Yii DAO implementation. - yii

If I only use DAO to save data in Yii , can I use the rules function of the model ? Of course I would not be declaring AR instance . Can I still validate using rules function ?

Create a new model class extending CModel.
Create the rules method as normal.
You can then do
$model = new MyModel();
$model->myAttribute = 'value';
if ($model->validate())
{
Yii::app()->db->createCommand()
->update(
'MyTable',
array('myAttribute' => $model->myAttribute),
'key=:id',
array(':id' => 'key')
);
}

Yes, you can use without problems.
Here are some links that can help you:
http://www.yiiframework.com/doc/guide/1.1/en/database.dao
http://www.yiiframework.com/forum/index.php/topic/25825-dao-vs-activerecord-methods/
http://www.sheldmandu.com/php/php-mvc-frameworks/yii-dao-vs-active-record-performance

Related

Can't insert into database with save()

I am having an issue inserting a record into the database. I am a beginner with the Yii framework, so I may have made some stupid mistakes.
This is from the SiteController
public function actionCreatePost(){
$model = new PostForm();
$post = new Post();
if ($model->load(Yii::$app->request->post()) && $model->validate()) {
$post->body = $model->body;
$post->title = $model->title;
$post->save();
return $this->redirect('index');
}else {
return $this->render('createPost', ['model' => $model]);
}
}
This is from the Post class
public function behaviors()
{
return [
[
'class' => TimestampBehavior::className(),
'createdAtAttribute' => 'created_at',
'updatedAtAttribute' => 'updated_at',
'value' => new Expression('NOW()'),
],
[
'class' => BlameableBehavior::className(),
'createdByAttribute' => 'id_author',
]
];
}
The issue is that you have created a PostForm class for the form (which is correct) but you are then trying to load the response into the Post class - a completely different class. This won’t work without modification.
If you have a look at the response:
var_dump(Yii:$app->request->post());
You will see the form data is located within the PostForm key. Yii will therefore only load the data into the PostForm class.
The correct solution is therefore to create a savePost() function within the PostForm eg:
public function savePost(){
$model = new Post();
$model->propertyABC = $this->propertyABC
...etc...
$model->save();
So the action would appear as follows:
$model = new PostForm();
If($model->load(Yii::$app->request->post()) && $model->validate()){
$model->savePost();
The other option is to rename the key from PostForm to Post. Yii will then load the data but this is not the best approach as it is a bit obscure.
Hope that helps
I would guess the issue is with the validation.
I can see several issues I will point out. First, I cannot figure out why are you creating a new PostForm, loading the data in it and verifying it, just to dump some values in a new Post and save it. Are there some functions, you are running in the PostForm model, that are triggered by load or verify? If that is not the case, I would suggest dropping one of the models, and using only the other. Usually, that is the Form model. It serves as a link between the ActiveForm and the model handling everything. You can do everything in the createPost() function in the Form model, and then in the controller it will look like
if ($model->load(Yii::$app->request->post())) {
$model->save();
return $this->redirect('index');
}
Second of all, you can dump post->getErrors() before the save to see if there are any errors with the validation. What you can also do, is call $post->save(false) instead. If you pass false to it, it will not trigger $post->validate(), and some errors can be neglected. Please, let me know if there is anything unclear.

Yii - Calling api request within CConsole

I have the following issue:
I have a local db with comments and I need to do some actions with some users I'm getting via an API request.
Code is something like this:
class RunCronCommand extends CConsoleCommand {
public function actionIndex() {
...
$comments = Comment::model()->findAll('status = :status', array(':status' => Comment::ACTIVE));
foreach ($comments as $comment) {
$profile = Yii::app()->api->get('/users/'. $comment->user_id . '/getProfile');
}
...
}
When I execute the command I'm getting this error
exception 'CException' with message 'Property "CConsoleApplication.api" is not defined.' in /var/www/core/trunk/common/lib/Yii/base/CComponent.php:131
Any thoughts?
thanks in advance!
Thank you for your reply.
Got it fixed by adding the class into console/config/main.php
'components' => array(
'api' => array(
'class' => 'common.extensions.Api.Api'
),
You will have to rethink the design of the application.
From your example, you might want to use Curl, although I think this might be overkill/
To run an action in a controller, you can use something like
Yii::import('application.modules.moduleName.controllers.ControllerName');
$controller_instance = new ControllerName("Default");
$controller_instance->actionIndex();
Look here for additional information.

Instantiate model with columns

How can I instantiate a model and get all columns already declared in the instance?
$modelA = User::findFirst();
echo $modelA->id; //OK
$modelB = new User();
echo $modelA->id; //Id is undeclared causing errors instead of returning blank
Currently I need to declare by hand the model columns in the event onConstruct but I want to make use of the database introspection strategy and get properties declared from the table schema schema when I use new User();.
Anyone knows something that can help me out?!
Try the Annotations Strategy mentioned on that page.
So, something like
class Test extends \Phalcon\Mvc\Model
{
/**
* #Primary
* #Identity
* #Column(type="integer", nullable=false)
*/
public $id;
...
Get an instance of the meta-data adapter from the services container:
<?php
use Phalcon\Mvc\Model\MetaData\Apc as ApcMetaData,
Phalcon\Mvc\Model\MetaData\Strategy\Annotations as StrategyAnnotations;
$di['modelsMetadata'] = function() {
// Instantiate a meta-data adapter
$metaData = new ApcMetaData(array(
"lifetime" => 86400,
"prefix" => "my-prefix"
));
Get the columns for your model like so:
<?php
$test = new Test();
// Get Phalcon\Mvc\Model\Metadata instance
$metaData = $test->getModelsMetaData();
// Get fields names
$attributes = $metaData->getAttributes($test);
print_r($attributes);
// Get fields data types
$dataTypes = $metaData->getDataTypes($test);
print_r($dataTypes);
All of the above can be found in the link.
Also check out the MetaData APIs.
Hope that helps.

zend_db standalone

i want to use zend_db standalone cos zend framework is too much for my project but i'm new with it,
is it correct to do this:
$pdoParams = array(PDO::MYSQL_ATTR_INIT_COMMAND => 'SET NAMES
UTF8;');
$params = array(
'host' => 'localhost',
'username' => 'ss_fraat',
'password' => 'jos10',
'dbname' => '_a2hDB',
'driver_options' => $pdoParams
);
try {
$db = Zend_Db::factory('PDO_MYSQL', $params);
//set default adapter
Zend_Db_Table_Abstract::setDefaultAdapter($db);
} catch (Exception $e) {
exit($e->getMessage());
}
//save Db in registry for later use
Zend_Registry::set('dbAdapter', $db);
then in any class do this:
$db = Zend_Registry::get('db');
/** quote to avoid sql injection */
$date = $db->quote('1980-01-01');
$sql = 'SELECT * FROM product WHERE name = ' . $date;
$result = $db->query($sql);
$db->query(); //run a query
i really need to do this
Zend_Db_Table_Abstract::setDefaultAdapter($db);
i get this code from a website,
is it necessary to use Zend_Db_Table_Abstract if i'm not using the full zend framework,
or it is better for example to use this:
$db = Zend_Db::factory( ...options... );
$select = new Zend_Db_Select($db);
what i want is to setup a pdo/mysql connexion in my bootstrap php page and be able to get that db instance in any class without starting a new connexion to execute queries but i'm not sure how to do that use Zend_Db_Table_Abstract or Zend_Db_Select use the registry Zend_Registry::set('dbAdapter', $db) or not
thanks a lot
The purpose of Zend_Db_Table_Abstract is so you can create your own model classes based around the Table Data Gateway design pattern. The idea of that pattern is that you have a class that encapsulates all the sql you would need for interfacing with a table. So the assumption is that you will be creating model classes that extend Zend_Db_Table_Abstract for each table. If you are going to do that, then you will want to call Zend_Db_Table_Abstract::setDefaultAdapter($db) in your setup/bootstrap. Recent versions of ZF provide as an alternative a quick way of getting basic functionality without having to create a custom class definition by just instantiating Zend_Db_Table:
$userTable = new Zend_Db_Table('users');
In summary, none of this particularly has to do with the MVC part of the framework, although some people choose to use Zend_db as the basis for db connections and models, instead of using a more fully featured ORM like Doctrine or Propel.
The other code you provided simply illustrates that you do not need to use Zend_Db_Table_Abstract either -- you can simply setup an instance of a Zend_Db_Adapter and use that instance to call query() or its other methods.

CakePHP: get user info in models

I'm moving some of my find code inside models.
Previously in my controller I had
$this->Book->Review->find('first', array(
'conditions' => array(
'Review.book_id' => $id,
'Review.user_id' => $this->Auth->user('id')
)
));
so in my Review model I put something like
function own($id) {
$this->contain();
$review = $this->find('first', array(
'conditions' => array(
'Review.book_id' => $id,
'Review.user_id' => AuthComponent::user('id')
)
));
return $review;
}
So I'm calling AuthComponent statically from the Model. I know I can do this for the method AuthComponent::password(), which is useful for validation. But I'm getting errors using the method AuthComponent::user(), in particular
Fatal error: Call to a member function
check() on a non-object in
/var/www/MathOnline/cake/libs/controller/components/auth.php
on line 663
Is there a way to get the info about the currently logged user from a model?
Create a new function in the "app_model.php" ("AppModel.php" in CakePHP 2.x), so it will be available at all models within our application:
function getCurrentUser() {
// for CakePHP 1.x:
App::import('Component','Session');
$Session = new SessionComponent();
// for CakePHP 2.x:
App::uses('CakeSession', 'Model/Datasource');
$Session = new CakeSession();
$user = $Session->read('Auth.User');
return $user;
}
in the model:
$user = $this->getCurrentUser();
$user_id = $user['id'];
$username = $user['username'];
The way that I use is this:
App::import('component', 'CakeSession');
$thisUserID = CakeSession::read('Auth.User.id');
It seems to work quite nicely :-)
I think the code is fine as it is and belongs in the Controller, or at the very least it needs to receive the ids from the Controller and not try to get them itself. The Model should only be concerned with fetching data from a data store and returning it. It must not be concerned with how the data is handled in the rest of the application or where the parameters to its request are coming from. Otherwise you paint yourself into a corner where the ReviewModel can only retrieve data for logged in users, which might not always be what you want.
As such, I'd use a function signature like this:
function findByBookAndUserId($book_id, $user_id) {
…
}
$this->Review->findByBookAndUserId($id, $this->Auth->user('id'));
There is a nice solution by Matt Curry. You store the data of the current logged user in the app_controller using the beforeFilter callback and access it later using static calls. A description can be found here:
http://www.pseudocoder.com/archives/2008/10/06/accessing-user-sessions-from-models-or-anywhere-in-cakephp-revealed/
EDIT: the above link is outdated: https://github.com/mcurry/cakephp_static_user
I think this is not good idea to get value from Session. Better solution to get logged user id inside any model simply try this:
AuthComponent::user('id');
This will work almost every where. View, Model and Controller
Dirtiest way would be to just access the user information in the Session. Least amount of overhead associated with that.
The "proper" way would probably be to instantiate the AuthComponent object, so that it does all the stuff it needs to be fully operational. Much like a death star, the AuthComponent doesn't really work well when not fully setup.
To get a new AC object, in the model:
App::import( 'Component', 'Auth' );
$this->Auth = new AuthComponent();
Now you can use $this->Auth in the model, same as you would in the controller.
For CakePHP 3.x this easy component is available: http://cakemanager.org/docs/utils/1.0/components/globalauth/. Direct accessing the Session is not possible because of different SessionKeys.
With the GlobalAuthComponent you can access your user-data everywhere with: Configure::read('GlobalAuth');.
Greetz
Bob
I use cake 2.2 and these both work great:
$this->Session->read('Auth.User');
//or
$this->Auth->user();
You can also get a field of currently logged in user:
$this->Session->read('Auth.User.email');
//or
$this->Auth->user()['email'];
None of these solutions work in CakePHP version 3. Anyone know of a way to do this? Right now, I'm completely stepping around the framework by accessing the $_SESSION variable directly from my model.