Listview item or subitem onchange event - vb.net

When I have a listview with like 46 items, where each item has 4 subitems, the values of the subitems are changing with time, I use the values of subitems to draw a pie chart when an item in the list view is selected using this code:
Chart1.Series("Series1").ChartType = SeriesChartType.Pie
Chart1.Series("Series1").Points.Clear()
If ListView3.FocusedItem.SubItems(1).Text > 0 Then
Chart1.Series("Series1").Points.AddY(ListView3.FocusedItem.SubItems(1).Text)
End If
If ListView3.FocusedItem.SubItems(2).Text > 0 Then
Chart1.Series("Series1").Points.AddY(ListView3.FocusedItem.SubItems(2).Text)
End If
If ListView3.FocusedItem.SubItems(3).Text > 0 Then
Chart1.Series("Series1").Points.AddY(ListView3.FocusedItem.SubItems(3).Text)
End If
If ListView3.FocusedItem.SubItems(4).Text > 0 Then
Chart1.Series("Series1").Points.AddY(ListView3.FocusedItem.SubItems(4).Text)
End If
Is there a way to detect a change of a subitem's value? Like onchange event in textbox, but for items or subitems, because I want the pie chart to update when a subitem value changes.
this code changes the sub items
For xx As Integer = 0 To ListView3.Items.Count - 1
If ListView3.Items(xx).SubItems(0).Text = googleXMLdocument...<s:name>(j).Value Then
If j + 1 = 1 Then
ListView3.Items(xx).SubItems(1).Text += 1
End If
If j + 1 = 2 Then
ListView3.Items(xx).SubItems(2).Text += 1
End If
If j + 1 = 3 Then
ListView3.Items(xx).SubItems(3).Text += 1
End If
If j + 1 > 4 Then
ListView3.Items(xx).SubItems(4).Text += 1
End If
End If
Next

Try this code. This way the chart will automatically get updated if there is any change in the subitems. You will not require a timer.
For xx As Integer = 0 To ListView3.Items.Count - 1
If ListView3.Items(xx).SubItems(0).Text = googleXMLdocument...<s:name>(j).Value Then
If j + 1 = 1 Then
ListView3.Items(xx).SubItems(1).Text += 1
End If
If j + 1 = 2 Then
ListView3.Items(xx).SubItems(2).Text += 1
End If
If j + 1 = 3 Then
ListView3.Items(xx).SubItems(3).Text += 1
End If
If j + 1 > 4 Then
ListView3.Items(xx).SubItems(4).Text += 1
End If
End If
Next
Put the below code after the above code in a loop. You can also do away with the FocusedItem
Chart1.Series("Series1").Points.Clear()
Chart1.Series("Series1").Points.AddY (ListView3.FocusedItem.SubItems(1).Text)
Chart1.Series("Series1").Points.AddY (ListView3.FocusedItem.SubItems(2).Text)
Chart1.Series("Series1").Points.AddY (ListView3.FocusedItem.SubItems(3).Text)
Chart1.Series("Series1").Points.AddY (ListView3.FocusedItem.SubItems(4).Text)

Related

For Next VBA skips half

I am trying to make a simple VBA in Excel, to copy some data I am trying to regroup. I seems to work good for some part, but it skips a row and column everytime! The problem must be somewhere in the double For..Next.. I am using, but I can't find it:
The result I get:
For i = 1 To AantalPag 'HIERRR
GezSite = BeginCel.Offset(i + 1) 'HIERRR
For iweek = 1 To AantalWeek
GezWeek = BeginCel.Offset(0, iweek)
For i2 = 1 To AantalWeekData
If BeginCelData.Offset(i2 - 1) = GezWeek Then
For i3 = 1 To AantalSitesData
If BeginCelData.Offset(0, i3) = GezSite Then
Sommetje = Sommetje + BeginCelData.Offset(i2 - 1, i3 - 1)
Else
i3 = i3 + 1
End If
Next i3
'BeginCel.Offset(i, iweek) = Sommetje
'Sommetje = 0
Else
i2 = i2 + 1
End If
Next i2
BeginCel.Offset(i, iweek) = Sommetje
Sommetje = 0
iweek = iweek + 1
Next iweek
i = i + 1
Next i
The code below will print the numbers from 1 to 100 in the Immediate window.
For n = 1 to 100
Debug.Print n
Next n
The code below will print every other number in the Immediate window. This is because n is incremented both by n = n + 1 and then again by Next n.
For n = 1 to 100
Debug.Print n
n = n + 1
Next n

Excel VBA how to set number sequence to start at middle of the row?

I previously have a Excel sheet with VBA coding that fills column, row 1 to 10 with the number 1, row 11 to 20 with number 2 and so on. The code I've used is as follows:
Sub fill()
Dim ID
ID = 1
For c = 1 To 34
ActiveWorkbook.Sheets("Sheet1").Cells(c, 1) = ID
ActiveWorkbook.Sheets("Sheet1").Cells(c + 1, 1) = ID
c = c + 1
If (c Mod 10) = 0 Then
ID = ID + 1
End If
Next c
End Sub
Now I want to change it so that the code starts at row 3 onwards. Meaning row 3 to 12 = 1, row 13 to 22 = 2 and so on. So I changed the 'For' statement to:
For c = 3 To 34
But what happens is that the number 1 appears from row 3 to row 10, and then continues with number 2 in row 11 to 20. Not what I was expecting.
Therefore, what would be the best method of changing the code?
If you want exactly the same output but two rows lower, you can use:
Sub fill()
Dim ID
ID = 1
For c = 1 To 34
ActiveWorkbook.Sheets("Sheet1").Cells(c + 2, 1) = ID
ActiveWorkbook.Sheets("Sheet1").Cells(c + 3, 1) = ID
c = c + 1
If (c Mod 10) = 0 Then
ID = ID + 1
End If
Next c
End Sub
If you still only want to go to row 34 but start in row 3, change the 34 to 32 in the above code.
You can also do it without looping and this is easier to adjust the parameters:
Sub fill()
Const NUMBER_OF_ROWS As Long = 34
Const START_ROW As Long = 3
Const ID As Long = 1
Const NUMBER_IN_GROUP As Long = 10
With ActiveWorkbook.Sheets("Sheet1").Cells(START_ROW, 1).Resize(NUMBER_OF_ROWS)
.Value = .Parent.Evaluate("INDEX(INT((ROW(" & .Address & ")-" & START_ROW & ")/" & _
NUMBER_IN_GROUP & ")+" & ID & ",)")
End With
End Sub
When i understand you write, this should work:
You can use the loop how you did at the beginning. and just add plus 2 to c in the ActiveWorkbook.Sheets("Tabelle1").Cells(c + 2, 1) = ID
Sub fill()
Dim ID
ID = 1
For c = 1 To 34
ActiveWorkbook.Sheets("Tabelle1").Cells(c + 2, 1) = ID
ActiveWorkbook.Sheets("Tabelle1").Cells(c + 3, 1) = ID
c= c+1
If (c Mod 10) = 0 Then
ID = ID + 1
End If
Next c
End Sub
something like that should be the simplest way:
Sub fill()
Dim i As Integer
Dim j As Integer
For i = 1 To 4
For j = 1 To 10
ActiveWorkbook.Sheets("Sheet1").Cells(j + (i - 1) * 10 + 2, 1) = i
Next j
Next i
End Sub
EDIT:
No, the simplest way would be type formula into A3:
=ROUNDDOWN(((ROW()-3))/10,0)+1
end drag it donw.

Loop through a string to find the odd numbers VB

I am looping through a card number finding all the odd numbers and multiplying them by the card digits. Its kind of hard to explain. I am having trouble multiplying the odd number and the card number. Here's an example my teacher gave me. You multiply card number 1 and and odd number 1 and so forth. I am not getting any errors, it just kind of freezes.
Sums
Card #: 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6
Multiples 1 2 3 4 5 6 7 8
Evens: 2 4 6 8 0 2 4 6 32 =Sum 1
Odds: 1 6 15 28 45 6 21 40 162 =Sum 2
Sum 3: 194
194 =Sum 3
Step 4: =1+9+4 = 14
= 1 + 4 = 5 = check digit
Public Class Payment
Private Sub OK_Click(sender As Object, e As EventArgs) Handles OK.Click
Dim Sum1 = 0
Dim Sum2 = 0
Dim Sum3 = 0
Dim ready As Boolean
Dim ccnumb = CardNumber.Text
Format(CardNumber.Text, "################")
Dim exp = Mid(ExpDate.Text, 1, 3)
Dim checkdigit = 0
If FullName.TextLength = 0 Or cardtype.Text.Length = 0 And ccnumb.Length <= 16 Or exp.Length = 2 Then
MessageBox.Show("Please enter all credit card information before proceeding.")
ready = False
Else ready = True
End If
If ready = True Then
For Each num As Char In ccnumb
If CInt(CStr(num)) Mod 2 <> 0 Then
Sum1 += CInt(CStr(num)) * CInt(CStr(num)) Mod 2 <> 0
Else
Sum2 += CInt(CStr(num))
End If
Next
Sum3 = Sum1 + Sum2
Do While Sum3 > 10
For j = 0 To Sum3.ToString.Length - 1
For k = 1 To Sum3.ToString.Length - 1
Sum3 = j + k
Next
Next
Loop
Do While exp.Length > 1
checkdigit = Mid(ExpDate.Text, 1, 1) + Mid(ExpDate.Text, 1, 2)
Loop
If Sum3 = checkdigit Then
MessageBox.Show("Congratulations! Your payment was successful.")
CustInv.Show()
Else MessageBox.Show("The checkdigit," & Space(1) & Sum3 & Space(1) & "does not match the month code," & Space(1) & checkdigit & "." & Space(1) & "Please reenter your card information.")
End If
End If
End Sub
"it kind of freezes" is lay speak for "my code enters an infinite loop".
This looks suspicious:
Do While Sum3 > 10
For j = 0 To Sum3.ToString.Length - 1
For k = 1 To Sum3.ToString.Length - 1
Sum3 = j + k
Next
Next
Loop
To enter the loop, Sum3 must be greater than 10. For the loop to exit, Sum3 must not be greater than 10, but your code only increments Sum3, so Sum3 can only stay greater than 10.
This means that once entered, this loop is infinite.
If changing outer loop to inside loop doesn't help you
Try this
Do While Sum3 > 10 and j < sum3 ' adding j < sum3 might stop the loop
For j = 0 To Sum3.ToString.Length - 1
For k = 1 To Sum3.ToString.Length - 1
Sum3 = j + k
Next
Next
Loop

vba array element removal

j = LBound(arrayTime)
Do Until j = UBound(arrayTime)
j = j + 1
b = b + 1
cnc = b + r
MsgBox cnc
If cnc > 7 Then
b = 0
r = 0
cnc = b + r
End If
numMins = Sheet5.Cells(cnc + 3, 2) - arrayTime(j)
If numMins < 0 Then
g = g + 1
ReArrangeArray arrayTime, j
'ReDim Preserve arrayTime(numrows - 1 + g)
'arrayTime(numrows - 1 + g) = arrayTime(j)
'MsgBox (arrayTime(numrows - 1 + g))
Else
Sheet5.Cells(cnc + 3, 2) = numMins
End If
Loop
If the if statement is true I want to be able to put the array value at the end of the array and remove that value from its current spot. As the code is, it just adds it to the end and increases the size of the array from 12 to 13. How can I get the array to remain size 12 and still place the value at the end of the array and then remove it from its original position? I do not want to touch the array values in front. Just want to take that value and move it to the end.
For instance
array(1,2,3,4,5)
If statement
j on third loop.
array(j)=3
end array should be
array(1,2,4,5,3)
You could use a helper Sub like this one:
Sub ReArrangeArray(inputArray as Variant, indexToSwap as long)
Dim I As Long
Dim tempVal As Variant
If indexToSwap >= LBound(inputArray) And indexToSwap < UBound(inputArray) Then
tempVal = inputArray(indexToSwap)
For I = indexToSwap To UBound(inputArray) - 1
inputArray(i) = inputArray(i + 1)
Next I
InputArray(UBound(inputArray)) = tempVal
End If
End Sub
To be called by your main Sub as follows:
ReArrangeArray arrayTime, j

InvalidArgument=Value of '2' is not valid for 'index'

Dim group11_0_count = 0
Dim group11_1_count = 0
Dim group11_2_count = 0
Dim m As Integer = 0
Dim n As Integer = 0
Dim increment2 As Integer
For m = 0 To machings2.Items.Count - 1
For n = 0 To 3
If machings2.Items(m).ToString.Chars(n) = "1" Then
increment2 = increment2 + 1
End If
Next
If (increment2 = 0) Then
group11_0_count = group11_0_count + 1
group11_1_0.Items.Add(machings2.Items(m))
End If
If (increment2 = 1) Then
group11_1_count = group1_1_count + 1
group11_1_1.Items.Add(machings2.Items(m))
End If
If (increment2 = 2) Then
group11_2_count = group1_2_count + 1
group11_1_2.Items.Add(machings2.Items(m))
End If
increment2 = 0
Next
If (group11_0_count > 0 AndAlso group11_1_count > 0) Then
Dim result = ""
Dim index As Integer = 0
Dim gg As Integer = 0
Dim hh As Integer = 0
Dim i As Integer = 0
For hh = 0 To group11_1_count - 1
For gg = 0 To group11_0_count - 1
result = ""
index = 0
For i = 0 To 3
If group11_1_0.Items(gg).ToString.Chars(i) <> group11_1_1.Items(hh).ToString.Chars(i) Then
result &= "-"
index = index + 1
Else
result &= group11_1_0.Items(gg).ToString.Chars(i)
End If
Next
If (index = 1) Then
machings3.Items.Add(result)
End If
Next
Next
End If
I am comparing the items of two combobox items like that
combobox1 items
0000
combobox items
0001
0010
the result will be like that in machings3 combobox
000-
00-0
Here the differnce between two items indicated by - sign
But i am getting InvalidArgument=Value of '2' is not valid for 'index'.
I Can't make sense out of your source and where the IndexOutOfRangeException occurs. But you know that you need 3 Items in a Combobox to access Item with Index 2?! Every collection starts with 0.