How can I do a count distinct selection? Basically I have all these charges and I want to count only the number of distinct employees involved with that charge. (I already have other fields for the group by)
SELECT COUNT(DISTINCT employeeid) FROM ....
Simple as: select count(distinct(field)) from table
Live sample: http://sqlfiddle.com/#!3/81379/2/3
You can put a DISTINCT in a COUNT (in TSQL):
SELECT COUNT(DISTINCT(employee)) ...
Related
I need to sum the result of count of a column in one query.
Is it possible to have like this query?
SELECT sum(count(pro_id)) from jalasat group by pro_id
You have not mentioned which SQL database you are using so you may modify this slightly to fit it to what you are using:
SELECT SUM(cnt) FROM (SELECT COUNT(pro_id) as cnt
FROM jalasat
GROUP BY continent) as t1
I want to count the number of ABC group using id.
SELECT group, count(id) as total FROM `user` WHERE group=`ABC`;
What's wrong?
Many thanks.
Include the columns in the select list in group by clause when using aggregate functions.
SELECT group, count(id) as total FROM user
WHERE group=`ABC`
GROUP BY group
Else simply get the count with out using other columns in the select statement.
SELECT count(id) as total FROM user
WHERE group=`ABC`
Try this:
SELECT group, count(id) as total FROM `user`
group by group having group like 'ABC';
If you want to get COUNT of users, who has the "group" field = "ABC"
SELECT count(id) as total FROM user WHERE group='ABC';
Also, it's better to avoid using SQL keywords in column names (GROUP is an SQL keyword)
I would like to combine these two SQL queries into one.
SELECT COUNT() as total_grants, SUM("CURRENT_AWARD") as total_spent FROM t;
SELECT YEAR, COUNT(), SUM('CURRENT_AWARD') FROM t GROUP BY YEAR AS by_year;
The first query shows the total number of grants, and the total spent. The second is the same, but by year.
Is this possible? I've already combined two queries into one in the first query, but I can't figure out how to use an AS clause properly in the second query.
Thanks for any help.
How about using CROSS JOIN
SELECT YEAR,
COUNT(*),
SUM('CURRENT_AWARD') ,
t2.total_grants,
t2.total_spent
FROM t
CROSS JOIN
(
SELECT COUNT(*) as total_grants,
SUM("CURRENT_AWARD") as total_spent
FROM t
) t2
GROUP BY YEAR;
Maybe something like this?
SELECT BY_YEAR, COUNT(), SUM('CURRENT_AWARD') FROM t GROUP BY rollup(by_year);
(I think rollup can be rdbms/version dependent...)
Try this.
SELECT YEAR, COUNT(*) as total_grants, SUM(CURRENT_AWARD) as total_spent
FROM t
GROUP BY YEAR;
COUNT(*) will count all rows in table t, including ones with NULL. If you want to ignore rows with NULL, count a specific column. For example, COUNT(CURRENT_AWARD).
You don't need the quotes around CURRENT_AWARD since this identifier contains only letters and underscores.
Looking for sql to get distinct names and count of those names from a sql table:
Structure:
id
name
other details
Do I use distinct to get each group and then count through those to get:
name1 count(name1)
name2 count(name2)
etc
Thanks
Rob.
When you want a COUNT() or a SUM(), you're using an AGGREGATE FUNCTION based on a GROUP BY clause.
As GROUP BY brings together all records with the same values specified in the GROUP BY columns, you're already getting the same effect as DISTINCT.
Except that DISTINCT doesn't allow aggregates, and GROUP BY does.
SELECT
name,
COUNT(*) AS count_of_name
FROM
yourTable
GROUP BY
name
Try :
SELECT *, COUNT(*) FROM my_table GROUP BY name
Something like this?
select name,COUNT(name) FROM Persons GROUP BY name
In the end I used:
SELECT DISTINCT `school`,COUNT(`school`) AS cat_num FROM table GROUP BY school order by cat_num DESC
I'm currently doing this query to find the guy who makes the most calls:
SELECT
`commenter_name`,
COUNT(*) AS `calls`
FROM `comments`
GROUP BY `commenter_name`
ORDER BY `calls` LIMIT 1
What I want now is to be able to find out how many total unique callers. I tried using DISTINCT but I didn't get anywhere.
SELECT COUNT(DISTINCT 'commenter_name') FROM 'comment';
SELECT DISTINCT `commenter_name` FROM `comments`
Select Count(*) From (Select DISTINCT commenter_name from comment) as CmtCnt;