I have a Yii STAT Relation that's defined to provide a grouped SUM result, however when I access the relation in my View, the only value is the latest single value rather than each value.
For example, here's my relation:
'total_salaries_by_job' => array(
self::STAT,
'Employee',
'department_id',
'select' => 'job_type_id, SUM(salary)',
'group'=>"job_type_id"
)
This generates the following SQL:
SELECT
department_id AS c
, job_type_id
, SUM(salary) AS s
FROM Employee AS t
WHERE t.department_id = 1
GROUP BY
department_id
, job_type_id
Running that manually, the result set is:
c | job_type_id | s
------+----------------+---------
1 | 1 | 233000
------+----------------+---------
1 | 2 | 25000
------+----------------+---------
1 | 3 | 179000
However, in my view, if I do the following:
<pre>
<?php print_r($department->total_salaries_by_job); ?>
</pre>
The result is simply: 179000, whereas I was expecting it to be an array with 3 elements.
Is returning just 1 value the way STAT relations work or is there something else I need to be doing?
Is it possible to do what I'm attempting?
You can do what you are after, but you can't use a STAT relationship to do it. Rather, use a Normal HAS_MANY relationship and use your same select statement.
Related
Say I have the following data:
Passes
ID | Pass_code
-----------------
100 | 2xBronze
101 | 1xGold
102 | 1xSilver
103 | 2xSteel
Passengers
ID | Passengers
-----------------
100 | 2
101 | 5
102 | 1
103 | 3
I want to count then create a ticket in the output of:
ID 100 | 2 pass (bronze)
ID 101 | 5 pass (because it is gold, we count all passengers)
ID 102 | 1 pass (silver)
ID 103 | 2 pass (steel)
I was thinking something like the code below however, I am unsure how to finish my case statement. I want to substring pass_code so that we get show pass numbers e.g '2xBronze' should give me 2. Then for ID 103, we have 2 passes and 3 customers so we should output 2.
Also, is there a way to firstly find '2xbronze' if the pass_code contained lots of other things such as '101001, 1xbronze, FirstClass' - this may change so i don't want to substring, could we search for '2xbronze' and then pull out the 2??
SELECT
CASE
WHEN Passes.pass_code like '%gold%' THEN Passengers.passengers
WHEN Passes.pass_code like '%steel%' THEN SUBSTRING(passes.pass_code, 1,1)
WHEN Passes.pass_code like '%bronze%' THEN SUBSTRING(passes.pass_code, 1,1)
WHEN Passes.pass_code like '%silver%' THEN SUBSTRING(passes.pass_code, 1,1)
else 0 end as no,
Passes.ID,
Passes.Pass_code,
Passengers.Passengers
FROM Passes
JOIN Passengers ON Passes.ID = Passengers.ID
https://dbfiddle.uk/?rdbms=oracle_18&fiddle=db698e8562546ae7658270e0ec26ca54
So assuming you are indeed using Oracle (as your DB fiddle implies).
You can do some string magic with finding position of a splitter character (in your case the x), then substringing based on that. Obviously this has it's problems, and x is a bad character seperator as well.. but based on your current set.
WITH PASSCODESPLIT AS
(
SELECT PASSES.ID,
TO_Number(SUBSTR(PASSES.PASS_CODE, 0, (INSTR(PASSES.PASS_CODE, 'x')) - 1)) AS NrOfPasses,
SUBSTR(PASSES.PASS_CODE, (INSTR(PASSES.PASS_CODE, 'x')) + 1) AS PassType
FROM Passes
)
SELECT
PASSCODESPLIT.ID,
CASE
WHEN PASSCODESPLIT.PassType = 'gold' THEN Passengers.Passengers
ELSE PASSCODESPLIT.NrOfPasses
END AS NrOfPasses,
PASSCODESPLIT.PassType,
Passengers.Passengers
FROM PASSCODESPLIT
INNER JOIN Passengers ON PASSCODESPLIT.ID = Passengers.ID
ORDER BY PASSCODESPLIT.ID ASC
Gives the result of:
ID NROFPASSES PASSTYPE PASSENGERS
100 2 bronze 2
101 5 gold 5
102 1 silver 1
103 2 steel 3
As can also be seen in this fiddle
But I would strongly advise you to fix your table design. Having multiple attributes in the same column leads to troubles like these. And the more variables/variations you start storing, the more 'magic' you need to keep doing.
In this particular example i see no reason why you don't simply have the 3 columns in Passes, also giving you the opportunity to add new columns going forward. I.e. to keep track of First class.
You can extract the numbers using regexp_substr(). So I think this does what you want:
SELECT (CASE WHEN p.pass_code LIKE '%gold%'
THEN TO_NUMBER(REGEXP_SUBSTR(p.pass_code, '^[0-9]+'))
ELSE pp.passengers
END) as num,
p.ID, p.Pass_code, pp.Passengers
FROM Passes p JOIN
Passengers pp
ON p.ID = pp.ID;
Here is a db<>fiddle.
This converts the leading digits in the code to a number. Also note the use of table aliases to simplify the query.
I have the following SQL query:
SELECT TOP 3 accounts.username
,COUNT(accounts.username) AS count
FROM relationships
JOIN accounts ON relationships.account = accounts.id
WHERE relationships.following = 4
AND relationships.account IN (
SELECT relationships.following
FROM relationships
WHERE relationships.account = 8
);
I want to return the total count of accounts.username and the first 3 accounts.username (in no particular order). Unfortunately accounts.username and COUNT(accounts.username) cannot coexist. The query works fine removing one of the them. I don't want to send the request twice with different select bodies. The count column could span to 1000+ so I would prefer to calculate it in SQL rather in code.
The current query returns the error Column 'accounts.username' is invalid in the select list because it is not contained in either an aggregate function or the GROUP BY clause. which has not led me anywhere and this is different to other questions as I do not want to use the 'group by' clause. Is there a way to do this with FOR JSON AUTO?
The desired output could be:
+-------+----------+
| count | username |
+-------+----------+
| 1551 | simon1 |
| 1551 | simon2 |
| 1551 | simon3 |
+-------+----------+
or
+----------------------------------------------------------------+
| JSON_F52E2B61-18A1-11d1-B105-00805F49916B |
+----------------------------------------------------------------+
| [{"count": 1551, "usernames": ["simon1", "simon2", "simon3"]}] |
+----------------------------------------------------------------+
If you want to display the total count of rows that satisfy the filter conditions (and where username is not null) in an additional column in your resultset, then you could use window functions:
SELECT TOP 3
a.username,
COUNT(a.username) OVER() AS cnt
FROM relationships r
JOIN accounts a ON r.account = a.id
WHERE
r.following = 4
AND EXISTS (
SELECT 1 FROM relationships t1 WHERE r1.account = 8 AND r1.following = r.account
)
;
Side notes:
if username is not nullable, use COUNT(*) rather than COUNT(a.username): this is more efficient since it does not require the database to check every value for nullity
table aliases make the query easier to write, read and maintain
I usually prefer EXISTS over IN (but here this is mostly a matter of taste, as both techniques should work fine for your use case)
I already have the code to display the highest aggregate value for a ID.
select max(fk3_job_role_id),max(sum(no_of_placements))
from fact_accounts
group by fk3_job_role_id
the result looks like:
[max(fk3_job_role_id)] | [max(sum(no_of_placements))]
-----------------------|-----------------------------
5 | 25
However, i want to display the job_role_desc instead of fk3_job_role_id represented by the same id.
The table for it looks like:
[job_role_id] | [job_role_desc]
--------------------------------
1 | job1
2 | job2
3 | job3
4 | job4
5 | job5
select job_role_desc,T.total_sum from fact_accounts where job_role_id in (select max(fk3_job_role_id),max(sum(no_of_placements)) as total_sum from fact_accounts group by fk3_job_role_id) T
You need to query for the job description by using a subquery. The above query first fetches the data according to the query inside the brackets( also known popularly as a subquery ). The result returned from this query is used to compare with all the other id's in the main table by a simple "in" clause.
Edit
If you also need the sum of placements you can get it by using a reference to the table created during the execution of the subquery
I have 3 SQL SERVER data tables :
TBL_HOUSE :
|"ID_HOUSE"|"ID_PERSONS"|"QTY_PERSONS"|
|"1" |"|1|2|3|" |"|1|2|1|" |
|"2" |"|2|" |"|3|" |
TBL_PERSON :
|"ID_PERSON"|"ID_PETS"|"QTY_PETS"|
|"1" |"|3|1|" |"|1|2|" |
|"2" |"|1|2|" |"|3|1|" |
TBL_PET :
|"ID_PET"|"PET_TYPE"|"PET_PRICE"|
|"1" |"DOG" |"500" |
|"2" |"CAT" |"200" |
I have to make two queries.
The first for retrieve the number of each PET in a house.
ie. : In the HOUSE"2", there is 3 PERSON"2"
for each PERSON"2" there is 3 DOG and 1 CAT
In total in the HOUSE"2" is 9 DOG and 3 CAT.
The second to get the total value of pets in a house.
In HOUSE"2", the total value is 5100. (3*(3*500+1*200) = 5100)
Can you help me to write these queries?
Thanks a lot.
Sorry, it's all I can do for you. Your DataBase design makes me feel sick.
This query return you TBL_Person table in a NORMAL form. I hope you are smart enough to do the same with another tables and count all amounts that you need.
WITH Split(id_person, stpos_pets, stpos_qpets,endpos_pets, endpos_qpets)
AS(
SELECT id_person, 0 AS stpos_pets, 0 AS stpos_qpets, CHARINDEX('|',id_pets) AS endpos_pets, CHARINDEX('|',qty_pets) AS endpos_qpets
from TBL_PERSON
UNION ALL
SELECT TBL_PERSON.id_person, endpos_pets+1,endpos_qpets+1, CHARINDEX('|',id_pets,endpos_pets+1),CHARINDEX('|',qty_pets,endpos_qpets+1)
FROM TBL_PERSON,Split
WHERE endpos_pets > 0 AND #t.id_person=split.id_person
)
SELECT 'Id' = TBL_PERSON.id_person,
'Pets' = SUBSTRING(id_pets,stpos_pets,COALESCE(NULLIF(endpos_pets,0),LEN('|3|1|')+1)-stpos_pets),
'Quantity' = SUBSTRING(qty_pets,stpos_qpets,COALESCE(NULLIF(endpos_qpets,0),LEN('|3|1|')+1)-stpos_qpets)
FROM Split,TBL_PERSON
Where stpos_pets>0 and endpos_pets>0 and stpos_qpets>0 and endpos_qpets>0 and TBL_PERSON.id_person=split.id_person
I have a rails 3.2 app running on PostgreSQL, and have some data I want to display in my view, which is stored in the database in this structure:
+----+--------+------------------+--------------------+
| id | name | sched_start_date | task |
+----+--------+------------------+--------------------+
| 1 | "Ben" | 2013-03-01 | "Check for debris" |
+----+--------+------------------+--------------------+
| 2 | "Toby" | 2013-03-02 | "Carry out Y1.1" |
+----+--------+------------------+--------------------+
| 3 | "Toby" | 2013-03-03 | "Check oil seals" |
+----+--------+------------------+--------------------+
I would like to display a list of tasks for each name, and for the names to be ordered ASC by the first sched_start_date they have, which should look like ...
Ben
2013-03-01 – Check for debris
Toby
2013-03-02 – Carry out Y1.1
2013-03-03 – Check oil seals
The approach I starting taking was to run a query for unique names and order them by sched_start_date ASC, then run a query for each name to get their tasks.
To get a list of unique names, the SQL would look like this.
select *
from (
select distinct on (name) name, sched_start_date
from tasks
) p
order by sched_start_date;
I would like to know if this is the correct approach (querying for unique names then running another query for all their tasks), or if there is a better rails way.
To get the data sorted like you describe, you might want to use min() as window function in the ORDER BY clause:
SELECT name, sched_start_date, task
FROM tasks
ORDER BY min(sched_start_date) OVER (PARTITION BY name), 1, 2, 3
Your original query would need an additional ORDER BY item to get the earliest date per name:
SELECT DISTINCT ON (name) name, sched_start_date, task
FROM tasks
ORDER BY 1, 2, 3;
I also added task (3) as last ORDER BY item to break ties, in case there can be more than one per date.
But the output is still ordered by name, not by date.
Getting your peculiar format with all data stuffed into one column is a bit more complex:
SELECT one_col
FROM (
WITH x AS (
SELECT name, min(sched_start_date) AS min_start
FROM tasks
GROUP BY 1
)
SELECT 2 AS rnk, name
,sched_start_date::text || ' – ' || task AS one_col
,sched_start_date, min_start
FROM tasks
JOIN x USING (name)
UNION ALL
SELECT 1 AS rnk, name, name, NULL::date, min_start
FROM x
ORDER BY min_start, name, rnk, sched_start_date, task
) y
Assuming that you have associations in your model you would be able to run
#employees = Employee.order(:name, :sched_start_date, :task).includes(:tasks)
You could then iterate over them:
#employees.each do |employee|
employee.name
employee.tasks.each do |task|
task.name
end
end
This isn't gonna exactly match your needs, but should show you where to start.