(Range("A1").Value)
If a = vbNullString Then
MsgBox "None"
Else
MsgBox MatchWithRegex(Range("A1").Value)
End If
End Sub
First EDIT:
My solution would be something as follows. I'd write a function that first tests if the Pattern exists in the string, then if it does, I'd split it based on brackets, and choose the bracket that matches the pattern. Let me know if that works for you.
Function ExtractPNumber(sInput As String) As String
Dim aValues
Dim sOutput As String
sOutput = ""
If sInput Like "*[[]P[1-5][]]*" Then
aValues = Split(sInput, "[")
For Each aVal In aValues
If aVal Like "P[1-5][]]*" Then
sOutput = aVal
End If
Next aVal
End If
ExtractPNumber = Left(sOutput, 2)
End Function
Sub TestFunction()
Dim sPValue As String
sPValue = ExtractPNumber(Range("A2").Value)
If sPValue = vbNullString Then
'Do nothing or input whatever business logic you want
Else
Sheet2.Range("A1").Value = sPValue
End If
End Sub
OLD POST:
In VBA, you can use the Like Operator with a Pattern to represent an Open Bracket, the letter P, any number from 1-5, then a Closed Bracket using the below syntax:
Range("A1").Value LIke "*[[]P[1-5][]]*"
EDIT: Fixed faulty solution
If you're ok with blanks and don't care if *>5, I would do this and copy down column 4:
=IF(ISNUMBER(SEARCH("[P?]",FirstSheet!$W2)), FirstSheet!$W2, "")
Important things to note:
? is the wildcard symbol for a single character; you can use * if you're ok with multiple characters at that location
will display cell's original value if found, leave blank otherwise
Afterwards, you can highlight the column and remove blanks if needed. Alternatively, you can replace the blank with a placeholder string.
If * must be 1-5, use two columns, E and D, respectively:
=MID(FirstSheet!$W2,SEARCH("[P",FirstSheet!$W2)+2,1)
=IF(AND(ISNUMBER($E2),$E2>0,$E2<=5,MID($W2,SEARCH("[P",FirstSheet!$W2)+3,1))), FirstSheet!$W2, "")
where FirstSheet is the name of your initial sheet.
Let's assume that we have one module with only one Sub in it, and there are no comments. How to identify all variable names ? Is it possible to identify names of variables which are not defined using Dim ? I would like to identify them and replace each with some random name to obfuscate my code (O0011011010100101 for example), replace part is much easier.
List of characters which could be use in names of macros, functions and variables :
ABCDEFGHIJKLMNOPQRSTUVWXYZdefghijklmnopqrstuvwxyzg€‚„…†‡‰Š‹ŚŤŽŹ‘’“”•–—™š›śťžź ˇ˘Ł¤Ą¦§¨©Ş«¬®Ż°±˛ł´µ¶·¸ąş»Ľ˝ľżŔÁÂĂÄĹĆÇČÉĘËĚÍÎĎĐŃŇÓÔŐÖ×ŘŮÚŰÜÝŢßŕáâăäĺćçčéęëěíîďđńňóôőö÷řůúűüýţ˙ÉĘËĚÍÎĎĐŃŇÓÔŐÖ×ŘŮÚŰÜÝŢßŕáâăäĺćçčéęëěíîďđńňóôőö÷řůúűüýţ˙
Below are my function I've wrote recenlty :
Function randomName(n as integer) as string
y="O"
For i = 2 To n:
If Rnd() > 0.5 Then
y = y & "0"
Else
y = y & "1"
End If
Next i
randomName=y
End Function
In goal to replace given strings in another string which represent the code of module I use below sub :
Sub substituteNames()
'count lines in "Module1" which is part of current workbook
linesCount = ActiveWorkbook.VBProject.VBComponents("Module1").CodeModule.CountOfLines
'read code from module
code = ActiveWorkbook.VBProject.VBComponents("Module1").CodeModule.Lines(StartLine:=1, Count:=linesCount)
inputStr = Array("name1", "name2", "name2") 'some hardwritten array with string to replace
namesLength = 20 'length of new variables names
For i = LBound(inputStr) To UBound(inputStr)
outputString = randomName(namesLength-1)
code = Replace(code, inputStr(i), outputString)
Next i
Debug.Print code 'view code
End Sub
then we simply substitute old code with new one, but how to identify strings with names of variables ?
Edition
Using **Option Explicit ** decrease safety of my simple method of obfuscation, because to reverse changes you only have to follow Dim statements and replace ugly names with something normal. Except that to make such substitution harder, I think it's good idea to break the line in the middle of variable name :
O0O000O0OO0O0000 _
0O00000O0OO0
the simple method is also replacing some strings with chains based on chr functions chr(104)&chr(101)&chr(108)&chr(108)&chr(111) :
Sub stringIntoChrChain()
strInput = "hello"
strOutput = ""
For i = 1 To Len(strInput)
strOutput = strOutput & "chr(" & Asc(Mid(strInput, i, 1)) & ")&"
Next i
Debug.Print Mid(strOutput, 1, Len(strOutput) - 1)
End Sub
comments like below could make impression on user and make him think that he does not poses right tool to deal with macro etc.:
'(k=Äó¬)w}ż^¦ů‡ÜOyúm=ěËnóÚŽb W™ÄQó’ (—*-ĹTIäb
'R“ąNPÔKZMţ†üÍQ‡
'y6ű˛Š˛ŁŽ¬=iýQ|˛^˙ ‡ńb ¬ĂÇr'ń‡e˘źäžŇ/âéç;1qýěĂj$&E!V?¶ßšÍ´cĆ$Âű׺Ůî’ﲦŔ?TáÄu[nG¦•¸î»éüĽ˙xVPĚ.|
'ÖĚ/łó®Üă9Ę]ż/ĹÍT¶Mµę¶mÍ
'q[—qëýY~Pc©=jÍ8˘‡,Ú+ń8ŐűŻEüńWü1ďëDZ†ć}ęńwŠbŢ,>ó’Űçµ™Š_…qÝăt±+‡ĽČgřÍ!·eŠP âńđ:ŶOážű?őë®ÁšńýĎáËTbž}|Ö…ăË[®™
You can use a regular expression to find variable assignments by looking for the equals sign. You'll need to add a reference to the Microsoft VBScript Regular Expressions 5.5 and Microsoft Visual Basic for Applications Extensibility 5.3 libraries as I've used early binding.
Please be sure to back up your work and test this before using it. I could have gotten the regex wrong.
UPDATE:
I've refined the regular expressions so that it no longer catches datatypes of strongly typed constants (Const ImAConstant As String = "Oh Noes!" previously returned String). I've also added another regex to return those constants as well. The last version of the regex also mistakenly caught things like .Global = true. That was corrected. The code below should return all variable and constant names for a given code module. The regular expressions still aren't perfect, as you'll note that I was unable to stop false positives on double quotes. Also, my array handling could be done better.
Sub printVars()
Dim linesCount As Long
Dim code As String
Dim vbPrj As VBIDE.VBProject
Dim codeMod As VBIDE.CodeModule
Dim regex As VBScript_RegExp_55.RegExp
Dim m As VBScript_RegExp_55.match
Dim matches As VBScript_RegExp_55.MatchCollection
Dim i As Long
Dim j As Long
Dim isInDatatypes As Boolean
Dim isInVariables As Boolean
Dim datatypes() As String
Dim variables() As String
Set vbPrj = VBE.ActiveVBProject
Set codeMod = vbPrj.VBComponents("Module1").CodeModule
code = codeMod.Lines(1, codeMod.CountOfLines)
Set regex = New RegExp
With regex
.Global = True ' match all instances
.IgnoreCase = True
.MultiLine = True ' "code" var contains multiple lines
.Pattern = "(\sAs\s)([\w]*)(?=\s)" ' get list of datatypes we've used
' match any whole word after the word " As "
Set matches = .Execute(code)
End With
ReDim datatypes(matches.count - 1)
For i = 0 To matches.count - 1
datatypes(i) = matches(i).SubMatches(1) ' return second submatch so we don't get the word " As " in our array
Next i
With regex
.Pattern = "(\s)([^\.\s][\w]*)(?=\s\=)" ' list of variables
' begins with a space; next character is not a period (handles "with" assignments) or space; any alphanumeric character; repeat until... space
Set matches = .Execute(code)
End With
ReDim variables(matches.count - 1)
For i = 0 To matches.count - 1
isInDatatypes = False
isInVariables = False
' check to see if current match is a datatype
For j = LBound(datatypes) To UBound(datatypes)
If matches(i).SubMatches(1) = datatypes(j) Then
isInDatatypes = True
Exit For
End If
'Debug.Print matches(i).SubMatches(1)
Next j
' check to see if we already have this variable
For j = LBound(variables) To i
If matches(i).SubMatches(1) = variables(j) Then
isInVariables = True
Exit For
End If
Next j
' add to variables array
If Not isInDatatypes And Not isInVariables Then
variables(i) = matches(i).SubMatches(1)
End If
Next i
With regex
.Pattern = "(\sConst\s)(.*)(?=\sAs\s)" 'strongly typed constants
' match anything between the words " Const " and " As "
Set matches = .Execute(code)
End With
For i = 0 To matches.count - 1
'add one slot to end of array
j = UBound(variables) + 1
ReDim Preserve variables(j)
variables(j) = matches(i).SubMatches(1) ' again, return the second submatch
Next i
' print variables to immediate window
For i = LBound(variables) To UBound(variables)
If variables(i) <> "" And variables(i) <> Chr(34) Then ' for the life of me I just can't get the regex to not match doublequotes
Debug.Print variables(i)
End If
Next i
End Sub