I would like help with this sql. I need to find the latest date for each circuit ID (field name-strip_ec_circuit_id) based on a created date(field name-create_bill_date). I need to only find the latest date, while the other ones can be deleted. Can you help me do this?
This is a basic group by query that should work in any database:
select strip_ec_circuit_id, max(create_bill_date) as lastDate
from t
group by strip_ec_circuit_id
I'm not sure what you mean by delete all the others. Do you actually want to delete the rows from the table that are not the max?
Related
I was trying to understand how history tables work in HANA.
I have a query whether the following requirement can be achieved using history table.
Suppose, I've a table which maintains site and article wise STOCK.
The STOCK gets updated according to the change in inventory.
Now, if I want the current as well as the previous picture of site-article wise stock can I use the history table for same.
I created a history table and inserted a row in it which gives output :
SELECT site,article,stock FROM PH_STOCK_HISTORY AS OF utctimestamp '2019-05-22 12:36:17.909';
I updated the stock and re-run the query :
SELECT site,article,stock FROM PH_STOCK_HISTORY AS OF utctimestamp '2019-05-22 12:37:38.55'
Now, I want to get the earlier and the current picture of my stock in the same query.
Is that feasible to achieve this ?
May be you can achieve this by Union query.
SELECT site,article,stock FROM PH_STOCK_HISTORY AS OF utctimestamp '2019-05-22 12:36:17.909'
union
SELECT site,article,stock FROM PH_STOCK_HISTORY AS OF now();
Try this :)
I am trying to write a query to find out whether a record exist more than one or not in a given period of time. And even if it exist, how many times the same record has been repeated.
Now to solve this issue, I have sorted the records.
select * from table_name where date = ? and date > ? order by email
And trying to count the number of times the same record exist.But I am not able to figure out a way to count the number of times the same record exists.
Here is a problem.The image below holds the basic data structure.
Here is the expected output for a year
The table above holds Xyz name and xyz#email.com data three times. And the name Abc and email abc#email.com two times and the third record name Def and email def#email.com two times. Now what I am trying to figure out a way to find out the number of times each records are being repeated in a given period of time using a single query. I am thinking to make use of recursion on a record and count till it didn't find a different record after sorting it. But using recursion on every records seems expensive.
Is there a better solution to solve this problem ?
Regards
Group and count.
SELECT column_to_compare1, column_to_compare2, COUNT(*)
FROM table_name
WHERE [date] BETWEEN #date1 AND #date2
GROUP BY column_to_compare1, column_to_compare2
HAVING COUNT(*) > 1 -- IF YOU WANT TO ONLY INCLUDE RECORDS WITH DUPLICATES
Between is inclusive, so you can adjust your dates with DATEADD if you really want between.
You can use the COUNT function to do this.
To do this using your own query:
SELECT Name, Email, COUNT(*) AS count
FROM table_name
WHERE date BETWEEN '01/01/2005' AND '31/12/2005'
GROUP BY Name, Email
However your example query is poor so I cannot give you a better solution. Here is an example of this working: SQL Fiddle
EDIT: Updated my solution to match you expected output.
I have been struggling with creating a query in Access to select a distinct field with the criteria of having the newest entry in the database.
Heres a brief summary of how what my table conssists of. I have a table with surveying data collected from 2007 to the present. We have field with a survey marks name with corresponding adjustment data. In the corresponding data there is field with the adjusmtent date. Many of the marks have been occupied mutiple times and only want to retrieve the most recent occupation information.
Roughly i want to
SELECT DISTINCT STATUS_POINT_DESIGNATION
FROM __ALL_ADJUSTMENTS
WHERE [__ALL_ADJUSMENTS]![ADJ_DATE]=MAX(ADJ_DATE)
I seem to be getting confused how relate the select a distinct value with a constraint. Any Suggestions?
DH
Seems you could achieve your aim of getting the latest observation for each survey point by a summary function:
SELECT STATUS_POINT_DESIGNATION, Max(ADJ_DATE) AS LatestDate, Count(STATUS_POINT_DESIGNATION) AS Observations
FROM __ALL_ADJUSTMENTS
GROUP BY STATUS_POINT_DESIGNATION;
I have written SQL query which brings data from multiple tables and displays the same in this format..
I want the Sum of Total for every person and display in a new column, like the below.
Can you point some examples doing same kind of stuff please..
If your RDBMS supports windowed aggregates you can add
,SUM(Total) OVER (PARTITION BY Name/*Or PersonId if not unique*/) AS All_Total
to your SELECT list
look for "sum" and "group by". But note, that grouping by name will invalidate the startDate and endDate.
edit: ah, mssql - nvm ;)
I am trying to develop a SQL Server 2005 query but I'm being unsuccessful at the moment. I trying every different approach that I know, like derived tables, sub-queries, CTE's, etc, but I couldn't solve the problem. I won't post the queries I tried here because they involve many other columns and tables, but I will try to explain the problem with a simpler example:
There are two tables: PARTS_SOLD and PARTS_PURCHASED. The first contains products that were sold to customers, and the second contains products that were purchased from suppliers. Both tables contains a foreign key associated with the movement itself, that contains the dates, etc.
Here is the simplified schema:
Table PARTS_SOLD:
part_id
date
other columns
Table PARTS_PURCHASED
part_id
date
other columns
What I need is to join every row in PARTS_SOLD with a unique row from PARTS_PURCHASED, chose by part_id and the maximum "date", where the "date" is equal of before the "date" column from PARTS_PURCHASED. In other words, I need to collect some information from the last purchase event for the item for every event of selling this item.
The problem itself is that I didn't find a way of joining the PARTS_PURCHASED table with PARTS_SOLD table using the column "date" from PARTS_SOLD to limit the MAX(date) of the PARTS_PURCHASED table.
I could have done this with a cursor to solve the problem with the tools I know, but every table has millions of rows, and perhaps using cursors or sub-queries that evaluate a query for every row would make the process very slow.
You aren't going to like my answer. Your database is designed incorrectly which is why you can't get the data back out the way you want. Even using a cursor, you would not get good data from this. Assume that you purchased 5 of part 1 on May 31, 2010. Assume on June 1, you sold ten of part 1. Matching just on date, you would match all ten to the May 31 purchase even though that is clearly not correct, some parts might have been purchased on May 23 and some may have been purchased on July 19, 2008.
If you want to know which purchased part relates to which sold part, your database design should include the PartPurchasedID as part of the PartsSold record and this should be populated at the time of the purchase, not later for reporting when you have 1,000,000 records to sort through.
Perhaps the following would help:
SELECT S.*
FROM PARTS_SOLD S
INNER JOIN (SELECT PART_ID, MAX(DATE)
FROM PARTS_PURCHASED
GROUP BY PART_ID) D
ON (D.PART_ID = S.PART_ID)
WHERE D.DATE <= S.DATE
Share and enjoy.
I'll toss this out there, but it's likely to contain all kinds of mistakes... both because I'm not sure I understand your question and because my SQL is... weak at best. That being said, my thought would be to try something like:
SELECT * FROM PARTS_SOLD
INNER JOIN (SELECT part_id, max(date) AS max_date
FROM PARTS_PURCHASED
GROUP BY part_id) AS subtable
ON PARTS_SOLD.part_id = subtable.part_id
AND PARTS_SOLD.date < subtable.max_date