Finding the list of people who have birthday this week - sql

Question

I am trying to list the people who have birthday this week with this code:
declare #START_DATE date;
set #START_DATE = DATEADD(dd, 1 - DATEPART(dw, getdate()), getdate())
declare #END_DATE date;
set #END_DATE = DATEADD(dd,6, #START_DATE)
set DATEFIRST 1
SELECT #START_DATE as StartDate, Personel.DogumTarihi , #END_DATE as EndDate
,[Adi]
,[Soyadi]
,[BirimAdi]
,[DogumTarihi]
,[MudurlukAdi]
,[Gorevi]
,[CepTelefonu]
,[EvTelefonu]
from Personel
where (
DATEPART(m, Personel.DogumTarihi) = DATEPART(m, #START_DATE)
and DATEPART(DAY, Personel.DogumTarihi) >= DATEPART(DAY, #START_DATE)
and DATEPART(DAY, Personel.DogumTarihi) <= DATEPART(DAY, #END_DATE)
)
OR (
DATEPART(m, Personel.DogumTarihi) = (DATEPART(m, #START_DATE)+ 1)
and DATEPART(DAY, Personel.DogumTarihi) <= DATEPART(DAY, #END_DATE)
)
First I set the start date and calculate the end date according to start date. Then I set Monday as the first day of week.
But everytime I run this, I receive a different Start date. I am quite new to Ms Sql Scripting, I may be doing sth wrong in the declarations but I couldn'd find it. Thanks in advance.

Answer 1

Try this:
SELECT DATEADD(WEEK, DATEDIFF(DAY, 0, GETDATE())/7, 0) FirstDayOfCurrentWeek,
DATEADD(YEAR, DATEDIFF(YEAR, DogumTarihi, GETDATE()), [DogumTarihi]) BirthdayThisYear,
DATEADD(WEEK, 1, DATEADD(WEEK, DATEDIFF(DAY, 0, GETDATE())/7, 0)) FirstDayOfNextWeek
,[Adi]
,[Soyadi]
,[DogumTarihi]
,[BirimAdi]
,[MudurlukAdi]
,[Gorevi]
,[CepTelefonu]
,[EvTelefonu]
FROM Personel
WHERE DATEADD(YEAR, DATEDIFF(YEAR, [DogumTarihi], GETDATE()), [DogumTarihi]) >= DATEADD(WEEK, DATEDIFF(DAY, 0, GETDATE())/7, 0)
AND
DATEADD(YEAR, DATEDIFF(YEAR, [DogumTarihi], GETDATE()), [DogumTarihi]) < DATEADD(WEEK, 1, DATEADD(WEEK, DATEDIFF(DAY, 0, GETDATE())/7, 0))

Answer 2

ok, one more attempt:
where
case when year(#START_DATE) = year(#END_DATE) THEN '1' ELSE CASE WHEN month(#birthdate) = 12 THEN '0' WHEN month(#birthdate) = 1 THEN '1' ELSE '9' END END
+ RIGHT('0' + CONVERT(varchar(2), MONTH(#birthdate)),2)
+ RIGHT('0' + CONVERT(varchar(2), DAY(#birthdate)),2)
between
case when year(#START_DATE) = year(#END_DATE) THEN '1' ELSE '0' END
+ RIGHT('0' + CONVERT(varchar(2), MONTH(#START_DATE)),2)
+ RIGHT('0' + CONVERT(varchar(2), DAY(#START_DATE)),2)
and
'1'
+ RIGHT('0' + CONVERT(varchar(2), MONTH(#END_DATE)),2)
+ RIGHT('0' + CONVERT(varchar(2), DAY(#END_DATE)),2)

Answer 3

sql should let you specify the week directly
DATEPART(ww,GETDATE())
or in oracle: to_char( mydate, 'ww' )

Answer 4

In order to cope with the my problem I revised the code above according to answers:
set DATEFIRST 1
declare #START_DATE date;
set #START_DATE = DATEADD(dd, 1 - DATEPART(dw, getdate()), getdate())
declare #END_DATE date;
set #END_DATE = DATEADD(dd,6, #START_DATE)
SELECT #START_DATE as StartDate,
(case when
(DATEPART(m, #START_DATE) = DATEPART(m, #END_DATE))
then
(case when (DATEPART(DAY, Personel.DogumTarihi) >= DATEPART(DAY, #START_DATE) and DATEPART(DAY, Personel.DogumTarihi) <= DATEPART(DAY, #END_DATE)) then Personel.DogumTarihi else 0 end)
else
(case when DATEPART(m, Personel.DogumTarihi) = DATEPART(m, #START_DATE)
then
(case when (DATEPART(DAY, Personel.DogumTarihi) >= DATEPART(DAY, #START_DATE)) then Personel.DogumTarihi else 0 end)
else
(case when (DATEPART(DAY, Personel.DogumTarihi) <= DATEPART(DAY, #END_DATE)) then Personel.DogumTarihi else 0 end)
end
)
end),
#END_DATE as EndDate, [TCKN]
,[Adi]
,[Soyadi]
,[BirimAdi]
,[DogumTarihi]
,[MudurlukAdi]
,[Gorevi]
,[CepTelefonu]
,[EvTelefonu]
,[VakifTelefonu]
from Personel where
DATEPART(m, #START_DATE) = DATEPART(m, #END_DATE)
OR DATEPART(m, Personel.DogumTarihi) = DATEPART(m, #START_DATE)
OR DATEPART(m, Personel.DogumTarihi) = DATEPART(m, #END_DATE)
Now it is taking the case where "the start and end date of the month are in the same week (like this week)" into account. It looks like it is bringing right results..

Answer 5

Let's have a try:
declare #today datetime
set #today = getdate()
-- erase the hours
set #today = dateadd(hh, -datepart(hh, #today), #today)
-- erase the minutes
set #today = dateadd(mi, -datepart(mi, #today), #today)
-- erase the seconds
set #today = dateadd(ss, -datepart(ss, #today), #today)
-- erase the milliseconds
set #today = dateadd(ms, -datepart(ms, #today), #today)
-- go to start of current week (sunday!)
set #today = dateadd(dd, 1-datepart(dw, #today), #today)
select * from MYTABLE
where DATECOL between
dateadd(yy, datepart(yy, DATECOL) - datepart(yy, #today), #today) and
dateadd(d, 7, dateadd(yy, datepart(yy, DATECOL) - datepart(yy, #today), #today))
Apparently SqlServer 2012 has a DATEFROMPARTS function, in 2005 we will have to use this roundabout way to trim a date.
To select a birthday, I exchange the "today's year" for the record's year. For the end-date of the range I add 7 days to that. Note that you want to search from sunday 0:00 to saturday 23:59.
This will probably still fail if halfway during the week a new year starts and the birthday you want is in the new year.