Out of hour calculation
An out of hour calendar defined as below,Here WeekNumber starts from 1 = Monday to 5 = Friday
CalendarId WeekNumber StartTime EndTime
600 1 1900-01-01 00:00 1900-01-01 08:00
600 1 1900-01-01 18:00 1900-01-01 23:59
600 2 1900-01-01 00:00 1900-01-01 08:00
600 2 1900-01-01 18:00 1900-01-01 23:59
600 3 1900-01-01 00:00 1900-01-01 08:00
600 3 1900-01-01 18:00 1900-01-01 23:59
600 4 1900-01-01 00:00 1900-01-01 08:00
600 4 1900-01-01 18:00 1900-01-01 23:59
600 5 1900-01-01 00:00 1900-01-01 08:00
600 5 1900-01-01 18:00 1900-01-01 23:59
I would like to apply this calendar to another table called events to find records falls in these day and times ?
Edit
The Structure of event table as follows
EventID StartDateTime TotalTimeInSec WeekNumber
1 2009-07-05 07:44 100 1
2 2009-07-05 08:40 200 1
3 2009-07-05 09:35 150 1
4 2009-07-05 10:37 200 1
5 2009-07-05 19:37 200 1
6 2009-07-05 20:37 200 1
The required output will be after appyling the calendar
EventID StartDateTime TotalTimeInSec WeekNumber
1 2009-07-05 07:44 100 1
5 2009-07-05 19:37 200 1
6 2009-07-05 20:37 200 1
Select a.WeekNumber,a.startDateTime,b.starttime,b.EndTime
from tblEvents a,(Select WeekNumber,Starttime,EndTime from tblMain) b
where a.startDateTime between b.starttime and b.EndTime
and a.WeekNumber = b.WeekNumber
Select E.*
From tblEvent E
Full outer Join tblMain M on E.WeekNumber = M.WeekNumber
Where E.StartDateTime Between M.StartTime and M.EndTime
I don't believe a full outer join is what you're asking for. And the other answer didn't seem to handle your method of storing time ranges as datetime values. The only tricky part seems to be handling that date math. You can find different ways to do that check, but I think this is one solution.
SELECT e.*
FROM
Events as e INNER JOIN Calendar as c
ON c.WeekNumber = e.WeekNumber
WHERE
/* CAST(CAST(e.StartDateTime AS TIME) AS DATETIME) -- later versions */
e.StartDateTime - DATEADD(dd, DATEDIFF(dd, 0, e.StartDateTime), 0)
BETWEEN c.StartTime and e.EndTime
Related
I have a table that is currently in the following format
ID
Title
CreatedOn
1
Test 1
2021-04-26 08:00:00
2
Test 2
2021-04-26 10:00:00
3
Test 3
2021-04-27 09:00:00
4
Test 4
2021-04-28 14:00:00
5
Test 5
2021-04-28 16:00:00
6
Test 6
2021-04-28 12:00:00
7
Test 7
2021-04-29 13:00:00
8
Test 8
2021-04-30 06:00:00
9
Test 9
2021-05-17 10:00:00
10
Test 10
2021-05-18 19:00:00
11
Test 11
2021-05-18 23:00:00
12
Test 12
2021-05-19 16:00:00
13
Test 13
2021-05-20 07:00:00
14
Test 14
2021-05-21 14:00:00
15
Test 15
2021-05-21 10:00:00
16
Test 16
2021-04-30 10:00:00
What I would like to do is a query that would tell me how many requests have been Monday to Friday per hour. So aggregate all the data into just rows of Monday to Friday.
So the query should return
Day
Hour
Count
Monday
08:00
1
Monday
10:00
2
Tuesday
10:00
1
Tuesday
19:00
1
Tuesday
23:00
1
Wednesday
14:00
1
Wednesday
16:00
2
Wednesday
12:00
1
etc.. How do I achieve this?
So far I have the following
SELECT
DATENAME(WEEK, CreatedOn) AS Week,
DATEPART(Hour, CreatedOn) AS Hour,
COUNT(*) AS Requests
FROM [Enterprise32].[dbo].[nav_EmailEstimateRequests]
where CreatedOn > '2021-01-01'
GROUP BY DATENAME(WK, CreatedOn),DATEPART(Hour, CreatedOn)
ORDER BY DATENAME(WK, CreatedOn);
But the above query returns each week so Week 1 up until Week 21. Please guide me in the right direction.
Thank you!
You want weekday for the date part:
SELECT DATENAME(WEEKDAY, CreatedOn) AS Weekday,
DATEPART(Hour, CreatedOn) AS Hour,
COUNT(*) AS Requests
FROM [Enterprise32].[dbo].[nav_EmailEstimateRequests]
WHERE CreatedOn > '2021-01-01'
GROUP BY DATENAME(WEEKDAY, CreatedOn), DATEPART(Hour, CreatedOn), DATEPART(WEEKDAY, CreatedOn)
ORDER BY DATEPART(WEEKDAY, CreatedOn), Hour;
Note: I included DATEPART(weekday, ) in the GROUP BY, so you could use it in the ORDER BY.
I have a temp table
BusinessDate SSQ_CompScore
2011-01-05 00:00:00.000 41
2011-01-06 00:00:00.000 6
2011-01-07 00:00:00.000 1
2011-01-10 00:00:00.000 8
2011-01-11 00:00:00.000 48
2011-01-12 00:00:00.000 50
2011-01-13 00:00:00.000 59
I need to calculate delta for each current date.
I have prepared a solution but it doesn't work where date as not consecutive.
Can you please help?
select t1.businessdate, t1.ssq_compscore, (t2.ssq_compscore - t1.ssq_compscore) as delta
from #temp t1
left join #temp t2 on t1.businessdate = DATEADD(dd,1,t2.businessdate)
where t1.businessdate >='20180814'
Result set should be as
BusinessDate SSQ_CompScore Delta
2011-01-05 00:00:00.000 41 NULL
2011-01-06 00:00:00.000 6 35
2011-01-07 00:00:00.000 1 5
2011-01-10 00:00:00.000 8 7
2011-01-11 00:00:00.000 48 40
2011-01-12 00:00:00.000 50 2
2011-01-13 00:00:00.000 59 9
Not sure if this is the most efficient way but it works as far as I see
SELECT businessdate, SSQ_CompScore ,
SSQ_CompScore - (SELECT SSQ_CompScore
FROM temp
WHERE businessdate < t1.businessdate
ORDER BY businessdate DESC
LIMIT 1) as delta
FROM temp t1
ORDER BY businessdate ASC
How to find the date difference in hours between two records with nearest datetime value and it must be compared in same group?
Sample Data as follows:
Select * from tblGroup
Group FinishedDatetime
1 03-01-2009 00:00
1 13-01-2009 22:00
1 08-01-2009 03:00
2 01-01-2009 10:00
2 13-01-2009 20:00
2 10:01-2009 10:00
3 27-10-2008 00:00
3 29-10-2008 00:00
Expected Output :
Group FinishedDatetime Hours
1 03-01-2009 00:00 123
1 13-01-2009 22:00 139
1 08-01-2009 03:00 117
2 01-01-2009 10:00 216
2 13-01-2009 20:00 82
2 10:01-2009 10:00 82
3 27-10-2008 00:00 48
3 29-10-2008 00:00 48
Try this:
Select t1.[Group], DATEDIFF(HOUR, z.FinishedDatetime, t1.FinishedDatetime)
FROM tblGroup t1
OUTER APPLY(SELECT TOP 1 *
FROM tblGroup t2
WHERE t2.[Group] = t1.[Group] AND t2.FinishedDatetime<t1.FinishedDatetime
ORDER BY FinishedDatetime DESC)z
I have a table which looks like you can see below:
Id Date ScheduledTimeFrom ScheduledTimeTo ActualTimeFrom ActualTimeTo
1 2013-01-01 1899-12-30 07:00:00 1899-12-30 18:00:00 1899-12-30 07:23:00 1899-12-30 17:15:00
I need to calculate per half hour how many records exists, the output should be like:
Time Actual Count:
7:00 4
7:30 4
8:00 4
8:30 4
9:00 4
9:30 5
10:00 5
10:30 6
11:00 7
11:30 8
12:00 8
12:30 8
13:00 8
13:30 8
14:00 8
14:30 8
15:00 7
15:30 7
16:00 7
16:30 6
17:00 5
17:30 4
18:00 4
I already tried to make a helper table which should hold the times per halfhour. I have joined this helpertable with the table that contains the data and after that I tried to use a group by function but it was not working.
My query was like:
Create table period (timefrom datetime, timeto datetime)
insert into period
select '1899-12-30 07:00:00.000', '1899-12-30 07:30:00.000'
Union all
select '1899-12-30 07:30:00.000', '1899-12-30 08:00:00.000'
select *
from period p left join table1 t on t.ActualTimeFrom < p.timeto and t.ActualTimeTo >=p.timefrom
Grouping this give me no desired result....
Anyone an idea how to come to the result?
P.s. I am using sql server 2005.
After snooping around and testing it on my side, looks like this date function could be the answer:
DATEADD(mi,DATEDIFF(mi,0,YOUR_DATE_COLUMN)/30*30,0)
I have a table that hold the start date and the end date of a financial period.
CHARGE_PERIOD_ID START_DATE END_DATE
13 2013-03-31 00:00:00.000 2013-04-27 00:00:00.000
14 2013-04-28 00:00:00.000 2013-05-25 00:00:00.000
15 2013-05-26 00:00:00.000 2013-06-29 00:00:00.000
16 2013-06-30 00:00:00.000 2013-07-27 00:00:00.000
17 2013-07-28 00:00:00.000 2013-08-24 00:00:00.000
18 2013-08-25 00:00:00.000 2013-09-28 00:00:00.000
19 2013-09-29 00:00:00.000 2013-10-26 00:00:00.000
20 2013-10-27 00:00:00.000 2013-11-23 00:00:00.000
21 2013-11-24 00:00:00.000 2013-12-28 00:00:00.000
22 2013-12-29 00:00:00.000 2014-01-25 00:00:00.000
23 2014-01-26 00:00:00.000 2014-02-22 00:00:00.000
24 2014-02-23 00:00:00.000 2014-03-29 00:00:00.000
The user of a report wants the current financial year split into 12 periods and want to give to feed in 2 parameters into the report , a year and a period number which will go into my sql . So something like #year=2014 #period=1 will be recieved . I have to write some sql to go to this table and set a period start date of 31/03/2014 and a period end date of 27/04/2014.
So in pseudo code:
Look up period 1 for 2014 and return period start date of 31/03/2014 and period end date of 27/04/2014.
#PERIOD_START_DATE = select the the first period that starts in March for the given year . all financial period starts in March.
#PERIOD_END_DATE = select the corresponding END_DATE from the table .
The question is how to begin to code this or my design approach? Should I create a function that calcualtes this or should I do a CTE and add a column which will hold the period number in the way they want etc .
Thinking about it more I think I need a mapping table . So the real question is can I do this without a mapping table ?
DECLARE #Year INT
DECLARE #Period INT
SET #Year= 2013
SET #Period = 1
;WITH CTE AS
(
SELECT *, ROW_NUMBER() OVER (PARTITION BY
CASE WHEN MONTH([START_DATE])<3 THEN YEAR([START_DATE]) -1 ELSE YEAR([START_DATE]) END
ORDER BY
CASE WHEN MONTH([START_DATE])<3 THEN YEAR([START_DATE]) - 1 ELSE YEAR([START_DATE]) END
,CASE WHEN MONTH([START_DATE])<3 THEN MONTH([START_DATE]) + 12 ELSE MONTH([START_DATE]) END
) AS RN
FROM Periods
)
SELECT * FROM CTE
WHERE RN = #Period
AND CASE WHEN MONTH([START_DATE])<3 THEN YEAR([START_DATE]) -1 ELSE YEAR([START_DATE]) END = #Year
SQLFiddle DEMO