I'm implementing my drag&drop method. I need that when user drags something on my app window I can get that file URL. NSURL needs to be converted to char. Thats OK. But how to remove file:// from url? My current code:
pboard = [sender draggingPasteboard];
NSString *url = [[NSURL URLFromPasteboard:pboard] absoluteString];
input_imageN = strdup([url UTF8String]);
its OK, but it gives url with file:// prefix. I tried using
NSURL *fileUrl = [[NSURL URLFromPasteboard:pboard] isFileURL];
NSString *url = [fileUrl absoluteString];
NSLog(#"url: %#", [NSURL URLFromPasteboard:pboard]);
input_imageN = strdup([url UTF8String]);
but it says that
Cannot initialize a variable of type 'NSURL *' with an rvalue of type 'BOOL' (aka 'signed char')
at
NSURL *fileUrl = [[NSURL URLFromPasteboard:pboard] isFileURL];
To go from a file URL to the path as a C string in the appropriate representation for the filesystem, you'd do:
NSURL *fileURL = [NSURL URLFromPasteboard: pboard];
NSString *filePath = [fileURL path];
char *filesystemRepresentation = [filePath filesystemRepresentation];
This avoids assumptions that stripping off the scheme leaves you with just the path, or that the filesystem is definitely happy accepting UTF8-encoded paths.
url = [url stringByReplacingOccurencesOfString:#"file://" withString:#""];
Hope this helps. Cheers!
#user23743's answer is correct. Since iOS 7 though NSURL has its own filestSystemRepresentation method.
In Swift:
if let fileURL = NSURL(fromPasteboard: pboard) {
let representation = fileURL.fileSystemRepresentation
}
if let fileURL = NSURL(from: pboard)?.filePathURL {
}
has been most effective for me.
Related
What are the rules for passing the string parameter such as %JOHN% in a GET request url
my request url is supposed to look like: https://somesite.com/search/name?name=%SEARCH_KEYWORD%
Try#1: I did this
NSURL* url = [NSURL URLWithString:[NSString stringWithFormat:#"https://somesite.com/search/name?name=%%%#%%",SEARCH_KEYWORD]];
O/P: nil
Try#2:
NSURL* url = [NSURL URLWithString:[NSString stringWithFormat:#"https://somesite.com/search/name?name=%JOE%"]];
**O/P:
https://somesite.com/search/name?name=JOE
Any suggestions?
You can use NSURLComponents to build URLs:
Objective-C:
NSURLComponents *components = [NSURLComponents componentsWithString:#"https://google.com"];
components.query = #"s=%search keywords%"
NSURL *url = components.URL;
Swift (careful with ! in production, I used to test in Playgrounds):
let components = NSURLComponents(string: "https://google.com")!
components = "s=%search keywords%"
let url = components!
print(url) // "https://google.com?s=%25search%20keywords%25"
Also if you need more complex queries NSURLComponent have a queryItems property.
You are making a mistake, just use a single %#.
Example:
NSString *string = #"JOE";
NSURL *url = [[NSURL alloc] initWithString:[NSString stringWithFormat:#"https://somesite.com/search/name?name=%#",string]];
I have an NSTextView control that could potentially have links in it. How do I get the full url of the link?
Here is what I have so far
-(BOOL)textView:(NSTextView *)aTextView clickedOnLink:(id)aLink atIndex:(NSUInteger)charIndex
{
NSURL *htmlURL = [NSURL fileURLWithPathComponents:[aLink pathComponents]];
}
This gives me a URL that begins with file://localhost ... How do I get rid of that portion of the URL?
NSURL* url = [NSURL URLWithString:#"http://localhost/myweb/index.html"];
NSString* reducedUrl = [NSString stringWithFormat:
#"%#://%#",
url.scheme,
[url.pathComponents objectAtIndex:1]];
I have the following code that makes a Google Places API request. The parameters are statically set at the moment. How would I go about making those parameters (types and lat/lon and the Google Key - which I've defined as a constant in the .h file) objects instead?
My problem arises with the NSURL because I can't add format specifiers to it.
thanks for any help.
-(void)ParseXML_of_Google_PlacesAPI
{
NSURL *googlePlacesURL = [NSURL URLWithString:#"https://maps.googleapis.com/maps/api/place/search/xml?location=34.0522222,-118.2427778&radius=500&types=bar&sensor=false&key=MyGoogleAPIKey"];
NSData *xmlData = [NSData dataWithContentsOfURL:googlePlacesURL];
xmlDocument = [[GDataXMLDocument alloc]initWithData:xmlData options:0 error:nil];
NSArray *arr = [xmlDocument.rootElement elementsForName:#"result"];
for(GDataXMLElement *e in arr )
{
[placesOutputArray addObject:e];
}
Good ol' stringWithFormat?
`NSString* urlToCall = [NSString stringWithFormat:#"http:://url.to.webservice/api?param1=%#¶m2=%#", param1, param2]`
This may be helpful for you
float lat=34.0522222,lon=-118.2427778;
NSString *typestr=#"bar";
NSString *key=#"MyGoogleAPIKey";
NSURL *url=[NSURL URLWithString:[NSString stringWithFormat:#"https://maps.googleapis.com/maps/api/place/search/xml?location=%f,%f&radius=500&types=%#&sensor=false&key=%#",lat,lon,typestr,key]];
NSLog(#"url values ==%#",url);
Format specifiers directly to NSURL like this:
NSURL *googlePlacesURL = [NSURL URLWithString:[NSString stringWithFormat:#"http:://url.to.webservice/api?param1=%#%param2=%#", param1, param2]];
I'm trying to load an audio file into AVAudioPlayer on the iPad. When I run it on the iPad it finds it in the bundle fine. However, if I try and run it through the simulator, I get a null error for NSURL. Here's the snippet of code (num is an arbitrary int):
NSString *name = [NSString stringWithFormat:#"st-answermachine-%i", num];
NSLog(#"name = %#", name);
NSString *path = [[NSBundle mainBundle] pathForResource:name ofType:#"m4a"];
NSLog(#"path = %#", path);
NSURL *url = [NSURL URLWithString:path];
NSLog(#"url = %#", url);
In the simluator, the Debugger Console traces this:
name = st-answermachine-1
path = /Users/joe/Library/Application Support/iPhone Simulator/3.2/Applications/B85E9CC8-6E39-47B9-XXXX-1E3A2CE145D1/MyApp.app/st-answermachine-1.m4a
url = (null)
But if I try it on the device, I get this:
name = st-answermachine-1
path = /var/mobile/Applications/116DA1CB-EA13-4B80-XXXX-EBD46C8E2095/MyApp.app/st-answermachine-1.m4a
url = /var/mobile/Applications/116DA1CB-EA13-4B80-XXXX-EBD46C8E2095/MyApp.app/st-answermachine-1.m4a
Any ideas why I might have this problem please?
Thanks!
URLWithString: expects a string containing an actual URL as its parameter (e.g. 'http://blah/' or 'file:///blah'). URLs can't contain spaces (as the simulator's path does), and that's why it's failing.
As Evan suggests, you need to use fileURLWithPath: to convert a path string to a URL object.
I am having string at first the method calls with timestamp value nil and I am getting converted the string into url .next time when I click load more results button again the method calls with time stamp value assigned to it.but the url string is not converting into NSURL iam getting the null value into it.
-(NSMutableArray*)getTextMessagesArray:(NSString *)endTimestamp
{
printf("\n endtimestamp value...%s",[endTimestamp UTF8String]);
NSString *urlString = #"http://123.237.186.221:8080/upload/textRequest.jsp";
urlString = [urlString stringByAppendingString:#"?beginTimestamp="];
urlString = [urlString stringByAppendingString:#"&endTimestamp="];
if([endTimestamp length]>0)
{
urlString = [urlString stringByAppendingString:endTimestamp];
}
printf("\n &*(*(((urlString...%s",[urlString UTF8String]);
NSURL* aUrl = [NSURL URLWithString:urlString];
NSLog(#"url in appdelegaare in text...%#",aUrl);
[textParser parseXMLFileAtURL:aUrl];
textMessagesList = [textParser getTextMessagesList];
printf("\n textMessagesList Count in appDelegate....%d",[textMessagesList count]);
return textMessagesList;
}
The result I am getting in console is:
&*(*(((urlString...http://123.237.186.221:8080/upload/textRequest.jsp?endTimestamp=2010-10-08 16:20:47.0
url in appdelegaare in text...(null)
Guy's can any one suggest me why this happening
Anyone's help will be much appreciated.
Thanks to all,
Monish.
Your problem is that valid URLs cannot contains spaces. You want to do something along the following lines:
NSString *escapedUrlString = [urlString stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
// escapedUrlString should be "http://123.237.186.221:8080/upload/textRequest.jsp?endTimestamp=2010-10-08%2016:20:47.0"
NSURL *aUrl = [NSURL URLWithString:escapedUrlString];
This might be what you wanted.