I am using SQLite and am trying to return the total of one column buy_price in the column TOTAL while at the same time returning all of the data. I do not want/need to group the data as I need to have the data in each returned row.
id date pool_name pool_id buy_price TOTAL
1 09/01/12 azp 5 20
2 09/02/12 mmp 6 10
3 09/03/12 pbp 4 5
4 09/04/12 azp 7 20
5 09/05/12 nyp 8 5 60
When I include something like SUM(buy_price) as TOTAL it only returns one row. I need all rows returned along with the total of all buy_price entries.
It sounds like this is what you are looking for:
select id,
dt,
pool_name,
pool_id,
buy_price,
(select sum(buy_price) from yourtable) total
from yourtable
see SQL Fiddle with Demo
Select * from yourtable
union
select 'Total',
' ',
' ',
' ',
sum(buy_price)
from yourtable
you can add a row on the bottom like this instead of adding a new column...
Related
quoteId price
1 50
1 50
2 10
3 40
3 40
3 40
4 10
In this table I always get the same price for each quoteId.
Example: quoteId = 1 has multiple entries with the price of 50.
By using SUM I get the total sum of the price column which is:50 + 50 + 10 + 40 + 40 + 40 + 10 = 240
However, I only want to sum the unique price for quoteId which is:
50+10+40+10 = 110
How can I approch this?
Another option is DISTINCT
Example
Select MyTotal = sum(price)
from (Select Distinct quoteId,price From YourTable) A
Returns
MyTotal
110
Following query will work:
select sum(price)
from yourTablename
group by quoteId,price;
You need a nested query to compute an intermediate value by quoteId using avg ( or max or min with your data)
But you need know why you have duplicate value by quotedId, may be you have a mistake before.
select sum(price) from (
select
quoteId,
avg(price) price,
from
your_table
group by
quoteId
) as x
This query is compliant with ISO standard SQL and will works with several database engine
I have a simple question regarding oracle sql. So i have this table
WEEKNUM DATA
1 10
2 4
3 6
4 7
So i want to make a view that shows like this,
WEEKNUM DATA ACCUM_DATE
1 10 10
2 4 14
3 6 20
4 7 27
I spend hours on this simple one but couldnt get any luck
thanks a lot
SELECT weeknum,
data,
sum(data) over (order by weeknum) accum_data
FROM your_table_name
should work. I'm using the sum analytic function here and assuming that you want to start with the smallest weeknum value and keep increasing the running total as the weeknum values increase. I'm also assuming that you never want to reset the accumulated sum. If you're trying to do something like generating an accumulated sum that restarts each year, you'd want to add a partition by to the analytic function.
You could use a Cross JOin in this case
Query:
select
A.WEEKNUM
, A.DATA
, SUM(B.DATA) DA
from table1 A
cross join table1 B
WHERE A.WEEKNUM>=B.WeekNUM
GROUP BY A.WEEKNUM
, A.DATA
order by A.WEEKNUM
Result:
WEEKNUM DATA DA
1 10 10
2 4 14
3 6 20
4 7 27
Thanks guys but i just found out this method works perfectly,
OVER (ORDER BY WEEKNUM ROWS BETWEEN UNBOUNDED PRECEDING AND CURRENT ROW) AS CUMULATIVE_WEIGHT
Or use a sub-select to calculate:
select WEEKNUM, DATA, (select sum(DATA) from tablename t2
where t2.weeknum <= t1.weeknum) as ACCUM_DATE
from tablename t1
I am dealing with a poorly designed database column which has values like this
ID cid Score
1 1 3 out of 3
2 1 1 out of 5
3 2 3 out of 6
4 3 7 out of 10
I want the aggregate sum and percentage of Score column grouped on cid like this
cid sum percentage
1 4 out of 8 50
2 3 out of 6 50
3 7 out of 10 70
How do I do this?
You can try this way :
select
t.cid
, cast(sum(s.a) as varchar(5)) +
' out of ' +
cast(sum(s.b) as varchar(5)) as sum
, ((cast(sum(s.a) as decimal))/sum(s.b))*100 as percentage
from MyTable t
inner join
(select
id
, cast(substring(score,0,2) as Int) a
, cast(substring(score,charindex('out of', score)+7,len(score)) as int) b
from MyTable
) s on s.id = t.id
group by t.cid
[SQLFiddle Demo]
Redesign the table, but on-the-fly as a CTE. Here's a solution that's not as short as you could make it, but that takes advantage of the handy SQL Server function PARSENAME. You may need to tweak the percentage calculation if you want to truncate rather than round, or if you want it to be a decimal value, not an int.
In this or most any solution, you have to count on the column values for Score to be in the very specific format you show. If you have the slightest doubt, you should run some other checks so you don't miss or misinterpret anything.
with
P(ID, cid, Score2Parse) as (
select
ID,
cid,
replace(Score,space(1),'.')
from scores
),
S(ID,cid,pts,tot) as (
select
ID,
cid,
cast(parsename(Score2Parse,4) as int),
cast(parsename(Score2Parse,1) as int)
from P
)
select
cid, cast(round(100e0*sum(pts)/sum(tot),0) as int) as percentage
from S
group by cid;
Functionality I'm trying to add to my DB2 stored procedure:
Select a MIN() date from a joined table column.
IF there was more than one row in this joined table, append a " * " to the date.
Thanks, any help or guidance is much appreciated.
It's not clear which flavor of DB2 is needed nor if any suggestion worked. This works on DB2 for i:
SELECT
T1.joinCol1,
max( T2.somedateColumn ),
count( t2.somedateColumn ),
char(max( T2.somedateColumn )) concat case when count( T2.somedateColumn )>1 then '*' else '' end
FROM joinFile1 t1 join joinFile2 t2
on joinCol1 = joinCol2
GROUP BY T1.joinCol1
ORDER BY T1.joinCol1
The SQL is fairly generic, so it should translate to many environments and versions.
Substitute table and column names as needed. The COUNT() here actually counts rows from the JOIN rather than the number of times the specific date occurs. If a count of duplicate dates is needed, then some changes to this example are also needed.
Hope this helps
Say I have result coming as
1 Jeff 1
2 Jeff 333
3 Jeff 77
4 Jeff 1
5 Jeff 14
6 Bob 22
7 Bob 4
8 Bob 5
9 Bob 6
Here the value 1 is repeated twice(in 3 column)
So, this query gets the count as 2 along with the * concatenated along with it
SELECT A.USER_VAL,
DECODE(A.CNT, '1', A.CNT, '0', A.CNT, CONCAT(A.CNT, '*')) AS CNT
FROM (SELECT DISTINCT BT.USER_VAL, CAST(COUNT(*) AS VARCHAR2(2)) AS CNT
FROM SO_BUFFER_TABLE_8 BT
GROUP BY BT.USER_VAL) A
I have a sql / sqlite question. I need to write a query that select some values from a sqlite database table. I always want the maximal returned records to be 20. If the total selected records are more than 20 I need to select 20 records that are spread evenly (no random) over the total records. It is also important that I always select the first and last value from the table when sorted on the date. These records should be inserted first and last in the result.
I know how to accomplish this in code but it would be perfect to have a sqlite query that can do the same.
The query Im using now is really simple and looks like this:
"SELECT value,date,valueid FROM tblvalue WHERE tblvalue.deleted=0 ORDER BY DATE(date)"
If I for example have these records in the talbe and to make an easier example the maximum result I want is 5.
id value date
1 10 2010-04-10
2 8 2010-04-11
3 8 2010-04-13
4 9 2010-04-15
5 10 2010-04-16
6 9 2010-04-17
7 8 2010-04-18
8 11 2010-04-19
9 9 2010-04-20
10 10 2010-04-24
The result I would like is spread evenly like this:
id value date
1 10 2010-04-10
3 8 2010-04-13
5 10 2010-04-16
7 8 2010-04-18
10 10 2010-04-24
Hope that explain what I want, thanks!
Something like this should work for you:
SELECT *
FROM (
SELECT v.value, v.date, v.valueid
FROM tblvalue v
LEFT OUTER JOIN (
SELECT min(DATE(date)) as MinDate, max(DATE(date)) as MaxDate
FROM tblvalue
WHERE tblvalue.deleted = 0
) vm on DATE(v.date) = vm.MinDate or DATE(v.date) = vm.MaxDate
WHERE tblvalue.deleted = 0
ORDER BY vm.MinDate desc, Random()
LIMIT 20
) a
ORDER BY DATE(date)
I think you want this:
SELECT value,date,valueid FROM tblvalue WHERE tblvalue.deleted=0
ORDER BY DATE(date), Random()
LIMIT 20
In other words you want select rows with date column, so that date is from the sorted list of dates, from where we take every odd element? And add the last recorded element (with the latest date)? And everything limited to max 20 rows?
If that's the case, then I think this one should do:
SELECT id,value,date FROM source_table WHERE date IN (SELECT date FROM source_table WHERE (rowid-1) % 2 = 0 OR date = (SELECT max(date) FROM source_table) ORDER BY date) LIMIT 20