I need to truncate a comma at the end of a string, sort of like this:
NSString *string = #" this text has spaces before and after ";
NSString *trimmedString = [string stringByTrimmingCharactersInSet:
[NSCharacterSet whitespaceCharacterSet]];
instead of whitespaceCharacterSet is there something like commaCharacterSet ?
If every string has a comma/white space at the beginning and end:
NSRange range = NSMakeRange(1, [string length-1]);
NSString *trimmedString = [string substringWithRange:range];
if you just want to trim the comma:
[NSCharacterSet characterSetWithCharactersInString:#","];
Related
I want to trim the occurence of special characters in a string
String has :
prevs: Case Number
____________________
In this i want to remove -------- this dash from this string .I have tried like this :
NSCharacterSet *trim = [NSCharacterSet characterSetWithCharactersInString:#"-"];
NSString *stringNew = [[previousString2 componentsSeparatedByCharactersInSet:trim] componentsJoinedByString:#""];
Thanks in Advance!
Try This:
NSString *stringWithoutDash = [yourString stringByReplacingOccurrencesOfString:#"-" withString:#""];
NSString *trimedString = [myString stringByReplacingOccurrencesOfString:#"-" withString:#""];
Use regular expression, the pattern [\\s_]{4,} searches for 4 and more whitespace or underscore characters.
NSString *trimmedString = [previousString2 stringByReplacingOccurrencesOfString:#"[\\s_]{4,}" withString:#"" options:NSRegularExpressionSearch range:NSMakeRange(0, previousString2.length)];
If the underscore characters are really dashes reaplace the character in the pattern.
You can use below code to remove your special string.
NSString *yourString = #"This is your string with speical character --------";
NSCharacterSet *removedCharacterSet = [NSCharacterSet characterSetWithCharactersInString:#"--------"];
NSString *finalString = [[yourString componentsSeparatedByCharactersInSet:removedCharacterSet] componentsJoinedByString:#""];
NSLog (#"Your final string : %#", finalString);
I have a string that looks like this:
(
TEST STRING
)
I want to remove the parentheses and the white spaces between the parentheses, but not remove the white space within the string.
Basically, I just want the string. I looked into trimming and replacing, but I don't think they applied here.
Any hint on how to go on about solving this problem?
Thanks
This should work:
NSString *originalString = #"( TEST STRING )";
NSString *newString = [originalString stringByReplacingOccurrencesOfString:#"( " withString:#""];
newString = [newString stringByReplacingOccurrencesOfString:#" )" withString:#""];
I would consider using (NSRegularExpressionSearch | NSAnchoredSearch)
something like this (I'm writing code on the fly so its probably not correct.
NSRange rng = [myString rangeOfString:#"([ \t\n\r]*" options:(NSRegularExpressionSearch | NSAnchoredSearch)];
NSRange rng = [myString rangeOfString:#"[ \t\n\r]*)" options:(NSRegularExpressionSearch | NSAnchoredSearch | NSBackWardsSearch)];
if ( rng.length && rng2.length )
{
myString = [myString substringToIndex:rng2.location];
myString = [myString substringFromIndex:rng.location];
}
Remove the ()
string = [string stringByTrimmingCharactersInSet:[NSCharacterSet characterSetWithCharactersInString:#"()"]];
And trim the white space.
string = [string stringByTrimmingCharactersInSet:[NSCharacterSet whitespaceAndNewlineCharacterSet]];
NSCharacterSet *unwantedChar = [NSCharacterSet characterSetWithCharactersInString:#" "#"\"-[}()\n "];
NSString *requiredString = [[string componentsSeparatedByCharactersInSet:unwantedChar] componentsJoinedByString: #""];
I have a string that I like to trim the first and last character. What is the equivalent of ltrim/rtrim in IOS?
This is the string:
"["email#email.com","email#email.com"]"
I want to remove only the first and last double quotes.
substringWithRange:
string = [string substringWithRange:(NSRange){1, str.length - 2}];
NSString *str = #" sample string ";
NSString *trimmedString = [str stringByTrimmingCharactersInSet:[NSCharacterSet whitespaceCharacterSet]];
NSString *myString = #"A B C D E F G";
I want to remove the spaces, so the new string would be "ABCDEFG".
You could use:
NSString *stringWithoutSpaces = [myString
stringByReplacingOccurrencesOfString:#" " withString:#""];
If you want to support more than one space at a time, or support any whitespace, you can do this:
NSString* noSpaces =
[[myString componentsSeparatedByCharactersInSet:[NSCharacterSet whitespaceCharacterSet]]
componentsJoinedByString:#""];
Taken from NSString
stringByReplacingOccurrencesOfString:withString:
Returns a new string in which all occurrences of a target string in the receiver are replaced by another given string.
- (NSString *)stringByReplacingOccurrencesOfString:(NSString *)target withString:(NSString *)replacement
Parameters
target
The string to replace.
replacement
The string with which to replace target.
Return Value
A new string in which all occurrences of target in the receiver are replaced by replacement.
All above will works fine. But the right method is this:
yourString = [yourString stringByTrimmingCharactersInSet:[NSCharacterSet whitespaceCharacterSet]];
It will work like a TRIM method. It will remove all front and back spaces.
Thanks
if the string is mutable, then you can transform it in place using this form:
[string replaceOccurrencesOfString:#" "
withString:#""
options:0
range:NSMakeRange(0, string.length)];
this is also useful if you would like the result to be a mutable instance of an input string:
NSMutableString * string = [concreteString mutableCopy];
[string replaceOccurrencesOfString:#" "
withString:#""
options:0
range:NSMakeRange(0, string.length)];
You can try this
- (NSString *)stripRemoveSpaceFrom:(NSString *)str {
while ([str rangeOfString:#" "].location != NSNotFound) {
str = [str stringByReplacingOccurrencesOfString:#" " withString:#""];
}
return str;
}
Hope this will help you out.
Consider the following example:
" Hello this is a long string! "
I want to convert that to:
"Hello this is a long string!"
OS X 10.7+ and iOS 3.2+
Use the native regexp solution provided by hfossli.
Otherwise
Either use your favorite regexp library or use the following Cocoa-native solution:
NSString *theString = #" Hello this is a long string! ";
NSCharacterSet *whitespaces = [NSCharacterSet whitespaceCharacterSet];
NSPredicate *noEmptyStrings = [NSPredicate predicateWithFormat:#"SELF != ''"];
NSArray *parts = [theString componentsSeparatedByCharactersInSet:whitespaces];
NSArray *filteredArray = [parts filteredArrayUsingPredicate:noEmptyStrings];
theString = [filteredArray componentsJoinedByString:#" "];
Regex and NSCharacterSet is here to help you. This solution trims leading and trailing whitespace as well as multiple whitespaces.
NSString *original = #" Hello this is a long string! ";
NSString *squashed = [original stringByReplacingOccurrencesOfString:#"[ ]+"
withString:#" "
options:NSRegularExpressionSearch
range:NSMakeRange(0, original.length)];
NSString *final = [squashed stringByTrimmingCharactersInSet:[NSCharacterSet whitespaceAndNewlineCharacterSet]];
Logging final gives
"Hello this is a long string!"
Possible alternative regex patterns:
Replace only space: [ ]+
Replace space and tabs: [ \\t]+
Replace space, tabs and newlines: \\s+
Performance rundown
This solution: 7.6 seconds
Splitting, filtering, joining (Georg Schölly): 13.7 seconds
Ease of extension, performance, number lines of code and the number of objects created makes this solution appropriate.
Actually, there's a very simple solution to that:
NSString *string = #" spaces in front and at the end ";
NSString *trimmedString = [string stringByTrimmingCharactersInSet:
[NSCharacterSet whitespaceAndNewlineCharacterSet]];
NSLog(#"%#", trimmedString)
(Source)
With a regex, but without the need for any external framework:
NSString *theString = #" Hello this is a long string! ";
theString = [theString stringByReplacingOccurrencesOfString:#" +" withString:#" "
options:NSRegularExpressionSearch
range:NSMakeRange(0, theString.length)];
A one line solution:
NSString *whitespaceString = #" String with whitespaces ";
NSString *trimmedString = [whitespaceString
stringByReplacingOccurrencesOfString:#" " withString:#""];
This should do it...
NSString *s = #"this is a string with lots of white space";
NSArray *comps = [s componentsSeparatedByCharactersInSet:[NSCharacterSet whitespaceCharacterSet]];
NSMutableArray *words = [NSMutableArray array];
for(NSString *comp in comps) {
if([comp length] > 1)) {
[words addObject:comp];
}
}
NSString *result = [words componentsJoinedByString:#" "];
Another option for regex is RegexKitLite, which is very easy to embed in an iPhone project:
[theString stringByReplacingOccurencesOfRegex:#" +" withString:#" "];
Try This
NSString *theString = #" Hello this is a long string! ";
while ([theString rangeOfString:#" "].location != NSNotFound) {
theString = [theString stringByReplacingOccurrencesOfString:#" " withString:#" "];
}
Here's a snippet from an NSString extension, where "self" is the NSString instance. It can be used to collapse contiguous whitespace into a single space by passing in [NSCharacterSet whitespaceAndNewlineCharacterSet] and ' ' to the two arguments.
- (NSString *) stringCollapsingCharacterSet: (NSCharacterSet *) characterSet toCharacter: (unichar) ch {
int fullLength = [self length];
int length = 0;
unichar *newString = malloc(sizeof(unichar) * (fullLength + 1));
BOOL isInCharset = NO;
for (int i = 0; i < fullLength; i++) {
unichar thisChar = [self characterAtIndex: i];
if ([characterSet characterIsMember: thisChar]) {
isInCharset = YES;
}
else {
if (isInCharset) {
newString[length++] = ch;
}
newString[length++] = thisChar;
isInCharset = NO;
}
}
newString[length] = '\0';
NSString *result = [NSString stringWithCharacters: newString length: length];
free(newString);
return result;
}
Alternative solution: get yourself a copy of OgreKit (the Cocoa regular expressions library).
OgreKit (Japanese webpage --
code is in English)
OgreKit (Google
autotranslation):
The whole function is then:
NSString *theStringTrimmed =
[theString stringByTrimmingCharactersInSet:
[NSCharacterSet whitespaceAndNewlineCharacterSet]];
OGRegularExpression *regex =
[OGRegularExpression regularExpressionWithString:#"\s+"];
return [regex replaceAllMatchesInString:theStringTrimmed withString:#" "]);
Short and sweet.
If you're after the fastest solution, a carefully constructed series of instructions using NSScanner would probably work best but that'd only be necessary if you plan to process huge (many megabytes) blocks of text.
according from #Mathieu Godart is best answer, but some line is missing , all answers just reduce space between words , but when if have tabs or have tab in place space , like this:
" this is text \t , and\tTab between , so on "
in three line code we will :
the string we want reduce white spaces
NSString * str_aLine = #" this is text \t , and\tTab between , so on ";
// replace tabs to space
str_aLine = [str_aLine stringByReplacingOccurrencesOfString:#"\t" withString:#" "];
// reduce spaces to one space
str_aLine = [str_aLine stringByReplacingOccurrencesOfString:#" +" withString:#" "
options:NSRegularExpressionSearch
range:NSMakeRange(0, str_aLine.length)];
// trim begin and end from white spaces
str_aLine = [str_aLine stringByTrimmingCharactersInSet:[NSCharacterSet whitespaceAndNewlineCharacterSet]];
the result is
"this is text , and Tab between , so on"
without replacing tab the resul will be:
"this is text , and Tab between , so on"
You can also use a simple while argument. There is no RegEx magic in there, so maybe it is easier to understand and alter in the future:
while([yourNSStringObject replaceOccurrencesOfString:#" "
withString:#" "
options:0
range:NSMakeRange(0, [yourNSStringObject length])] > 0);
Following two regular expressions would work depending on the requirements
#" +" for matching white spaces and tabs
#"\\s{2,}" for matching white spaces, tabs and line breaks
Then apply nsstring's instance method stringByReplacingOccurrencesOfString:withString:options:range: to replace them with a single white space.
e.g.
[string stringByReplacingOccurrencesOfString:regex withString:#" " options:NSRegularExpressionSearch range:NSMakeRange(0, [string length])];
Note: I did not use 'RegexKitLite' library for the above functionality for iOS 5.x and above.