In Oracle PL/SQL I was used to write:
SELECT * FROM MY_TABLE WHERE ROWNUM <= 100;
in order to fetch only the first 100 records of the table named MY_TABLE.
What could be the equivalent SELECT statement in SQL SERVER?
In SQL-Server You can Use TOP to select the no. of rows.
SELECT TOP 100 * FROM MY_TABLE
select top 100 * from tbl
column name is required or use *
SELECT TOP 100 * FROM TABLE
You can also filter rows by using where class
SELECT TOP 100 * FROM YOURTABLE WHERE YOURCONDITION
In SQL Server 2012, you can use OFFSET and FETCH to determine which rows to return. They're documented under ORDER BY; This makes sense since asking for 100 rows, when tables are by definition unordered, gives unpredictable results.
Similarly, if you use other's answers, re: TOP, you should also have an ORDER BY clause, or else it's not defined which rows will be returned.
SELECT TOP 100 * FROM MY_TABLE
Sorry if I misunderstood.
Edit: Must be faster
Related
I want to fire a Query "SELECT * FROM TABLE" but select only from row N+1. Any idea on how to do this?
For SQL Server 2012 and above, use this:
SELECT *
FROM Sales.SalesOrderHeader
ORDER BY OrderDate
OFFSET (#Skip) ROWS FETCH NEXT (#Take) ROWS ONLY
https://stackoverflow.com/a/19669165/1883345
SQL Server:
select * from table
except
select top N * from table
Oracle up to 11.2:
select * from table
minus
select * from table where rownum <= N
with TableWithNum as (
select t.*, rownum as Num
from Table t
)
select * from TableWithNum where Num > N
Oracle 12.1 and later (following standard ANSI SQL)
select *
from table
order by some_column
offset x rows
fetch first y rows only
They may meet your needs more or less.
There is no direct way to do what you want by SQL.
However, it is not a design flaw, in my opinion.
SQL is not supposed to be used like this.
In relational databases, a table represents a relation, which is a set by definition. A set contains unordered elements.
Also, don't rely on the physical order of the records. The row order is not guaranteed by the RDBMS.
If the ordering of the records is important, you'd better add a column such as `Num' to the table, and use the following query. This is more natural.
select *
from Table
where Num > N
order by Num
Query: in sql-server
DECLARE #N INT = 5 --Any random number
SELECT * FROM (
SELECT ROW_NUMBER() OVER(ORDER BY ID) AS RoNum
, ID --Add any fields needed here (or replace ID by *)
FROM TABLE_NAME
) AS tbl
WHERE #N < RoNum
ORDER BY tbl.ID
This will give rows of Table, where rownumber is starting from #N + 1.
In order to do this in SQL Server, you must order the query by a column, so you can specify the rows you want.
Example:
select * from table order by [some_column]
offset 10 rows
FETCH NEXT 10 rows only
Do you want something like in LINQ skip 5 and take 10?
SELECT TOP(10) * FROM MY_TABLE
WHERE ID not in (SELECT TOP(5) ID From My_TABLE ORDER BY ID)
ORDER BY ID;
This approach will work in any SQL version. You need to stablish some order (by Id for example) so all rows are provided in a predictable manner.
I know it's quite late now to answer the query. But I have a little different solution than the others which I believe has better performance because no comparisons are performed in the SQL query only sorting is done. You can see its considerable performance improvement basically when value of SKIP is LARGE enough.
Best performance but only for SQL Server 2012 and above. Originally from #Majid Basirati's answer which is worth mentioning again.
DECLARE #Skip INT = 2, #Take INT = 2
SELECT * FROM TABLE_NAME
ORDER BY ID ASC
OFFSET (#Skip) ROWS FETCH NEXT (#Take) ROWS ONLY
Not as Good as the first one but compatible with SQL Server 2005 and above.
DECLARE #Skip INT = 2, #Take INT = 2
SELECT * FROM
(
SELECT TOP (#Take) * FROM
(
SELECT TOP (#Take + #Skip) * FROM TABLE_NAME
ORDER BY ID ASC
) T1
ORDER BY ID DESC
) T2
ORDER BY ID ASC
What about this:
SELECT * FROM table LIMIT 50 OFFSET 1
This works with all DBRM/SQL, it is standard ANSI:
SELECT *
FROM owner.tablename A
WHERE condition
AND n+1 <= (
SELECT COUNT(DISTINCT b.column_order)
FROM owner.tablename B
WHERE condition
AND b.column_order>a.column_order
)
ORDER BY a.column_order DESC
PostgreSQL: OFFSET without LIMIT
This syntax is supported, and it is in my opinion the cleanest API compared to other SQL implementations as it does not introduce any new keywords:
SELECT * FROM mytable ORDER BY mycol ASC OFFSET 1
that should definitely be standardized.
The fact that this is allowed can be seen from: https://www.postgresql.org/docs/13/sql-select.html since LIMIT and OFFSET can be given independently, since OFFSET is not a sub-clause of LIMIT in the syntax specification:
[ LIMIT { count | ALL } ]
[ OFFSET start [ ROW | ROWS ] ]
SQLite: negative limit
OFFSET requires LIMIT in that DBMS, but dummy negative values mean no limit. Not as nice as PostgreSQL, but it works:
SELECT * FROM mytable ORDER BY mycol ASC LIMIT -1 OFFSET 1
Asked at: SQLite with skip (offset) only (not limit)
Documented at: https://sqlite.org/lang_select.html
If the LIMIT expression evaluates to a negative value, then there is no upper bound on the number of rows returned.
MySQL: use a huge limit number
Terrible API design, the documentation actually recommends it:
SELECT * FROM tbl LIMIT 1,18446744073709551615;
Asked at: MySQL skip first 10 results
Node.js Sequelize ORM implements it
That ORM allows e.g. findAll({offset: without limit:, and implements workarounds such as the ones mentioned above for each different DBMS.
In Faircom SQL (which is a pseudo MySQL), i can do this in a super simple SQL Statement, just as follows:
SELECT SKIP 10 * FROM TABLE ORDER BY Id
Obviously you can just replace 10 with any declared variable of your desire.
I don't have access to MS SQL or other platforms, but I'll be really surprised MS SQL doesn't support something like this.
DECLARE #Skip int= 2, #Take int= 2
SELECT * FROM TABLE_NAME
ORDER BY Column_Name
OFFSET (#Skip) ROWS FETCH NEXT (#Take) ROWS ONLY
try below query it's work
SELECT * FROM `my_table` WHERE id != (SELECT id From my_table LIMIT 1)
Hope this will help
You can also use OFFSET to remove the 1st record from your query result like this-
Example - find the second max salary from the employee table
select distinct salary from employee order by salary desc limit 1 OFFSET 1
For SQL Server 2012 and later versions, the best method is #MajidBasirati's answer.
I also loved #CarlosToledo's answer, it's not limited to any SQL Server version but it's missing Order By Clauses. Without them, it may return wrong results.
For SQL Server 2008 and later I would use Common Table Expressions for better performance.
-- This example omits first 10 records and select next 5 records
;WITH MyCTE(Id) as
(
SELECT TOP (10) Id
FROM MY_TABLE
ORDER BY Id
)
SELECT TOP (5) *
FROM MY_TABLE
INNER JOIN MyCTE ON (MyCTE.Id <> MY_TABLE.Id)
ORDER BY Id
While using SELECT TOP 5 * FROM SOMETABLE gives me an error
ORA-00923: FROM keyword not found where expected
I am using Oracle 11g . I am aware of using rownum for doing the same thing but just wondering SQL TOP usage is not at all supported in Oracle ? Anything need to do extra to make SQL TOP working in Oracle ??
Oracle does not support TOP. Use ROWNUM
SELECT * FROM your_table
WHERE ROWNUM <= 5
SQLFiddle example
No, Oracle does not support TOP.
As you point out, the best approach is to use rownum. Another option is the analytical function ROW_NUMBER.
The rownum keyword, while it gets you the said no. of records, does so only after applying the order by clause if you have one.
So if the SQL server query is as below, it will give you 10 most recently created records.
Select TOP 10 * from mytable order by created_date desc
But to fit Oracle, when you write this, it gets you the 10 records (that may not be the most recent ones) and arranges them in descending order, which is not what you wanted.
Select * from mytable where rownum < 10 order by created_date desc
So writing with an additional select like this would help:
SELECT * FROM (Select * from mytable order by created_date desc) where rownum < 10
SQL TOP does NOT work for Oracle.
How do you select a random rows from a table?
For example, if there are 1000 rows in a table matching the criteria that I want, I want to select just 20 random ones.
Like TOP, but random.
Thanks, and this is for SQL Server CE 3.5!
How about this?
SELECT TOP(20) * FROM myTable ORDER BY NEWID()
How about SELECT * FROM tbl_name ORDER BY RAND() LIMIT 0,20;
However if your db is with million rows Both newid() and rand() would perform slow.
There is a faster solution .Read this
I want to fetch records from a table in my sql server database in parts. Like, in one query I want to see first 1000 records, in next query next 1000 records. Likewise..
Is it possible with sql server ? I am using sql server 2008. While googling, I found LIMIT clause for mysql, but it does not work for sql server. So can any one give in Sql. Please help.
First 1000 records:
SELECT TOP 1000 *
FROM mytable
ORDER BY
mycolumn
General solution (supports offset)
SELECT *
FROM (
SELECT *,
ROW_NUMBER() OVER (ORDER BY mycolumn) rn
FROM mytable
) q
WHERE rn BETWEEN 1001 AND 2000
ORDER BY
mycolumn
Have also a look at T-sql: how to perform optimised Paging?
Is there any way to select, for example, first 10 rows of a table in T-SQL (working MSSQL)?
I think I saw something in Oracle defined as rownum meta variable, used in a following way
select * from Users where rownum<=10
But what about MSSQL?
select top(#count) * from users
If #count is a constant, you can drop the parentheses:
select top 42 * from users
(the latter works on SQL Server 2000 too, while the former requires at least 2005)
You can use Microsoft's row_number() function to decide which rows to return. That means that you aren't limited to just the top X results, you can take pages.
SELECT *
FROM (SELECT row_number() over (order by UserID) AS line_no, *
FROM dbo.User) as users
WHERE users.line_no < 10
OR users.line_no BETWEEN 34 and 67
You have to nest the original query though, because otherwise you'll get an error message telling you that you can't do what you want to in the way you probably should be able to in an ideal world.
Msg 4108, Level 15, State 1, Line 3
Windowed functions can only appear in the SELECT or ORDER BY clauses.
SELECT TOP 10 *
FROM Users
Note that if you don't specify an ORDER BY clause then any 10 rows could be returned, because "first 10 rows" doesn't really mean anything until you tell the database what ordering to use.
You can also use rowcount, but TOP is probably better and cleaner, hence the upvote for Mehrdad
SET ROWCOUNT 10
SELECT * FROM dbo.Orders
WHERE EmployeeID = 5
ORDER BY OrderDate
SET ROWCOUNT 0
Try this.
declare #topval int
set #topval = 5 (customized value)
SELECT TOP(#topval) * from your_database
SELECT TOP 10 * FROM TABLE_NAME ORDER BY ORDERED_UNIQUE_COLUMN
DESC
ORDERED_UNIQUE_COLUMN could be your incrementing primary key or a timestamp
Try this:
SELECT * FROM USERS LIMIT 10;