I have a contact table that includes the length of time each contact lived in the neighborhood:
ID First_Name Last_Name Neighborhood_Time
1 John Smith 1-2 years
2 Mary Jones 2-5 years
3 Dennis White 2-5 years
4 Martha Olson 5+ years
5 Jeff Black 5+ years
6 Jean Rogers 2-5 years
I want to show the percentage of time, the result would look like this:
One_to_2_Years Two_to_5_Years 5+_Years
16 50 33
This is what I'm using:
select
sum(case when Neighborhoods_time ='1-2 years' then 1 else 0 end)*100/(select count(*) from contact) as One_to_2_Years,
sum(case when Neighborhoods_time ='2-5 years' then 1 else 0 end)*100/(select count(*) from contact) as Two_to_6_Years,
sum(case when Neighborhoods_time ='5+years' then 1 else 0 end)*100/(select count(*) from contact) as Six_to_10_Years
from dbo.contact
This is my result:
One_to_2_Years Two_to_5_Years 5+_Years
0 0 16
16 33 0
0 16 16
I see the numbers under each column are correct, I'm having a problem summing them.
What am I missing?
Thanks.
Add Group by Neighborhoods_time
The basis of your query can be produced like
select
Neighborhood_Time,
100*COUNT(*)/(Select COUNT(*) from contact) as percentvalue
from
contact
group by
Neighborhood_Time
If you want to arrange it horizontally, then you should use a pivot
select
*
from
(
select
Neighborhood_Time,
100*COUNT(*)/(Select COUNT(*) from contact) as percentvalue
from
contact
group by
Neighborhood_Time
) src
PIVOT
( SUM(percentvalue) for Neighborhood_Time in ([1-2 years],[2-5 years],[5+ years])) as pt
Related
This question already has answers here:
SUM of grouped COUNT in SQL Query
(17 answers)
Closed 12 months ago.
There is this query:
select town, count(town)
from user
group by town
which returns
Town Count
Copenhagen 5
NewYork 6
Athens 7
But I would like an additional line which shows all towns number:
Town Count
Copenhagen 5
NewYork 6
Athens 7
All 18
Probably not the best way, but I believe this should work:
WITH counts_by_town AS (
SELECT town, COUNT(town) AS cnt
FROM user
GROUP BY 1
)
SELECT town, cnt
FROM counts_by_town
UNION ALL
SELECT 'All' AS town, SUM(cnt) AS cnt
FROM counts_by_town;
This is my table:
index_melanoma_yr Total_Melanoma Total_Virus
2000 700 12
2001 746 7
2002 724 12
2003 815 15
2004 893 16
2005 1020 22
I would like to count by 5 year increments. So, 2000-2004, 2005-2009, etc. I can hard code this, but since there are so many years, I'm wondering if there is a more efficient way.
Here's how I got the initial counts:
SELECT index_melanoma_yr,
COUNT(DISTINCT PersonID) AS Total_Melanoma,
SUM( CASE
WHEN index_virus_yr IS NOT NULL THEN
1
ELSE
0
END
) AS Total_Virus
FROM Asare_ViralMelanoma_IndexDates
GROUP BY index_melanoma_yr
ORDER BY index_melanoma_yr
you can perform some simple maths year / 5 * 5 on the year column, and then GROUP BY that. Assuming that the year column is integer
SELECT MIN(index_melanoma_yr) AS Year_Start,
MAX(index_melanoma_yr) AS Year_End,
COUNT(DISTINCT PersonID) AS Total_Melanoma,
SUM( CASE
WHEN index_virus_yr IS NOT NULL THEN
1
ELSE
0
END
) AS Total_Virus
FROM Asare_ViralMelanoma_IndexDates
GROUP BY index_melanoma_yr / 5 * 5
ORDER BY Year_Start
The simple SELECT query would return the data as below:
Select ID, User, Country, TimeLogged from Data
ID User Country TimeLogged
1 Samantha SCO 10
1 John UK 5
1 Andrew NZL 15
2 John UK 20
3 Mark UK 10
3 Mark UK 20
3 Steven UK 10
3 Andrew NZL 15
3 Sharon IRL 5
4 Andrew NZL 25
4 Michael AUS 5
5 Jessica USA 30
I would like to return a sum of time logged for each user grouped by ID
But for only ID numbers where both of these values Country = UK and User = Andrew are included within their rows.
So the output in the above example would be
ID User Country TimeLogged
1 John UK 5
1 Andrew NZL 15
3 Mark UK 30
3 Steven UK 10
3 Andrew NZL 15
First you need to identify which IDs you're going to be returning
SELECT ID FROM MyTable WHERE Country='UK'
INTERSECT
SELECT ID FROM MyTable WHERE [User]='Andrew';
and based on that, you can then filter to aggregate the expected rows.
SELECT ID,
[User],
Country,
SUM(Timelogged) as Timelogged
FROM mytable
WHERE (Country='UK' OR [User]='Andrew')
AND ID IN( SELECT ID FROM MyTable WHERE Country='UK'
INTERSECT
SELECT ID FROM MyTable WHERE [User]='Andrew')
GROUP BY ID, [User], country;
So, you have described what you need to write almost perfectly but not quite. Your result table indicates that you want Country = UK OR User = Andrew, rather than AND
You need to select and group by, then include a WHERE:-
Select ID, User, Country, SUM(Timelogged) as Timelogged from mytable
WHERE Country='UK' OR User='Andrew'
Group by ID, user, country
I have two tables employee and department,Employee table schema(Eid,Ename,DOJ,Sal,Dept ID) and Department schema(Dept id,Dname).So what i want in output is count the no. of employee by each department and according to experience.
Output:
dept |0-5yrs|5-10yrs|10-15yrs
HR | 4 | 9 | 0
Account | 2 | 3 | 1
what I mean by the output is 4 employees in HR department have less than 5 years of experience and 9 people have more than 5 and less than 10 years of experience and 0 have 10-15 years of experience
You can use a pivot table in Microsoft SQL, like this:
select p.DName, p.Under5, p.From5To10, p.MoreThan10
from (
select d.DName, case when datediff(day, e.DOJ, getdate()) / 365 < 5 then 'Under5' when datediff(day, e.DOJ, getdate()) / 365 > 10 then 'MoreThan10' else 'From5To10' end as ExperienceBucket
from Employee e
join Department d on e.[Dept Id] = d.[Dept Id]
) as s
pivot (
count(ExperienceBucket)
for ExperienceBucket in (Under5, From5To10, MoreThan10)
) as p
I have a table named People in the following format:
Date | Name.
When I count the people by Grouping By Name with
Select Date, Name, count(*)
From People
Group By Date, Name;
Will give the following
Date Name count(*)
10 Peter 25
10 John 30
10 Mark 25
11 Peter 15
11 John 10
11 Mark 5
But I would like the following result:
Date Peter John Mark
10 25 30 25
11 15 10 5
Is this possible? This is a simple example of a more complicated database. If someone helps me in solving this problem I will use the concept to implement it in my table
Thanks!
Select Date
, count(case when Name = 'Peter' then 1 else null end)
, count(case when Name = 'John' then 1 else null end)
, count(case when Name = 'Mark' then 1 else null end)
From People
Group By Date;
another option different from turbanoff's if, for some reason, you find yourself in a situation that you cant apply a group by:
Select distinct(P.Date),
(select count(*) from People where date=p.date and name='Peter') as Peter,
(select count(*) from People where date=p.date and name='John') as John,
(select count(*) from People where date=p.date and name='Mark') as Mark
From People P