I want to select the second row only from the table. From the ClientUserName column.
SELECT
ClientUserName, DestHost, count(DestHost) counts
FROM
#ProxyLog_record
WHERE
ClientUserName = (Select top 1 ClientUserName from #ProxyLog_count_2)
GROUP BY
ClientUserName, DestHost
ORDER BY
counts DESC
The (Select top 1 ClientUserName from #ProxyLog_count_2) shows top 1 only but I need to get the 2nd data from that table. How can I do this?
Presumably, you are using SQL Server. The "top 1" is selecting a random row from the table, because you have no order by clause.
If you want the second row inserted into the table, the way to do this is to define an auto-incrementing column in the table. The create table statement should include:
create table #ProxyLog_count_2 (
ProxyLog_Count_2_id int not null identity(1,1),
...
)
You can then get the second row inserted by using the simple where clause:
where ProxyLog_Count_2_id = 2
Easiest way would be to use the ROW_NUMBER() method like so:
WITH c AS (
SELECT
ClientUserName, DestHost, count(DestHost) counts, ROW_NUMBER() OVER(ORDER BY count(DestHost)) AS rowNum
FROM
#ProxyLog_record
GROUP BY
ClientUserName, DestHost
)
SELECT ClientUserName, DestHost, counts
FROM c
WHERE rowNum = 2
(Don't use count(DestHost) counts if it's not required, or use another CTE to save counting twice)
Try:
SELECT
ClientUserName, DestHost, count(DestHost) counts
FROM
#ProxyLog_record
WHERE
ClientUserName = (
;with cte as
(
select ROW_NUMBER() over (order by ClientUserName) as rn, *
from #ProxyLog_count_2
)
select ClientUserName from cte where rn=2
)
GROUP BY
ClientUserName, DestHost
ORDER BY
counts DESC
Based on what you've tried so far...
SELECT top 1
ClientUserName, DestHost, count(DestHost) counts
FROM
#ProxyLog_record
WHERE
ClientUserName <> (Select top 1 ClientUserName from #ProxyLog_count_2)
GROUP BY
ClientUserName, DestHost
ORDER BY
counts DESC
You could use ROW_NUMBER()...
You could use a cursor...
You could put an identifier in the top row to allow you to filter it out (and then subsequently, select the top 1 again and you'd have it).
Otherwise, if there is something identifiable about the 2nd row (does it have the highest something, or the lowest, or the most recent date, etc.),
Wjy not just select top 2 and take the aecomd row from esult set?
SELECT Top 1 a.ClientUserName, a.DestHost, a.counts
FROM
(
SELECT Top 2
ClientUserName, DestHost, count(DestHost) counts
FROM
#ProxyLog_record
WHERE
ClientUserName = (Select top 1 ClientUserName from #ProxyLog_count_2)
GROUP BY
ClientUserName, DestHost
ORDER BY
counts DESC
)
as a
ORDER BY a.Counts ASC
Related
I have a table as follow
ID
ORDERNO
1
123
1
123
2
456
2
456
During every select query done via application using JDBC, only the grouped records based on ORDERNO should be picked.
That means, for example, during first select query only details related to ID = 1, but we cannot specify the ID number in where clause because we do not know how many number of IDs will be there in future. So the query should yield only one set of records; application will delete those records after picking, hence next select query will result in picking other set of records. How to achieve it?
You can use TOP WITH TIES for this
SELECT TOP (1) WITH TIES
t.ID,
t.ORDERNO
FROM YourTable t
ORDER BY
t.ID;
If you want to select and delete at the same time you could delete using an OUTPUT clause
WITH cte AS (
SELECT TOP (1) WITH TIES
t.ID,
t.ORDERNO
FROM YourTable t
ORDER BY
t.ID
)
DELETE cte
OUTPUT deleted.*;
As one option you could select on the MIN(ID) like:
SELECT *
FROM yourtable
WHERE ID = (SELECT MIN(ID) FROM yourtable);
You could also use window functions to do this:
SELECT ID, ORDERNO
FROM
(
SELECT ID, ORDERNO
DENSE_RANK() OVER (ORDER BY ID ASC) AS dr
FROM yourtable
)dt
WHERE dr = 1;
order your rows and select top n number of rows that you want :
select top (1) with ties ID, ORDERNO
from tablename
order by ID asc
I want to exclude records where id > 5 then select the top 1 of it order by date. How can I achieve this? Each record has audit_line which is unique field for each record. Recent SQL script is on below:
SELECT *
FROM db.table
HAVING COUNT(id) > 5
If you want id > 5 then you want where:
select top (1) t.*
from db.table t
where id > 5
order by date;
You can use row-numbering for this.
Note that if you have no other column to order by, you can do ORDER BY (SELECT NULL), but then you may get different results on each run.
SELECT *
FROM (
SELECT *, ROW_NUMBER() OVER (PARTITION BY id ORDER BY some_other_column) rn
FROM table
) t
WHERE rn = 5;
I have thousands of groups in a table, something like :
1..
1..
2..
2..
2..
2..
3..
3..
.
.
.
10000..
10000..
How can i make a select that give me the Top 3 groups each time.
I Want something like select Top 3 from rows , but it have to return the first three groups not the first three rows.
You can try this :
;with cte as (
select distinct groupId from mytable order by groupid
)
select * from mytable where TheGroupId in (select top 3 groupdid from cte)
You can use DENSE_RANK to assign a number to each group. All members of the same group will have the same number. Then in an outer query, select top 3 groups:
SELECT *
FROM (SELECT *, DENSE_RANK() OVER (ORDER BY id) AS rnk
FROM mytable ) t
WHERE t.rnk <= 3
The above query assumes that id is the column used to group records together.
SQL Fiddle Demo
Use Ranking function Row_Number() :
SELECT *
FROM (SELECT *,
Row_number()
OVER(
partition BY GroupId
ORDER BY GroupId) AS [rn]
FROM YourTable) t
WHERE rn <= 3
Check this MSDN doc for details of all ranking functions.
There is a sql TOP statement that does this
SELECT TOP number|percent column_name(s) FROM table_name;
a description of what it does and how it is used in alternative sql statements for example for mysql and ms access can be found here: http://www.w3schools.com/sql/sql_top.asp
My bad i misread your question, this will return the top rows not groups, could you explain what you are trying to do in more detail?
SELECT *
FROM
(SELECT *
,ROW_NUMBER() OVER (PARTITION BY [Group] ORDER BY [Group] ASC)rn
FROM TableName
)A
WHERE rn <= 3
I used this code to select last 5 rows from table:
SELECT TOP(5) * FROM tbl_reg ORDER BY Id DESC
But I want to reorder this result ( the last five rows returned ) By Id ASC
How can I do this?
Use a subquery:
select t.*
from (SELECT TOP(5) * FROM tbl_reg ORDER BY Id DESC) t
order by id ASC;
My query is as follows
BEGIN
WITH MyCTE
AS (
SELECT T.MusicAlbumTitle
,D.musicTitle
,D.mVideoID
,D.musicFileName
,T.ReleaseDate AS ReleasedDate
,D.MusicLength
,D.musicSinger
,D.MusicVideoID
,D.ExternalLink
,D.CoverImg
,ROW_NUMBER() OVER (
PARTITION BY D.MusicVideoID ORDER BY D.mVideoID
) AS row_num
FROM dbo.Music_Video T
JOIN dbo.Music_Video_Details D ON T.MusicVideoID = D.MusicVideoID
WHERE T.PortalID = #PortalID
AND T.CultureCode = #CultureCode
AND T.ComingSoon <> 1
GROUP BY T.MusicAlbumTitle
,D.musicTitle
,D.mVideoID
,T.ReleaseDate
,D.musicFileName
,D.MusicLength
,D.musicSinger
,D.MusicVideoID
,D.ExternalLink
,D.CoverImg
)
SELECT a.mVideoID
,a.MusicVideoID
,a.musicFileName
,a.MusicAlbumTitle
,a.ReleasedDate
,a.row_num
,a.CoverImg
,a.ExternalLink
,a.musicTitle
,a.MusicLength
FROM MyCTE a
WHERE row_num = 1
ORDER BY MusicVideoID DESC
END
I need to achieve total row count from last select statement.
which mean total row count that is being selected.
or any idea that might be use in this condition
How can i do this ..
Please add COUNT(*) OVER() in your select, which returns total rows selected as a new column.
Ex:
SELECT
*,
COUNT(*) OVER() AS [Total_Rows]
FROM YourTable
Just to be clear, you need to add the count to the CTE, not the outer query. The outer select is returning only one row, so the count would always be one.
The CTE should start:
WITH MyCTE
AS (
SELECT T.MusicAlbumTitle
,D.musicTitle
,D.mVideoID
,D.musicFileName
,T.ReleaseDate AS ReleasedDate
,D.MusicLength
,D.musicSinger
,D.MusicVideoID
,D.ExternalLink
,D.CoverImg
,ROW_NUMBER() OVER (
PARTITION BY D.MusicVideoID ORDER BY D.mVideoID
) AS row_num,
COUNT(*) over () as total_count