Objective C - How to receive two int in same parameter - objective-c

Question

I need to write a method like this:
-(void)doStuff:(int)options;
Based in the a typedef enum like this:
typedef enum
{
FirstOption,
SecondOption,
ThirdOption
} MyOptions
What I need to to do in order to be able to call the method in this way (i.e. calling the method with more than one option "enabled":
[self doStuff:(FirstOption | ThirdOption)];
Do I need to setup the typedef enum differently? And how I check the options received in the method, a simple if (options == ...)?

Answer 1

What you call for is a bit array. Define your options like this:
enum MyOptions
{
FirstOption = 0x01, // first bit
SecondOption = 0x02, // second bit
ThirdOption = 0x04, // third bit
... = 0x08 ...
};
Combine the options like you suggested, with |, and test for them with & (options & SecondOption).
- (void) doStuff: (MyOptions) options
{
if ( options & FirstOption )
{
// do something fancy
}
if ( options & SecondOption )
{
// do something awesome
}
if ( (options & SecondOption) && ( options & ThirdOption) )
{
// do something sublime
}
}

Answer 2

I'm no expert at Obj-C, but in other languages I would use flags. If each value is a power of two, then it will have only one bit set for that value. You can use that bit as a bool for a particular option.
FirstOption = 1
SecondOption = 2
ThirdOption = 4
FirstAndThird = FirstOption | ThirdOption; // Binary Or sets the bits
// Binary And checks the bits
IsFirst = FirstAndThird & FirstOption == FirstOption; // is true
IsSecond = FirstAndThird & SecondOption == SecondOption; // is false
IsThird = FirstAndThird & ThirdOption == ThirdOption; // is true
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