I am writing out a series of files in a while loop, they are named
1.dat, 2.dat, 3.dat...
but I need the numbers to be formatted to -
00001.dat, 00002.dat, 00003.dat...
so that the file order is maintained when reading them back in. Is there a way to change the format of the while loop iterator?
Use the "format into string" node, it allows to pad integer with zeros:
Related
I have a csv file, the one from https://www.kaggle.com/jolasa/waves-measuring-buoys-data-mooloolaba/downloads/waves-measuring-buoys-data-mooloolaba.zip/1. The first entries look like this:
The first column has dates which I'm trying to read with this command:
matrix = dlmread ('waves-measuring-buoys-data/WavesMooloolabaJan2017toJun2019.csv',',',1,0);
(If referring to file on Kaggle, note that I slightly modified the directory and file names for ease of reading)
Then when I check a date by printing matrix(2,1), I get 1 instead of 01/01/2017 00:00.
How do I get the correct format?
csvread is only for numeric inputs.
Use csv2cell from the io package instead, to obtain your data as a string, and then perform any necessary string operatios and conversions accordingly.
I'm currently trying to read from a CSV files ( separated with semicolon ';') with decimal numbers formatted with a comma(,) as a decimal separator instead of a dot (.).
i.e: the number 12356.12 is stored as 12356,12.
In the source's projection, what would be the correct format to read the value correctly?
The format should in Java Decimal Format
If your CSV file's columnDelimiter is a comma (','), your first concern is how to avoid your number data won't be treated as different columns. Since your number data is stored as 12356,12, so my suggests as below :
Change the columnDelimiter as | or other special characters.
2.Set escape char. Please see this description:
In addition, 12356,12 can't be identified as Decimal format in ADF automatically. And no such mechanism o turn , into .. So I think you need to transfer data as string temporary. Then convert it into Decimal in your destination with java code.
True answer is in the comments: In the copy job the culture can be defined, which influences the decimal separator. Go to "mapping" > "Type conversion settings" > "culture" and chose en-us, de-de or whatever works for you. Be aware that this will also influence other types like dates.
I have created a Fortran 90 code to filter and convert the text output of another program in a csv form. The file contains a table with columns of various types (character, real, integer). There is a column that generally contains decimal values (probability values). BUΤ, in some rows, where the value should be decimal "1.000", the value is actually integer "1".
I use "F5.3" specifier to read this column and I have the same format statement for every row of the table. So, when the code finds "1", it reads ".001", because it does not find a decimal point.
What ways could I use to correctly (and generally) read integers among other decimals?
Could I specify "unformatted" input only for a number of "spaces"?
The data edit descriptor fw.d for floating point format specification is for input normally used with zero d (it cannot be ommited). Nonzero d is used in the rare case when the floating point data is stored as scaled integers, or you do some unit conversion from the integer values.
You could try using list-directed input: use a * instead of a format specifier. This would be for the entire read, not selected items. Or you could read the lines into a string test their contents to decide how to read them. If the sub-string has a decimal point: read (string(M:N), '(F5.3)') value. If it doesn't, use a different format, e.g., perhaps read as as F5.0.
P.S. "unformatted" is reading binary data without conversion ... it is a direct copy of the data from the file to the data item. "listed-directed" is the Fortran term for reading & converting data without using a format specification.
well here's someting new to me: f90 allows a mix of comma and space delimiters for a simple list directed read:
read(unit,*)v1,v2,v3,v4
with input
1.222 2 , 3.14 , 4
yields
1.222000 2.000000 3.140000 4.000000
I have made a program which takes a 1000 digit number as input.
It is fixed, so I put this input into the code file itself.
I would obviously be storing it as Integer type, but how do I do it?
I have tried the program by having 1000 digits in the same line. I know this is the worst possible code format! But it works.
How can assign the variable this number, and split its lines. I read somewhere something about eos? Ruby, end of what?
I was thinking that something similar to comments could be used here.
Help will be appreciated.
the basic idea is to make this work:
a=3847981438917489137897491412341234
983745893289572395725258923745897232
instead of something like this:
a=3847981438917489137897491412341234983745893289572395725258923745897232
Haskell doesn't have a way to split (non-String) literals across multiple lines. Since Strings are an exception, we can shoehorn in other literals by parsing a multiline String:
v = read
"32456\
\23857\
\23545" :: Integer
Alternately, you can use list syntax if you think it's prettier:
v = read . concat $
["32456"
,"24357"
,"23476"
] :: Integer
The price you pay for this is that some work will be done (once) at runtime, namely, the parsing (e.g. read).
I am trying out a classic format string vulnerability. I want to know how exactly the following format string works:
"%NNN$hhn" where 'N' is any number.
E.g: printf("%144$hhn",....);
How does it work and how do I use this to overwrite any address I want with arbitrary value?
Thanks and Regards,
Hrishikesh Murali
It's a POSIX extension (not found in C99) which will simply allow you to select which argument from the argument list to use for the source of the data.
With regular printf, each % format specifier grabs the current argument from the list and advances the "pointer" to the next one. That means if you want to print a single value in two different ways, you need something like:
printf ("%c %d\n", chVal, chVal);
By using positional specifiers, you can do this as:
printf ("%1$c %1$d\n", chVal);
because both format strings will use the first argument as their source.
Another example on the wikipedia page is:
printf ("%2$d %2$#x; %1$d %1$#x",16,17);
which will give you the output:
17 0x11; 16 0x10
It basically allows you to disconnect the order of the format specifiers from the provided values, letting you bounce around the argument list in any way you want, using the values over and over again, in any arbitrary order.
Now whether you can use this as an user attack vector, I'm doubtful, since it only adds a means for the programmer to change the source of the data, not where the data is sent to.
It's no less secure than the regular style printf and I can see no real vulnerabilities unless you have the power to change the format string somehow. But, if you could do that, the regular printf would also be wide open to abuse.