NSFormatter for BOOL - objective-c

I have set up my simple Xcode project with a table that is binded to an array controller. It works fine if the array controller is full of entities with a string attribute. However I want to change the attribute to a BOOL and have the table show the string "true" or "false" based on the BOOL.
I have overrided the following two methods from NSFormatter:
-(NSString*) stringForObjectValue:(id)object {
//what is the object?
NSLog(#"object is: %#", object);
if(![object isKindOfClass: [ NSString class ] ] ) {
return nil;
}
//i'm tired....just output hello in the table!!
NSString *returnStr = [[NSString alloc] initWithFormat:#"hello"];
return returnStr;
}
-(BOOL)getObjectValue: (id*)object forString:string errorDescription:(NSString**)error {
if( object ) {
return YES;
}
return NO;
}
So the table gets populated with "hello" if the attribute is a string however if I switch it to a boolean, then the table gets populated with lots of blank spaces.
I don't know if this helps but on the line where I'm outputting the object, it outputs __NSCFString if the attribute is a string and "Text Cell" if I switch the attribute to a boolean. This is something else I don't understand.

Ok, it's not 100% clear what you're trying to do from the code, but first things first - BOOL is not an object, it's basically 0 or 1, so to place BOOL values into an array, you're probably best off using NSNumber:
NSNumber *boolValue = [NSNumber numberWithBool:YES];
and placing these into your array. Now you want to change your method:
-(NSString*) stringForObjectValue:(id)object {
NSNumber *number = (NSNumber *)object;
if ([number boolValue] == YES)
return #"true";
else
return #"false";
}
There's a few things here - for example, you want to avoid passing around id references if you can (if you know all your objects in the NSArray are NSNumber, you shouldn't need to).

Related

distinctUnionOfObjects case insensitive

I have an array of NSDictionary. Each array item has a key named "Name". Now I want to remove duplicate entries based on this name value.
This work perfectly:
aMyArray = [aMyArray valueForKeyPath:#"#distinctUnionOfObjects.Name"];
The problem are that result array still contains duplicates string, based on the case. Ex: [#"Franck", "franck"]
How can I remove these duplicate?
Thanks
You could try to do this
// in your class implementation
- (BOOL)isEqual:(id)object {
if (![object isKindOfClass:[self class]]) {
return NO;
}
typeof(self) obj = (typeof(self))object;
return ([self.Name caseInsensitiveCompare:obj.Name] == NSOrderedSame);
}
- (NSUInteger)hash
{
return [[self.Name lowercaseString] hash];
}
// and then
NSSet *distinctObjects = [[NSSet alloc] initWithArray:array];
NSArray *result = distinctObjects.allObjects;
Alternatively you could customise this KVC collection operator by swizzling valueForKeyPath: to parse your custom DSL, possibly winding up with something like
aMyArray = [aMyArray valueForKeyPath:#"#distinctUnionOfObjects[caseInsensitive].Name"];
which doesn't seem to be a good idea for me, but it certainly a viable solution to your problem.

How can I force NSTextField to only allow numbers?

In Interface Builder I’ve created a textfield and stuck an NSNumberFormatter into the cell. However, the user can still type text into the textfield. Is there any way to restrict the input to numbers only using interface builder? I thought that was the point of the NSNumberFormatter.
Every formatter has this method:
- (BOOL) getObjectValue: (id*) object forString: (NSString*) string
errorDescription: (NSError**) error;
This is valid for every formatter.
If the string is not valid it returns false and the object passed as argument (dereferenced) will be nil.
So instead of dropping a number formatter to the text field, use your own formatter as instance variable.Observe the text field implementing the delegate protocol so that at every change of the text you can be notified.
Then invoke this method:
NSNumber* number;
BOOL success=[formatter getObjectValue: &number forString: [myTextField stringValue] errorDescription:nil];
At this point if success is false (or check if number is nil), there is an invalid string in the text field, so do the action that is more appropriate for you (maybe delete the entire string, or display 0.0 as value).
There is also another method:
- (BOOL) isPartialStringValid : (NSString*) partialString: (NSString*) partialString
errorDescription: (NSString*) error;
This way you can know if a partial string is valid.For example with the scientific notation "1e" is not valid, but is partially valid because the user may add 1 and it will become "1e1".
Create an NSNumberFormatter subclass and put this in the implementation. In your code, set the YKKNumberFormatter as the formatter for the NSTextField/UITextField.
#implementation YKKNumberFormatter
- (BOOL)isPartialStringValid:(NSString *)partialString newEditingString:(NSString **)newString errorDescription:(NSString **)error {
// Make sure we clear newString and error to ensure old values aren't being used
if (newString) { *newString = nil;}
if (error) {*error = nil;}
static NSCharacterSet *nonDecimalCharacters = nil;
if (nonDecimalCharacters == nil) {
nonDecimalCharacters = [[[NSCharacterSet decimalDigitCharacterSet] invertedSet] retain];
}
if ([partialString length] == 0) {
return YES; // The empty string is okay (the user might just be deleting everything and starting over)
} else if ([partialString rangeOfCharacterFromSet:nonDecimalCharacters].location != NSNotFound) {
return NO; // Non-decimal characters aren't cool!
}
return YES;
}
#end

iOS asserting NSMutableArray contains 2 objects, regardless of index

I have the following test case in my iOS application :
-(void) testTwoDefaultUsersExist
{
NSString * expected;
NSString * actual;
expected = #"John Smith";
actual = [[[userService getAllUsers]objectAtIndex:0] fullName];
STAssertEqualObjects(expected, actual, #"Not equal");
expected = #"Dave Brown";
actual = [[[userService getAllUsers]objectAtIndex:1] fullName];
STAssertEqualObjects(expected, actual, #"Not equal");
}
The above just checks that my call to [userService getAllUsers] returns 2 User objects, one with a name of John Smith, the other with Dave Brown. This appears to work fine for this scenario, but I have other cases where that ordering may change, so John may be placed in index 1 rather than 0
Question : How can I assert that the NSMutableArray, being returned from the call to [userService getAllUsers] contains those 2 objects, regardless of ordering?
Can you not simply use the NSArray method -containsObject:? An NSMutableArray is still an NSArray, so you can do:
NSArray * expected = [NSArray arrayWithObjects:#"John Smith", #"Dave Brown", nil];
NSArray * actual = [[userService getAllUsers] valueForKey:#"fullName"];
for(NSString * name in expected) {
STAssertTrue([actual containsObject:name], #"Missing name");
}
Note the (ab)use of -valueForKey: to transform an array of user objects into an array of NSString objects, making the -containsObject: call simpler. This will only work if your user object is key-value coding compliant for the fullName property.
NSMutableArray always contains the elements as you insert them to the array
You can iterate over the elements that you insert and test if they're at the NSArray using:
- (NSUInteger)indexOfObject:(id)anObject
If the object is not found it returns NSNotFound, that can be used with the Unit Test Framework that you choice
Greetings
Assert on equality like this
NSAssert1([userService getAllUsers].count == 2, #"SomeDescription", nil);
If you want to search an array for the existence of some strings, use the following function
- (BOOL) containsAllNames:(NSArray*)arrToSearch namesToSearch:(NSArray*)arr
{
BOOL containsAll = YES;
for (NSString *name in arr) {
BOOL containsCurrent = NO;
for (NSString *nameToSearch in arrToSearch) {
if ([name isEqualToString:nameToSearch]) {
containsCurrent = YES;
break;
}
}
if (!containsCurrent) {
containsAll = NO;
}
}
return containsAll;
}
Call it like
NSArray *toSearch = [NSArray arrayWithObjects:#"John Smith", #"Dave Brown", nil];
[self containsAllNames:YourArray namesToSearch:toSearch];

How to check if an NSDictionary or NSMutableDictionary contains a key?

I need to check if an dict has a key or not. How?
objectForKey will return nil if a key doesn't exist.
if ([[dictionary allKeys] containsObject:key]) {
// contains key
}
or
if ([dictionary objectForKey:key]) {
// contains object
}
More recent versions of Objective-C and Clang have a modern syntax for this:
if (myDictionary[myKey]) {
}
You do not have to check for equality with nil, because only non-nil Objective-C objects can be stored in dictionaries(or arrays). And all Objective-C objects are truthy values. Even #NO, #0, and [NSNull null] evaluate as true.
Edit: Swift is now a thing.
For Swift you would try something like the following
if let value = myDictionary[myKey] {
}
This syntax will only execute the if block if myKey is in the dict and if it is then the value is stored in the value variable. Note that this works for even falsey values like 0.
if ([mydict objectForKey:#"mykey"]) {
// key exists.
}
else
{
// ...
}
When using JSON dictionaries:
#define isNull(value) value == nil || [value isKindOfClass:[NSNull class]]
if( isNull( dict[#"my_key"] ) )
{
// do stuff
}
I like Fernandes' answer even though you ask for the obj twice.
This should also do (more or less the same as Martin's A).
id obj;
if ((obj=[dict objectForKey:#"blah"])) {
// use obj
} else {
// Do something else like creating the obj and add the kv pair to the dict
}
Martin's and this answer both work on iPad2 iOS 5.0.1 9A405
One very nasty gotcha which just wasted a bit of my time debugging - you may find yourself prompted by auto-complete to try using doesContain which seems to work.
Except, doesContain uses an id comparison instead of the hash comparison used by objectForKey so if you have a dictionary with string keys it will return NO to a doesContain.
NSMutableDictionary* keysByName = [[NSMutableDictionary alloc] init];
keysByName[#"fred"] = #1;
NSString* test = #"fred";
if ([keysByName objectForKey:test] != nil)
NSLog(#"\nit works for key lookups"); // OK
else
NSLog(#"\nsod it");
if (keysByName[test] != nil)
NSLog(#"\nit works for key lookups using indexed syntax"); // OK
else
NSLog(#"\nsod it");
if ([keysByName doesContain:#"fred"])
NSLog(#"\n doesContain works literally");
else
NSLog(#"\nsod it"); // this one fails because of id comparison used by doesContain
Using Swift, it would be:
if myDic[KEY] != nil {
// key exists
}
Yes. This kind of errors are very common and lead to app crash. So I use to add NSDictionary in each project as below:
//.h file code :
#interface NSDictionary (AppDictionary)
- (id)objectForKeyNotNull : (id)key;
#end
//.m file code is as below
#import "NSDictionary+WKDictionary.h"
#implementation NSDictionary (WKDictionary)
- (id)objectForKeyNotNull:(id)key {
id object = [self objectForKey:key];
if (object == [NSNull null])
return nil;
return object;
}
#end
In code you can use as below:
NSStrting *testString = [dict objectForKeyNotNull:#"blah"];
For checking existence of key in NSDictionary:
if([dictionary objectForKey:#"Replace your key here"] != nil)
NSLog(#"Key Exists");
else
NSLog(#"Key not Exists");
Because nil cannot be stored in Foundation data structures NSNull is sometimes to represent a nil. Because NSNull is a singleton object you can check to see if NSNull is the value stored in dictionary by using direct pointer comparison:
if ((NSNull *)[user objectForKey:#"myKey"] == [NSNull null]) { }
Solution for swift 4.2
So, if you just want to answer the question whether the dictionary contains the key, ask:
let keyExists = dict[key] != nil
If you want the value and you know the dictionary contains the key, say:
let val = dict[key]!
But if, as usually happens, you don't know it contains the key - you want to fetch it and use it, but only if it exists - then use something like if let:
if let val = dict[key] {
// now val is not nil and the Optional has been unwrapped, so use it
}
I'd suggest you store the result of the lookup in a temp variable, test if the temp variable is nil and then use it. That way you don't look the same object up twice:
id obj = [dict objectForKey:#"blah"];
if (obj) {
// use obj
} else {
// Do something else
}
if ([MyDictionary objectForKey:MyKey]) {
// "Key Exist"
}
As Adirael suggested objectForKey to check key existance but When you call objectForKeyin nullable dictionary, app gets crashed so I fixed this from following way.
- (instancetype)initWithDictionary:(NSDictionary*)dictionary {
id object = dictionary;
if (dictionary && (object != [NSNull null])) {
self.name = [dictionary objectForKey:#"name"];
self.age = [dictionary objectForKey:#"age"];
}
return self;
}
if ( [dictionary[#"data"][#"action"] isKindOfClass:NSNull.class ] ){
//do something if doesn't exist
}
This is for nested dictionary structure

get type of NSNumber

I want to get the type of NSNumber instance.
I found out on http://www.cocoadev.com/index.pl?NSNumber this:
NSNumber *myNum = [[NSNumber alloc] initWithBool:TRUE];
if ([[myNum className] isEqualToString:#"NSCFNumber"]) {
// process NSNumber as integer
} else if ([[myNum className] isEqualToString:#"NSCFBoolean"]) {
// process NSNumber as boolean
}
Ok, but this doesn't work, the [myNum className] isn't recognized by the compiler.
I'm compiling for iPhone.
I recommend using the -[NSNumber objCType] method.
It allows you to do:
NSNumber * n = [NSNumber numberWithBool:YES];
if (strcmp([n objCType], #encode(BOOL)) == 0) {
NSLog(#"this is a bool");
} else if (strcmp([n objCType], #encode(int)) == 0) {
NSLog(#"this is an int");
}
For more information on type encodings, check out the Objective-C Runtime Reference.
You can get the type this way, no string comparisons needed:
CFNumberType numberType = CFNumberGetType((CFNumberRef)someNSNumber);
numberType will then be one of:
enum CFNumberType {
kCFNumberSInt8Type = 1,
kCFNumberSInt16Type = 2,
kCFNumberSInt32Type = 3,
kCFNumberSInt64Type = 4,
kCFNumberFloat32Type = 5,
kCFNumberFloat64Type = 6,
kCFNumberCharType = 7,
kCFNumberShortType = 8,
kCFNumberIntType = 9,
kCFNumberLongType = 10,
kCFNumberLongLongType = 11,
kCFNumberFloatType = 12,
kCFNumberDoubleType = 13,
kCFNumberCFIndexType = 14,
kCFNumberNSIntegerType = 15,
kCFNumberCGFloatType = 16,
kCFNumberMaxType = 16
};
typedef enum CFNumberType CFNumberType;
If all you want is to differentiate between booleans and anything else, you can make use of the fact that boolean NSNumbers always return a shared instance:
NSNumber *num = ...;
if (num == (void*)kCFBooleanFalse || num == (void*)kCFBooleanTrue) {
// num is boolean
} else {
// num is not boolean
}
NSNumber explicitly doesn't guarantee that the returned type will match the method used to create it, so doing this at all is probably a bad idea.
However, you could probably do something like this (you could also compare to objc_getClass("NSCFNumber") etc., but this is arguably more portable):
Class boolClass = [[NSNumber numberWithBool:YES] class];
/* ... */
if([myNum isKindOfClass:boolClass]) {
/* ... */
}
In Swift:
let numberType = CFNumberGetType(answer)
switch numberType {
case .charType:
//Bool
case .sInt8Type, .sInt16Type, .sInt32Type, .sInt64Type, .shortType, .intType, .longType, .longLongType, .cfIndexType, .nsIntegerType:
//Int
case .float32Type, .float64Type, .floatType, .doubleType, .cgFloatType:
//Double
}
Use the method -[NSNumber objCType] method to get the type.
If the type's equal to #encode(BOOL), or the number itself is kCFBooleanFalse, or kCFBooleanTrue, it's a boolean.
If it's anything else but 'c', it's a number.
If it's 'c', what appears to be the only way supported way, without checking against private class names, or comparing against undocumented singletons, is to turn make an array of one element, the number, and then use NSJSONSerialization to get the string representation. Finally, check if the string representation contains the string "true" or "false". Here is the full code for checking if an NSNumber is a BOOL:
-(BOOL)isBool
{
if(!strcmp(self.objCType, #encode(BOOL)) ||
self == (void*)kCFBooleanFalse ||
self == (void*)kCFBooleanTrue)
{
return YES;
}
if(strcmp(self.objCType, "c"))
{
return NO;
}
NSString * asString = [[NSString alloc] initWithData:[NSJSONSerialization dataWithJSONObject:#[self] options:kNilOptions error:nil] encoding:NSUTF8StringEncoding];
return [asString containsString:#"true"] || [asString containsString:#"false"];
}
Note that using NSJSONSerialization is slow and if #NO/#YES ever stops always equalling kCFBooleanFalse/kCFBooleanTrue, then this method probably shouldn't be used in a tight loop.
The reason the compiler warns you and it doesn't work is because -[NSObject className] is declared in a category on NSObject on Mac OS X (in NSScriptClassDescription.h) and not declared on iPhone. (It doesn't support AppleScript, obviously.) NSStringFromClass([myNum class]) is what you should use to be safe across all platforms. Odds are that -className is declared as a simple wrapper around NSStringFromClass() anyway...
NSString *classString = NSStringFromClass([myNum class]);
That should ger the string you want.
To check that NSNumber contains a bool value Try this:
if (strcmp([myNumber objCType], [#(YES) objCType]) == 0)
NSLog(#"%#", [myNumber boolValue] ? #"true" : #"false");
objCType documentation states that The returned type does not necessarily match the method the number object was created with
Secondly, other methods of comparing the class of number to a given class type or assuming boolean number instances to be shared singletons are not documented behaviour.
A more(not completely though) reliable way is to depend on NSJSONSerialisation as it correctly recognises number instances created with bool and outputs true/false in json. This is something we can expect Apple to take care of while moving with new SDKs and on different architectures. Below is the code:
+(BOOL) isBoolType:(NSNumber*) number {
NSError* err;
NSData* jsonData = [NSJSONSerialization dataWithJSONObject:#{#"key":number}
options:0
error:&err];
NSString* jsonString = [[NSString alloc]
initWithData:jsonData
encoding:NSUTF8StringEncoding];
return [jsonString containsString:#"true"]
|| [jsonString containsString:#"false"];
}
Swift Version
NSNumber is a class-cluster so each underlying type can be figured from the instance. This code avoids hard-coding the different NSNumber types by creating an instance of the expected type, and then comparing it against the unknown type.
extension NSNumber {
var isBool: Bool {
return type(of: self) == type(of: NSNumber(booleanLiteral: true))
}
}
check object is of NSNumber type :
if([obj isKindOfClass:NSClassFromString(#"__NSCFNumber")])
{
//NSNumber
}