I have a vector which points from my camera to an object I want to point to, so I want to make a quaternion which rotates the camera so that it points to that vector. So i do this (using glm)
glm::quat rotation=glm::angleAxis(0.0f,vector);
If i understand that function correctly in the case of a vector of, for example, (0.0f,0.0f,-1.0f), the camera should point forward in the depth axis, and with no roll. But i don't know why, in that case it creates this quaternion:
x:-0
y:-0
z:-0
w:1
wich does nothing, and the x,y,z values only differ from 0 if the angle parameter passed to angleAxis() is different from 0. Why does this happen? if i pass angle 0, shouldn't it simply create a rotation with only yaw and pitch, and no roll?
Already go the answer: (on the gameDev forum, from the user clb)
No, your understanding is off. Angle-axis rotation generates rotation about the given axis, by the given angle. If you don't specify an angle, you'll always get identity back. This is because rotation a zero angle, be it about any axis, of course does not rotate at all.
What you are thinking about is the LookAt rotation. I am not sure what the function signature in glm is, but I'm sure they have a similar function. Use a LookAt rotation to orient one direction vector to face towards another vector.
Related
Using a homography matrix, I am able to find a mapping from one image to another. From this matrix I can also compute a relative rotation matrix between the two images. How can I then compute an absolute rotation matrix? And what are the differences between these two matrices?
General points:
A general homography between images does not imply a camera motion that is a pure rotation.
However, camera motion that is a pure rotation, or one whose translation is very small compared to the distance from the camera and the scene, is well modeled by a homography.
Specifically to your question:
A "relative" rotation is just that, a motion from the orientation of the first camera to the one of the second camera.
An "absolute" rotation, or orientation, describes a motion with respect to a specified "reference" coordinate frame that is constant and independent of the camera motion.
As a special case, if you have only two camera poses, and you use the first one as the reference, then the relative pose of the second one is also its absolute pose.
below you can see the result of the optical flow if a camera makes a translation movement. If the camera makes a roll rotation the result looks like the second picture. Is it possible to retrieve the yaw angle from a camera if its only rotation around the yaw axis?
I think in the optical flow you can recognize if the camera is rotating around the yaw axis (z-axis), but i don't know how to retrieve the information how much the cam has rotated.
I would be gradeful for any hints. Thanks
Translation:
Roll rotation:
Orientation of camera:
If you have a pure rotation of your cam then you can use findhomography. You need four point correspondence in your pictures. For a pure rotation the homography matrix is already a rotation matrix. Otherwise you need to decompose the homograohy matrix. For a camera movement off 6 dof you can use the function find essential matrix and decompose this to translation and rotation.
Here's the task:
We have an Mesh, drawn in position POS with rotation ROT
Also we have a camera Which position and rotation is relative to Mesh For example camera point is CPOS and camera rotation is CROT.
How to calculate resulting angle for camera? I was assuming that it something like:
camera.rotation.x = mesh.rotation.x + viewport.rotation.x
camera.rotation.y = mesh.rotation.y + viewport.rotation.y
camera.rotation.z = mesh.rotation.z + viewport.rotation.z
That worked strange and wrong.
Then I decided to read about it on docs and completely dissapointed.
There are several kind of rotation structures (Euler, Quaternion). But What a want is something different.
Imagine, like you are on spaceship. And it moves in space. You are sitting at starboard turret and looking at objects. They seems like passing by...
Then you want to turn your head - Angel of your head is known to you (in raw opengl, I'd just multiplied head rotation matrix on ship's rotation matrix and got my projection matrix).
In other words I want only x and y axis for camera rotations, combined in matrix. Then I want to multiply it with position-rotation matrix of an object. And this final matrix would be my projection matrix.
How could I do the same in THREE.js?
-----EDIT-----
Thank you for the answer.
Which coords should I give to a camera? It should be local, mesh relative coords, or something absolute?
I understand, that this questions are obvious, but there's no any description about relative objects in THREE.JS docs (besides api description). And the answer might be ambiguous.
Add the camera as a child of the mesh like so:
mesh.add( camera );
When the camera is a child of an object, the camera's position and orientation are specified relative to the parent object.
You can set the camera's orientation by setting either the camera's quaternion or Euler rotation -- your choice.
Please note that the renderer updates the object's matrix and matrixWorld for you. You do not need to do that manually.
three.js r.63
I've found this beautiful quick way to remove gravity from accelerometer readings. However, I have a 6dof IMU (xyz gyro, xyz accel, no magnetometer) so I am not sure if I can use this code (I tried and it doesn't work correctly).
How would someone remove the gravity component? It's a big obstacle because I can't proceed with my project.
EDIT:
What I have:
quaternion depicting the position of aircraft (got that using Extended Kalman Filter)
acceleration sensor readings (unfiltered; axes aligned as the plane is aligned; gravity is also incorporated in these readings)
What I want:
remove the gravity
correct (rotate) the accelerometer readings so it's axes will be aligned with earth's frame of reference's axes
read the acceleration towards earth (now Z component of accelerometer)
Basically I want to read the acceleration towards earth no matter how the plane is oriented! But first step is to remove gravity I guess.
UPDATE: OK, so what you need is to rotate a vector with quaternion. See here or here.
You rotate the measured acceleration vector with the quaternion (corresponding to the orientation) then you substract gravity [0, 0, 9.81] (you may have -9.81 depending on your sign conventions) from the result. That's all.
I have implemented sensor fusion for Shimmer 2 devices based on this manuscript, I highly recommend it. It only uses accelerometers and gyroscopes but no magnetometer, and does exactly what you are looking for.
The resource you link to in your question is misleading. It relies on the quaternion that comes from sensor fusion. In other words, somebody already did the heavy lifting for you, already prepared the gravity compensation for you.
I'm using a 3d engine and need to translate between 3d world space and 2d screen space using perspective projection, so I can place 2d text labels on items in 3d space.
I've seen a few posts of various answers to this problem but they seem to use components I don't have.
I have a Camera object, and can only set it's current position and lookat position, it cannot roll. The camera is moving along a path and certain target object may appear in it's view then disappear.
I have only the following values
lookat position
position
vertical FOV
Z far
Z near
and obviously the position of the target object.
Can anyone please give me an algorithm that will do this using just these components?
Many thanks.
all graphics engines use matrices to transform between different coordinats systems. Indeed OpenGL and DirectX uses them, because they are the standard way.
Cameras usually construct the matrices using the parameters you have:
view matrix (transform the world to position in a way you look at it from the camera position), it uses lookat position and camera position (also the up vector which usually is 0,1,0)
projection matrix (transforms from 3D coordinates to 2D Coordinates), it uses the fov, near, far and aspect.
You could find information of how to construct the matrices in internet searching for the opengl functions that create them:
gluLookat creates a viewmatrix
gluPerspective: creates the projection matrix
But I cant imagine an engine that doesnt allow you to get these matrices, because I can ensure you they are somewhere, the engine is using it.
Once you have those matrices, you multiply them, to get the viewprojeciton matrix. This matrix transform from World coordinates to Screen Coordinates. So just multiply the matrix with the position you want to know (in vector 4 format, being the 4ยบ component 1.0).
But wait, the result will be in homogeneous coordinates, you need to divide X,Y,Z of the resulting vector by W, and then you have the position in Normalized screen coordinates (0 means the center, 1 means right, -1 means left, etc).
From here it is easy to transform multiplying by width and height.
I have some slides explaining all this here: https://docs.google.com/presentation/d/13crrSCPonJcxAjGaS5HJOat3MpE0lmEtqxeVr4tVLDs/present?slide=id.i0
Good luck :)
P.S: when you work with 3D it is really important to understand the three matrices (model, view and projection), otherwise you will stumble every time.
so I can place 2d text labels on items
in 3d space
Have you looked up "billboard" techniques? Sometimes just knowing the right term to search under is all you need. This refers to polygons (typically rectangles) that always face the camera, regardless of camera position or orientation.