View Missing Numbers in a Sequence by date - sql-server-2005

Question

I have a table name "Numerator" has 3 columns: No_Fact, Numerat and Date. Like this:
No_Fact Numerat Date
1207020015 000713 2012-07-02 00:00:00.000
1207020016 000720 2012-07-02 00:00:00.000
1207020017 000722 2012-07-02 00:00:00.000
1207020019 000723 2012-07-02 00:00:00.000
1207020022 000724 2012-07-02 00:00:00.000
1207020021 000733 2012-07-02 00:00:00.000
1207020020 000734 2012-07-02 00:00:00.000
1207020018 000735 2012-07-02 00:00:00.000
1208120001 000766 2012-08-12 00:00:00.000
1208120002 000769 2012-08-12 00:00:00.000
1208230001 000777 2012-08-23 00:00:00.000
1208230002 000780 2012-08-23 00:00:00.000
I want to view some missing numbers between numbers inside Numerat column, so I have tried using the code that is:
SELECT A.Numerat+1 AS 'MISSING FROM', MIN(B.Numerat)-1 AS 'TO'
FROM Numerator A, Numerator B
WHERE A.Numerat < B.Numerat
GROUP BY A.Numerat
HAVING A.Numerat+1 < MIN(B.Numerat)
ORDER BY 1
And result set:
MISSING FROM TO
714 719
721 721
725 732
736 765
767 768
770 776
778 779
This is a code that nice.
But the sequence numbers is too many, to be incompatible with the need to be concise. So I only want to show part rows today (2012-08-23) only, likes this:
MISSING FROM TO
778 779
I am very grateful to anyone who can decode it, Thank You.
There's an interesting thing when the next line in the insert in the table,
I show began on August 23 2012:
No_Fact Numerat Date
1208230001 000777 2012-08-23 00:00:00.000
1208230002 000780 2012-08-23 00:00:00.000
1208250001 000782 2012-08-25 00:00:00.000
1208250002 000783 2012-08-25 00:00:00.000
1208250003 000784 2012-08-25 00:00:00.000
1208250004 000785 2012-08-25 00:00:00.000
1208250005 000786 2012-08-25 00:00:00.000
1208250006 000788 2012-08-25 00:00:00.000
1208250007 000789 2012-08-25 00:00:00.000
1208250008 000790 2012-08-25 00:00:00.000
1208250009 000793 2012-08-25 00:00:00.000
1208250010 000794 2012-08-25 00:00:00.000
As my original purpose, that I want to see the missing numbers in the Numerat column and to summarily I only just wanted to show a line I enter this day alone, then with advice from bluefeet I use the following code:
SELECT A.Numerat+1 AS 'MISSING FROM', MIN(B.Numerat)-1 AS 'TO'
FROM Numerator A
INNER JOIN Numerator B
ON A.Numerat < B.Numerat
AND a.Tanggal = DATEADD(DAY, DATEDIFF(DAY, 0, GetDate()), 0)
GROUP BY A.Numerat
HAVING A.Numerat+1 < MIN(B.Numerat)
ORDER BY 1
and achieving results:
MISSING FROM TO
787 787
791 792
If we look carefully there is a missing number that does not appear, that is:
MISSING FROM TO
781 781
But we do not know exactly, including the date do it? Is 23 or 25. In this case it is not important to know exactly falls on what the date this missing number, obviously there is one number missing, it should be noted, and due on the 24th of all public holidays, let us enter it on the 25th. Can anyone help?

Answer 1

Here are a few different ways to do this query, all have incorporated the date into it:
SELECT A.Numerat+1 AS 'MISSING FROM', MIN(B.Numerat)-1 AS 'TO'
FROM test A
INNER JOIN test B
ON A.Numerat < B.Numerat
AND a.dt = DATEADD(DAY, DATEDIFF(DAY, 0, GetDate()), 0)
GROUP BY A.Numerat
HAVING A.Numerat+1 < MIN(B.Numerat)
ORDER BY 1
See SQL Fiddle with Demo
Or
;with cte as
(
select numerat, dt,
row_number() over(partition by dt order by numerat) rn
from test
where dt = DATEADD(DAY, DATEDIFF(DAY, 0, GetDate()), 0)
)
select c.Numerat+1 MissingFrom, t.Numerat-1 [To]
from cte c
inner join test t
on c.Numerat < t.Numerat
where c.rn = 1
See SQL Fiddle with Demo
Or you can use a MAX() aggregate with no date:
SELECT max([Missing From]), max([to])
FROM
(
SELECT A.Numerat+1 AS 'MISSING FROM', MIN(B.Numerat)-1 AS 'TO'
FROM test A
INNER JOIN test B
ON A.Numerat < B.Numerat
GROUP BY A.Numerat
HAVING A.Numerat+1 < MIN(B.Numerat)
) x
See SQL Fiddle with Demo