I have an NSDictionary filled with data. If this was php it might be accessed by something like:
$data = $array['all_items'][0]['name'];
How do I do something similar in objective c? ($array would be an NSDictionary)
The equivalent code in Objective-C is:
id data = [[[array objectForKey:#"all_items"] objectAtIndex:0] objectForKey:#"name"];
Note that objectForKey: is a method of NSDictionary, and objectAtIndex: is a method of NSArray.
A shortcut in Xcode 4.5, using LLVM 4.1, is:
id data = array[#"all_items"][0][#"name"];
Also note that if "array" is an NSDictionary instance and you want to get an array of all values in the dictionary, you use the allValues method of NSDictionary:
id data = [array allValues][0][#"name"];
Of course, allValues returns an unsorted array, so accessing the array by index is not very useful. More typically, you'd see:
for (NSDictionary* value in [array allValues])
{
id data = value[#"name"];
// do something with data
}
Unfortunately the objective-c version is not as elegant syntactically as the PHP version:
NSDictionary *array = ...;
NSArray *foo = [array objectForKey#"all_items"];
NSDictionary *bar = [foo objectAtIndex:0];
NSString *data = [bar objectForKey#"name"];
For brevity, you can do this on a single line as:
NSString *data = [[[array objectForKey#"all_items"] objectAtIndex:0] objectForKey#"name"];
You should use it,
NSString *value = [[multiArray objectAtIndex:1] objectAtIndex:0];
You can look the question here
Related
I have an NSArray, where each object contains a specific class called Card. Card has a description method. I want to join all objects in the array using the output of the description method, separated by spaces. Is there a simple to do this, without manually iterating the NSArray and manipulating NSString?
Something akin to the following made-up code?
NSArray *myArray = getCards(); // fetches 10 items or more
NSString *myString = [myArray joinUsingDescriptionMethodSeparatedBy:#" "];
or
NSString *myString = [NSString stringFromArrayDescriptionMethods:myArray separatedBy:#" "];
Naturally ,I could implement this myself but I suspect there could be something already present that does this.
I don't think that there is such a method. You can also implement it in a Category for NSString.
Sorry, I found this:
NSString * result = [[array valueForKey:#"description"] componentsJoinedByString:#""];
From the documentation:
Constructs and returns an NSString object that is the result of
interposing a given separator between the elements of the array.
- (NSString *)componentsJoinedByString:(NSString *)separator
Do this for description method of each NSArray item:
NSMutableString * result = [[NSMutableString alloc] init];
for (NSObject * obj in array)
{
[result appendString:[NSString stringWithFormat:#" %#"[obj description]]];
}
NSLog(#"The concatenated string is %#", result);
I am trying to split the string into parts and insert into a table how should i do it?
I got an error for splitting of the array which is: -[__NSArrayI componentsSeparatedByString:]: unrecognized selector sent to instance 0x7a421e0
NSArray *BusRoute = alightDesc;
int i;
int count = [BusRoute count];
for (i = 0; i < count; i++)
{
NSDictionary *dic = [BusRoute objectAtIndex: i];
NSDictionary *STEPS = [dic valueForKey:#"STEPS"];
NSString *AlightDesc = [STEPS valueForKey:#"AlightDesc"];
NSLog(#"AlightDesc = %#", AlightDesc);
NSArray *aDescArray = [AlightDesc componentsSeparatedByString:#","];
NSLog(#"aDescArray = %#", aDescArray);
}
This is the string which I'm splitting, i got it from the NSLog
AlightDesc = (
"Block1",
"Block2",
"Block3"
)
please help I'm stuck thanks.
Objective C is not a strongly typed language. All you know for sure about [STEPS valueForKey:#"AlightDesc"] is that it will return an object (of type id). When you wrote NSString *AlightDesc = [STEPS valueForKey:#"AlightDesc"] the compiler did not complain because NSString * is a valid object type. Unfortunately there is a logic error in your code so that what was actually stored under the key #"AlightDesc" is an NSArray. As others have mentioned, NSArray does not respond to componentsSeparatedByString: so you get an error at runtime.
The easy fix for this is to correct your logic: Either store an NSString in the first place or treat what you get out as an NSArray. As #janusfidel mentioned you can use an NSArray perfectly well in a table by using objectAtIndex: to get the string for the entry you want.
In some more complicated cases you may not know what you will be getting out of a dictionary for a particular key. In that case in Objective C you can just ask the object:
id anObject = [STEPS valueForKey:#"AlightDesc"];
if ([anObject isKindOfClass:[NSString class]]) {
NSString *aString = (NSString *)anObject;
// Treat as a string ...
} else if ([anObject isKindOfClass:[NSString class]]) {
// Object is an array ...
Your NSString *AlightDesc should look like this
NSString *AlightDesc = "Block1,Block2,Block3";
NSArray *aDescArray = [AlightDesc componentsSeparatedByString:#","];
If your string is what you say it is
AlightDesc = ("Block1","Block2","Block3");
then your string is the problem because it's already broken up.
I have a string array as such:
NSArray *names;
names = [NSArray arrayWithObjects:
#"FirstList",
#"SecondList",
#"ThirdList",
nil];
I'm trying to assign an element of this string array to a string variable as such:
NSString *fileName = names[0]; // "Incompatible types in initialization"
or with casting
NSString *fileName = (NSString)names[0]; // "Conversion to non-scalar type requested"
I'm trying to do this, so I can use the string in a method that takes a string as an argument, such as:
NSString *plistPath = [bundle pathForResource:filetName ofType:#"plist"];
Is there no way to assign an element of a string array to a string variable?
Update from 2014: The code in this post actually would work these days since special syntactic support has been added to the framework and compiler for indexing NSArrays like names[0]. But at the time this question was asked, it gave the error mentioned in this question.
You don't use C array notation to access NSArray objects. Use the -objectAtIndex: method for your first example:
NSString *fileName = [names objectAtIndex:0];
The reason for this is that NSArray is not "part of Objective-C". It's just a class provided by Cocoa much like any that you could write, and doesn't get special syntax privileges.
NSArray is a specialized array class unlike C arrays. To reference its contents you send it an objectAtIndex: message:
NSString *fileName = [names objectAtIndex:0];
If you want to perform an explicit cast, you need to cast to an NSString * pointer, not an NSString:
NSString *fileName = (NSString *)[names objectAtIndex:0];
With the new Objective-C literals is possible to use:
NSString *fileName = names[0];
So your code could look like this:
- (void)test5518658
{
NSArray *names = #[
#"FirstList",
#"SecondList",
#"ThirdList"];
NSString *fileName = names[0];
XCTAssertEqual(#"FirstList", fileName, #"Names doesn't match ");
}
Check Object Subscripting for more information.
I am trying to create an NSArray of bool values. How many I do this please?
NSArray *array = [[NSArray alloc] init];
array[0] = YES;
this does not work for me.
Thanks
NSArrays are not c-arrays. You cant access the values of an NSArray with array[foo];
But you can use c type arrays inside objective-C without problems.
The Objective-C approach would be:
NSMutableArray *array = [[NSMutableArray alloc] init];
[array addObject:[NSNumber numberWithBool:YES]];
//or
[array addObject:#(NO)];
...
BOOL b = [[array objectAtIndex:0] boolValue];
....
[array release];
EDIT: New versions of clang, the now standard compiler for objective-c, understand Object subscripting. When you use a new version of clang you will be able to use array[0] = #YES
Seems like you've confused c array with objc NSArray. NSArray is more like a list in Java, into which you can add objects, but not values like NSInteger, BOOL, double etc. If you wish to store such values in an NSArray, you first need to create a mutable array:
NSMutableArray* array = [[NSMutableArray alloc] init];
And then add proper object to it (in this case we'll use NSNumber to store your BOOL value):
[array addObject:[NSNumber numberWithBool:yourBoolValue]];
And that's pretty much it! If you wish to access the bool value, just call:
BOOL yourBoolValue = [[array objectAtIndex:0] boolValue];
Cheers,
Pawel
Use [NSNumber numberWithBool: YES] to get an object you can put in the collection.
How do I convert NSMutableArray to NSArray in objective-c?
NSArray *array = [mutableArray copy];
Copy makes immutable copies. This is quite useful because Apple can make various optimizations. For example sending copy to a immutable array only retains the object and returns self.
If you don't use garbage collection or ARC remember that -copy retains the object.
An NSMutableArray is a subclass of NSArray so you won't always need to convert but if you want to make sure that the array can't be modified you can create a NSArray either of these ways depending on whether you want it autoreleased or not:
/* Not autoreleased */
NSArray *array = [[NSArray alloc] initWithArray:mutableArray];
/* Autoreleased array */
NSArray *array = [NSArray arrayWithArray:mutableArray];
EDIT: The solution provided by Georg Schölly is a better way of doing it and a lot cleaner, especially now that we have ARC and don't even have to call autorelease.
I like both of the 2 main solutions:
NSArray *array = [NSArray arrayWithArray:mutableArray];
Or
NSArray *array = [mutableArray copy];
The primary difference I see in them is how they behave when mutableArray is nil:
NSMutableArray *mutableArray = nil;
NSArray *array = [NSArray arrayWithArray:mutableArray];
// array == #[] (empty array)
NSMutableArray *mutableArray = nil;
NSArray *array = [mutableArray copy];
// array == nil
you try this code---
NSMutableArray *myMutableArray = [myArray mutableCopy];
and
NSArray *myArray = [myMutableArray copy];
Objective-C
Below is way to convert NSMutableArray to NSArray:
//oldArray is having NSMutableArray data-type.
//Using Init with Array method.
NSArray *newArray1 = [[NSArray alloc]initWithArray:oldArray];
//Make copy of array
NSArray *newArray2 = [oldArray copy];
//Make mutablecopy of array
NSArray *newArray3 = [oldArray mutableCopy];
//Directly stored NSMutableArray to NSArray.
NSArray *newArray4 = oldArray;
Swift
In Swift 3.0 there is new data type Array. Declare Array using let keyword then it would become NSArray And if declare using var keyword then it's become NSMutableArray.
Sample code:
let newArray = oldArray as Array
In objective-c :
NSArray *myArray = [myMutableArray copy];
In swift :
var arr = myMutableArray as NSArray
NSArray *array = mutableArray;
This [mutableArray copy] antipattern is all over sample code. Stop doing so for throwaway mutable arrays that are transient and get deallocated at the end of the current scope.
There is no way the runtime could optimize out the wasteful copying of a mutable array that is just about to go out of scope, decrefed to 0 and deallocated for good.
If you're constructing an array via mutability and then want to return an immutable version, you can simply return the mutable array as an "NSArray" via inheritance.
- (NSArray *)arrayOfStrings {
NSMutableArray *mutableArray = [NSMutableArray array];
mutableArray[0] = #"foo";
mutableArray[1] = #"bar";
return mutableArray;
}
If you "trust" the caller to treat the (technically still mutable) return object as an immutable NSArray, this is a cheaper option than [mutableArray copy].
Apple concurs:
To determine whether it can change a received object, the receiver of a message must rely on the formal type of the return value. If it receives, for example, an array object typed as immutable, it should not attempt to mutate it. It is not an acceptable programming practice to determine if an object is mutable based on its class membership.
The above practice is discussed in more detail here:
Best Practice: Return mutableArray.copy or mutableArray if return type is NSArray
i was search for the answer in swift 3 and this question was showed as first result in search and i get inspired the answer from it
so here is the swift 3 code
let array: [String] = nsMutableArrayObject.copy() as! [String]