I get this error while trying to persist an entity 'UserAccount' into the database table.
#Entity
#Table(name = "user_account")
public class UserAccount extends BaseEntity {
#OneToMany(cascade = CascadeType.ALL)
#JoinColumn(name = "useraccount_id")
#MapKeyEnumerated(EnumType.STRING)
private Map<PhoneType, PhoneNumber> phones = new HashMap<PhoneType, PhoneNumber>();
//... other attributes
//... default constructor, getters and setters
}
public enum PhoneType {
HOME("home"),
MOBILE("mobile"),
FAX("fax"),
WORK("work");
private String value;
PhoneType(String value) {
this.value = value;
}
#JsonValue
public String getValue() {
return value;
}
}
#Entity
#Table(name = "phone_number")
public class PhoneNumber extends BaseEntity {
private String areaCode;
private String number;
//... default constructor, getters and setters
}
and finally..
public class UserAccountRepository {
#Inject
EntityManager entityManager;
#Override
public UserAccount save(UserAccount userAccount) {
if (userAccount.getId() == null) {
entityManager.persist(userAccount);
} else {
userAccount = entityManager.merge(userAccount);
}
return userAccount;
}
//.. other methods
}
Caused by: java.lang.ClassCastException: java.lang.String cannot be cast to java.lang.Enum
at org.eclipse.persistence.mappings.converters.EnumTypeConverter.convertObjectValueToDataValue(EnumTypeConverter.java:165)
at org.eclipse.persistence.mappings.foundation.AbstractDirectMapping.extractIdentityFieldsForQuery(AbstractDirectMapping.java:568)
at org.eclipse.persistence.internal.queries.MappedKeyMapContainerPolicy.getKeyMappingDataForWriteQuery(MappedKeyMapContainerPolicy.java:145)
at org.eclipse.persistence.mappings.OneToManyMapping.updateTargetRowPostInsertSource(OneToManyMapping.java:1425)
at org.eclipse.persistence.mappings.OneToManyMapping.performDataModificationEvent(OneToManyMapping.java:936)
at org.eclipse.persistence.internal.sessions.CommitManager.commitAllObjectsWithChangeSet(CommitManager.java:162)
at org.eclipse.persistence.internal.sessions.AbstractSession.writeAllObjectsWithChangeSet(AbstractSession.java:4387)
at org.eclipse.persistence.internal.sessions.UnitOfWorkImpl.commitToDatabase(UnitOfWorkImpl.java:1493)
at org.eclipse.persistence.internal.sessions.UnitOfWorkImpl.commitToDatabaseWithChangeSet(UnitOfWorkImpl.java:1583)
at org.eclipse.persistence.internal.sessions.UnitOfWorkImpl.issueSQLbeforeCompletion(UnitOfWorkImpl.java:3258)
at org.eclipse.persistence.internal.sessions.RepeatableWriteUnitOfWork.issueSQLbeforeCompletion(RepeatableWriteUnitOfWork.java:357)
at org.eclipse.persistence.transaction.AbstractSynchronizationListener.beforeCompletion(AbstractSynchronizationListener.java:160)
at org.eclipse.persistence.transaction.JTASynchronizationListener.beforeCompletion(JTASynchronizationListener.java:70)
at com.sun.enterprise.transaction.JavaEETransactionImpl.commit(JavaEETransactionImpl.java:452)
... 94 more
Other questions with same error suggest to add #Enumerated(EnumType.STRING) on the attribute of type Enum, I have used #MapKeyEnumerated(EnumType.STRING) on the phones Map, but I still see get this error. Any clues where am I wrong?
Please let me know if I haven't asked the question as per the SO guidance, I will correct it (as this is my 1st question).
I made a change to the PhoneNumber class as below
#Entity
#Table(name = "phone_number")
public class PhoneNumber extends BaseEntity {
private PhoneType type;
private String areaCode;
private String number;
//... default constructor, getters and setters
}
and then added #MapKey(name = "type") in the UserAccount as below.
#OneToMany(cascade = CascadeType.ALL)
#JoinColumn(name = "useraccount_id")
#MapKeyEnumerated(EnumType.STRING)
#MapKey(name = "type")
private Map<PhoneType, PhoneNumber> phones = new HashMap<PhoneType, PhoneNumber>();
With these changes I am now able to save the UserAccount object successfully into the db tables.
When I run my createStudentDemo class I get the following error:
INFO: HHH000412: Hibernate Core {5.4.11.Final}
Exception in thread "main"
org.hibernate.internal.util.config.ConfigurationException: Could not
locate cfg.xml resource [hibernate.cfg.xml] at
org.hibernate.boot.cfgxml.internal.ConfigLoader.loadConfigXmlResource(ConfigLoader.java:53) at
org.hibernate.boot.registry.StandardServiceRegistryBuilder.configure(StandardServiceRegistryBuilder.java:215) at org.hibernate.cfg.Configuration.configure(Configuration.java:258)
at org.hibernate.cfg.Configuration.configure(Configuration.java:244)
at
com.luv2code.hibernate.demo.CreateStudentDemo.main(CreateStudentDemo.java:15)
I don't understand why I have this error.
Here is the code of my createStudentDemo class:
package com.luv2code.hibernate.demo;
import org.hibernate.Session;
import org.hibernate.SessionFactory;
import org.hibernate.cfg.Configuration;
import com.luv2code.hibernate.demo.entity.Student;
public class CreateStudentDemo {
public static void main(String[] args) {
// create session factory
SessionFactory factory= new Configuration()
.configure("hibernate.cfg.xml")
.addAnnotatedClass(Student.class)
.buildSessionFactory();
// create session
Session session = factory.getCurrentSession();
try {
//create a student object
System.out.println("creating new student object");
Student tempStudent = new Student("Paul", "Wall", "paul#luv2code.com");
//start a transaction
session.beginTransaction();
// save the student object
System.out.println("Saving the student...");
session.save(tempStudent);
//commit transaction
session.getTransaction().commit();
System.out.println("Done !");
}
finally {
factory.close();
}
}
}
and here is the code for my class student:
package com.luv2code.hibernate.demo.entity;
import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.Id;
import javax.persistence.Table;
#Entity
#Table(name="student")
public class Student {
public Student() {
}
#Id
#Column(name="id")
private int id;
#Column(name="first_name")
private String firstName;
#Column(name="last_name")
private String lastName;
#Column(name="email")
private String email;
public Student(String firstName, String lastName, String email) {
this.firstName = firstName;
this.lastName = lastName;
this.email = email;
}
public int getId() {
return id;
}
public void setId(int id) {
this.id = id;
}
public String getFirstName() {
return firstName;
}
public void setFirstName(String firstName) {
this.firstName = firstName;
}
public String getLastName() {
return lastName;
}
public void setLastName(String lastName) {
this.lastName = lastName;
}
public String getEmail() {
return email;
}
public void setEmail(String email) {
this.email = email;
}
#Override
public String toString() {
return "Student [id=" + id + ", firstName=" + firstName + ", lastName=" + lastName + ", email=" + email + "]";
}
}
and here is the code of my hibernate.cfg.xml file:
<!DOCTYPE hibernate-configuration PUBLIC
"-//Hibernate/Hibernate Configuration DTD 3.0//EN"
"http://www.hibernate.org/dtd/hibernate-configuration-3.0.dtd">
<hibernate-configuration>
<session-factory>
<!-- JDBC Database connection settings -->
<property name="connection.driver_class">com.mysql.cj.jdbc.Driver</property>
<property name="connection.url">jdbc:mysql://localhost:3306/hb_student_tracker?useSSL=false&serverTimezone=UTC</property>
<property name="connection.username">hbstudent</property>
<property name="connection.password">hbstudent</property>
<!-- JDBC connection pool settings ... using built-in test pool -->
<property name="connection.pool_size">1</property>
<!-- Select our SQL dialect -->
<property name="dialect">org.hibernate.dialect.MySQLDialect</property>
<!-- Echo the SQL to stdout -->
<property name="show_sql">true</property>
<!-- Set the current session context -->
<property name="current_session_context_class">thread</property>
</session-factory>
</hibernate-configuration>
and here is the location of my files:
Can someone help me please?
You hibernate.cfg.xml should be in classpath. Put it in src folder.
i met a problem in Studying with Spring data solr,this is my Configuration Class:
#Configuration
#EnableSolrRepositories(basePackages={"cn.likefund.solr.repository"}, multicoreSupport=true)
public class SolrContext {
static final String SOLR_HOST = "http://192.168.11.157:8080/solr";
#Bean
public SolrClient solrClient() {
return new HttpSolrClient(SOLR_HOST);
}
}
and this is my Repository:
package cn.likefund.solr.repository;
import java.util.List;
import org.springframework.data.solr.repository.SolrCrudRepository;
import cn.likefund.solr.model.Activity;
public interface ActivityRepository extends SolrCrudRepository<Activity, String>{
List<Activity> findByName(String name);
}
when I start the application,the message in console is this
error
When I delete the method findByName in the repository,the application start with no problem, i just want to the method findByName worked,anybody know what should i do with this problem?
here is the Activity Class:
#Entity
#SolrDocument(solrCoreName ="core_activity")
public class Activity implements Serializable{
private static final long serialVersionUID = 1566434582540525979L;
#Id
#Field(value = "id")
private String id;
#Field(value = "CREATEDT")
private String createdt;
#Indexed
#Field(value = "NAME")
private String name;
public String getId() {
return id;
}
public void setId(String id) {
this.id = id;
}
public String getCreatedt() {
return createdt;
}
public void setCreatedt(String createdt) {
this.createdt = createdt;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
}
So, obviously the CrudRepository is not created .
when you delete the findByName, can you manually query your repo ? (just to be sure the problem comes from the method, and not the SOLR schema)
have you tried to annotate annotate the method to explicitly set the query ? Something like
#Query("NAME:?0")
List findByName(String name);
I am trying to query my hibernate table for a RunEntity. The first where clause in the query searches for RunEntities where the testName = the passed value testname. In the stacktrace, it mentions that it cannot find a match for type testname in the RunEntity, but the RunEntity object explicitly has a string named testName with setters and getters and #Column notation.
Table setup
CREATE TABLE RunEntity (ID INTEGER IDENTITY,TestNumber INTEGER NOT NULL, TestName varchar(50) NOT NULL, ENVIRONMENT VARCHAR(50) NOT NULL, Source VARCHAR(50), Date TIMESTAMP, RESULTFILES BLOB);
Query
#Query("SELECT r FROM RunEntity r WHERE r.testName = :testname AND r.testNumber = :testnumber AND r.environment = :environment AND r.source = :source")
public List<RunEntity> findByNameNumberEnvironmentSource(
#Param("testname") String testname,
#Param("testnumber") int testnumber,
#Param("environment") String environment,
#Param("source") String source);
Entity
package com.web_application;
import java.sql.Timestamp;
import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import javax.persistence.Id;
import javax.persistence.Table;
import javax.persistence.Lob;
#Entity
#Table(name = "TESTRUNS")
public class RunEntity {
private int ID;
private int testNumber;
private String testName;
private String environment;
private String source;
private String passOrFail;
private Timestamp date;
private byte[] resultFiles;
#Id
#Column(name = "ID")
#GeneratedValue
public int getID()
{
return this.ID;
}
public void setID(int ID){this.ID = ID;}
#Column(name="TestNumber")
public int getTestNumber()
{
return this.testNumber;
}
public void setTestNumber(int testNum){this.testNumber = testNum;}
#Column(name="TestName")
public String testName()
{
return this.testName;
}
public void setTestName(String testName){this.testName = testName;}
#Column(name="Environment")
public String getEnvironment()
{
return this.environment;
}
public void setEnvironment(String enviro){this.environment = enviro;}
#Column(name="Source")
public String getSource()
{
return this.source;
}
public void setSource(String src){this.source = src;}
#Column(name="PassOrFail")
public String getPassOrFail()
{
return this.passOrFail;
}
public void setPassOrFail(String pOrF){this.passOrFail = pOrF;}
#Column(name="Date")
public Timestamp getDate()
{
return this.date;
}
public void setDate(Timestamp dates){this.date = dates;}
#Lob
#Column(name="ResultFiles")
public byte[] getResultFiles()
{
return this.resultFiles;
}
public void setResultFiles(byte[] file){this.resultFiles = file;}
}
Part of stacktrace
Caused by: org.hibernate.QueryException: could not resolve property: testname of: com.web_application.RunEntity [SELECT r FROM com.web_application.RunEntity r WHERE r.testname = :testname AND r.testNumber = :testnumber AND r.environment = :environment AND r.source = :source]
at org.hibernate.QueryException.generateQueryException(QueryException.java:137)
at org.hibernate.QueryException.wrapWithQueryString(QueryException.java:120)
at org.hibernate.hql.internal.ast.QueryTranslatorImpl.doCompile(QueryTranslatorImpl.java:234)
at org.hibernate.hql.internal.ast.QueryTranslatorImpl.compile(QueryTranslatorImpl.java:158)
at org.hibernate.engine.query.spi.HQLQueryPlan.<init>(HQLQueryPlan.java:126)
at org.hibernate.engine.query.spi.HQLQueryPlan.<init>(HQLQueryPlan.java:88)
at org.hibernate.engine.query.spi.QueryPlanCache.getHQLQueryPlan(QueryPlanCache.java:190)
at org.hibernate.internal.AbstractSessionImpl.getHQLQueryPlan(AbstractSessionImpl.java:301)
at org.hibernate.internal.AbstractSessionImpl.createQuery(AbstractSessionImpl.java:236)
at org.hibernate.internal.SessionImpl.createQuery(SessionImpl.java:1800)
at org.hibernate.jpa.spi.AbstractEntityManagerImpl.createQuery(AbstractEntityManagerImpl.java:328)
... 66 more
Change this
#Column(name="TestName")
public String testName()
{
return this.testName;
}
to
#Column(name="TestName")
public String getTestName()
{
return this.testName;
}
Property access Naming convention is important.Try to use IDE for example (Eclipse Getter-Setter,instead using manually doing it)
Correct your testName() getter to getTestName(). You are using Property Access and have to stick to JavaBeans convention.
I'am developing a java web EE application using EJB, JPA and netbeans. I've created a table with sql named users for registration and login and another table named prescripts which has 3 foreign keys refering to the primary key idusers of users(docid, pharmid, patid).
I also created with net beans entity bean named users and a session bean named UsersFacade and for prescripts an entity bean: prescripts and session bean: PrescriptsFacade.
My question is this:
Why in users ejb all variables(columns) are declared as they are(string for string, integer for integer etc) and in prescripts are declared as users?
//users.java
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
#Basic(optional = false)
#Column(name = "idusers")
private Integer idusers;
#Column(name = "user_type")
private String userType;
#Column(name = "name")
private String name;
#Column(name = "nickname")
private String nickname;
//prescripts.java
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
#Basic(optional = false)
#Column(name = "idprescripts")
private Integer idprescripts;
#Column(name = "data")
private String data;
#JoinColumn(name = "pharm_id", referencedColumnName = "idusers")
#ManyToOne
private Users users;
#JoinColumn(name = "doc_id", referencedColumnName = "idusers")
#ManyToOne
private Users users1;
#JoinColumn(name = "pat_id", referencedColumnName = "idusers")
#ManyToOne
private Users users2;
For users i use this code in a servlet to insert a row in sql base:
Users currentUsers;
currentUsers = new Users();
String Type = request.getParameter("user_type");
String Name = request.getParameter("name");
String Nickname = request.getParameter("nickname");
currentUsers.setUserType(Type);
currentUsers.setName(Name);
currentUsers.setNickname(Nickname);
UsersFacade.create(currentUsers);
How am i supposed to insert a row in prescripts this way?
This doesn't work(it shows error null pointer exception):
currentPresc = new Prescripts();
String PatID = request.getParameter("pat_id");
String DocID = request.getParameter("doc_id");
String PharmID = request.getParameter("pharm_id");
String Data = request.getParameter("data");
int patid = Integer.parseInt(PatID);
int docid = Integer.parseInt(DocID);
int pharmid = Integer.parseInt(PharmID);
currentUsers = UsersFacade.find(patid);
currentPresc.setUsers(currentUsers);
currentUsers = UsersFacade.find(docid);
currentPresc.setUsers1(currentUsers);
currentUsers = UsersFacade.find(pharmid);
currentPresc.setUsers2(currentUsers);
currentPresc.setData(Data);
PrescriptsFacade.create(currentPresc);
I skipped the set and get methods and some variables for simplifying reasons. Please any help is really very appreciated, i am stucked with this 2 weeks now :'(
I send you the whole classes of users and prescripts:
Prescripts.java
package entities;
import java.io.Serializable;
import javax.persistence.Basic;
import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import javax.persistence.GenerationType;
import javax.persistence.Id;
import javax.persistence.JoinColumn;
import javax.persistence.ManyToOne;
import javax.persistence.NamedQueries;
import javax.persistence.NamedQuery;
import javax.persistence.Table;
#Entity
#Table(name = "prescripts")
#NamedQueries({
#NamedQuery(name = "Prescripts.findAll", query = "SELECT p FROM Prescripts p"),
#NamedQuery(name = "Prescripts.findByIdprescripts", query = "SELECT p FROM Prescripts p WHERE p.idprescripts = :idprescripts"),
#NamedQuery(name = "Prescripts.findByData", query = "SELECT p FROM Prescripts p WHERE p.presc = :presc")})
public class Prescripts implements Serializable {
private static final long serialVersionUID = 1L;
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
#Basic(optional = false)
#Column(name = "idprescripts")
private Integer idprescripts;
#JoinColumn(name = "doc_id", referencedColumnName = "idusers")
#ManyToOne
private Users doc_id;
#JoinColumn(name = "pat_id", referencedColumnName = "idusers")
#ManyToOne
private Users pat_id;
#JoinColumn(name = "pharm_id", referencedColumnName = "idusers")
#ManyToOne
private Users pharm_id;
#Column(name = "presc")
private String presc;
public Prescripts() {
}
public Prescripts(Users pat_id, Users pharm_id, Users doc_id, String presc) {
this.pharm_id = pharm_id;
this.doc_id = doc_id;
this.pat_id = pat_id;
this.presc = presc;
}
public Integer getIdprescripts() {
return idprescripts;
}
public void setIdprescripts(Integer idprescripts) {
this.idprescripts = idprescripts;
}
public String getPresc() {
return presc;
}
public void setPresc(String presc) {
this.presc = presc;
}
public Users getPharmId() {
return pharm_id;
}
public void setPharmId(Users pharm_id) {
this.pharm_id = pharm_id;
}
public Users getDocId() {
return doc_id;
}
public void setDocId(Users doc_id) {
this.doc_id = doc_id;
}
public Users getPatId() {
return pat_id;
}
public void setPatId(Users pat_id) {
this.pat_id = pat_id;
}
#Override
public int hashCode() {
int hash = 0;
hash += (idprescripts != null ? idprescripts.hashCode() : 0);
return hash;
}
#Override
public boolean equals(Object object) {
// TODO: Warning - this method won't work in the case the id fields are not set
if (!(object instanceof Prescripts)) {
return false;
}
Prescripts other = (Prescripts) object;
if ((this.idprescripts == null && other.idprescripts != null) || (this.idprescripts != null && !this.idprescripts.equals(other.idprescripts))) {
return false;
}
return true;
}
#Override
public String toString() {
return "entities.Prescripts[idprescripts=" + idprescripts + "]";
}
}
Users.java
package entities;
import java.io.Serializable;
import java.util.Collection;
import java.util.List;
import javax.persistence.*;
import javax.xml.bind.annotation.XmlTransient;
#Entity
#Table(name = "users")
#NamedQueries({
#NamedQuery(name = "Users.findAll", query = "SELECT u FROM Users u"),
#NamedQuery(name = "Users.findByIdusers", query = "SELECT u FROM Users u WHERE u.idusers = :idusers"),
#NamedQuery(name = "Users.findByUserType", query = "SELECT u FROM Users u WHERE u.userType = :userType"),
#NamedQuery(name = "Users.findByNickname", query = "SELECT u FROM Users u WHERE u.nickname = :nickname"),
#NamedQuery(name = "Users.findByName", query = "SELECT u FROM Users u WHERE u.name = :name"),
#NamedQuery(name = "Users.findByPassword", query = "SELECT u FROM Users u WHERE u.password = :password"),
#NamedQuery(name = "Users.findByEmail", query = "SELECT u FROM Users u WHERE u.email = :email"),
#NamedQuery(name = "Users.findByCity", query = "SELECT u FROM Users u WHERE u.city = :city"),
#NamedQuery(name = "Users.findByStreet", query = "SELECT u FROM Users u WHERE u.street = :street"),
#NamedQuery(name = "Users.findByAt", query = "SELECT u FROM Users u WHERE u.at = :at"),
#NamedQuery(name = "Users.findByAmka", query = "SELECT u FROM Users u WHERE u.amka = :amka"),
#NamedQuery(name = "Users.findByAfm", query = "SELECT u FROM Users u WHERE u.afm = :afm"),
#NamedQuery(name = "Users.findByVerify", query = "SELECT u FROM Users u WHERE u.verify = :verify")})
public class Users implements Serializable {
#OneToMany(mappedBy = "pat_id")
private List<Prescripts> prescriptsList;
#OneToMany(mappedBy = "doc_id")
private List<Prescripts> prescriptsList1;
#OneToMany(mappedBy = "pharm_id")
private List<Prescripts> prescriptsList2;
private static final long serialVersionUID = 1L;
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
#Basic(optional = false)
#Column(name = "idusers")
private Integer idusers;
#Column(name = "user_type")
private String userType;
#Column(name = "name")
private String name;
#Column(name = "nickname")
private String nickname;
#Column(name = "password")
private String password;
#Column(name = "email")
private String email;
#Column(name = "city")
private String city;
#Column(name = "street")
private String street;
#Column(name = "AT")
private String at;
#Column(name = "AMKA")
private String amka;
#Column(name = "AFM")
private String afm;
#Column(name = "verify")
private Boolean verify;
public Users() {
}
public Users( String userType,String name,String nickname, String password, String email, String city, String street, String at,
String amka, String afm, Boolean verify)
{
this.userType= userType;
this.name= name;
this.nickname= nickname;
this.password= password;
this.email = email;
this.city = city;
this.street = street;
this.at = at;
this.amka = amka;
this.afm = afm;
this.verify=verify;
}
public Integer getIdusers() {
return idusers;
}
public void setIdusers(Integer idusers) {
this.idusers = idusers;
}
public String getUserType() {
return userType;
}
public void setUserType(String userType) {
this.userType = userType;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public String getNickname() {
return nickname;
}
public void setNickname(String nickname) {
this.nickname = nickname;
}
public String getPassword() {
return password;
}
public void setPassword(String password) {
this.password = password;
}
public String getEmail() {
return email;
}
public void setEmail(String email) {
this.email = email;
}
public String getCity() {
return city;
}
public void setCity(String city) {
this.city = city;
}
public String getStreet() {
return street;
}
public void setStreet(String street) {
this.street = street;
}
public String getAt() {
return at;
}
public void setAt(String at) {
this.at = at;
}
public String getAmka() {
return amka;
}
public void setAmka(String amka) {
this.amka = amka;
}
public String getAfm() {
return afm;
}
public void setAfm(String afm) {
this.afm = afm;
}
public Boolean getVerify() {
return verify;
}
public void setVerify(Boolean verify) {
this.verify = verify;
}
#Override
public int hashCode() {
int hash = 0;
hash += (idusers != null ? idusers.hashCode() : 0);
return hash;
}
#Override
public boolean equals(Object object) {
// TODO: Warning - this method won't work in the case the id fields are not set
if (!(object instanceof Users)) {
return false;
}
Users other = (Users) object;
if ((this.idusers == null && other.idusers != null) || (this.idusers != null && !this.idusers.equals(other.idusers))) {
return false;
}
return true;
}
#Override
public String toString() {
return "entities.Users[idusers=" + idusers + "]";
}
public List<Prescripts> getPrescriptsList() {
return prescriptsList;
}
public void setPrescriptsList(List<Prescripts> prescriptsList) {
this.prescriptsList = prescriptsList;
}
public List<Prescripts> getPrescriptsList1() {
return prescriptsList1;
}
public void setPrescriptsList1(List<Prescripts> prescriptsList1) {
this.prescriptsList1 = prescriptsList1;
}
public List<Prescripts> getPrescriptsList2() {
return prescriptsList2;
}
public void setPrescriptsList2(List<Prescripts> prescriptsList2) {
this.prescriptsList2 = prescriptsList2;
}
}
The main question seems to be why variables in the User-class is declared as Integer, but the "user_id-variable" in Prescript is declared as User.
This is simply the way EJB3 works. You are thinking to much in terms of sql and relational databases. You define the primary key of tables (e.g. Users.idusers) as if it was a column, but references to other objects (entities, to be precise) are defined using the natural object. Therefore the Prescripts.users is declared as a Users-object. The EJB platform will take care of transforming this into a database column (in this case probably named users_idusers), with the correct type (in this case Integer), but this is taken care of and you shouldn't need to care about that.
You should go through a EJB3 tutorial or two - there are plenty of these, and make sure you complete the tutorials. You seemed to have missed some of the basics. Also note that your code could have been much simpler. The "#Column"-annotations are usually not needed, mapped_by is usually not needed, column-names ditto, etc. Also use singular names (User instead of Users). The common standard for primarykeys is simply #Id Long id, making it easy to remember the name of the primary key for all entities (but some prefer distinct names).
To answer your actual problem we would need more information, including what is on TestServlet.java line 233. Your code seems more or less correct, but it is hard for others to verify that. Finding the Users-object from EntityManger/facade and then setting it into the Prescipts-object is the correct way to do it.
In java, relations between entities (in a entity-relationship model) is represented as references to objects, (one-to-one) or lists of references to objects (one-to-many)
A relational database implements relations between entities (rows in tables) as foreign keys, that matches the primary key for a row in another table.
(The word "relational" in a "relational database" does actually just mean that the columns (tuples) in a table is related to each other...The foreign key stuff is an addition.)
I generally considered smart to start with a proper entity-relationshop model before designing database tables all willy nilly...