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enter image description hereI want to know the start bi-week date and end bi-week date.
means i want to get bi-weekly data from the below table structure.
create table #temp(
EmployeeID int,
TEDate datetime,
EmpFNamenvarchar(100),
EmpLName nvarchar(100)
)
go
insert into #temp (EmployeeID ,EmpFName,EmpLName,TEDate)
Select 2019,'roz','Ahmad','2019-04-23'
union all
Select 2019,'roz','Ahmad','2019-04-17'
union all
Select 2019,'roz','Ahmad','2019-04-29'
select * from #temp
How to do it? I have used below approach but still getting wrong results at the end.
Select *,
DATEADD(WEEK, DATEPART(wk, TEDate),
DATEADD(YEAR, year(TEDate) - 1900, 0)) - 4 - DATEPART(DW, DATEADD(WEEK, DATEPART(wk, TEDate),
DATEADD(YEAR, year(TEDate) - 1900, 0)) - 4) + 1 AS [BiWEEK_START],
DATEADD(WEEK, DATEPART(wk, TEDate),
DATEADD(YEAR, year(TEDate) - 1900, 0)) - 4 - DATEPART(DW, DATEADD(WEEK, DATEPART(wk, TEDate),
DATEADD(YEAR, year(TEDate) - 1900, 0)) - 4) + 14 AS [BiWEEK_END]
from #temp
Desired results:
4/17/2019
4/14/2019
4/27/2019
4/22/2019
4/14/2019
4/27/2019
4/23/2019
4/14/2019
4/27/2019
4/29/2019
4/28/2019
5/11/2019
5/3/2019
4/28/2019
5/11/2019
5/6/2019
4/28/2019
5/11/2019
5/8/2019
4/28/2019
5/11/2019
5/13/2019
5/12/2019
5/25/2019
Ok, here are two solutions. The problem is, you have to be able to tell which bi week a TEDate belongs to just by looking at the TEDate, otherwise you have to define either a list of the bi weeks or tell your query where to start. For the second query you should be able to put in any bi week start date and it should still work.
DECLARE #bi_weeks TABLE
(
StartDate DATE,
EndDate DATE
);
INSERT INTO #bi_weeks VALUES
('20190317','20190330'),
('20190331','20190413'),
('20190414','20190427'),
('20190428','20190511'),
('20190512','20190525');
DECLARE #emp_data TABLE
(
EmployeeID INT,
TEDate DATETIME,
EmpFName NVARCHAR(100),
EmpLName NVARCHAR(100)
);
INSERT INTO #emp_data (EmployeeID ,EmpFName,EmpLName,TEDate) VALUES
(2019,'roz','Ahmad','2019-03-20'),
(2019,'roz','Ahmad','2019-04-01'),
(2019,'roz','Ahmad','2019-04-13'),
(2019,'roz','Ahmad','2019-04-23'),
(2019,'roz','Ahmad','2019-04-17'),
(2019,'roz','Ahmad','2019-04-29');
--This is the first way where we join to a list of known bi week start and end dates
SELECT ed.*, bw.*
FROM #emp_data ed
LEFT JOIN #bi_weeks bw ON ed.TEDate BETWEEN bw.StartDate AND bw.EndDate
ORDER BY 2
--This is the second way where we tell our query a known start date and then use it to
--calculate the rest of the start and end dates.
DECLARE #initial_bi_week_start_date DATE = '20190414';
With empdataCTE AS
(
SELECT *,
[initial_bi_week_start_date] = #initial_bi_week_start_date ,
[bi_week_start] =
DATEADD(DAY,
(DATEDIFF(DAY, #initial_bi_week_start_date, TEDate) / 14 +
IIF(TEDate < #initial_bi_week_start_date, 1, 0) * -1) * 14,
#initial_bi_week_start_date)
FROM #emp_data ed
)
SELECT *, DATEADD(DAY, 13, [bi_week_start]) [bi_week_end]
FROM empdataCTE;
I'm looking to populate a table with dates, based upon values contained within another.
Source : tblA
dtFrom dtTo
2019-01-01 2019-01-03
2019-02-01 2019-02-02
2019-03-01 2019-03-01
Destination : tblB
sDate
2019-01-01
2019-01-02
2019-01-03
2019-02-01
2019-02-02
2019-03-01
SQL Server 2014. As always, thanks in advance :-)
You can use a recursive CTE:
with dates as (
select dtfrom as dt, dtto
from tblA
union all
select dateadd(day, 1, dt), dtto
from dates
where dt < dtto
)
insert tblB (sDate)
select distinct dt
from dates;
The select distinct is only necessary to handle overlapping periods. If you know there are no overlaps, then don't use it.
You can use union to combine values from both columns into one rowset:
insert tblB
(sDate)
select distinct dt
from (
select dtFrom as dt
from tblA
union all
select dtTo
from tblA
) s
Use the always handy Calendar Table, which is a table that holds 1 row for each day, for all days between specific years. You can add additional columns like IsBusinessDay or WorkingStartHour / WorkingEndHour to make your date queries much easier.
-- Create Calendar Table
DECLARE #StartDate DATE = '2000-01-01'
DECLARE #EndDate DATE = '2050-01-01'
SET DATEFIRST 1 -- 1: Monday, 7: Sunday
CREATE TABLE CalendarTable (
Date DATE PRIMARY KEY,
IsWorkingDay BIT
-- Other columns you might need
)
;WITH RecursiveCTE AS
(
SELECT
Date = #StartDate
UNION ALL
SELECT
Date = DATEADD(DAY, 1, R.Date)
FROM
RecursiveCTE AS R
WHERE
DATEADD(DAY, 1, R.Date) <= #EndDate
)
INSERT INTO CalendarTable (
Date,
IsWorkingDay)
SELECT
Date = R.Date,
IsWorkingDay = CASE WHEN DATEPART(WEEKDAY, R.Date) BETWEEN 1 AND 5 THEN 1 ELSE 0 END
FROM
RecursiveCTE AS R
OPTION
(MAXRECURSION 0)
Now with your calendar table, just join with a BETWEEN and INSERT to your destination table. You can use DISTINCT to make sure dates don't repeat:
INSERT INTO tblB (
sDate)
SELECT DISTINCT
sDate = C.Date
FROM
tlbA AS A
INNER JOIN CalendarTable AS C ON C.Date BETWEEN A.dtFrom AND A.dtTo
Let's say for example that you only want to insert records that are working days (monday to friday). You just need to filter the calendar table and done. You can add whichever logic you want on your table and just filter it when using, without repeating complex datetime logics.
INSERT INTO tblB (
sDate)
SELECT DISTINCT
sDate = C.Date
FROM
tlbA AS A
INNER JOIN CalendarTable AS C ON C.Date BETWEEN A.dtFrom AND A.dtTo
WHERE
C.IsWorkingDay = 1
With a Calendar you can inner join on the ranges to produce an Insert statement.
DECLARE #StartDate DATETIME = (SELECT MIN(dtFrom) FROM tblA)
DECLARE #EndDate DATETIME = (SELECT MAX(dtTo) FROM tblB)
;WITH Calendar as
(
SELECT CalendarDate = #StartDate, CalendarYear = DATEPART(YEAR, #StartDate), CalendarMonth = DATEPART(MONTH, #StartDate)
UNION ALL
SELECT CalendarDate = DATEADD(MONTH, 1, CalendarDate), CalendarYear = DATEPART(YEAR, CalendarDate), CalendarMonth = DATEPART(MONTH, CalendarDate)
FROM Calendar WHERE DATEADD (MONTH, 1, CalendarDate) <= #EndDate
)
INSERT INTO tblB
SELECT DISTINCT
C.CalendarDate
FROM
Calendar C
INNER JOIN tblA A ON C.CalendarDate BETWEEN A.dtFrom AND A.dtTo
You can achieve this result by using the below queries.
Steps 1 - Create a Custom Function which will take date range as a parameter and will return date series.
CREATE FUNCTION [dbo].[GenerateDateRange]
(#StartDate AS DATE,
#EndDate AS DATE,
#Interval AS INT
)
RETURNS #Dates TABLE(DateValue DATE)
AS
BEGIN
DECLARE #CUR_DATE DATE
SET #CUR_DATE = #StartDate
WHILE #CUR_DATE <= #EndDate BEGIN
INSERT INTO #Dates VALUES(#CUR_DATE)
SET #CUR_DATE = DATEADD(DAY, #Interval, #CUR_DATE)
END
RETURN;
END;
Step 2 - Join this custom function with your table tblA and insert the record in tblb as needed
insert tblb
select b.* from tblA a cross apply dbo.GenerateDateRange(a.dtFrom, a.dtTo, 1) b
I want to know how to list all months in specific period of time which doesn't have any order. If you can help me.
I have Order Table has OrderDate column
I just make this:
select distinct month(Order.OrderDate) from Order where year(Order.OrderDate) = 1997
the result will show me the months that have order in specific year only
what should i do to complete this query
You need to retrieve the months in which no orders are placed for that we can use below query
;WITH months(MonthNumber) AS
(
SELECT 1
UNION ALL
SELECT MonthNumber+1
FROM months
WHERE MonthNumber < 12
)
SELECT DATENAME( month , DATEADD( month ,MonthNumber , 0 ) )
FROM months
EXCEPT
SELECT DISTINCT month([Order].OrderDate)
FROM [Order]
WHERE YEAR([Order].OrderDate) = 1997
You can try using left join like below
DEMO
select * from
(
VALUES (1),(2),(3),(4),(5),(6),(7),(8),(9),(10),(11),(12)
) AS M(val)
left join t1 on month(OrderDate)=val
and year(orderdate)=1997
where month(OrderDate) is null
The problem here is that if we we have a date range, then we may go beyond single year, for example 01-Jul-2017 to 30-Jun-2018 has 2 years, therefore creating a month range may NOT work in this scenario. The possible solution is to have a list of all the months in range along with the year, so that when we search an order, we'll search by the month and year both.
-- this is test order table, just to test the output
declare #order table(OrderDate date);
insert into #order(OrderDate) values('2018-01-01')
declare #dateRange table(d datetime not null primary key);
-- date range input parameter
declare #startDate date = '2017-06-01';
declare #endDate date = '2018-06-30';
-- modifying date range so that we go from start
-- of the month to the end of the month in the range
set #startDate = cast(year(#startDate) as varchar(100)) + '-' + cast(month(#startDate) as varchar(100)) + '-1';
set #endDate = dateadd(day, -1, dateadd(month, 1, cast(year(#endDate) as varchar(100)) + '-' + cast(month(#endDate) as varchar(100)) + '-1'));
-- creating dates for every month
declare #d date = #startDate;
while(#d <= #endDate)
begin
insert into #dateRange(d) values(#d);
set #d = dateadd(month, 1, #d);
end
-- selecting all the months in the range where
-- order does not exists
select cast(year(t.d) as varchar(100)) + '-' + DATENAME(month, t.d) as [Month]
from #dateRange as t
where not exists(
select 1
from #order as x
where month(x.OrderDate) = month(t.d) and year(x.OrderDate) = year(t.d)
)
order by t.d
Output: (notice that 2018-January is missing from result because it has an order)
Month
------------------
2017-June
2017-July
2017-August
2017-September
2017-October
2017-November
2017-December
2018-February
2018-March
2018-April
2018-May
2018-June
You are looking for a LEFT JOIN
CREATE TABLE Orders
(
OrderDate DATE
);
INSERT INTO Orders VALUES
('2018-01-01'),
('2018-03-01'),
('2018-05-15');
DECLARE #MND DATE = (SELECT MIN(OrderDate) FROM Orders);
DECLARE #MXD DATE = (SELECT MAX(OrderDate) FROM Orders);
WITH CTE AS
(
SELECT #MND OrderDate
UNION ALL
SELECT DATEADD(Month, 1, CTE.OrderDate)
FROM CTE
WHERE CTE.OrderDate <= DATEADD(Month, -1, #MXD)
)
SELECT MONTH(CTE.OrderDate) [Months]
FROM CTE LEFT JOIN Orders O ON MONTH(CTE.OrderDate) = MONTH(O.OrderDate)
AND
YEAR(CTE.OrderDate) = YEAR(O.OrderDate)
WHERE O.OrderDate IS NULL;
-- Add extra conditions here to filter the period needed
Returns:
+--------+
| Months |
+--------+
| 2 |
| 4 |
+--------+
Demo
I have a table which contains following columns
userid,
game,
gameStarttime datetime,
gameEndtime datetime,
startdate datetime,
currentdate datetime
I can retrieve all the playing times but I want to count the total playing time per DAY and 0 or null if game not played on a specific day.
Take a look at DATEDIFF to do the time calculations. Your requirements are not very clear, but it should work for whatever you're looking to do.
Your end result would probably look something like this:
SELECT
userid,
game,
DATEDIFF(SS, gameStarttime, gameEndtime) AS [TotalSeconds]
FROM [source]
GROUP BY
userid,
game
In the example query above, the SS counts the seconds between the 2 dates (assuming both are not null). If you need just minutes, then MI will provide the total minutes. However, I imagine total seconds is best so that you can convert to whatever unit of measure you need accurate, such as hours that might be "1.23" or something like that.
Again, most of this is speculation based on assumptions and what you seem to be looking for. Hope that helps.
MSDN Docs for DATEDIFF: https://msdn.microsoft.com/en-us/library/ms189794.aspx
You may also look up DATEPART if you want the minutes and seconds separately.
UPDATED BASED ON FEEDBACK
The query below breaks out the hour breakdowns by day, splits time across multiple days, and shows "0" for days where no games are played. Also, for your output, I have to assume you have a separate table of users (so you can show users who have no time in your date range).
-- Define start date
DECLARE #BeginDate DATE = '4/21/2015'
-- Create sample data
DECLARE #Usage TABLE (
userid int,
game nvarchar(50),
gameStartTime datetime,
gameEndTime datetime
)
DECLARE #Users TABLE (
userid int
)
INSERT #Users VALUES (1)
INSERT #Usage VALUES
(1, 'sample', '4/25/2015 10pm', '4/26/2015 2:30am'),
(1, 'sample', '4/22/2015 4pm', '4/22/2015 4:30pm')
-- Generate list of days in range
DECLARE #DayCount INT = DATEDIFF(DD, #BeginDate, GETDATE()) + 1
;WITH CTE AS (
SELECT TOP (225) [object_id] FROM sys.all_objects
), [Days] AS (
SELECT TOP (#DayCount)
DATEADD(DD, ROW_NUMBER() OVER (ORDER BY x.[object_id]) - 1, #BeginDate) AS [Day]
FROM CTE x
CROSS JOIN CTE y
ORDER BY
[Day]
)
SELECT
[Days].[Day],
Users.userid,
SUM(COALESCE(CONVERT(MONEY, DATEDIFF(SS, CASE WHEN CONVERT(DATE, Usage.gameStartTime) < [Day] THEN [Day] ELSE Usage.gameStartTime END,
CASE WHEN CONVERT(DATE, Usage.gameEndTime) > [Day] THEN DATEADD(DD, 1, [Days].[Day]) ELSE Usage.gameEndTime END)) / 3600, 0)) AS [Hours]
FROM [Days]
CROSS JOIN #Users Users
LEFT OUTER JOIN #Usage Usage
ON Usage.userid = Users.userid
AND [Days].[Day] BETWEEN CONVERT(DATE, Usage.gameStartTime) AND CONVERT(DATE, Usage.gameEndTime)
GROUP BY
[Days].[Day],
Users.userid
The query above yields the output below for the sample data:
Day userid Hours
---------- ----------- ---------------------
2015-04-21 1 0.00
2015-04-22 1 0.50
2015-04-23 1 0.00
2015-04-24 1 0.00
2015-04-25 1 2.00
2015-04-26 1 2.50
2015-04-27 1 0.00
I've edited my sql on sql fiddle and I think this might get you what you asked for. to me it looks a little more simple then the answer you've accepted.
DECLARE #FromDate datetime, #ToDate datetime
SELECT #Fromdate = MIN(StartDate), #ToDate = MAX(currentDate)
FROM Games
-- This recursive CTE will get you all dates
-- between the first StartDate and the last CurrentDate on your table
;WITH AllDates AS(
SELECT #Fromdate As TheDate
UNION ALL
SELECT TheDate + 1
FROM AllDates
WHERE TheDate + 1 <= #ToDate
)
SELECT UserId,
TheDate,
COALESCE(
SUM(
-- When the game starts and ends in the same date
CASE WHEN DATEDIFF(DAY, GameStartTime, GameEndTime) = 0 THEN
DATEDIFF(HOUR, GameStartTime, GameEndTime)
ELSE
-- when the game starts in the current date
CASE WHEN DATEDIFF(DAY, GameStartTime, TheDate) = 0 THEN
DATEDIFF(HOUR, GameStartTime, DATEADD(Day, 1, TheDate))
ELSE -- meaning the game ends in the current date
DATEDIFF(HOUR, TheDate, GameEndTime)
END
END
),
0) As HoursPerDay
FROM (
SELECT DISTINCT UserId,
TheDate,
CASE
WHEN CAST(GameStartTime as Date) = TheDate
THEN GameStartTime
ELSE NULL
END As GameStartTime, -- return null if no game started that day
CASE
WHEN CAST(GameEndTime as Date) = TheDate
THEN GameEndTime
ELSE NULL
END As GameEndTime -- return null if no game ended that day
FROM Games CROSS APPLY AllDates -- This is where the magic happens :-)
) InnerSelect
GROUP BY UserId, TheDate
ORDER BY UserId, TheDate
OPTION (MAXRECURSION 0)
Play with it your self on sql fiddle.
I need to make a temporary table that holds of range of dates, as well as a couple of columns that hold placeholder values (0) for future use. The dates I need are the first day of each month between $startDate and $endDate where these variables can be several years apart.
My original sql statement looked like this:
select dbo.FirstOfMonth(InsertDate) as Month, 0 as Trials, 0 as Sales
into #dates
from customer
group by dbo.FirstOfMonth(InsertDate)
"FirstOfMonth" is a user-defined function I made that pretty much does what it says, returning the first day of the month for the provided date with the time at exactly midnight.
This produced almost exactly what I needed until I discovered there were occasionally gaps in my dates where I had a few months were there were no records insert dates. Since my result must still have the missing months I need a different approach.
I have added the following declarations to the stored procedure anticipating their need for the range of the dates I need ...
declare $startDate set $startDate = select min(InsertDate) from customer
declare $endDate set $endDate = select max(InsertDate) from customer
... but I have no idea what to do from here.
I know this question is similar to this question but, quite frankly, that answer is over my head (I don't often work with SQL and when I do it tends to be on older versions of SQL Server) and there are a few minor differences that are throwing me off.
I needed something similar, but all DAYS instead of all MONTHS.
Using the code from MatBailie as a starting point, here's the SQL for creating a permanent table with all dates from 2000-01-01 to 2099-12-31:
CREATE TABLE _Dates (
d DATE,
PRIMARY KEY (d)
)
DECLARE #dIncr DATE = '2000-01-01'
DECLARE #dEnd DATE = '2100-01-01'
WHILE ( #dIncr < #dEnd )
BEGIN
INSERT INTO _Dates (d) VALUES( #dIncr )
SELECT #dIncr = DATEADD(DAY, 1, #dIncr )
END
This will quickly populate a table with 170 years worth of dates.
CREATE TABLE CalendarMonths (
date DATETIME,
PRIMARY KEY (date)
)
DECLARE
#basedate DATETIME,
#offset INT
SELECT
#basedate = '01 Jan 2000',
#offset = 1
WHILE (#offset < 2048)
BEGIN
INSERT INTO CalendarMonths SELECT DATEADD(MONTH, #offset, date) FROM CalendarMonths
SELECT #offset = #offset + #offset
END
You can then use it by LEFT joining on to that table, for the range of dates you require.
I would probably use a Calendar table. Create a permanent table in your database and fill it with all of the dates. Even if you covered a 100 year range, the table would still only have ~36,525 rows in it.
CREATE TABLE dbo.Calendar (
calendar_date DATETIME NOT NULL,
is_weekend BIT NOT NULL,
is_holiday BIT NOT NULL,
CONSTRAINT PK_Calendar PRIMARY KEY CLUSTERED (calendar_date)
)
Once the table is created, just populate it once in a loop, so that it's always out there and available to you.
Your query then could be something like this:
SELECT
C.calendar_date,
0 AS trials,
0 AS sales
FROM
dbo.Calendar C
WHERE
C.calendar_date BETWEEN #start_date AND #end_date AND
DAY(C.calendar_date) = 1
You can join in the Customers table however you need to, outer joining on FirstOfMonth(InsertDate) = C.calendar_date if that's what you want.
You can also include a column for day_of_month if you want which would avoid the overhead of calling the DAY() function, but that's fairly trivial, so it probably doesn't matter one way or another.
This of course will not work in SQL-Server 2000 but in a modern database where you don't want to create a permanent table. You can use a table variable instead creating a table so you can left join the data try this. Change the DAY to HOUR etc to change the increment type.
declare #CalendarMonths table (date DATETIME, PRIMARY KEY (date)
)
DECLARE
#basedate DATETIME,
#offset INT
SELECT
#basedate = '01 Jan 2014',
#offset = 1
INSERT INTO #CalendarMonths SELECT #basedate
WHILE ( DATEADD(DAY, #offset, #basedate) < CURRENT_TIMESTAMP)
BEGIN
INSERT INTO #CalendarMonths SELECT DATEADD(HOUR, #offset, date) FROM #CalendarMonths where DATEADD(DAY, #offset, date) < CURRENT_TIMESTAMP
SELECT #offset = #offset + #offset
END
A starting point of a useful kludge to specify a range or specific list of dates:
SELECT *
FROM
(SELECT CONVERT(DateTime,'2017-1-1')+number AS [Date]
FROM master..spt_values WHERE type='P' AND number<370) AS DatesList
WHERE DatesList.Date IN ('2017-1-1','2017-4-14','2017-4-17','2017-12-25','2017-12-26')
You can get 0 to 2047 out of master..spt_values WHERE type='P', so that's five and a half year's worth of dates if you need it!
Tested below and it works, though it's a bit convoluted.
I assigned arbitrary values to the dates for the test.
DECLARE #SD smalldatetime,
#ED smalldatetime,
#FD smalldatetime,
#LD smalldatetime,
#Mct int,
#currct int = 0
SET #SD = '1/15/2011'
SET #ED = '2/02/2012'
SET #FD = (DATEADD(dd, -1*(Datepart(dd, #SD)-1), #sd))
SET #LD = (DATEADD(dd, -1*(Datepart(dd, #ED)-1), #ED))
SET #Mct = DATEDIFF(mm, #FD, #LD)
CREATE TABLE #MyTempTable (FoM smalldatetime, Trials int, Sales money)
WHILE #currct <= #Mct
BEGIN
INSERT INTO #MyTempTable (FoM, Trials, Sales)
VALUES
(DATEADD(MM, #currct, #FD), 0, 0)
SET #currct = #currct + 1
END
SELECT * FROM #MyTempTable
DROP TABLE #MyTempTable
For SQL Server 2000, this stackoverflow post looks promising for a way to temporarily generate dates calculated off of a start and end date. It's not exactly the same but quite similar. This post has a very in-depth answer on truncating dates, if needed.
In case anyone stumbles on this question and is working in PostgreSQL instead of SQL Server 2000, here is how you might do it there...
PostgreSQL has a nifty series generating function. For your example, you could use this series of all days instead of generating an entire calendar table, and then do groupings and matchups from there.
SELECT current_date + s.a AS dates FROM generate_series(0,14,7) AS s(a);
dates
------------
2004-02-05
2004-02-12
2004-02-19
(3 rows)
SELECT * FROM generate_series('2008-03-01 00:00'::timestamp,
'2008-03-04 12:00', '10 hours');
generate_series
---------------------
2008-03-01 00:00:00
2008-03-01 10:00:00
2008-03-01 20:00:00
2008-03-02 06:00:00
2008-03-02 16:00:00
2008-03-03 02:00:00
2008-03-03 12:00:00
2008-03-03 22:00:00
2008-03-04 08:00:00
(9 rows)
I would also look into date_trunc from PostgreSQL using 'month' for the truncator field to maybe refactor your original query to easily match with a date_trunc version of the calendar series.
select top (datediff(D,#start,#end)) dateadd(D,id-1,#start)
from BIG_TABLE_WITH_NO_JUMPS_IN_ID
declare #start datetime
set #start = '2016-09-01'
declare #end datetime
set #end = '2016-09-30'
create table #Date
(
table_id int identity(1,1) NOT NULL,
counterDate datetime NULL
);
insert into #Date select top (datediff(D,#start,#end)) NULL from SOME_TABLE
update #Date set counterDate = dateadd(D,table_id - 1, #start)
The code above should populate the table with all the dates between the start and end. You would then just join on this table to get all of the dates needed. If you only needed a certain day of each month, you could dateadd a month instead.
SELECT P.Id
, DATEADD ( DD, -P.Id, P.Date ) AS Date
FROM (SELECT TOP 1000 ROW_NUMBER () OVER (ORDER BY (SELECT NULL)) AS Id, CAST(GETDATE () AS DATE) AS Date FROM master.dbo.spt_values) AS P
This query returns a table calendar for the last 1000 days or so. It can be put in a temporary or other table.
Create a table variable containing a date for each month in a year:
declare #months table (reportMonth date, PRIMARY KEY (reportMonth));
declare #start date = '2018', #month int = 0; -- base 0 month
while (#month < 12)
begin
insert into #months select dateAdd(month, #month, #start);
select #month = #month + 1;
end
--verify
select * from #months;
This is by far the quickest method I have found (much quicker than inserting rows 1 by 1 in a WHILE loop):
DECLARE #startDate DATE = '1900-01-01'
DECLARE #endDate DATE = '2050-01-01'
SELECT DATEADD(DAY, sequenceNumber, #startDate) AS TheDate
INTO #TheDates
FROM (
SELECT ones.n + 10*tens.n + 100*hundreds.n + 1000*thousands.n + 10000*tenthousands.n AS sequenceNumber
FROM
(VALUES(0),(1),(2),(3),(4),(5),(6),(7),(8),(9)) ones(n),
(VALUES(0),(1),(2),(3),(4),(5),(6),(7),(8),(9)) tens(n),
(VALUES(0),(1),(2),(3),(4),(5),(6),(7),(8),(9)) hundreds(n),
(VALUES(0),(1),(2),(3),(4),(5),(6),(7),(8),(9)) thousands(n),
(VALUES(0),(1),(2),(3),(4),(5),(6),(7),(8),(9)) tenthousands(n)
WHERE ones.n + 10*tens.n + 100*hundreds.n + 1000*thousands.n + 10000*tenthousands.n <= DATEDIFF(day, #startDate, #endDate)
) theNumbers
SELECT *
FROM #TheDates
ORDER BY TheDate
The recursive answer:
DECLARE #startDate AS date = '20220315';
DECLARE #endDate AS date = '20230316'; -- inclusive
WITH cte_minutes(dt)
AS (
SELECT
DATEFROMPARTS(YEAR(#startDate), MONTH(#startDate), 1)
UNION ALL
SELECT
DATEADD(month, 1, dt)
FROM
cte_minutes
WHERE DATEADD(month, 1, dt) < #endDate
)
SELECT
dt
into #dates
FROM
cte_minutes
WHERE
dt >= #startDate
AND
dt <= #endDate
OPTION (MAXRECURSION 2000);
DROP TABLE dbo.#dates