Making stringWithContentsOfURL asynchronous - Is it safe? - objective-c

Question

I attempted to make -[NSString stringWithContentsOfURL:encoding:error:] asynchronous, by running it a-synchronically from a background thread:
__block NSString *result;
dispatch_queue_t currentQueue = dispatch_get_current_queue();
void (^doneBlock)(void) = ^{
printf("done! %s",[result UTF8String]);
};
dispatch_async(dispatch_get_global_queue(DISPATCH_QUEUE_PRIORITY_DEFAULT,
(unsigned long)NULL), ^(void) {
result = [NSString stringWithContentsOfURL:[NSURL URLWithString:#"http://www.google.com/"] encoding:NSUTF8StringEncoding error:nil];
dispatch_sync(currentQueue, ^{
doneBlock();
});
});
Its working fine, and most importantly, its asynchronous.
My question is if it's safe to do this, or could there be any threading problems etc.?
Thanks in advance :)

Answer 1

That should be safe, but why reinvent the wheel?
NSURLRequest *req = [NSURLRequest requestWithURL:[NSURL URLWithString:#"http://www.google.com"]];
[NSURLConnection sendAsynchronousRequest:req queue:[NSOperationQueue mainQueue] completionHandler:^(NSURLResponse *response, NSData *data, NSError *error) {
NSString *result = [[NSString alloc] initWithData:data encoding:NSUTF8StringEncoding];
// etc
}];

Answer 2

You can also use:
dispatch_queue_t queue = dispatch_get_global_queue(DISPATCH_QUEUE_PRIORITY_DEFAULT, 0);
dispatch_async(queue, ^{
NSError *error = nil;
NSString *searchResultString = [NSString stringWithContentsOfURL:[NSURL URLWithString:searchURL]
encoding:NSUTF8StringEncoding
error:&error];
if (error != nil) {
completionBlock(term,nil,error);
}
else
{
// Parse the JSON Response
NSData *jsonData = [searchResultString dataUsingEncoding:NSUTF8StringEncoding];
NSDictionary *searchResultsDict = [NSJSONSerialization JSONObjectWithData:jsonData
options:kNilOptions
error:&error];
if(error != nil)
{
completionBlock(term,nil,error);
}
else
{
//Other Work here
}
}
});
But yes, it should be safe. I've been told though to use NSURLConnection instead due to error calls and such when communicating via the internet. I'm still doing research into this.

Answer 3

-(void)loadappdetails:(NSString*)appid {
NSString* searchurl = [#"https://itunes.apple.com/lookup?id=" stringByAppendingString:appid];
[self performSelectorInBackground:#selector(asyncload:) withObject:searchurl];
}
-(void)asyncload:(NSString*)searchurl {
NSURL* url = [NSURL URLWithString:searchurl];
NSError* error = nil;
NSString* str = [NSString stringWithContentsOfURL:url encoding:NSUTF8StringEncoding error:&error];
if (error != nil) {
NSLog(#"Error: %#", error);
}
NSLog(#"str: %#", str);
}