This is my sum clause
Select *,(sum(current_bal-curr_bal_now)/
current_bal from base
Group by month
This gives me an error because I'm not using current_bal in the group by.
Is there a way of not using group by current_bal aswell as month as it completely messes up the output layout.
Thanks
Another guess...
SELECT *,
( sum(current_bal) OVER (PARTITION BY month) ) / current_bal
FROM base
The problem is that the sum will return you only a value, so, in your all select, Current_bal is different. Which one should choose ?
If what you want is add every division, something like this:
Select sum(current_bal/current_bal)
from base
Group by month
will work
Related
SELECT SUM(Total_A ) FROM Materials_List
This is the snippet of code that I have.
I need it to calculate by month and display by month using SQL.
I also would like it to be a code I can use for any month in the year not just one month at a time.
You seem to be looking for simple aggregation:
select
year(materials_datetime) yr,
month(materials_datetime) mn,
sum(total_a) sum_total_a
from materials_list
group by
year(materials_datetime),
month(materials_datetime)
order by yr, mn
This assumes that column materials_datetime contains the date/time that you want to use to aggregate the data.
Beginner SQL Question:
I'm trying to do a group by, by year and I'm getting funny results. I am using SQL Server 2008.
First, I tried
select count(applicationkey) , approveddate from ida.applications group by approveddate
To get a count of applications by date. However, I am interested in applications by year in stead of day so I tried
select count(applicationkey) , approveddate from ida.applications group by year(approveddate)
When I do this, I get an error message -Column 'ida.applications.ApprovedDate' is invalid in the select list because it is not contained in either an aggregate function or the GROUP BY clause.-
However, if I do this I get results
select count(applicationkey) from ida.applications group by year(approveddate)
I get results. Its just I want to be able to see what year matches to which count, which I cannot do for some reason. Does anyone know why I am having this problem?
select count(applicationkey),
year(approveddate)
from ida.applications
group by year(approveddate)
group by must match fields in select if not using an aggregate.
You have all the correct parts there, just include the year(approveddate) in your select like so
select count(applicationkey), year(approveddate)
from ida.applications
group by year(approveddate)
In a group query, columns selected have to be aggregate functions or appear in the group-by list, because otherwise SQL wouldn't know which of the multiple values for the column in the group to use.
You can fix your query easily by using
select count(applicationkey) , year(approveddate)
from ida.applications group by year(approveddate)
-- the year displayed is from the group by list
I'm working with a large transaction data set and would like to group a count of individual customer transactions by month. I am unable to use the timestamp function in the GROUP BY and return the following error:
BAD_QUERY (expression STRFTIME_UTC_USEC([DATESTART], '%b') in GROUP BY is invalid)
Is there a simple workaround to achieve this or should I build a calendar table (which may be the simplest option)?
You have to use an alias:
SELECT STRFTIME_UTC_USEC(DATESTART, '%b') as month, COUNT(TRANSACTION)
FROM datasetId.tableId
GROUP BY month
#Charles is correct but as an aside you can also group by column number.
SELECT STRFTIME_UTC_USEC(DATESTART, '%b') as month, COUNT(TRANSACTION) as count
FROM [datasetId.tableId]
GROUP BY 1
ORDER BY 2 DESC
I have folowing sql query an di want to get previous of max value from table.
select max(card_no),vehicle_number
FROM WBG.WBG_01_01
group by vehicle_number
Through this query i got each maximum card number of each vehicle.But i want to get previouse of that max.For example
if vehicle number has card number 21,19,17,10,5,6,1 and i want to get 19 from max function
Please anyone tell me how can i do this in sql.
Another idea would be to use analytics, something like this:
select
vehicle_number,
prev_card_no
from (
select
card_no,
vehicle_number,
lag(card_no) over
(partition by vehicle_number order by card_no) as prev_card_no,
max(card_no) over
(partition by vehicle_number) as max_card_no
FROM WBG.WBG_01_01
)
where max_card_no = card_no;
Of course, this doesn't take into account your seemingly arbitrary ordering from your question, nor would it work with duplicate maximum numbers.
try this one:
select max(card_no),vehicle_number
FROM WBG.WBG_01_01
where card_no < (Select max(card_no) from WBG.WBG_01_01 group by vehicle_number)
group by vehicle_number
I want to select a date from oracle table formatted like select (to_char(req_date,'MM/YYYY')) but I also want to order the result set on this date format.
I want them to be ordered like dates not strings.
Like this
09/2009
10/2009
11/2009
12/2009
01/2010
02/2010
03/2010
04/2010
05/2010
06/2010
07/2010
08/2010
09/2010
10/2010
11/2010
12/2010
Not like
01/2010
02/2010
03/2010
04/2010
05/2010
06/2010
07/2010
08/2010
09/2009
09/2010
10/2009
10/2010
11/2009
11/2010
12/2009
12/2010
Any way to do this in sql?
Full SQL is:
SELECT (to_char(req_date,'MM/YYYY')) as monthYear, count(req_id) as count
FROM REQUISITION_CURRENT t
GROUP BY to_char(req_date,'MM/YYYY')
Thanks
Try this. It works and it's efficient, but looks a little messy.
select to_char(trunc(req_date, 'MM'),'MM/YYYY') as monthYear
,count(req_id) as count
from requisition_current
group
by trunc(req_date, 'MM')
order
by trunc(req_date, 'MM');
Try this
select monthyear,yr,month,count(req_id)
from
(
SELECT (to_char(req_date,'MM/YYYY')) as monthYear, to_char(req_date,'YYYY') yr, to_char(req_date,'mm') month, req_id
FROM REQUISITION_CURRENT t
) x
GROUP BY monthyear,yr,month
order by yr, month
Please try
Select req_date, (to_char(req_date,'MM/YYYY')) from MY_TABLE order by req_date
You are free to add additional sort fields, even if they are the same field.
Just use order by req_date instead of order by to_char(req_date,'MM/YYYY').
Try
SELECT ...
ORDER BY MIN(req_date)
That'll get around Oracle's rules about what can be selected after a GROUP BY.
I am considerably late to the party, but the most intuitive way I've found to achieve this is the following:
SELECT DISTINCT
to_char(req_date,'MM/YYYY') as monthYear,
count(req_id) as count
FROM
REQUISITION_CURRENT t
GROUP BY
to_char(req_date,'MM/YYYY')
ORDER BY
to_date(monthYear,'MM/YYYY')
It's may not the most computationally efficient method since it converts the date to a character and then back to a date, but that is precisely what you are asking a query like this to do. It also saves you from adding support columns or nesting subqueries.