I am having troubles converting a short Zulu date format to a NSDate Object. I have found some answers for converting Zulu strings but mine looks like:
20111210T1000
And based on my researches, I am trying to do:
NSDateFormatter *f = [[NSDateFormatter alloc] init];
[f setDateFormat:#"yyyyMMdd'T'HHmmss Z"];
NSDate *date = [f dateFromString:[str stringByReplacingOccurrencesOfString:#"Z" withString:#" +0000"]];
[f release];
I've tried many ways but my date is still nil...
How should I set my NSDateFormatter?
Here is a quick fix, in your date string you miss the timezone in the format, you should append (Paris one here) to your string and it should work. Also the format was wrong.
NSDateFormatter* df = [[NSDateFormatter alloc]init];
[df setDateFormat:#"yyyyMMdd'T'SSSZ"];
NSString* str = #"20111210T1000-0100"; // NOTE -0100, GMT +1 Paris zone
NSDate* date = [df dateFromString:str];
NSLog(#"%#", date);
Related
I have a date string formatted as "September 10, 2013". How can I convert this representation into a format such as "yyyy/mm/dd".
NSString *strDate = #"September 10, 2013";
NSDateFormatter *df = [[NSDateFormatter alloc] init];
[df dateFromString:strDate];
NSDate *date = [df dateFromString:strDate];
[df setDateFormat:#"yyyy/mm/dd"];
NSString* temp = [[NSString alloc] init];
temp = [df stringFromDate:date];
NSLog(#"date i required %#", temp);
temp object is null here.
Thanks in advance.
Let's rework your original code, and discuss it as well:
NSString *strDate = #"September 10, 2013";
NSDateFormatter *df = [[NSDateFormatter alloc] init];
For the input you're attempting to parse, you've got to provide a format string for your date formatter. If you don't, the date formatter is going to use defaults that are determined by the settings in your Date & Time control panel. Not only do these settings vary from locale to locale, they're subject to whatever changes the user may have effected. Another way of putting it is that they might not match the format of the date string you're attempting to convert.
You also don't want to rely on predefined styles such as NSDateFormatterShortStyle, NSDateFormatterMediumStyle or NSDateFormatterLongStyle. They're meant for date display (if you're willing to accept the Date & Time control panel settings), not for parsing.
There's a document you should consult, which is Unicode Technical Standard #35. Look in the table labeled "Date Field Symbol Table." Based on the information presented there (and your input), you'd set up your date converter to parse with a format string like this one:
[df setDateFormat:#"MMMM dd, yyyy"];
Now you can use your date formatter to parse your date string, and it'll work:
NSDate *date = [df dateFromString:strDate];
From this point onward, you're looking pretty good (though I've removed a superfluous line or two throughout all of this):
[df setDateFormat:#"yyyy/MM/dd"];
NSString *temp = [df stringFromDate:date];
NSLog(#"date i required %#", temp);
Best wishes to you in your endeavors.
You can use the NSDateFormatterclass -- look at the stringFromDate and dateFromString methods.
UPDATE: you have a couple of problems -- first, you need to tell the formatter what the initial format should be. Second, you have a format problem with the second format string -- 'm' is minutes, 'M' is months. You should review the documentation here. Here is an example:
NSString *strDate = #"September 10, 2013";
NSDateFormatter *df = [[NSDateFormatter alloc] init];
[df setDateStyle:NSDateFormatterLongStyle];
[df dateFromString:strDate];
NSDate *dat = [df dateFromString:strDate];
[df setDateFormat:#"yyyy/MM/dd"];
NSString* t = [df stringFromDate:dat];
NSLog(#"date i required %#", t);
I have a timestamp coming from server that looks like this:
2013-04-18T08:49:58.157+0000
I've tried removing the colons, I've tried all of these:
Converting an ISO 8601 timestamp into an NSDate: How does one deal with the UTC time offset?
Why NSDateFormatter can not parse date from ISO 8601 format
Here is where I am at:
+ (NSDate *)dateUsingStringFromAPI:(NSString *)dateString {
NSDateFormatter *dateFormatter;
dateFormatter = [[NSDateFormatter alloc] init];
//#"yyyy-MM-dd'T'HH:mm:ss'Z'" - doesn't work
//#"yyyy-MM-dd'T'HH:mm:ssZZZ" - doesn't work
//#"yyyy-MM-dd'T'HH:mm:sss" - doesn't work
[dateFormatter setDateFormat:#"yyyy-MM-dd'T'HH:mm:ss'Z'"];
[dateFormatter setTimeZone:[NSTimeZone timeZoneWithName:#"GMT"]];
// NSDateFormatter does not like ISO 8601 so strip the milliseconds and timezone
dateString = [dateString substringWithRange:NSMakeRange(0, [dateString length]-5)];
return [dateFormatter dateFromString:dateString];
}
One of my biggest questions is, is the date format I have above really ISO 8601? All the examples I have seen from people the formats of each are slightly different. Some have ...157-0000, others don't have anything at the end.
This works for me:
NSString *dateString = #"2013-04-18T08:49:58.157+0000";
NSDateFormatter *formatter = [[NSDateFormatter alloc] init];
[formatter setDateFormat:#"yyyy-MM-dd'T'HH:mm:ss.SSSZ"];
// Always use this locale when parsing fixed format date strings
NSLocale *posix = [[NSLocale alloc] initWithLocaleIdentifier:#"en_US_POSIX"];
[formatter setLocale:posix];
NSDate *date = [formatter dateFromString:dateString];
NSLog(#"date = %#", date);
There is New API from Apple! NSISO8601DateFormatter
NSString *dateSTR = #"2005-06-27T21:00:00Z";
NSISO8601DateFormatter *formatter = [[NSISO8601DateFormatter alloc] init];
NSDate *date = [formatter dateFromString:dateSTR];
NSLog(#"%#", date);
I also have the native API, which is way cleaner... This is the implementation I got in my DateTimeManager class:
+ (NSDate *)getDateFromISO8601:(NSString *)strDate{
NSISO8601DateFormatter *formatter = [[NSISO8601DateFormatter alloc] init];
NSDate *date = [formatter dateFromString: strDate];
return date;
}
Just copy and paste the method, it would do the trick. Enjoy it!
The perfect and best solution that worked for me is:
let isoFormatter = ISO8601DateFormatter();
isoFormatter.formatOptions = [ISO8601DateFormatter.Options.withColonSeparatorInTime,
ISO8601DateFormatter.Options.withFractionalSeconds,
ISO8601DateFormatter.Options.withFullDate,
ISO8601DateFormatter.Options.withFullTime,
ISO8601DateFormatter.Options.withTimeZone]
let date = isoFormatter.date(from: dateStr);
For further more detail, you can refer to apple's official documentation: https://developer.apple.com/documentation/foundation/nsiso8601dateformatter
I'm having problems converting a string into a NSDate object and I'm not sure why.
NSString* tester= #"2012-11-26T10:20:40.187";
NSLog(#"", tester); //Print the Date String
NSDateFormatter *formatter = [[NSDateFormatter alloc] init];
[formatter setDateFormat:#"yyyy'-'MM'-'dd'T'HH':'mm':'ss'Z'"];
NSDate *date = [formatter dateFromString:tester]; //Store the date
NSDateFormatter *output = [[NSDateFormatter alloc] init];
[output setDateStyle:NSDateFormatterMediumStyle];
NSLog(#"DATE OBJECT:%#\nDATE STRING: \"%#\"", [output stringFromDate:date]); //Print the NSDate object and the string
But all I seem to get is:
DATE OBJECT:(null)
DATE STRING: "2012-11-26T10:20:40.187"
I figure it has something to do with the .187 but I'm not sure. I'm sorry if this is a duplicate but I couldn't figure this out.
Thank you very much in advance!
The abbrevation for milliseconds is "S"not Z which is TimeZone.
It seems that you have read the correct document where that example is from, but
you missed the link to the Unicode Technical Standard #35.
See NsDateFormatter Docu, search for "Formatters in Mac OS X v10.4 use version tr35-4."
try that below:
[formatter setDateFormat:#"yyyy'-'MM'-'dd'T'HH':'mm':'ss.SSS"];
See also NSDateFormatter Question
I have a string "2012-06-04" and am having a hard time converting it to: June 4, 2012.
Is there a quick way to transform this? I come from a ruby world where you would convert everything to seconds and that back out to the format you need it. Is there a reference that shows how to do that?
Thanks
One way to do so is to convert the string to an NSDate using the NSDateFormatter with the 2012-06-04 format, and then convert the NSDate back to a string using the June 4, 2012 format:
NSString* input = #"2012-06-04";
NSDateFormatter* df = [[NSDateFormatter alloc] init];
[df setDateFormat:#"yyyy-MM-dd"];
NSDate* date = [df dateFromString:input];
[df setDateFormat:#"MMMM d, yyyy"];
return [df stringFromDate:date];
The format string's syntax is described in UTS #35.
Something like
NSDateFormatter *fromDateFormatter = [[NSDateFormatter alloc] init];
fromDateFormatter.dateFormat = #"yyyy-MM-dd";
NSDate *date = [fromDateFormatter dateFromString:#"2012-06-04"];
NSLog(#"%#", date);
NSDateFormatter *toDateFormatter = [[NSDateFormatter alloc] init];
toDateFormatter.dateFormat = #"MMMM d, yyyy";
NSString *toDate = [toDateFormatter stringFromDate:date];
NSLog(#"%#", toDate);
#=> 2012-05-30 20:51:12.205 Untitled[1029:707] 2012-06-03 23:00:00 +0000
#=> 2012-05-30 20:51:12.206 Untitled[1029:707] June 4, 2012
To work this out you can use Apple's class references NSDateFormatter and other sources like this IPHONE NSDATEFORMATTER DATE FORMATTING TABLE and some trial and error
I have this string: 2012-01-12T21:01:00 and this code:
NSDateFormatter *df = [[NSDateFormatter alloc] init];
[df setDateFormat:#"yyyy-MM-dd hh:mm:ss a"];
NSDate* arrivalTime=[df dateFromString:field_arrival_time];
But it returns nil. What date format should I use to parse this string?
Your string 2012-01-12T21:01:00 contains the literal T (At least I believe it's a literal, it doesn't appear to signify a timezone). You must include this in your date format.
[df setDateFormat:#"yyyy-MM-dd'T'hh:mm:ss"];
Note the lack of the a in the date format, using it will require your input string to use AM or PM preceded by a white space. For more information on special characters with NSDateFormatter take a look at the Date Formatting Guide paying extra attention to the Fixed Formats.
Edit: Your input string does not specify a timezone, it will probably be interpreted as UTC and be localized to the timezone of your machine when you output it through NSLog().
I have tried a lot on your string but never get result. only nil shows on console. but when i remove character "T" from your string it gives perfect result.
[f setDateFormat:#"yyyy-MM-dd HH:mm:ss"];
NSDate *date = [f dateFromString:#"2012-01-12 21:01:00"];
NSLog(#"date %#", date);
NSDateFormatter *f2 = [[NSDateFormatter alloc] init];
[f2 setDateFormat:#"dd-MM-yyyy"];
NSString *s = [f2 stringFromDate:date];
NSLog(#"S %#", s);
/// OutPut : S 12-01-2012