In a Mule flow, I would like to add an Exception Handler that forwards messages to a "retry queue" when there is an exception. However, I don't want this retry logic to run automatically. Instead, I'd rather receive a notification so I can review the errors and then decide whether to retry all messages in the queue or not.
I don't want to receive a notification for every exception. I'd rather have a scheduled job that runs every 15 minutes and checks to see if there are messages in this retry queue and then only send the notification if there are.
Is there any way to determine how many messages are currently in a persistent VM queue?
Assuming you use the default VM queue persistence mechanism and that the VM connector is named vmConnector, you can do this:
final String queueName = "retryQueue";
int messageCount = 0;
final VMConnector vmConnector = (VMConnector) muleContext.getRegistry()
.lookupConnector("vmConnector");
for (final Serializable key : vmConnector.getQueueProfile().getObjectStore().allKeys())
{
final QueueKey queueKey = (QueueKey) key;
if (queueName.equals(queueKey.queueName))
{
messageCount++;
}
}
System.out.printf("Queue %s has %d pending messages%n", queueName, messageCount);
Related
I am using ActiveMQ with Java Spring. I have enabled scheduler and I managed to create scheduled jobs (programmatically). I have also managed to write a method to remove them based on job id. I have been using JmsTemplate to browse a queue, but it only works when the queue has some messages waiting. I can't find job id when the queue is empty.
My question is how am I supposed to get scheduled job id?
From your question it sounds like you want to see what messages are scheduled, so to accomplish that you need to create a Producer that publishes on the Destination named: "ActiveMQ.Scheduler.Management". Once that's done you create a new Message and set some properties and add a Reply To destination so the scheduler knows where to send your Messages. Then all you need to do is process the messages with a Consumer that is subscribed to that Reply To destination.
Connection connection = createConnection();
Session session = connection.createSession(false, Session.AUTO_ACKNOWLEDGE);
// Create the Browse Destination and the Reply To location
Destination requestBrowse = session.createTopic(ScheduledMessage.AMQ_SCHEDULER_MANAGEMENT_DESTINATION);
Destination browseDest = session.createTemporaryQueue();
// Create the "Browser"
MessageConsumer browser = session.createConsumer(browseDest);
connection.start();
// Send the browse request
MessageProducer producer = session.createProducer(requestBrowse);
Message request = session.createMessage();
request.setStringProperty(ScheduledMessage.AMQ_SCHEDULER_ACTION,
ScheduledMessage.AMQ_SCHEDULER_ACTION_BROWSE);
request.setJMSReplyTo(browseDest);
producer.send(request);
Message scheduled = browser.receive(5000);
while (scheduled != null) {
// Do something clever...
}
Additional details are documented in this blog post.
I am trying to code a simple consumer using librabbitmq. It is working, but when I do execute amqp_basic_consume, it consumes the entire queue.
What I want is for it to get a single message, process it and repeat.
I tried using a basic_qos to have the consumer prefetch 1 at a time, but that seems to have no effect at all.
The basic setup and loop:
// set qos of 1 message at a time
if (!amqp_basic_qos(conn, channel, 0, 1, 0)) {
die_on_amqp_error(amqp_get_rpc_reply(conn), "basic.qos");
}
// Consuming the message
amqp_basic_consume(conn, channel, queue, amqp_empty_bytes, no_local, no_ack, exclusive, amqp_empty_table);
while (run) {
amqp_rpc_reply_t result;
amqp_envelope_t envelope;
amqp_maybe_release_buffers(conn);
result = amqp_consume_message(conn, &envelope, &timeout, 0);
if (AMQP_RESPONSE_NORMAL == result.reply_type) {
strncpy(message, envelope.message.body.bytes, envelope.message.body.len);
message[envelope.message.body.len] = '\0';
printf("Received message size: %d\nbody: -%s-\n", (int) envelope.message.body.len, message );
if ( strncmp(message, "DONE",4 ) == 0 )
{
printf("XXXXXXXXXXXXXXXXXX Cease message received. XXXXXXXXXXXXXXXXXXXXX\n");
run = 0;
}
amqp_destroy_envelope(&envelope);
}else{
printf("Timeout.\n");
run = 0;
}
}
I expect to have a queue filled that I can start processing and if I hit ^C, the remaining messages are still in the queue. Instead, even if I have only processed one message, the entire queue is emptied.
This is the behavior when noAck is true. What will happen is that the messages will be pushed to the connected consumer as fast as the broker can send them, because it assumes that the consumer is able to accept them as they are acknowledged immediately upon delivery.
You would want to change noAck to false, then explicitly ack each message back to the broker in this case.
Alternatively, you could use a basic.get to pull messages from the broker one at a time as opposed to using a push-based consumer (there are folks out there who don't like this idea). Your use case will determine what is most appropriate, but based on the fact that you seem to have a full queue and fairly process-intensive messages, I would assume a basic.get would be just fine in this scenario. The question then would be to decide how often to poll when the queue is empty.
I'm having trouble to identify a way to delay message level in SpringAMQP.
I call a Webservice if the service is not available or if it throws some exception I store all the requests into RabbitMQ queue and i keep retry the service call until it executes successfully. If the service keeps throwing an error or its not available the rabbitMQ listener keeps looping.( Meaning Listener retrieves the message and make service call if any error it re-queue the message)
I restricted the looping until X hours using MessagePostProcessor however i wanted to enable delay on message level and every time it tries to access the service. For example 1st try 3000ms delay and second time 6000ms so on until i try x number of time.
It would be great if you provide a few examples.
Could you please provide me some idea on this?
Well, it isn't possible the way you do that.
Message re-queuing is fully similar to transaction rallback, where the system returns to the state before an exception. So, definitely you can't modify a message to return to the queue.
Probably you have to take a look into Spring Retry project for the same reason and poll message from the queue only once and retries in memory until successful answer or retry policy exhausting. In the end you can just drop message from the queue or move it into DLQ.
See more info in the Reference Manual.
I added CustomeMessage delay exchange
#Bean
CustomExchange delayExchange() {
Map<String, Object> args = new HashMap<>();
args.put("x-delayed-type", "direct");
return new CustomExchange("delayed-exchange", "x-delayed-message", true, false, args);
}
Added MessagePostProcessor
if (message.getMessageProperties().getHeaders().get("x-delay") == null) {
message.getMessageProperties().setHeader("x-delay", 10000);
} else {
Integer integer = (Integer) message.getMessageProperties().getHeaders().get("x-delay");
if (integer < 60000) {
integer = integer + 10000;
message.getMessageProperties().setHeader("x-delay", integer);
}
}
First time it delays 30 seconds and adds 10seconds each time till it reaches 600 seconds.This should be configurable.
And finally send the message to
rabbitTemplate.convertAndSend("delayed-exchange", queueName,message, rabbitMQMessagePostProcessor);
I want to consume multiple messages from specific queue or a specific exchange with a given key.
so the scenario is as follow:
Publisher publish message 1 over queue 1
Publisher publish message 2 over queue 1
Publisher publish message 3 over queue 1
Publisher publish message 4 over queue 2
Publisher publish message 5 over queue 2
..
Consumer consume messages from queue 1
get [message 1, message 2, message 3] all at once and handle them in one call back
listen_to(queue_name , num_of_msg_to_fetch or all, function(messages){
//do some stuff with the returned list
});
the messages are not coming at the same time, it is like events and i want to collect them in a queue, package them and send them to a third party.
I also read this post:
http://rabbitmq.1065348.n5.nabble.com/Consuming-multiple-messages-at-a-time-td27195.html
Thanks
Don't consume directly from the queue as queues follow round robin algorithm(an AMQP mandate)
Use shovel to transfer the queue contents to a fanout exchange and consume messages right from this exchange. You get all messages across all connected consumers. :)
If you want to consume multiple messages from specific queue, you can try as below.
channel.queueDeclare(QUEUE_NAME, false, false,false, null);
Consumer consumer = new DefaultConsumer(channel){
#Override
public void handleDelivery(String consumerTag,
Envelope envelope,
AMQP.BasicProperties properties,
byte[] body)
throws IOException {
String message = new String(body, "UTF-8");
logger.info("Recieved Message --> " + message);
}
};
You might need to conceptually separate domain-message from RMQ-message. As a producer you'd then bundle multiple domain messages into a single RMQ-message and .produce() it to RMQ. Remember this kind of design introduces timeouts and latencies due to the existence of a window (you might take some impression from Kafka that does bundling to optimize I/O at the cost of latency).
As a consumer then, you'd have a consumer, with typical .handleDelivery implementation that would transform the received body for the processing: byte[] -> Set[DomainMessage] -> your listener.
I'd like to send a message to a RabbitMQ server and then wait for a reply message (on a "reply-to" queue). Of course, I don't want to wait forever in case the application processing these messages is down - there needs to be a timeout. It sounds like a very basic task, yet I can't find a way to do this. I've now run into this problem with Java API.
The RabbitMQ Java client library now supports a timeout argument to its QueueConsumer.nextDelivery() method.
For instance, the RPC tutorial uses the following code:
channel.basicPublish("", requestQueueName, props, message.getBytes());
while (true) {
QueueingConsumer.Delivery delivery = consumer.nextDelivery();
if (delivery.getProperties().getCorrelationId().equals(corrId)) {
response = new String(delivery.getBody());
break;
}
}
Now, you can use consumer.nextDelivery(1000) to wait for maximum one second. If the timeout is reached, the method returns null.
channel.basicPublish("", requestQueueName, props, message.getBytes());
while (true) {
// Use a timeout of 1000 milliseconds
QueueingConsumer.Delivery delivery = consumer.nextDelivery(1000);
// Test if delivery is null, meaning the timeout was reached.
if (delivery != null &&
delivery.getProperties().getCorrelationId().equals(corrId)) {
response = new String(delivery.getBody());
break;
}
}
com.rabbitmq.client.QueueingConsumer has a nextDelivery(long timeout) method, which will do what you want. However, this has been deprecated.
Writing your own timeout isn't so hard, although it may be better to have an ongoing thread and a list of in-time identifiers, rather than adding and removing consumers and associated timeout threads all the time.
Edit to add: Noticed the date on this after replying!
There is similar question. Although it's answers doesn't use java, maybe you can get some hints.
Wait for a single RabbitMQ message with a timeout
I approached this problem using C# by creating an object to keep track of the response to a particular message. It sets up a unique reply queue for a message, and subscribes to it. If the response is not received in a specified timeframe, a countdown timer cancels the subscription, which deletes the queue. Separately, I have methods that can be synchronous from my main thread (uses a semaphore) or asynchronous (uses a callback) to utilize this functionality.
Basically, the implementation looks like this:
//Synchronous case:
//Throws TimeoutException if timeout happens
var msg = messageClient.SendAndWait(theMessage);
//Asynchronous case
//myCallback receives an exception message if there is a timeout
messageClient.SendAndCallback(theMessage, myCallback);