I have a table SAMPLE having unique column(sal_id, gal_id) and amount, tax, date and some more columns.
SAMPLE table
actual_id, sal_id, gal_id, processed_flag, amount, tax date
1 101 201 Y 10 1 25-Aug-12
2 101 201 Y 20 3 27-Aug-12
3 101 201 N 15 2 29-Aug-12
Now I need to find the difference between unprocessed (process_flag='N') and proceed data (process_flag='Y') having maximum date. I need to calculate difference between amount and tax for (sal_id + gal_id) combination.
So the query return should be like this:
In this example, Since for (101, 201), we are having 2 processed row and (actual_id 2 having maximum date. So need to find difference between actual_id 3 & actual_id 2 row.
actual_id, sal_id, gal_id, total_amount, total_tax date
3 101 201 -5 (15-20) -1 (2-3) 29-Aug-12
I am using Oracle 11g. Please help me.
Try this:
WITH t AS (SELECT DISTINCT "sal_id" sid,"gal_id" gid,"processed_flag" pf, max("amount") over
(partition BY "sal_id","gal_id","processed_flag") am,
max("tax") over
(partition BY "sal_id","gal_id","processed_flag") tx,
max("actual_id") over
(partition BY "sal_id","gal_id","processed_flag") aid,
max("date") over
(partition BY "sal_id","gal_id","processed_flag") dt
FROM sample)
SELECT t1.aid, t1.sid, t1.gid, t1.am-t2.am, t1.tx-t2.tx, t1.dt FROM t t1 JOIN t t2 ON t1.sid=t2.sid AND t1.gid=t2.gid
WHERE t1.pf='N' AND t2.pf='Y';
Here is a fiddle
UPDATE: The previous answer assumes that max(date) also has the max(amount).
a much better solution can be:
WITH t AS (SELECT *
FROM sample s
WHERE s."date" = (SELECT max("date") FROM sample s_in
WHERE s_in."sal_id" = s."sal_id"
AND s_in."gal_id" = s."gal_id"
AND s_in."processed_flag" = s."processed_flag"))
SELECT t1."actual_id", t1."sal_id", t1."gal_id", t1."amount"-t2."amount" total_amount, t1."tax"-t2."tax" total_tax, t1."date"
FROM t t1 JOIN t t2 ON t1."sal_id"=t2."sal_id" AND t1."gal_id"=t2."gal_id"
WHERE t1."processed_flag"='N' AND t2."processed_flag"='Y';
Here is the fiddle
Related
I have a SQLite query which returns a user name and how much a user spent (done by SELECT SUM() from the different table).
Name
Spent
Adam
700
Mike
400
Steve
100
I have another table which contains discount amount with corresponding treshold:
Treshold
Discount
200
5
400
10
600
15
I need to find what discount each user has (if it does at all). So results would look like this:
Name
Spent
Discount
Total
Adam
700
15
595
Mike
400
10
360
Steve
100
0
100
You need a LEFT join of your query to the 2nd table and aggregation:
SELECT t1.name, t1.Spent,
COALESCE(MAX(t2.Discount), 0) Discount,
t1.Spent * (1 - 0.01 * COALESCE(MAX(t2.Discount), 0)) Total
FROM (SELECT name, SUM(Spent) Spent FROM table1 GROUP BY name) t1
LEFT JOIN table2 t2 ON t2.Treshold <= t1.Spent
GROUP BY t1.name;
See the demo.
I am in a hurry. Sorry.
with a as (
select name, sum(spent) spe
from test1
group by name)
select a.name
, a.spe
, max(tres)
, max(disc)
, spe -spe * (0 || '.' || disc) total
from test2, a
where tres <= a.spe
DEMO
I have two tables in PostgreSQL:
Demans_for_parts:
demandid partid demanddate quantity
40 125 01.01.17 10
41 125 05.01.17 30
42 123 20.06.17 10
Orders_for_parts:
orderid partid orderdate quantity
1 125 07.01.17 15
54 125 10.06.17 25
14 122 05.01.17 30
Basicly Demans_for_parts says what to buy and Orders_for_parts says what we bought. We can buy parts which do not list on Demans_for_parts.
I need a report which shows me all parts in Demans_for_parts and how many weeks past since the most recent matching row in Orders_for_parts. note quantity field is irrelevent here,
The expected result is (if more than one row per part show the oldes):
partid demanddate weeks_since_recent_order
125 01.01.17 2 (last order is on 10.06.17)
123 20.06.17 Unhandled
I think the tricky part is getting one row per table. But that is easy using distinct on. Then you need to calculate the months. You can use age() for this purpose:
select dp.partid, dp.date,
(extract(year from age(dp.date, op.date))*12 +
extract(month from age(dp.date, op.date))
) as months
from (select distinct on (dp.partid) dp.*
from demans_for_parts dp
order by dp.partid, dp.date desc
) dp left join
(select distinct on (op.partid) op.*
from Orders_for_parts op
order by op.partid, op.date desc
) op
on dp.partid = op.partid;
smth like?
with o as (
select distinct partid, max(orderdate) over (partition by partid)
from Orders_for_parts
)
, p as (
select distinct partid, min(demanddate) over (partition by partid)
from Demans_for_parts
)
select p.partid, min as demanddate, date_part('day',o.max - p.min)/7
from p
left outer join o on (p.partid = o.partid)
;
I have below 2 tables in SQL Server database.
Customer Main Expense Table
ReportID CustomerID TotalExpenseAmount
1000 1 200
1001 2 600
Attendee Table
ReportID AttendeeName
1000 Mark
1000 Sam
1000 Joe
There is no amount at attendee level. I have need to manually calculate individual attendee amount as mentioned below. (i.e split TotalExpenseAmount based on number of attendees and ensure individual split figures round to 2 decimals and sums up to the TotalExpenseAmount exactly)
The final report should look like:
ReportID CustID AttendeeName TotalAmount AttendeeAmount
1000 1 Mark 200 66.66
1000 1 Sam 200 66.66
1000 1 Joe 200 66.68
The final report will have about 1,50,000 records. If you notice the attendee amount I have rounded the last one in such a way that the totals match to 200. What is the best way to write an efficient SQL query in this scenario?
You can do this using window functions:
select ReportID, CustID, AttendeeName, TotalAmount,
(case when seqnum = 1
then TotalAmount - perAttendee * (cnt - 1)
else perAttendee
end) as AttendeeAmount
from (select a.ReportID, a.CustID, a.AttendeeName, e.TotalAmount,
row_number() over (partition by reportId order by AttendeeName) as seqnum,
count(*) over (partition by reportId) as cnt,
cast(TotalAmount * 1.0 / count(*) over (partition by reportId) as decimal(10, 2)) as perAttendee
from attendee a join
expense e
on a.ReportID = e.ReportID
) ae;
The perAttendee amount is calculated in the subquery. This is rounded down by using cast() (only because floor() doesn't accept a decimal places argument). For one of the rows, the amount is the total minus the sum of all the other attendees.
Doing something similar to #Gordon's answer but using a CTE instead.
with CTECount AS (
select a.ReportId, a.AttendeeName,
ROW_NUMBER() OVER (PARTITION BY A.ReportId ORDER BY A.AttendeeName) [RowNum],
COUNT(A.AttendeeName) OVER (PARTITION BY A.ReportId) [AttendeeCount],
CAST(c.TotalExpenseAmount / (COUNT(A.AttendeeName) OVER (PARTITION BY A.ReportId)) AS DECIMAL(10,2)) [PerAmount]
FROM #Customer C INNER JOIN #Attendee A ON A.ReportId = C.ReportID
)
SELECT CT.ReportID, CT.CustomerId, AT.AttendeeName,
CASE WHEN CC.RowNum = 1 THEN CT.TotalExpenseAmount - CC.PerAmount * (CC.AttendeeCount - 1)
ELSE CC.PerAmount END [AttendeeAmount]
FROM #Customer CT INNER JOIN #Attendee AT
ON CT.ReportID = AT.ReportId
INNER JOIN CTECount CC
ON CC.ReportId = CT.ReportID AND CC.AttendeeName = AT.AttendeeName
I like the CTE because it allows me to separate the different aspects of the query. The cool thing that #Gordon used was the Case statement and the inner calculation to have the lines total correctly.
I have a table with 3 fields like this sample table Tbl1
Person Cost FromDate
1 10 2009-1-1
1 20 2010-1-1
2 10 2009-1-1
I want to query it and get back the 3 fields and a generated field called ToDate that defaults to 2099-1-1 unless there is an actual ToDate implied from another entry for the person in the table.
select Person,Cost,FromDate,ToDate From Tbl1
Person Cost FromDate ToDate
1 10 2009-1-1 2010-1-1
1 20 2010-1-1 2099-1-1
2 10 2009-1-1 2099-1-1
You can select the minimum date from all dates that are after the record's date. If there is none you get NULL. With COALESCE you change NULL into the default date:
select
Person,
Cost,
FromDate,
coalesce((select min(FromDate) from Tbl1 later where later.FromDate > Tbl1.FromDate), '2099-01-01') as ToDate
From Tbl1
order by Person, FromDate;
Although Thorsten's answer is perfectly fine, it would be more efficient to use window-functions to match the derived end-dates.
;WITH nbrdTbl
AS ( SELECT Person, Cost, FromDate, row_nr = ROW_NUMBER() OVER (PARTITION BY Person ORDER BY FromDate ASC)
FROM Tbl1)
SELECT t.Person, t.Cost, t.FromDate, derived_end_date = COALESCE(nxt.FromDate, '9991231')
FROM nbrdTbl t
LEFT OUTER JOIN nbrdTbl nxt
ON nxt.Person = t.Person
AND nxt.row_nr = t.row_nr + 1
ORDER BY t.Person, t.FromDate
Doing a test on a 2000-records table it's about 3 times as efficient according to the Execution plan (78% vs 22%).
I am struggling to get this working, using T-SQL Query (SQL SERVER 2008) for the following problem:
Ky ProductID Start # End # Diff
1 100 10 12 0
2 100 14 20 2 (14 - 12)
3 100 21 25 1 (21 - 20)
4 100 30 33 5 (30 - 25)
1 110 6 16 0
2 110 20 21 4 (20 - 16)
3 110 22 38 1 (22 - 21)
as you can see I need the difference between values in two different rows and two columns.
I tried
with t1
( select ROW_NUMBER() OVER (PARTITION by ProductID ORDER BY ProductID, Start# ) as KY
, productid
, start#
, end#
from mytable)
and
select DATEDIFF(ss, T2.complete_dm, T1.start_dm)
, <Keeping it simple not including all the columns which I selected..>
FROM T1 as T2
RIGHT OUTER JOIN T1 on T2.Ky + 1 = T1.KY
and T1.ProductID = T2.ProductID
The problem with the above query is when the productID changes from 100 to 110 still it calculates the difference.
Any help in modifying the query or any simpler solution much appreciated.
Thanks
You can try below code for the required result :
select ky,Start,[End],(select [end] from table1 tt where (tt.ky)=(t.ky-1) and tt.ProductID=t.ProductID) [End_Prev_Row],
case ky when 1 then 0
else (t.start -(select [end] from table1 tt where (tt.ky)=(t.ky-1) and tt.ProductID=t.ProductID))
end as Diff
from table1 t
SQL FIDDLE
Try something like that. It should give you the difference you want. I'm getting the first row for each product in the first part and then recursively build up by using the next Ky.
with t1
as
(
select ProductID, Ky, 0 as Difference, [End#]
from mytable where ky = 1
union all
select m.ProductID, m.Ky, m.[Start#] - t1.[End#] as Difference, m.[End#]
from mytable m
inner join t1 on m.ProductID = t1.ProductID and m.Ky = t1.Ky + 1
)
select Ky, ProductID, Difference from t1
order by ProductID, Ky
As Anup has mentioned, your query seems to be working fine, I just removed DateDiff to calculate the difference, as I assume columns are not of DATE datatype from your example, I guess that was the issue, please find below the modified query
with t1
as
( select ROW_NUMBER() OVER (PARTITION by ProductID ORDER BY ProductID ) as KY
, productid
, st
, ed
from YourTable)
select T1.ProductID, t1.ST,t1.ED, ISNULL(T1.st - T2.ed,0) as Diff
FROM T1 as T2
RIGHT OUTER JOIN T1 on T2.KY+1 = T1.KY
and T1.ProductID = T2.ProductID
SELECT ROW_NUMBER() OVER (PARTITION by rc.ContractID ORDER BY rc.ID) AS ROWID,rc.ID,rc2.ID,rc.ContractID,rc2.ContractID,rc.ToDate,rc2.FromDate
FROM tbl_RenewContracts rc
LEFT OUTER JOIN tbl_RenewContracts rc2
ON rc2.ID = (SELECT MAX(ID) FROM tbl_RenewContracts rcs WHERE rcs.ID < rc.ID AND rcs.ContractID = rc.ContractID)
ORDER BY rc.ContractID
Replace your table name and columns and add calculated column to get the DATEDIFF.