My table in Oracle is like this
Col Col1 Col2 Col3 ColR
-- ---- ---- ---- ----
30 73 40 null -10
60 32 null 20 40
90 80 null null 10
80 45 81 30 50
I can also set 0 instead of null in the above column.
I need to find the min value from Col1,Col2,Col3 ignoring null or 0 and populate the ColR by subtracting from Col.
EDIT:
i wrote a CASE statement which doesn't work due to the null values inside my table.
SELECT col,col1,col2,col3,
CASE
WHEN Col1 < Col2 AND Col1 < Col3
THEN Col - Col1
WHEN Col2 < Col1 AND Col2 < Col3
THEN Col - Col2
ELSE Col - Col3
END ColR
FROM
(SELECT col,col1,
CASE
WHEN col22 IS NULL
THEN NULL( i can also SET TO 0 but it will mess WITH my other calculation TO find MIN)
ELSE ROUND( 100* ( (col22) / (col44)))
END col2 ,
CASE
WHEN col33 IS NULL
THEN NULL
ELSE ROUND( 100* ( (col33) / (col44)))
END col3
FROM TABLE
)
I have just included the case statement inside my select query. all the the column values all populated from another query.
It sounds like you want something like
SELECT least( (case when col1 is null or col1 = 0 then 999999999 else col1 end),
(case when col2 is null or col2 = 0 then 999999999 else col2 end),
(case when col3 is null or col3 = 0 then 999999999 else col3 end) )
FROM <<table name>>
where 999999999 is some numeric value that is large enough that it will always be larger than any other valid value. If it is possible that all three columns will have NULL or 0 values, then you'd probably want to add an additional check that if the result of that least function is 999999999 that you return 0 or NULL or whatever else makes sense.
#X-Zero was kind enough to put together a working SQL Fiddle example of this construct. Note that his example is filtering out the rows where all three columns have either NULL or 0 values.
// IF YOU NEED MINIMAL FROM COL1 or COL (ANY COLUMN)
SELECT MIN (COL1) FROM (SELECT * FROM TABLE WHERE COL1 IS NOT NULL)
Can you please elaborate I am not able to help you with this small set of info actually.
Oracle NVL Usage:
nvl(check_expression, replacement_value)
So
nvl(col2,0) ought to take of nulls that mess with your math.
So try:
CASE
WHEN nvl(col1,0) < nvl(col2,0) AND nvl(col1,0) < nvl(col3,0)
THEN Col - nvl(col1,0)
WHEN nvl(col2,0) < nvl(col1,0) AND nvl(col2,0) < nvl(col3,0)
THEN Col - nvl(col2,0)
ELSE Col - nvl(col3,0)
END ColR
EDIT: Taking X-Zero's point which I missed. I think if you replace the NULLS with 9999999 instead of 0, the logic will work, although that may be too specific to this sample data and not a real world solution.
If you want to ignore nulls in a column, you could wrap them with the NVL function. This replaces null values in a column with the value specified, for which you could use some large number. For example:
NVL(col1,99999)
Oracle Database SQL Reference - NVL: http://docs.oracle.com/cd/B19306_01/server.102/b14200/functions105.htm
Related
I have table like below:
I want result like even one column is null or empty string those records should not be display.
I want results like below:
select * from WHERE col1 IS NOT NULL AND col2 IS NOT NULL AND col3 IS NOT NULL AND col4 IS NOT NULL AND col5 IS NOT NULL....AND col9 IS NOT NULL
If you wanted an efficient way to do this, then one method would be a persistent computed column:
alter table t
add numNulls as ( (case when col1 is null then 1 else 0 end) +
(case when col2 is null then 1 else 0 end) +
(case when col3 is null then 1 else 0 end) +
. . .
) persisted;
You can index this column:
create index t_numNulls on t(numNulls);
And then you can use this in the select:
select t.*
from t
where num_nulls = 0;
That said, I suspect that your real problem is the data model. I am guessing that those 90 columns are really an "array" -- that is, all the same entity. These should be implemented as separate rows in a junction table.
I have two columns and I want to compare the values in each row and create a third column that will tell me true or false (or 0/1) like the below example.
Col1 Col2 Col3
24 24 true
45 45 true
56 54 false
78 98 false
Personally a CASE expression is probably the easiest and simplest way to do this.
SELECT col1,
col2,
CASE
WHEN col1 = col2 THEN 'True'
ELSE 'False'
END AS Is_A_Match
This should work for you:
select col1, col2, case when col1 = col2 then 'true' else 'false' end as col3
If you want to add a column into the table, then you can use a computed column:
alter table t add col3 as (case when col2 = col3 then 1 else 0 end)
If the columns can have NULL values and you want to treat those as equal, then the logic should take this into account.
This column is then available when referring to the table.
If you just want the result in a query, use a case expression as described in several other answers.
Simply use a case expression.
case when col1 = col2 then 'true' else 'false'
or in bit form
case when col1 = col2 then 1 else 0
How do I select a variable which gives an output the same as the excel function:
COUNTIFS(A1:D1,"<25", A1:D1, ">16")?
I.e. to count the number of times the values in my four fields are between 16 and 25.
You can do this with count() and case expressions. Note: case has an optional else clause; if it is not used, then the default else "value" is null. Count only counts non-null values, so you can combine these observations to write compact code. WHAT is counted doesn't matter; so the case expression may return a number (1 is usual, but 0 is just as valid and will give the same result, since the values are COUNTED, not SUMMED) - but you could also have a string like 'x' or a date in the case expression. Just to illustrate that, I will use a string.
select count( case when col > 16 and col < 25 then 'x' end ) as ct from your_table;
Here your_table is the name of your table, col is the name of the column containing the values, and ct is the name of the resulting column (the label for the count of values that satisfy your condition).
Of course, in a database you can get the same result more easily:
select count(*) as ct from your_table where col > 16 and col < 25;
Note, though, that the values are in one column.
If instead you have a table with four COLUMNS and many rows, and all the values in all columns are numbers, and you want to add a column showing how many values are strictly between 16 and 25 IN EACH ROW, the solution is different (but it uses the same ideas):
select col1, col2, col3, col4,
case when col1 > 16 and col1 < 25 then 1 else 0 end +
case when col2 > 16 and col2 < 25 then 1 else 0 end +
case when col3 > 16 and col3 < 25 then 1 else 0 end +
case when col4 > 16 and col4 < 25 then 1 else 0 end as ct
from my_table;
You would do this in a SQL query using case:
select sum(case when col between 16 and 25 then 1 else 0 end)
from t;
Note that between is inclusive in SQL, not exclusive, so based on your code logic:
select sum(case when col > 16 and col < 25 then 1 else 0 end)
from t;
Think, you have a 'user_table', where some of the user's 'status' are active (code-11) and others are inactive (code-22). You can count active and inactive with this sql below.
select count(case when status = 11 then 1 end) u_active, count(case when status = 22 then 1 end) u_inactive, from user_table;
I have a table like this one
ID Col1 Col2 Col3
-- ---- ---- ----
1 7 NULL 12
2 2 46 NULL
3 NULL NULL NULL
4 245 1 792
I wanted a query that yields the following result
ID Col1 Col2 Col3 MIN
-- ---- ---- ---- ---
1 7 NULL 12 7
2 2 46 NULL 2
3 NULL NULL NULL NULL
4 245 1 792 1
I mean, I wanted a column containing the minimum values out of Col1, Col2, and Col 3 for each row ignoring NULL values. In a previous question (What's the best way to select the minimum value from multiple columns?) there is an answer for non NULL values. I need a query as efficient as possible for a huge table.
Select Id,
Case When Col1 < Col2 And Col1 < Col3 Then Col1
When Col2 < Col1 And Col2 < Col3 Then Col2
Else Col3
End As MIN
From YourTableNameHere
Assuming you can define some "max" value (I'll use 9999 here) that your real values will never exceed:
Select Id,
Case When Col1 < COALESCE(Col2, 9999)
And Col1 < COALESCE(Col3, 9999) Then Col1
When Col2 < COALESCE(Col1, 9999)
And Col2 < COALESCE(Col3, 9999) Then Col2
Else Col3
End As MIN
From YourTableNameHere;
You didn't specify which version of Teradata you're using. If you're using version 14+ then you can use least.
Unfortunately least will return null if any of its arguments are null. From the docs:
LEAST supports 1-10 numeric values.
If numeric_value is the data type of the first argument, the return
data type is numeric. The remaining arguments in the input list must
be the same or compatible types. If either input parameter is NULL,
NULL is returned.
But you can get around that by using coalesce as Joe did in his answer.
select id,
least(coalesce(col1,9999),coalesce(col2,9999),coalesce(col3,9999))
from mytable
This might work:
Select id, Col1, Col2, Col3, least(Col1, Col2, Col3) as MIN From YourTableNameHere
in this way you don't need to check for nulls, just use min and a subquery
select tbl.id,tbl.col1,tbl.col2,tbl.col3,
(select min(t.col)
from (
select col1 as col from tbl_name t where t.id=tbl.id
union all
select col2 as col from tbl_name t where t.id=tbl.id
union all
select col3 as col from tbl_name t where t.id=tbl.id
)t)
from tbl_name tbl
Output:
1 7 NULL 12 7
2 2 46 NULL 2
3 NULL NULL NULL NULL
4 245 1 792 1
Just modify your query with coalesce():
Select Id,
(Case When Col1 <= coalesce(Col2, col3, col1) And
Col1 <= coalesce(Col3, col2, col1)
Then Col1
When Col2 <= coalesce(Col1, col3, col2) And
Col2 <= coalesce(Col3, col1, col2)
Then Col2
Else Col3
End) As MIN
From YourTableNameHere;
This doesn't require inventing a "magic" number or over-complicating the logic.
I found this solution to be more efficient than using multiple case statement clauses, which can get extremely lengthy when evaluating data from several columns across one row.
Also, I can't take credit for this solution as I found it on some website a year or so ago. Today I needed a refresh on this logic, and I couldn't find it anywhere. I found my old code and decided to share it in this forum now.
Creating your test table:
create table #testTable(ID int, Col1 int, Col2 int, Col3 int)
Insert into #testTable values(1,7,null,12)
Insert into #testTable values(2,2,46,null)
Insert into #testTable values(3,null,null,null)
Insert into #testTable values(4,245,1,792)
Finding min value in row data:
Select ID, Col1, Col2, Col3 ,(SELECT Min(v) FROM ( VALUES (Col1), (Col2), (Col3) ) AS value(v)) [MIN] from #testTable order by ID
Assume I have the following style table, col1 col2 and col3 have same value scopes, I want to select the records when two of the 3 columns have a value combination such as ('ab' and 'bc'), in the following example, the first 3 records should be selected. Any good way to do this? I am using Sybase.
| id | col1 | col2 | col3 |
1 ab bc null
2 null ab bc
3 ab ab bc
4 de ab xy
Thanks.
I don't have Sybase to check, but you can Try this:
select * from Table where (col1 = "ab" or col2 = "ab" or Col3 = "ab")
and (col1 = "bc" or col2 = "bc" or Col3 = "bc")
I agree that the answer given here is totally acceptable, however I feel that if there were more than a few columns that needed to be evaluated, nesting the comparisons in the WHERE clause could become a bit cumbersome and illegible. I had to overcome a similar problem and I found that the following technique was quite helpful (I have adapted it to solve the issue listed above). Note that the evaluation of Total in the outer query can be easily adapted to increase or decrease the number of columns that contain the criteria being evaluated:
SELECT *
FROM
(SELECT id
, col1
, col2
, col3
, SUM(CASE WHEN UPPER(col1) IN ('AB', 'BC') THEN 1 ELSE 0 END
+ CASE WHEN UPPER(col2) IN ('AB', 'BC') THEN 1 ELSE 0 END
+ CASE WHEN UPPER(col3) IN ('AB', 'BC') THEN 1 ELSE 0 END) as Total
FROM <table>
GROUP BY id
, col1
, col2
, col3) as results
WHERE Total >= 2
ORDER BY id