I have two ImageViews, one called imageView and the other called subView (which is a subview of imageView).
I want to blend the images on these views together, with the user being able to switch the alpha of the blend with a pan. My code works, but right now, the code is slow as we are redrawing the image each time the pan gesture is moved. Is there a faster/more efficient way of doing this?
BONUS Q: I want to allow for my subView image to drawn zoomed in. Currently I've set my subView to be UIViewContentModeCenter, however I can't seem to draw a zoomed in part of my image with this content mode. Is there any way around this?
My drawrect:
- (void)drawRect:(CGRect)rect
{
float xCenter = self.center.x - self.currentImage1.size.width/2.0;
float yCenter = self.center.y - self.currentImage1.size.height/2.0;
subView.alpha = self.blendAmount; // Customize the opacity of the top image.
UIGraphicsBeginImageContext(self.currentImage1.size);
CGContextRef c = UIGraphicsGetCurrentContext();
CGContextSetBlendMode(c, kCGBlendModeColorBurn);
[imageView.layer renderInContext:c];
self.blendedImage = UIGraphicsGetImageFromCurrentImageContext();
UIGraphicsEndImageContext();
[self.blendedImage drawAtPoint:CGPointMake(xCenter,yCenter)];
}
You need to use GPU for image processing which is far faster than using CPU (as you're doing right now).
You can use Core Image framework which is very fast and easy to use but requires iOS 5, or you can use Open GL directly but you need to be experienced and have some knowledge about Open GL Shading.
Related
I have an Image inside UIScrollView which i can zoom in and out.
I have a button that let the user rotate the Image 90 degrees:
(void)RotateImage {
CGAffineTransform rotateTrans = CGAffineTransformMakeRotation(-90.0 / 180.0 * 3.14);
BaseImg.transform = rotateTrans;
}
After the imaged is rotated i cannot zoom in and out.. the image is going crazy on the screen and going back to the UNRotated state.
What am i doing wrong? code examples will be great!
Thanks :)
UIScrollView likes to take over the transforms of the views it contains. There are two solutions:
Rotate the image without changing the containing view.
Create a UIView subclass that displays an image within a sublayer.
To rotate the image, see How to Rotate a UIImage 90 degrees?. If you're always and only doing 90 degree rotation, see #Peter Sarnowski's solution. To adapt it to what you're doing here, assuming that BaseImg is a UIImageView:
- (void) rotateImage
{
UIImage *sourceImage = [baseImg image];
UIImage *rotatedImage = [UIImage imageWithCGImage:[sourceImage CGImage] scale:1.0 orientation:UIImageOrientationRight];
[baseImg setImage:rotatedImage];
}
This will only rotate once. To have rotateImage work repeatedly, read the existing orientation property and move it on to the next in clockwise or anticlockwise order.
If the image is not square, you may also need to resize baseImg to reflect its new aspect ratio.
To create a UIView subclass, you need to have it store a CALayer as a sublayer of the view layer. Store the image in the sublayer, and transform the sublayer at will. This is faster, and allows arbitrary rotation, but you need to calculate your own scaling to prevent the rotate image going outside the view bounds.
To simply rotate image the code is perfect but to add zoom in and out and then add rotation you need to retain its transforms.Here is a sample code that can help you.
https://github.com/elc/iCodeBlogDemoPhotoBoard
I am new to Objective-C and I want to let a screenshot made with
CGSize imageSize = [[UIScreen mainScreen] bounds].size;
...
UIGraphicsBeginImageContext(imageSize);
...
UIImage *image = UIGraphicsGetImageFromCurrentImageContext();
UIGraphicsEndImageContext();
"fly in" (rotating and stoping in random angle) inside an own image container, looking like a small photo (shadow, white border). how could I realize that?
Since you have a vague question - and your code shows only how you are getting the screen image - here's a general answer.
Put the image on a CAImageLayer
Add a border or a shadow or whatever other chrome you need to your image layer (or on another layer underneath it)
Use Core Animation to animate this CAImageLayer to whatever position or state you want it to be in.
You can accomplish it with OpenGL ES.
Here is a great project which provides generic base OpenGL ES view transition class.
https://github.com/epatel/EPGLTransitionView
There are several predefined transitions, you can take as an example https://github.com/epatel/EPGLTransitionView/tree/master/src
Demo3Transition actually shows how to rotate the screenshot
https://github.com/epatel/EPGLTransitionView/blob/master/src/Demo3Transition.m
You can view available transitions in actions if you launch DemoProject.
I am working on one iPhone App wherein I need to make a portion of the image transparent by setting its alpha level to 0 as the user moves around his finger on the image. Basically if you happen to know the app store application iSteam, user should be able to move his finger around on a top image which will make the background image transparent.
Currently I am using two UIImageView. One that holds the background image and the other on top of it which holds a darker image. Now user should be able to draw random curves on this darker image which will make the part of the background image appear on top. I am not able to figure out how should go about making the top image transparent which the top most of two UIImageView holds.
Any idea on this? Also what should I use for this? Quartz or Open GL. I am a newbie to the iPhone App Dev and have absolutely no idea about these APIs so some guidance from the experts will surely help me getting ahead with iPhone SDK Development.
The UIImageView has a layer which you can refer to as its layer and talk to when you've linked your project to QuartzCore. As the user moves a finger, clip a clear shape in an opaque-color-filled graphics context the same size as the UIImageView, turn that into a CGImageRef, set that as a CALayer's contents (again this CALayer needs to be the same size as the UIImageView), and set that layer as the UIImageView's layer.mask. Wherever the mask is clear, that punches a transparent hole in the layer, which means the view, which means the image the UIImageView is showing. (If that doesn't work, because the UIImageView doesn't like your interfering with its layer, you can use a superview of the UIImageView instead.)
EDIT (next day) - Here's sample code for a layer's delegate that punches a circular hole in the center:
-(void)drawLayer:(CALayer *)layer inContext:(CGContextRef)c {
CGRect r = CGContextGetClipBoundingBox(c);
CGRect r2 = CGRectInset(r, r.size.width/2.0 - 10, r.size.height/2.0 - 10);
UIImage* maskim;
{
UIGraphicsBeginImageContextWithOptions(r.size, NO, 0);
CGContextRef c = UIGraphicsGetCurrentContext();
CGContextAddEllipseInRect(c, r2);
CGContextAddRect(c, r);
CGContextEOClip(c);
CGContextSetFillColorWithColor(c, [UIColor blackColor].CGColor);
CGContextFillRect(c, r);
maskim = UIGraphicsGetImageFromCurrentImageContext();
UIGraphicsEndImageContext();
}
CALayer* mask = [CALayer layer];
mask.frame = r;
mask.contents = (id)maskim.CGImage;
layer.mask = mask;
}
So, if that layer is a view's layer, and if the UIImageView is that view's subview, a hole is punched in the UIImageView.
Here's a screen shot of the result:
I'm working on making an iPhone App where there are two ImageViews and when you touch the top one, wherever you tapped, the bottom one shows instead.
Basically what I want to do is cut an ellipse/roundedrect out of an image. To do this I was thinking on either clipping the image, or changing the alpha pixels in the rect to zero. I am new to Quartz 2D Programming so I am not sure how to do this.
Assuming I have:
UIImageView *topImage;
UIImageView *bottomImage;
How do I delete a CGRect/Ellipse/RoundedRect from these images.
This is kind of like those lottery tickets that you have to scratch off to reveal if you won.
I would generally try to make a mask from a path (here containing a rounded rectangle), then masking the image with it, as demonstrated in the apple docs. The one of the benefits of this is that for hit testing all you need to do is CGPathContainsPoint with the point that was touched (as in it will test whether it was in the visible area of the image).
I tried this code:
CGContextRef ctx = UIGraphicsGetCurrentContext();
CGRect frame = CGRectMake(100, 100, 100, 100);
CGPathRef roundedRectPath = [self newPathForRoundedRect:frame radius:5];
CGContextAddPath(ctx, roundedRectPath);
CGContextClip (ctx);
CGPathRelease(roundedRectPath);
(Together with the rounded rect path function you sent)
This is on a white view and beneath the view there is a gray Window, so I thought this would just show gray instead of white in CGRect frame but it didn't do anything...
I have a UIImageView that is displaying an image that is wider and taller than the UIImageView is. I would like to pan the image within the view using an animation (so that the pan is nice and smooth).
It seems to me that I should be able to just adjust the bounds.origin of the UIImageView, and the image should move (because the image should paint inside the view with that as its origin, right?) but that doesn't seem to work. The bounds.origin changes, but the image draws in the same location.
What almost works is to change the contentsRect of the view's layer. But this begins as a unit square, even though the viewable area of the image is not the whole image. So I'm not sure how I would detect that the far edge of the image is being pulled into the viewable area (which I need to avoid, since it displays by stretching the edge out to infinity, which looks, well, sub-par).
My view currently has its contentsGravity set to kCAGravityTopLeft via Interface Builder, if that makes a difference (Is it causing the image to move?). No other options seemed to be any better, though.
UPDATE: to be clear, I want to move the image inside the view, while keeping the view in the same spot.
I'd highly recommend enclosing your UIImageView in a UIScrollView. Have the UIImageView display the full image, and set the contentSize on the UIScrollView to be the same as your UIImageView's size. Your window into the image will be the size of the UIScrollView, and by using scrollRectToVisible:animated: you can pan to particular areas on the image in an animated fashion.
If you don't want scroll bars to appear, you can set the showsHorizontalScrollIndicator and showsVerticalScrollIndicatorproperties to NO.
UIScrollView also provides pinch-zooming functionality, which may or may not be useful to you.
Brad Larson pointed me down the right road with his suggestion to put the UIImageView inside a UIScrollView.
In the end I put the UIImageView inside of a UIScrollView, and set the scrollView's contentSize and the imageView's bounds to be the same size as the image in the UIImage:
UIImage* image = imageView.image;
imageView.bounds = CGRectMake(0, 0, image.size.width, image.size.height);
scrollView.contentSize = image.size;
Then, I can animate the scrollView's contentOffset to achieve a nice panning effect:
[UIView beginAnimations:#"pan" context:nil];
[UIView setAnimationDuration:animationDuration];
scrollView.contentOffset = newRect.origin;
[UIView commitAnimations];
In my particular case, I'm panning to a random space in the image. In order to find a proper rect to pan to and a proper duration to get a nice constant speed, I use the following:
UIImage* image = imageView.image;
float xNewOrigin = [TCBRandom randomIntLessThan:image.size.width - scrollView.bounds.size.width];
float yNewOrigin = [TCBRandom randomIntLessThan:image.size.height - scrollView.bounds.size.height];
CGRect oldRect = scrollView.bounds;
CGRect newRect = CGRectMake(
xNewOrigin,
yNewOrigin,
scrollView.bounds.size.width,
scrollView.bounds.size.height);
float xDistance = fabs(xNewOrigin - oldRect.origin.x);
float yDistance = fabs(yNewOrigin - oldRect.origin.y);
float hDistance = sqrtf(powf(xDistance, 2) + powf(yDistance, 2));
float hDistanceInPixels = hDistance;
float animationDuration = hDistanceInPixels / speedInPixelsPerSecond;
I'm using a speedInPixelsPerSecond of 10.0f, but other applications might want to use a different value.